Remove First X Digits And Last Y Digits From A Cell

Sep 25, 2009

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))

As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.

Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).

Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 2003 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2))) As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

Does anyone have an idea on how to help with this?

Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.

However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.

I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.

=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)

1. Remove the first 4 digits from each "Appeal ID"

2. Insert a new column (first column) called "Chapter"

3. Run a v-lookup down the new column against a file that is stored on my desktop. The v-lookup will cross check the Appeal ID against the file to identify the Chapter

4. Sort the data alphabetically by Chapter

5. Create seperate Excel files for each Chapter ...

I have a excel file, I need to remove the first two digits if they are certain numbers, such as 12. For example, if the number is 12987654, then I need remove 12, and it will be "987654" , but if it is not 12 in the first two digits, then keep it no change, for example if it is 345678, then keep it.

I barely work with Excel formulas, now I need connect the excel file with my Database table. I need to make the file matches the DB.

I know how to remove the first part of a text, but not the end. I have a very large amount of data in which the first column contains a product description and then the UPC code. I need to isolate the product name from the UPC code into 2 columns. I used =RIGHT(B2,14) to isolate the UPC, but since the length of the product name varies, I'm not sure how to isolate the product name. I have looked at using the TRIM and TRUNC functions without any luck. 'Text to columns' doesn't work because I have multiple spaces, 'Text to columns' would work if I could used 2 digits as the delimiter, but the function doesn't allow that.

Can someone please suggest a function or formula for this?

Here is an examples of how the text appears in the field. (Note: I only need to cut off the UPC code, I need the measure information to stay).

some really long product name 12 oz 5 bag 09-99999-99999 another shorter name 2 oz 09-99999-99998

I was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits

I found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:

I have pasted over 1300 numbers in a list, all of which need to have 5 digits. However, when I pasted the 5 digit number (ie 00003) into the cell, it omits the leading 0's.

Is there any way to get these numbers back to having 5 digits....and if it omitted the 0's, can I put them back all in one fell swoop?

find a formula or function where i can remove the last 4 digits from cells. I have a spreadsheet where there was might have been concatenation do where 4 digits were added to the end of part numbers in a cell. I need to remove just the last 4 digits so that I can do matches later on. Each cell has a different number of characters and i just need to remove the last for Example 154758NE20 or NFD148574DE11. Need to remove the NE20 and DE11 respectively.

During work this thing stuck me that i have a column A1 an amount like 12345663..now what i want in column B1 the same amount but except first 3 digits..for example instead of 12345663 i want only 45663 in column b..

i have attachmed excel file. in that file total 8 colums among them i kept 8th colum empty .

but i want name racks in that file. i knw..it will confuses u. but once u see my attachemts u will realize.

eg: if G2 =XA06-G-001 I2 will be XA only..(XA is rack Name) if G2 =XB06-G-001 I2 will be XB only if G2 =XC06-G-001 I2 will be XC only if G2 =XD06-G-001 I2 will be XD only

i mean to say..i want only first two alpabatics of G2 in I2..

I am wanting to replace part of a cell ( the first two digits) with nothing - blank

eg cell contains 441298871657 and i want it to read 1298871657 I am looking for a function to do this, i have tried using the finf and replace function but if 44 appears somewhere else in the value this will also be replaced.

I'm struggling to find a good formula or code produce the below. I have a column that contains a text string followed by spaces then a number. I need to sparate these into two separate cells.

OldNew NewD-EUROBANK PROPERTIES REAL E 4D-EUROBANK PROPERTIES REAL E4D-ACTIVE INVESTMENT SA 12-SYNT 567D-ACTIVE INVESTMENT SA 12-SYNT567RSK HYDRO-NWKR 25(NORWAY REG 1RSK HYDRO-NWKR 25(NORWAY REG1ADRILL LTD 1ADRILL LTD 1OFFSHORE LIMITED 1OFFSHORE LIMITED 1TRATA PLC 2TRATA PLC 2

I am triying to write a formula adding two digit in the same cell and return the sum as a single digit as shown below. but not sure how to go about doing it. would appreciate any kind souls to help out.

C5 D5 E5 F5H5I5J5K529121958 D8 F8 H8 J8 2 3 1 4Let's say if 2+9 = 11, than I wan to break 11 into 1+1 = 2, how can I get it done?examplecell D8 is the sum of cell C5 and D5 which is 2+9 = 11. than 11 is further break down into 1+1 = 2cell F8 is the sum of cell E5 and F5 which is 1+2 = 3.Likewise for cell H8 is the sum of cell H5 and I5 which is 1+9 = 10. than 10 is further break down into 1+ 0 =1cell J8 is the sum of cell J5 and K5 which is 5+8 = 13, than 13 is futher break down into 1+ 3 = 4.

I need a function that can find a single digit in the cell containing the shifts worked. As an example, the cell may contain 1, 2, 3, 12, 13 or 23. I have tried using the FIND function, but so far I have not been able to make it work. I will continue to research the FIND function, but a function that would search a cell "containing" a specific digit would be ideal. If there is such a function out there.

Our software extract for our data base sucks and values do not align properly if all entries do not have tge exact same number of fields with data in them.

I have always done the alignment in excel manually. I can find where the data starts to misalign and would like to do this automatically.

There is an id number for each entry (row) that is 6 digits long. How can I search a row for a 6 digit number and return the address of that cell? i can use this address as a starting point and use the offset function to do so alignment from there.

I have a sheet with column A. This column A contains numbers from 1 number to 6 numbers.

So, one cell can have a '1' or a '999999' or any combination between them. Now this is the problem.

I want a formula that will fill those cells that don't contain a number up to 6 digits. So if a cell contains '254' I will like this formula to fill the cell like this: 000254.

This should happen with any number that don't have a number with six digits.

78 should be 000078, 78652 should be 078652 and so on.

I can't seem to find a way to find the max of only the last four digits of a cell, matching the first 8. As an example:

I have thousands of cells in a column like this, (and I can't add any columns to the sheet), and I have a cell with the first three digits and the second three digits. So, out of all these numbers, I want the MAX of ONLY the numbers with the first 8 digits of "800-123-". Also, the decimal on the end is how many times the number was called, and any the decimal and any number after it is to be ignored. The answer would be "800-123-0024", or "0024", I just need a faster way to find it without searching for it.

But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:

I would like to take the first three digits of column A and do a lookup of column B that would return the corresponding number from column C. For example, if I entered the formula for 103PH, the lookup would find the 103 in column B and return "2775.00" from column C...........