4th Column In Listbox As Percentage

Jul 22, 2014

I have a four column listbox where 4th column is percentage. In my source worksheet cells are formatted as percentage but when this is displayed in list box it shows approximately 10 decimals or maybe even more. How can I change my code only to show two decimals in 4th column?

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im trying to create a two column listbox that will transfer both columns to the listbox on the right and also transfer from the right to left currently right to left works but when I trasnfer from the left to right then the right to left only one column is moved.

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I want to track a friendly competition of squash games with a friend.

player1
player2
January

[Code].....

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i'm trying to crack what should surely be a simple problem. Attached is my spreadsheet.

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I have an excel spread sheet with columns of dates I am trying to get an average formula that counts dates less than a year old as 1 and blank cells and dates greater than a year old as 0 and then gives me a percentage. For example I have a column with 10 dates all less than 1 year old I would get 100% but if I had a column with 8 dates less than a year old and 1 dates older than a year, and 1 blank cell, I would get 80%

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Feb 8, 2008

I am trying to set up a listbox on a userform that will draw from 2 columns. The first column is an abbreviation of the phrase in the second column as shown below. When the user clicks the listbox arrow I want them to see the descriptor of the 1 - 3 character code since they are not always intuitive. When the selection is made I want the form to capture only the code.

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I have a single column of numerical values that may repeat many times within
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I require a flexible Formula:
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Column may be filtered – so only take into account Visible Filtered Cells.

The Formula will calculate and Return the numerical range of values that fall
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The Formula should Return two numeric values: a Start Value and an End Value
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The calculated Results: the two numeric values will be returned to separate
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This is my code:

VB:
Set R = WS3.Range("A:A").SpecialCells(xlCellTypeConstants)
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[Code].....

the third column is a time, and is showing up in the actualy listbox as a decimal rather than a time. How do you show at time(ex 12:42 PM)?

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I have tried this:

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Or:

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I have tried theproperties on the list box itself but it just resets,
I reckon this code controls the size,shape,location of the list box.

Option Explicit

Private Sub CheckBox1_Click()
If CheckBox1 Then
ListBox1.Visible = True
Else
ListBox1.Visible = False
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End Sub

Private Sub ListBox1_DblClick(ByVal Cancel As MSForms.ReturnBoolean)
Dim Target As Range
Dim MySel As Range

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i think this is because i am using the additem command.

can anyone suggest a way around this or alternative coding method??

Sub cmbFindAll_Click()
Dim strFind As String 'what to find
Dim rFilter As Range 'range to search
Set rFilter = Sheet1.Range("a2", Range("f65536").End(xlUp))
Set rng = Sheet1.Range("a2", Range("a65536").End(xlUp))
strFind = Me.TextBox1.Value
With Sheet1
If Not .AutoFilterMode Then .Range("A2").AutoFilter
rFilter.AutoFilter Field:=1, Criteria1:=strFind & "*"......................

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I am having trouble returning the value of the second column in a listbox.

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With UserForm3
With .ListBox1
.Clear
.ColumnCount = 2
.List = Application.Transpose(vaData)
.ListIndex = -1
End With
.Show vbModeless
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[Code] .....

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