Amendments In Function Convert Digits To Words (US Dollar)
Nov 1, 2009
Before I got this Function from your Form to convert digit to words.
Function is as following..right now i m getting as following:-
If i type 123..i m getting one Hundred twenty Three with this script as below.
But i want US Dollar one Hundred Twenty Three..
Can any one add the word "US Dollar" in this script.
Script..
Function English(ByVal N As Currency) As String
Const Thousand = 1000@
Const Million = Thousand * Thousand
Const Billion = Thousand * Million
Const Trillion = Thousand * Billion
How to convert any types format into Text with 5 digits in selection?
For instance, the content I select is "234", and I want it to convert to "00234". Just like the function "TEXT" in excel. How can I realize it promptly in VBA?
For my research in medicine I build a spreadsheet with google docs. After having received most of the data I transfered the spreadsheet into an excel file. The next thing I would like to do is to convert the words in the spreadsheet into numbers so I can calculate with them. For example: every row in column E consist of one of the two words: 'man' or 'woman'. I would like to convert the word 'man' into a '0' and the word 'woman' into a '1'. Is it possible to write a formula or function for this?
Note : It works for a value having two decimal places. It truncates if you have a value having more than two decimal places. Note : The following formula can convert amount one less than 1 trillion into words.
For example : $ 1,250.50 = One Thousand Two Hundred Fifty Dollars and Fifty Cents
I am trying to create a unique sample code by putting together the values of other cells that a user will input. It's all working well apart from the last part, where I am trying to include a decimal number. I want the decimal number to appear without the central "." and in a four digit format. e.g. 2.5 would appear as 0250, 14.25 would appear as 1425. This is the formlua I am using currently:
However, where the value of H4 is 2.5, I am getting a result of 0303 (I've put this part in bold). I have attached a small spreadsheet to aid understanding.
I am using the extract words function outline here [url]
I copied and pasted the function into a new sub and deleted the sub module1 and the end sub to make sure it is it own function I can call. I have called it in another macro I wrote and when I run the macro it bugs out at the first if statement. The code it has a problem with the Get_Word code below. It throws a "Run-time error: '1004': unable to get the Find property of the WorksheetFunction class."...
I have an issue with VLOOKUP. By runnig VLOOup we can get the data that there is present in a specified range. But how about to get the data DISPLAYED which is not there in the specified range. I tried combining IF and VLOOKUP functions. I am on a simple project now and I would be happy if I could get the answer immeidately
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I've been working on a method to search a single column of 1000+ cells containing a paragraph with a 250+ word keyword list (also in a single column). I'm needing only complete words to be searched/ displayed regardless of spacing & punctuation. I've tried multiple methods the past few days and the one that worked (Macro with 4 complex formulas) was unusable when scaled out to all 1,000 rows due to the extremely long calculating time. I don't know VBA yet but was able to modify and create a user defined function that does everything I need except it displays string results that are not whole words (Ex. search for air, word in cell is fair, displays a result for air).
PHP Code:Â
Function RangeSearch2(text As String, wordlist As Range, seperator As String, Optional caseSensitive As Boolean = False)    Dim strMatches As String    Dim res As Variant    Dim arrWords() As String    Dim skip As Boolean    skip = False    On Error Resume Next    Err.Clear    For Each word In wordlist            If caseSensitive = False Then     Â
I'm trying to write UDF which getting RegEx pattern and a certain cell as arguments and returns only matching string. For examples for string "The quick brown fox jumps over the lazy dog", and RegEx pattern "w{4}" the function will return two words "OVER" and "LAZY". What should I change in my code?
Function GetPattern(myPattern As String, myString As String) Dim regEx As RegExp Dim Matches As Object Set regEx = CreateObject("VBScript.RegExp")
With regEx .Pattern = myPattern .IgnoreCase = True End With GetPattern = regEx.Replace(myString, "$1") End Function
I want to have a few words shown based on figures in specific cells. I not quite sure how to explain, but i will try my best:
A1 = 5 A2 = 0 A3 = 7
The function i am using looks something like this:-
=IF(A1<6,"Do I Have Sickness Self Cert?","Do I Have Doctor's Paper?")
However, by using this function, if the cell is empty it still shows the first wording when i need it to show lets say between 1 & 6 shows the first wording and more than 6 shows the second wording! If you know what i mean... I know what i want to do but cant really explain it very well.
Maybe it should look something like this but it does not work the way i am doing it.
=IF(E156>1<6,"Do I Have Sickness Self Cert?","Do I Have Doctor's Paper?")
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...). Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05 DuToitskloof Pinotage/Merlot/Ruby Cabernet 1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 2003 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2))) As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
I have a column of words in Column A and I want to replace all the times that these words appear in the rest of the excel sheet with the words in Column B. If someone has already answered a similar problem link me to the thread because I can't find anything.
I don't have a clue as to how to convert this to VBA code.
When installed as a macro, the function works fine in a cell on my PC, but when I send the file to another pc, it still gives the name of my pc. I need it to return the name of thier pc.
