I m trying to develop an IF function that will go through each cell in a column and delete an entire row based on whether the Cell Value is identical to the one above or not. What i have thus far:
Sub RemoveDuplicate()
Dim i As Integer
Sheets("Pre-Allege").Activate
i = 2
Cells(i, FindCol + 2).Select
Do Until IsEmpty(Cells(i, FindCol + 2))
If Cells(i, FindCol + 2) = Cells(i - 1, FindCol + 2) Then Rows("i:i").Delete Shift:=xlUp
Else
i = i + 1
End If
Loop
End Sub
I have a sheet with rows that extend to about Column AT. In some of the rows, all the cells are populated with "--". I want to delete these rows. Other rows have "--"s but not in every cell. I tried to remove all the "--"s then running this code:
For t = 2 To Workbooks(WorkbookNm).Sheets("--").UsedRange.Rows.Count j = CStr(t) If Application.CountA(Workbooks(WorkbookNm).Sheets("--").Range("A" & j).EntireRow) = 0 Then Rows(t & ":" & Workbooks(WorkbookNm).Sheets("--").UsedRange.Rows.Count).Delete GoTo Step15__2: End If
It worked, but I had trouble re-adding the "--"s. So I'm wondering if there is a simple way to modify the above code, so that it looks for and deletes rows with only "--" and possibly nothing in the cells (e.g. Column AU and on)?
I'm trying to create a macro and having absolutely no luck with it. I want the macro to run through all the rows and delete all rows where every number in that row is less than a specified number (.03 for this particular case).
What is the fastest way to delete every cells that has data except for the first two rows?
I currently have this code but I find it a bit slow (and everything is replaced by column A to Z [which meets my need right now]).
Code: Sub delete() Application.ScreenUpdating = False lastrow = Activesheet.Cells(Rows.Count, "A").End(xlUp).Row Range("a3:z" & lastrow).delete End Sub
If I have a column of data called "ColStream" and want to delete all rows that don't contain the string "Production", whats the best way to achieve it?
I have tried a for each loop, with INSTR but as this moves down a cell from the cell whose row has just been deleted, skipping the "NEXT" row in the range, it doesn't give the correct results.
Incidentally, the end game is to copy all the remaining cells to the cell immediately below a cell called "StreamsDatabaseStart" in a worksheet called "ProdStreams" should anyone out there be feeling particularly charitable!
I need a Macro that will delete rows within a specific range that contain blank cells or preferably delete the rows where the first cell in the row contains a blank cell.
I went to the Macros page and pulled this macro to remove rows if they have blank cells:
Sub DeleteBlankRows2() 'Deletes the entire row within the selection if _ some of the cells WITHIN THE SELECTION contain no data. On Error Resume Next Selection.EntireRow.SpecialCells(xlBlanks).EntireRow.Delete On Error Goto 0 End Sub
I ran this and nothing happened. Does anyone have a fix or perhaps a better way to make this happen?
I have got a set of data in a workbook with Sheet 1 range A1 to K373 and a range of data in Sheet 2 ranging from A1 to A30. What I will like to do is to have a VBA code to loop through all the cells in Sheet 1 column C and check which are the cells which value matches those in Sheet 2. Those that matches in Sheet 1 will have the entire row deleted. I have come out with the following codes but it does not work.
I have a spreadsheet with three columns (check #, invoice #, vendor #). If a check pays multiple invoices, there is a separate row for each instance of invoice #. (ie if a check pays 10 invoices, there are 10 rows all with the same value for check # and vendor #, but different invoice #s). I need to concatenate the multiple rows to just one row per check #, with all the invoice #s in separate columns on the same row and delete the duplicate check # rows.
However, I can only use 10 columns, so if there are more than 8 invoices matching the same check #, the 10th column will need to contain invoices 9-n concatenated and separated by a space. I have over 5000 rows in the spreadsheet.
I am aware this is probably very simple, but I haven't been able to find a usable macro yet. I would like the data in the workbook that is not "Tuesday" (column L) and is not "3" or "4" (column I) to be deleted. All rows that have "Tuesday" and either "3" or "4" should not be deleted. Each row that is not deleted must have Tuesday in column L. All other cells are blank intentionally. The workbook will remain the same titled WKBK1 (no need to put the output data in a separate workbook nor separate spreadsheet).
Do you know what the macro would be so I don't have to copy and paste a formula over a large number of cells?
I am simply trying to delete all rows that have a value of less than 16 in the cell value's first 2 characters (column G).
Start with: 18N 18K 16K 16K 16K 14L 14L 13L 12L
End with: 18N 18K 16K 16K 16K
The code I am using:
Sub DeleteUnneededRows() Dim c For Each c In Worksheets("Sheet1").Range("G1:G500").Cells If Left(c.Value, 2) < "16" Then c.EntireRow.Delete End If Next End Sub
I need a macro to delete each row in which all cells contain the same value, always starting in cell G2 and going out an indefinite number of cell's. So, for one run, the range could be G2:BU2 and another it could be G2:PW2. Also, the number of row's is indefinite.
And an added complexity: I need it to ignore the cell in this search process if the cell contains "NC" - so if all the data in the row is the same except for a few that say NC - then it gets deleted. If the any of the cells in the row have other values, then that row does not get deleted - even if it contains "NC".
I have a report with about 7000 rows in it. I need a macro that will find all rows where column A and column B are the same as another rows column A and column B and delete both rows.
I need a macro that keeps any row that has a cell value that shows up twice and only twice in column A. All other rows would be deleted (except the header row, row 1). For example, If it's found only once, a third time or more than three times, delete those entire rows.
This is different than "keeping only duplicates" which would be 2 OR MORE.
A couple of things,
1. The workbook might not be sorted by column A, so a cell named "ABC0011" could show up in row 3, then again in row 8, in this case, keep both.
I am looking for something that will first delete all empty columns up until it runs into data, then delete all rows that are blank in Column A until it runs into data. In other words, I recieve different spreadsheets that start their data in different locations and I would like to have them always start in cell A1.
I have this worksheet that I did not create and notice it has entire rows and columns completely gone / deleted. For example, the only columns it has ranges from A to AI and then no more columns exist in the worksheet. For the rows, it has rows 1 through 77 but then it shows a gray background.
How did they do this? What is this called? How can I do this to Worksheets?
Each day I am going to have a list of about 300 different ID numbers, which i have already got a macro for creating, that outputs them into a single column on a sheet.
The next challenge Ill face now, is that I'll have a list of maybe 500 ID numbers in another spreadsheet.... I need a way to basically tell excel to keep rows that contain the numbers in 1 column on the list of 500, that correspond with those on the list of 300.
Numbers that are not found on the list of 300 ID numbers, must be deleted, along with the entire row.
I essentially need a macro that runs something like this that i found online, but instead of it just looking for the word "apple" as rows to delete, i would need it to check to see if the number is one of the 300 on my list.... and delete the row if it is not on the list
PHP Code:
Sub Delete_Rows()Dim rng As Range, cell As Range, del As RangeSet rng = Intersect(Range("A1:C20"), ActiveSheet.UsedRange)For Each cell In rngIf (cell.Value) = "Apple" _ThenIf del Is Nothing ThenSet del = cell Else: Set del = Union(del, cell)End IfEnd IfNext cellOn Error Resume Nextdel.EntireRow.DeleteEnd Sub
I need a VBA to delete rows with blank cells within columns F - AZ Columns A - E contain headers but also need to be deleted if cells in columns F -AZ are blank.
I have several lists that I need to be able to print out periodically.
The main worksheet that underpins each list is over 900 lines long and numerous calcs and formulae populate columns to provide the data for my 'print lists'.
I need my 'print lists' on seperate worksheets and I have linked the data from my main worksheet results, using IF statements to stop unwanted results being displayed by making the rows appear empty (i.e. to display "").
Due to the design of my main Worksheet it is inevitable that I have many rows in each 'print list' that are not required for that particular 'print list'.
I want to remove the 'empty' rows from the print sheets at the time of printing. I cannot use the GoTo > Special > Blanks > Delete Rows because the rows are not recognised as being 'blank'.
I have attached 2 screenshots of my 'print lists'.
P.S. I am not assuming anything but I have searched on OZGRID and it appears to me that I might need to use Excel/VBA?
So i don't have any events that i know of that should trigger my macros to run. But everytime i delete a cell, or hide rows, it seems all my code/macros just auto run. And i had a few times when i hid the rows, the code would start, and then my excel application would crash.
I would like a macro that deletes rows based on having two blank cells in adjacent columns. I have achieved this with the following code however i need it to only delete rows below a certain row. How would i achieve this?
Sub DeleteBlankARows() Dim r As Long For r = Cells(Rows.Count, 30).End(xlUp).Row To 1 Step -1 If Cells(r, 3) = "" And Cells(r, 4) = "" Then Rows(r).Delete Next r End Sub
Each week I run a report that produces over 2,000 rows. I have to manually go through and delete things, by the time I am done, there may only be 320 rows left. I would apply a recorded macro, but the report is not consistent each week. There may be more or fewer rows depending on the week.
I would like to be able to run a macro that looks in column B for a specific value and if it contains that specific value, I would like the cells to the right of it to have their contents cleared.
Next, in column C, I have...
Employee2's Name Employee2's Number SPACE
[Code]....
I would like to be able to delete the rows, starting from Employee 2 to just before the second SUB TOTAL.
I'm new to VBA and macros, using Excel 2010, and am trying to figure out how to delete all duplicate rows in a sheet where 2 or less of their values in column A is "1". I'd like have a script that is flexible enough to change to 3 or less if need be. I also have a header row that needs to be offset in the process.
A---B- 0--123 <-delete 0--123 <-delete 0--123 <-delete 1--123 <-delete based on this the value of column A 0--123 <-delete 0--123 <-delete 1--321 1--321 1--321 1--321 1--321
or
A---B- 0--123 <-delete 0--123 <-delete 1--123 <-delete 1--123 <-delete based on this the value of column A 0--123 <-delete 0--123 <-delete 1--321 1--321 1--321 1--321 1--321
My Excel program (Excel 2010) currently has several columns and each column looks for and pulls data from a specific file on my computer. Then I need to delete any duplicate data entries, count the number of unique entries and track the changes through a chart. I have everything done except I cannot figure out (or find on the internet) a way to search in multiple columns (more than 2) and delete just the duplicate cells. I want to delete the cells in a way where there is one left. For example if the code 12gf is duplicated three time, I want to be left with one 12gf (it doesnt matter what column the original one is left in). Additionally, column length changes and they are not sorted. I have attempted to attach an image of an example file below.
