Amendments In Function Convert Digits To Words (US Dollar)
Nov 1, 2009
Before I got this Function from your Form to convert digit to words.
Function is as following..right now i m getting as following:-
If i type 123..i m getting one Hundred twenty Three with this script as below.
But i want US Dollar one Hundred Twenty Three..
Can any one add the word "US Dollar" in this script.
Script..
Function English(ByVal N As Currency) As String
Const Thousand = 1000@
Const Million = Thousand * Thousand
Const Billion = Thousand * Million
Const Trillion = Thousand * Billion
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Nov 12, 2009
I keep seeing Right$(arg,arg) in VBA examples, but I am not sure what the dollar sign is doing.
Is it acting like a string declaration?
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Feb 2, 2010
this may be simple but I need to convent say
A1 = 09
B1 = 23
into
C1 = 0
D1 = 9
E1 = 2
F1 = 3
..etc
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Apr 24, 2009
Is there any formula to write digits convert into word ?
Eg: - Can 1020 Convert into "One thousand twenty" with the help of any formula ?
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Aug 19, 2014
How to convert any types format into Text with 5 digits in selection?
For instance, the content I select is "234", and I want it to convert to "00234". Just like the function "TEXT" in excel. How can I realize it promptly in VBA?
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Jun 7, 2006
How do I convert a list of downloaded zipcodes that preceed with zeroes into 5 digits?
i.e.
501 into 00501
and
1601 into 01601
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Aug 31, 2009
For my research in medicine I build a spreadsheet with google docs. After having received most of the data I transfered the spreadsheet into an excel file. The next thing I would like to do is to convert the words in the spreadsheet into numbers so I can calculate with them. For example: every row in column E consist of one of the two words: 'man' or 'woman'. I would like to convert the word 'man' into a '0' and the word 'woman' into a '1'. Is it possible to write a formula or function for this?
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Jun 1, 2014
Note : It works for a value having two decimal places. It truncates if you have a value having more than two decimal places. Note : The following formula can convert amount one less than 1 trillion into words.
For example : $ 1,250.50 = One Thousand Two Hundred Fifty Dollars and Fifty Cents
$1,250.50 is placed in cell B5.
Paste the following formula in cell C5.
source : [URL] .......
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Apr 9, 2008
Do any formulas can converts text to an anothers words ?
sample : if any words to ( LA CA LN & TN ) than Change to "USA"
Col: A will have the abnormal text .
Col: B want to consolidate that's to "US" if match with the certeria /
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Jul 1, 2008
In cell A1:A10 I have various words.
I am trying to convert them to a number assuming every letter = a number in sequence of the alphabet then is summed together. ie:
a=1, b=2, c=3, d=4 ............. z=26.
So the word Excel would equal 5+24+3+5+12 giving me the answer 49.
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Jan 17, 2008
how to convert figure into words eg 1250 (one thousand two hundred fifty only)
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Dec 23, 2013
how to convert dates to text without using addon, using VBA. like 23/12/2013 to Twenty third december, two thousand thirteen,
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Jun 20, 2014
how to convert numerical numbers to words in MS excel & MS world
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Jul 31, 2007
how can i do this in excel 2002?
for example.....
mod(95000000922019182020281000,97)=24
but in excel im getting the value as 0
also when i type the 24 digits its show like ..... # NUM!
if i put the function like =A1-FLOOR(A1,B1) its working for 13 digits but not for 24 digits.
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Apr 18, 2014
Formula that will convert uppercase words longer than three letters, into lowercase. Leaving the rest of the string unchanged?
For example,
Mary and John at IBM thought this was a GREAT OPPORTUNITY. Becomes:
Mary and John at IBM thought this was a great opportunity.
I have also tried using more func's REGEX.SUBSTITUTE but I couldn't get that to work either!
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Aug 8, 2008
I am trying to create a unique sample code by putting together the values of other cells that a user will input. It's all working well apart from the last part, where I am trying to include a decimal number. I want the decimal number to appear without the central "." and in a four digit format. e.g. 2.5 would appear as 0250, 14.25 would appear as 1425. This is the formlua I am using currently:
=IF(ISBLANK(B4),"",IF(LEFT(C4,1)="w",(B4&"-"&TEXT(F4,"YYMMDD")&C4&TEXT(G4,"HHMM")),(B4&"-"&TEXT(F4,"YYMMDD")&C4&LEFT(TEXT(H4,"00"),2)&RIGHT(TEXT(H4,"00"),2))))
However, where the value of H4 is 2.5, I am getting a result of 0303 (I've put this part in bold). I have attached a small spreadsheet to aid understanding.
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Jan 10, 2008
I am using the extract words function outline here [url]
I copied and pasted the function into a new sub and deleted the sub module1 and the end sub to make sure it is it own function I can call. I have called it in another macro I wrote and when I run the macro it bugs out at the first if statement. The code it has a problem with the Get_Word code below. It throws a "Run-time error: '1004': unable to get the Find property of the WorksheetFunction class."...
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Oct 31, 2008
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
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Jan 18, 2014
I am having trouble with some formulas displaying the results of the logical test as words.. For example.
=IF(E4>F4,100, IF(F4>E4, 200))
That works perfectly but I want "100" to be "Valid" and "200" to be "Invalid"
However...
=IF(E4>F4,Valid, IF(F4>E4, Invalid))
only results in the #NAME? error for me?
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Jul 31, 2008
I have an issue with VLOOKUP. By runnig VLOOup we can get the data that there is present in a specified range. But how about to get the data DISPLAYED which is not there in the specified range. I tried combining IF and VLOOKUP functions. I am on a simple project now and I would be happy if I could get the answer immeidately
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Apr 30, 2014
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
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Mar 19, 2014
I've been working on a method to search a single column of 1000+ cells containing a paragraph with a 250+ word keyword list (also in a single column). I'm needing only complete words to be searched/ displayed regardless of spacing & punctuation. I've tried multiple methods the past few days and the one that worked (Macro with 4 complex formulas) was unusable when scaled out to all 1,000 rows due to the extremely long calculating time. I don't know VBA yet but was able to modify and create a user defined function that does everything I need except it displays string results that are not whole words (Ex. search for air, word in cell is fair, displays a result for air).
PHP Code:Â
Function RangeSearch2(text As String, wordlist As Range, seperator As String, Optional caseSensitive As Boolean = False)   Â
Dim strMatches As String    Dim res As Variant    Dim arrWords() As String    Dim skip As Boolean    skip = False   Â
On Error Resume Next    Err.Clear    For Each word In wordlist            If caseSensitive = False Then     Â
[Code] ...........
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Dec 29, 2008
I'm trying to write UDF which getting RegEx pattern and a certain cell as arguments and returns only matching string. For examples for string "The quick brown fox jumps over the lazy dog", and RegEx pattern "w{4}" the function will return two words "OVER" and "LAZY". What should I change in my code?
Function GetPattern(myPattern As String, myString As String)
Dim regEx As RegExp
Dim Matches As Object
Set regEx = CreateObject("VBScript.RegExp")
With regEx
.Pattern = myPattern
.IgnoreCase = True
End With
GetPattern = regEx.Replace(myString, "$1")
End Function
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Mar 23, 2007
I am trying to parse a formatted text file. I am using the SPLIT function as
arr() = split(cline," ")
where cline is an input line. if the line input(cline) has multiple spaces between two words, how would it split that.
Eg :
abcd defg fefdcs fasdfasdsa
would the output of above be
arr(0) = abcd
arr(1) = defg
arr(2) = fefdcs
arr(3) = fasdfasdsa
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May 17, 2009
I want to have a few words shown based on figures in specific cells. I not quite sure how to explain, but i will try my best:
A1 = 5
A2 = 0
A3 = 7
The function i am using looks something like this:-
=IF(A1<6,"Do I Have Sickness Self Cert?","Do I Have Doctor's Paper?")
However, by using this function, if the cell is empty it still shows the first wording when i need it to show lets say between 1 & 6 shows the first wording and more than 6 shows the second wording! If you know what i mean... I know what i want to do but cant really explain it very well.
Maybe it should look something like this but it does not work the way i am doing it.
=IF(E156>1<6,"Do I Have Sickness Self Cert?","Do I Have Doctor's Paper?")
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Sep 25, 2009
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
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Sep 25, 2009
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
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Sep 20, 2006
I have a column of words in Column A and I want to replace all the times that these words appear in the rest of the excel sheet with the words in Column B. If someone has already answered a similar problem link me to the thread because I can't find anything.
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Dec 7, 2007
I don't have a clue as to how to convert this to VBA code.
When installed as a macro, the function works fine in a cell on my PC, but when I send the file to another pc, it still gives the name of my pc. I need it to return the name of thier pc.
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Dec 7, 2009
Sub xxxxxxx()
Keli = Cells(13, 8).Value
Valid1 = Application.WorksheetFunction.VLookup(Day(Keli), Range("ToTalList"), 2, False)
Valid2 = Application.WorksheetFunction.VLookup(Month(Keli), Range("ToTalList"), 3, False)
Valid3 = Application.WorksheetFunction.VLookup(Int(Year(Keli) / 100), Range("ToTalList"), 4, False)
Valid4 = Application.WorksheetFunction.VLookup(Year(Keli) - Int(Year(Keli) / 100) * 100, Range("ToTalList"), 5, False)
MsgBox Valid1 & " " & Valid2 & " " & Valid3 & " " & Valid4
End Sub
When I try to convert it to a usefull function I get a #Name? Error
What do i do wrong? The purpose is to create a date in to words function
Public Function DateInWords(Keli As Range)
Valid1 = Application.WorksheetFunction.VLookup(Day(Keli.Value), ThisWorkbook.Worksheets(1).Range("ToTalList"), 2, False)
Valid2 = Application.WorksheetFunction.VLookup(Month(Keli.Value), ThisWorkbook.Worksheets(1).Range("ToTalList"), 3, False)
Valid3 = Application.WorksheetFunction.VLookup(Int(Year(Keli.Value) / 100), ThisWorkbook.Worksheets(1).Range("ToTalList"), 4, False)
Valid4 = Application.WorksheetFunction.VLookup(Year(Keli.Value) - Int(Year(Keli.Value) / 100) * 100, ThisWorkbook.Worksheets(1).Range("ToTalList"), 5, False)
DateInWords = Valid1 & " " & Valid2 & " " & Valid3 & " " & Valid4
End Function
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