Complex Logical/conditional Formula

Jun 12, 2006

I am working between two worksheets. In one worksheet I have a list of
account numbers. In the second worksheet I have the same account numbers in
a different order. What I am trying to do is, If the account number from
worksheet one is found in the column with the account numbers in worksheet
two, I want to display the matching title for the account number that is in
the same row but different column in worksheet two.

So essentially (if acct # from column x in wks 1= an acct in number in
column m from wks 2, display the corresponding title in the same row of the
matching acct # found in column m). Is this possible?

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I have a sheet going like this:

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I need to colored the the max and lower value for every row (green for low and red for high) i did it well for first row with conditional formatting but i cant copy for the anothers ones and i dont want to do it row by row (i am so lazy). I did this for first Value and the copy format for the following values in row:

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The reference must be Absolute cause another way results become wrong for another values, but thats the problem cause i cant use it in below rows.

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[Code]......

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I have a complex request which I think can be done either via vb or a macro, not sure which is best?, will try to explain:

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2 = Level below that etc, etc

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223344
342423

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I have table A of 500 rows and need to compare it to table B of 2000 rows.

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For example with these two, from the second table to the first. IF column B equal to column and the corresponding column C equal to the corresponding column C, return for example "yes". Then I need to check the same thing for the corresponding other columns, but basically everything would be tied to B and C. The problem is the second table, larger one, is basically all over the place, I could manage to do this if we would be talking equal length tables, but I do not know what formulas I could use to check further down a row once we find an equal value.

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I've attached an example document where I think I'm getting close, just not sure if its possible.

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This is the formula which does work, although I would prefer for the sake of accuracy (and succeeding in the task of making the formula do exactly what I wanted it to do!!):

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The value of T9 is 2283.3 recurring.


There are two main parts to the SUM:

=ROUND(SUM(T9/1.5)/5,0)*(5)*(6.5%)+(26.25+15.81+1)

...and:

+SUM((T9/1.5)*(6.5%)+26.25+15.81+1)*19%


The challenge is to insert another:

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