Compiler Error: Method Or Data Member Not Found

May 9, 2009

I have designed ad workbook with a lot of combobox. The cbo are partly controlling other cbo. The sheet works perfekt and in the code they are handled as intented. So no mispelling of any cbo or sheetname.
Where I get my problem:
If the workbook is open and I close Excel then I get the "Compiler error: Method or data member not found".
But if I close only the workbook I don't get any Compiler error.
It is as if the problem is caused by a Excel problem - If Excel is closed the sheet is recalculated but closed and there fore ends in compiler errors.

This error is in Excel 2000 + 2003 + 2007 - so not version related.

I have been searching the net for a solution for this problem but haven´t had any luck so fare. I starting to believe that there is no solution to this proboem.

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Compile Error - Method Or Data Member Not Found

Feb 27, 2012

trying to convert an excel document to an XML document and am getting the above error. Microsoft Visual Basic highlights below.

Code:

' prompt user to save to a directory
With frmAuthenticate.dlg
.Filter = "XML Files |*.xml|"

[Code]....

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Compile Error: Method Or Data Member Not Found

Jul 3, 2009

This macro is part of the Pertmaster Risk Expert Application: It was not created by me nore modified by me, it is part of the PertMaster Risk Expert Software:

I am trying to run the Convert Lags To Tasks Macro Ver. 1.3 but i keep getting the following Error Message: Compile error: Method or Data member not found

Here is the list of the codes for the macro: I have not change any codes from the original pertmaster file....

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"compile Error: Method Or Data Member Not Found",

Mar 30, 2007

If Sheet6. Range("O8").Value = 4 Then
For Each cell In Sheet10.Range("B5", "B369")
If (cell.Value = Sheet6.Range("L24").Value) Then
cell.Offset(0, Sheet6.Range("L21").Value).Value = Sheet1.ActiveCell.Value
End If
Next cell
End If

it says the part of code causing the error is the end of the 'cell.offset' part, as highlighed: Sheet1.ActiveCell.Value. i tried replacing it with '.Selection', still get the same error.

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Jul 4, 2006

I'm getting a compile error whenever It gets to the .leftmargin line...its the "method or data member not found" compile error

With ActiveSheet.PageSetup
.PrintTitleRows = ""
.PrintTitleColumns = ""
End With
ActiveSheet.PageSetup.PrintArea = ""

With ActiveSheet.PageSetup
.LeftHeader = ""
.CenterHeader = ""
.RightHeader = ""
.LeftFooter = ""
.CenterFooter = ""
.RightFooter = ""

When I comment the margin stuff out, everything else is forrmated correctly, the landscape and all. It really doesn't that "application to inches."

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VBA Error Member Or Data Member Not Found

Jan 15, 2010

Private Sub UpdatePrice()
Sheet1.Range("E4").Value = Sheet2.Range("B1").Value + Sheet1.ComboBox1A.Value
End Sub

I can call it in Excel and it works no problem. When I close the workbook, I get the following error: "member or data member not found" with ComboBox1A highlighted in blue.

Is there any reason why I would get this only when I close the document?

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Dec 19, 2007

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In Tools/Options/General/Error Trapping I have Break on Unhandled Errors checked.

I have changed my error trapping lables.

I have copied the procedure and renamed it.

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Dec 10, 2008

I'm trying to get the Find and FindNext methods to work. Column C contains serial numbers and there's a chance that a serial number might appear more than once in the column. What I'm trying to do is get Excel to find the first occurance of the serial number, find what row it's on and then see if this matches the variable 'CurRowNo' (defined earlier in the code). If it doesn't I want it to look at the other occurances of the serial number, find what row they're on and see again if it matches CurRowNo.

The variable 'EngCount is the number of occurances of the serial number (also worked out earlier in the code). I've got the code below, but I get the error 'Method Range of Object Global Failed' on the FindNext line. I have no idea what this error means or why it's happening.

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May 14, 2007

The error is:
Method 'Range' of object '_Global' failed
Line it fails on:

Set r = Range("myRange")

Sub LearnCells()
Dim r As Range
Dim n As Long
Set r = Range("myRange")
For n = 1 To r.Rows.Count
If r.Cells(n, 1) = r.Cells(n + 1, 1) Then
MsgBox "Duplicate data in " & r.Cells(n + 1, 1).Address
End If
Next n

End Sub
Questions:

1) 1st Dim statement, is this valid? I still get a little unsure- in the data type lists in the help file, the list file does not list things like Workbook, Worksheet Range.
2) Why is the error ocurring?

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Oct 17, 2007

My worksheet contains several codes that I then have to lookup in a different worksheet in a different workbook to obtain the relevant data associated with that code. At present I do this by activating the appropriate worksheet, Using Find to locate the appropriate field in that worksheet and then using activecell.offset to get the needed data. This is the only time that these worksheets ever need to be activated so I was wondering if there is a way to do this without having to actually activate the sheet. As an exapmle this is what I currently do:

' variables defined earlier in the program, Tempsheet = workbooks(FileNm & ".xls").worksheet("Temp")

Spark = Cells(TRow, 8).Value
' Activate the reference Sheet
Workbooks("Waveguide Properties.xls").Worksheets("Spark Bends").Activate
Cells.Find(What:=Spark).Activate
COM = ActiveCell.Offset(0, 2).Value
Edge = ActiveCell.Offset(0, 3).Value
SparkArray(i, 1) = ActiveCell.Offset(0, 1).Value
SparkArray(i, 5) = ActiveCell.Offset(0, 4).Value
SparkArray(i, 6) = Spark
' Reactiave the workbook and worksheet I am working in
TempSheet.Activate

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Jun 17, 2008

If Not stfound Is Nothing Then 'if value is found then do this

is causing me a run time error 424 when I try and run my code "Object required". Entire code is pasted below...

Option Explicit ....

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Jan 15, 2010

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I want to be able to added the variable members to each group as such, I'm presuming this is best by a declaration.

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Jul 2, 2006

the if stattement works perfectly and does exactly what i want except when it comes to the else part. if there is no error the statements are run perfectly but if there is an error (in this case the error is generated when a match cannot be found in the spreadsheet) the else statement doesnt kick in and post the msgbox.
the code just crashes. and returns an error 1004 on the line i have highlighted in yellow

res = WorksheetFunction.Match(invvar, Columns(1), 0)
If Not IsError(res) Then

Me.txtClientID.Value = ws13. Cells(res, 7)
Me.txtNumber.Value = ws13.Cells(res, 7)
Me.txtDate.Value = ws13.Cells(res, 8)

'save client id as a variable
'Print to invoice------------------------------------------------------------------.....................

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Apr 26, 2006

I have some code that, although works fine in Excel 2003, does not in Excel 1997. I receive this error when I try running it:

COMPILE ERROR:
NAMED ARGUMENT NOT FOUND

Sub HPVAL()
Dim r As Range, myStr As String
myStr = "HP"
Set r = Cells. Find(What:=myStr, After:=ActiveCell, LookIn:=xlFormulas, LookAt _
:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:= _
False, SearchFormat:=False)
If Not r Is Nothing Then
r = r.Value
While Not r Is Nothing
Set r = Cells.FindNext(r)
If Not r Is Nothing Then
r = r.Value
End If
Wend
End If
End Sub

It looks like Excel is getting hung up on the "SearchFormat:=" portion of the code.

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Sep 10, 2008

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Also, sad to say, after several years of not working with a particular customers spreadsheets I am at a memory loss. I can't for the life of me figure out what I've done in many cases.

Looking around I did find an Excel to Java thing, which would be fine for use on a webpage. I'm thinking of a standalone executable type program I can build, put on a CD and send to them. This way they could pop in the CD and run the program... very simple.

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Further there appears to be a program call Excel translator, but the site has no pricing of the product. That is a big indicator I can't afford it. LOL

I'm a consultant to small mom & pop type businesses and there is no way I can justify a pricey, sophisticated software.

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Nov 23, 2009

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Dec 23, 2009

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Ultimately what I am looking for is something like this: ....

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Dec 17, 2009

The error that pops up has no information other than "File not found" in a dialog box with two buttons.

File not found (Error 53)

The file was not found where specified. This error has the following causes and solutions:

A statement, for example, Kill, Name, or Open, refers to a file that doesn't exist.
Check the spelling of the file name and the path specification.

An attempt has been made to call a procedure in a dynamic-link library (DLL) or Macintosh code resource, but the library or resource file name specified in the Lib clause of the Declare statement can't be found.

Check the spelling of the file name and the path specification.

In the development environment, this error occurs if you attempt to open a project or load a text file that doesn't exist.
Check the spelling of the project name or file name and the path specification.

For additional information, select the item in question and press F1 (in Windows) or HELP (on the Macintosh).

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May 16, 2009

I have a macro which prepares a report for equipment. The macro is a recorded macro and it runs perfectly on my system but when i am trying to run that in other system getting an error message"Error 448:arugument not found".Which i marked in red.

My macro code is as follows:

Sub Anirudha()
Application.ScreenUpdating = False
Range("G2").Select
ActiveCell.FormulaR1C1 = "=MID(RC4,4,6)"
Range("G2").Select
Selection.AutoFill Destination:=Range("G2:G931")
Range("G2:G931").Select
Range("A2:F2").Select

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how I can get at the code to fix it?

I tried to upload the file, but it is too big for the requirements.

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Dec 15, 2008

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Jul 27, 2009

The procedure below worked quite happily for two months. Now it (usually, but frustratingly not always) fails, with the following error on the asterixed line:

Paste Method of Worksheet Class Failed

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Sub Transfer_To_Invoicing()

Dim answer As Variant, active_workbook As Variant
day_num = Range("a127").Value
answer = MsgBox("Do you want to transfer " & Weekday(day_num) & "'s figures to the INVOICING SYSTEM now?", vbYesNo)
If answer vbYes Then Exit Sub
answer = MsgBox("Have you updated the values from the despatch sheets?", vbYesNo)
If answer vbYes Then Exit Sub
Range("a1:dj129").Copy
active_workbook = ActiveWindow.Caption
For Each w In Workbooks.............

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Jun 20, 2007

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The basic code works fine, but did not account for the user entering a Job# that was not in the system, so I added an If/Else to account for this...
The additional code took the If (Job# not found) route every time...
Following many hours of searching this site and variations of the error handling code, I still can not get it to work.

So I'm asking for your assistance to point out why the error handling (based on other successful code found here) is not working for me.

'Insert Link
Private Sub CommandButton3_Click()

If TextBox1.Value = "" Then
MsgBox "Please Insert a Job#"
Exit Sub
ElseIf TextBox2.Value = "" Then
MsgBox "Please Insert Quoters Initials"
Exit Sub
ElseIf TextBox3.Value = "" Then
MsgBox "Please Insert Quote Date"
Exit Sub

The 'Find' part of the code is working, as the correct cell is selected after running the code... but it gives the error message, instead of executing the rest of the code...

If I remove the 'On Error Resume Next', it stops on the find block, where on inspection FindR = Nothing.

So if FindR does = Nothing, how did it manage to select the cell?

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Jan 28, 2008

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Run Time Error '91':
Object Variable or With block variable not set.

Concept code follows. The commented strOCNumOF line contains the value that's found on the sheet. The uncommented line contains a value not found.

Sub find_test1()
Dim intFoundOnCur As Integer
Dim strOCNumOF As String

strOCNumOF = "AP4506"
'strOCNumOF = "BP6020"

intFoundOnCur = ThisWorkbook.ActiveSheet. Cells.Find(What:=strOCNumOF, SearchDirection:=xlPrevious, SearchOrder:=xlByRows).Row

End Sub

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Mar 7, 2013

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Based on the radio button selected, user can add in information to the columns adjacent to it, and then click a button to store that information in some rows below. The code for that button is stored in the sheet module. I have tried enabling macros and disabling macros and no change has appeared. What I have noticed though is that yesterday, when i opened the workbook, a yellow bar appeared asking if I wanted to "Enable Content". Today, that bar didn't appear.

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Dec 18, 2008

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Feb 8, 2012

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Set Ran = Worksheets(2).Range("A:A").Find(CompName, lookat:=xlPart)
If Not Ran Is Nothing Then
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MatchCol = Ran.Column
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HTML Code:
Public Sub move()

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