Delete Rows If Column Has Fewer Than X Matches To Part String Match

May 5, 2008

I have data sets on multiple worksheets within a workbook (over 70). Based on the begining of a string, I need to count all instances with that begining, and if there are fewer than 12 instances, delete the entire row.

Data set example:

In this example, I need to count each instance of rows starting with 1/* - 9/*, and delete rows as mentioned. In other data sets the string might start Gi1/*, and so on. In the following code, if I do not loop, and only test against 1 value type, and ONLY run it once, it works. As soone as I try to loop through all possibilities, or run the macro a second time, it blanks out the entire worksheet, starting at row 3.

Dim c As Long
c = Worksheets(i).Range("A" & Rows.Count).End(xlUp).Row
With Range("A3:A" & c)
If Application.WorksheetFunction.CountIf(Worksheets(i).Columns(1), "1/*") < 12 Then
. AutoFilter field:=1, Criteria1:="1/*"
.Offset(1).Resize(.Rows.Count - 1, 1).EntireRow.Delete
.AutoFilter

I have also tried to concatenate a variable with my CountIf criteria, but that fails miserably.

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Sub DeleteRepeatedRows()
' goes through coord. sheet and identifies duplicated lines, copies the date from the old row
' copies it into the new line, then deletes the old line
Dim rCell As Range
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rCell.EntireRow.Delete
End If.........................................

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range("B" & i).activate
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Dim i As Long, k As Long, n As Variant, r As Range
Application. ScreenUpdating = False
With Sheets("Source")
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ertret.jpg

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