Set 2 Column Listbox To Return 1st Column Value

Feb 8, 2008

I am trying to set up a listbox on a userform that will draw from 2 columns. The first column is an abbreviation of the phrase in the second column as shown below. When the user clicks the listbox arrow I want them to see the descriptor of the 1 - 3 character code since they are not always intuitive. When the selection is made I want the form to capture only the code.

IP In Progress
AMAwaiting Materials
ADAwaiting Design
CPCompleted.

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Lookup/Match: Compare A1 For The Values In Column B, Then Return The Corresponding Cell (column C) In Column D

Jan 31, 2008

I've been searching the forums for this problem but I can't seem to find any answers. Anyway, this is the problem. See screenshot.

I want to compare A1 for the values in column B, then return the corresponding cell (column C) in column D.
e.g. D1 = 2, D2 = 1, D3 = 4, D4 = 5 and D5 = 3.

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Jun 30, 2014

I have a listbox with 8 columns. Multiselect is enabled, and it must stay this way. As part of my program, after the user presses a command button, I need to use the row indexes of the selected rows in order to copy the selected information into an array which is then placed in a different listbox, and then delete the items from the original list. Pseudocode of what I want to do:

[Code] .....

But my understanding is that .ListIndex does not work this way with multiselect listboxes. I've tried searching for a solution for a while, but I cannot find one.

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Apr 4, 2014

im trying to create a two column listbox that will transfer both columns to the listbox on the right and also transfer from the right to left currently right to left works but when I trasnfer from the left to right then the right to left only one column is moved.

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Jun 7, 2014

I am trying to use a nested INDEX and MATCH array formula to return the value in column C when matching column A and column B, but with a few more criteria.

The range containing all the data

A
B
C

1
Cat 1
January 1, 2014
John

[Code] ..........

I am looking for the array formula to return the name of the person in column C who is in Cat 1 after the date in column B.

For example;
C7 should return "John" because B7 requests "January 15, 2014", which is after the value in B1
C8 should return "John" because B8 requests "February 15, 2014", which is after the value in B1
C9 should return "Andrew" because B9 requests "August 15, 2014", which is after the value in B4

The best try I had for the formula in C7 was

{(INDEX($A$1:$C$4,MATCH(1,($B$1:$B$4>=B7)*(A$1:$A$4=A7),0),3))}

This brings back "John" as desired in C7, but when copying down the table into C8 and C9 both C8 and C9 return Andrew.

I guess this is due to my ">=" condition in the Match formula and it is returning "Andrew" because "Andrew" is also after the date requested, but I cannot for the life of me work out how to get it to work.

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Feb 28, 2014

I have a spreadsheet of several thousand named items (in column B) with values associated with them in column A). The "name" field is a string of several alternative names for the item.

I have a list of ~50 items that I am trying to find the values for. Each uses one of the alternate names.

What I want is a function that will return the associated value in column A when one of my shortlist names is found.

For example, my big spreadsheet looks like:

AB
1dallas, DFW. 12345
2Atlanta, ATL, 23456
3Boston, BOS, 34567
4Chicago, CHI, 45678
5Los Angles, LA, LAX, 56789

And my list looks like

Atlanta
CHI

I want the output to look something like:

Atlanta2
CHI 4

Is the feasible? IT seems like there should be a way to do it....

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Feb 7, 2014

I have the following sample data set and I'm trying to return the appropriate column header based on criteria (i.e. DDD) and a number value which will be somewhere within the range of the table. In example below, the value returned should be Header 2 because the value is greater than those in Header 1 column (range H9 to L26).

Here's data table:

CriteriaHeader 1Header 2Header 3Header 4
ZZZ5.0015.0050.00130.00
ZZ5.0015.0050.00130.00
Z5.0015.0050.00130.00
YYY5.0015.0050.00130.00
YY5.0015.0050.00130.00
Y5.0015.0050.00130.00
DDD5.0015.0050.00130.00
DD5.0015.0025.0075.00
D5.0015.0020.0065.00
RRR5.0015.0015.0045.00
RR2.5010.0010.0030.00
R1.503.0010.0025.00
UUU0.751.505.0020.00
UU0.751.505.0020.00
U0.751.505.0020.00
P0.751.505.0020.00
T0.100.105.0018.00

CriteriaNumberValue
DDD10.00Header 1>>>=INDEX($I$9:$L$9,MATCH(I29,INDEX($I$10:$L$26,MATCH(H29,$H$10:$H$26),)))

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Jun 5, 2009

I have a tab that has 2 columns of data and I want to be able to return a value in column A if my data matches column B. If column B has the text TRUETRUE, I want to bring back the corresponding data in Column A. How do I return all the data in Column A for all the TRUETRUEs in column B? I can only get the first instance of TRUETRUE.

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Feb 19, 2009

I'm creating a macro that creates a co-ocurrence matrix from variables that are adjacent to each other.

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Dec 16, 2013

I have an array 20 Rows x 42 Columns, which contains a competition draw.

I need to search this array for a unique value and return whatever the time is in the first column on the same row as the value appears, and enter it into column C in the Womens Times sheet.

I also want to return into column D the court number from row 3.

The reason i want this automated is as teams enter / withdraw we may need to drag the games from court to court to fill gaps, so i want the Womens Times sheet to update accordingly.

I have been messing around with index and match, but cannot quite get it to return what i need.

I have attached an example ... on the sheet "Womens Times" in column A there is a list of game numbers ( #1W etc etc) indicating womens game #1 and so on. The main sheet i am using also has a seperate tab for the mens games, hence the designator of W or M on the end of the game number.

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Jan 23, 2014

I need the searchable list box to return data one column to the right of the "searched" column data.

This works mostly with Data Validation.

Named range "validationlist" with "=OFFSET(Choice!$AC$4,,,COUNTIF(Choice!$AC$4:$AC$14,"?*"))"

D9 has a drop down control. Enter the cell and type "br" and click the drop down arrow. Mouse to choose an item from the list box. If you chose "brown" , it will be entered in the cell. The returned item should be "banana" from the other column. How to do this?

Once working the control needs to be used across the row in more cells: E9, F9... all the way out to W9. And there has will be a Lookup to pull data from elsewhere above D9.

This worksheet ultimately needs to be uploaded to Skydrive and used as a collaborative worksheet as a 'web app'.

See attachment and formula output below.

[Code]............

searchableListBox-EF1.xlsx‎

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Jun 8, 2009

I am trying to get a formula that will search one column range “B” and pull data from another, “D”. Dates are down column “B” and some of those dates are repeated several times. In column “D” there is only one piece of data (a number) entered for each day. Eg, if 08/06/2009 has been entered 3 times in column “A”, there will only be data entered in 1 of the cells of column “D” and blank cells in the other 2.

Column B -- Column D
07/06/09 -- 54000
08/06/09
08/06/09 -- 62000
08/06/09
09/06/09 -- 61000

I couldn’t get the LOOKUP function to work properly, as there are duplicate dates in column “B” and I often got a result of 0 returned.

As I’ve only got 1 piece of data added in column “D” per day and any duplicate days would just have blank cells in “D”, I can actually get a SUMIF function to work, SUMIF(B3:B60,DATE(2009,6,8),D3:D60). Although it does work, it doesn’t feel right using it and I would prefer a formula that would return just the one cell, instead of the sum of a range of cells.

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I want to get value from reference one column and return value by corresponding row from another column. This can be done by vlookup column. But it find value from 1st column and return value from given relative column. That mean find from Left column and return value from right side given column number.

But I want find from Given column number and return value from given left column. For Further detail see the Attached file.

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Sep 18, 2012

I need a formula to return column header if there is data in the column, any data.But I also need to return the second, third, fourth header with data too

In column A row 2, I have =IF(M8"",$M$1,IF(N8"",$N$1,IF(O8"",$O$1,IF(P8"",$P$1,IF(Q8"",$Q$1,IF(R8"",$R$1,IF(S8"",$S$1,IF(T8"",$T$1,""))))))))

This returns the row 1 header for the first instance of data in row 2 columns M thru T But in B2, I need the second header with data in the column.

I need the results in yellow (1st, 2nd, 3rd, 4th) from the array to it's left

1St match2nd 3rd 4thColumn MColumn NColumn OColumn PColumn QColumn R
Column MColumn PColumn QData data2Data3
Column NColumn OColumn PColumn R Data Data2 data3 data4

Would use match/index but can't increment it to the second or 3rd match

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Also need to do this same operation with first column (state) and third column, which also is comprised of non-unique numbers.

Hlookup, lookup & pivot tables seem to not be a fit for this.

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=IF(ISNUMBER(VLOOKUP($E8,Su!$D:$K,7,FALSE)),VLOOKUP($E8,Su!$D:$K,7,FALSE),)*$I8

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Sep 3, 2008

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Jan 30, 2008

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Is it as simple as:

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If(...........)

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This is my code:

VB:
Set R = WS3.Range("A:A").SpecialCells(xlCellTypeConstants)
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[Code].....

the third column is a time, and is showing up in the actualy listbox as a decimal rather than a time. How do you show at time(ex 12:42 PM)?

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