Is there a way to get an equation for a trend line and have excel automatically export the equation to a cell where it can be used. The only way i currently know how to do this is to manually type the equation.
I got a pivot table with following details Row Values: Dept_Code, Super_group, Product_Group Column Values: Ending_Date Data: Sales, Availability%, Waste%, Number of Stores
i need to have a bar chart with trend line individually on each data items e.g.Sales, Availability% etc. when i tried to use trend line it prompts me to enter series i.e Ending_Date and it draws trend line for only that period comparing all data values. is there any way to have individual graph for Sales, Availability%, Waste%, Number of Stores with trend line covering
The trend Equation on a chart is of the form y= a+x.(b+c.x) I want to use that equation in a spreadsheet to calculate value of y for the value of x. I can do it manually by inserting the a+x.(b+c.x) in a cell but would like it to be automatic as the a, b, c in the Equation changes regularly as more data is acquired.
I want to use a line graph to display an amount over time - that's the easy part. On the other hand, I would like to have to group the lines based on a value.
A short example: Imagine you own 3 different stores and you're selling oranges. So your table looks like this: http://img179.imageshack.us/my.php?image=orangeshm4.jpg
Now I'd like to have one graph (3 different graphs won't work as the rows increase -I need to select the whole column as data source):
Date on the x axis, Oranges sold on the y axis, and one line per store (e.g. a green one for store A, a red one for B and a blue one of C, doesn't matter).
I was asked to make a trend graph showing activation's and deactivation's over time. My boss wanted it to be done automatically when you placed values into a simple excel sheet like the attached image (the graph would be below this).
I have a simple x y scatter graph, to which i have a trend line running through it, fine.
what i need to do is fine some values according to that trend line. e.g. my X axis goes up to 60 and my Y axis goes to 10, so if i draw accross at 55 from the trend line, i then go down to a number on my Y axis.
1. I use a number of x,y pairs 2. From x,y pairs I produce "scatter" type chart 3. From the chart I get trend line and its equation e.g. 5-order polinominal 4. I convert equation into excel formula 5. I apply formula onto the same range of x argument and produce graph 6. The graph is very much different from the trend line!!! I would expect exact match as I use equation/formula for the trend line.
On top of these graphs, i draw a line (insert a line shape) corresponding to a certain gradient in the data presented. I do not want this line to be exact (i.e. not point to point) as it is best to be drawn by eye so that the general 'gist' of the data can be found. What i would like, using any method available, is to be able to find the gradient of this line i have just drawn which obviosuly must be done taking into account the scale of the graph. The scales of the graph will not be consistent across all applications.
I've created a graph from data and need to add an average/net impact/trend line to the graph. From what I've read this needs to be an XY scatter, however, several efforts later and I can't seem to get it to work for me.
i have a stacked bar chart, similar to this: [URL] What i need is a trend line, similar to this: [URL] that shows the average of the bottom bar to date.
I want to show a stock chart in Open-High-Low-CLose format, then I hope that a trend line can be displayed at the same chart, what can I do? It seems like that stock chart can't be merged with another chart
I currently have in my equation the trend function to linear extrapolate the date a line would cross either my upper or lower limits (100.1 and 19.9) between 2 data points. However if the 2 data points span both the upper and lower limits (as per the 2 attached examples) then unfortunately the trend function is only able to return the 1 date (where I've specified the x value). Is there any way for the TREND function to trend the 2 values? Do I simply add the 2nd x value to the new x's?
I have attached both the data and their graphs to visually explain my problem : EF Workbook.xlsx
I am trying to find the exponential equation from a set of data in excel. The problem is that the graph does not follow the scatter plotted points on the graph. How would you remedy this?
I will admit I am a neophyte when it comes to VBA - I am JUST opening the book (never had to program before). I am trying to figure out how to create a VBA macro that will, with the click of the button, save the data in my worksheet (minus the header line) into a CSV file.
I can export the data I have into a CSV file the normal way, but I DONT want the header line included. And instead of manually removing it each time, Id like to just be able to export it, then send it to the DBA for integration.
Is there any possible to add a series to a graph table without having the line in the Graph. i just want to show the difference for information and not in the graph?
i have tried some different things (like having the difference in white so it is not visible, formatting the Axis etc)
I am trying to recreate the screen grab that I have copied and pasted in (purple bar chart). I am to create the bar chart, but I am unsure how to create the dotted line which is the national average.
I have created some charts for my work and one of them is a line chart that spreads across one year with values for each month. Well they want the graph to always show one month ahead of where we are out. So there is actuals in for Sep. but then the line graph drops all the way to 0 for Oct. I don't want to have the graph bottom out when there is a zero. Does anyone know how to fix this?
how to have different format on a line grapgh. I have a series of data points for sales figures. The first 10 are actual data and the next 5 are projections. I want to have a line graph with solid color format for the actuals and a dashed format for the projections.
I need to create a line graph that has 2 lines for each person, one with the amount, one with the points. The X-Axis is by Weeks going up. How can I do this without making a separate series for each? I've attached an example.
We are trying to create a stacked bar graph with an average line. Each time we try to add in the average data to the graph it adds it to the stacked bar. The stacked bar should represent the inpatient & outpatient cases at a hospital for the current year (months showing across the as columns). The line should represent the previous 2-yr average total. Anyone have an idea how to add a line to the stacked bar graph? It has us stumped.
I have two line graphs I plot on a 12-month graph. In addition to these lines, I have a range, high, mid, low, for target percentages. Currently, I have plotted the high, mid, low lines and made them dashed. What I would like to do instead of just having these ranges shown as lines (w/ the graph background showing), is use the area graph function to color shade just the area between the high, mid, and low. Is this possible?
I have a question about creating a line graph, here's the scenario:
Once per week I update our inventory quantity in cells B1, B2, B3. I'd like to show these quantities on a graph which compares the quantity with the date. When the quantity gets updated it would automatically add week 2, when the quantity gets updated again it would again expand the graph and add week 3. Is this even possible?
I have a bar graph (horizontal) for the values say Jan 1.25 Feb 2.63 Mar -1.5. This works fine; now I would like to insert static comparison lines for the values 2 and -2, i.e. a straight valued at 2 that goes Jan to Mar and another straight line at -2 from Jan to Mar..
X-Axis = Week1:Week13 Y-Axis =Revenue for each week.
I have a line graph. If "Week9:Week13" have no value, my graphs line drops to 0. How do I make my line graph show no value when no value is inputed for "Week9:Week13"? I think I need to incorporate the =NA() in the original formula but I'm not sure how to do this.