Extract 2nd Number From A String

Feb 15, 2013

I wanted to return the second number in a string such as this:"0 of 0 jobs ... View all jobs"

The following worked perfectly:=MID(U3,FIND("f", U3)+1,LEN(U3)-FIND("f", U3)-23)

Until this line came up:"1 of 1 job ... View all jobs"

Obviously the "jobs" changed to "job" because of there being only 1, so the "-23" no longer worked. I need this to get the second number out of the string and it can change because the data is being refreshed from a website so it could easily change from one line to another.

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Extract The Last Number From A String?

Jun 20, 2014

It's for listing items to eBay. Ink Toners to be precise, the macro I have creates everything I need for a listing with a few msg prompts and importing data from another sheet. Saves me hours of work. Each cartridge has a Black, Cyan, Magenta, Yellow. The macro works fine for cartridge sets that go under one name. E.g: Brother TN325 Black, TN325 Cyan, TN325 Yellow... etc.

I've run into an issue with some cartridges which have different names: HP C530a Black, C531a Cyan, C532a Yellow...

I set the macro up to deal with different number, by removing the last character of the "tonername" string "C530", then replacing it with "C531".. etc.

What I haven't factored in is the ones with an A on the end. I need a way to tell it to ignore the a if there is one.

To make it clear, I will be inputting the text: C530a From this, I need to create 3 more strings: C531a, c532a and C533a

Here's the snippet of code I'm using to achieve what I'm already doing.

Code:
Selection.Replace What:=A, Replacement:=Left(y, Len(y) - 1) & "1"
Selection.Replace What:=b, Replacement:=Left(y, Len(y) - 1) & "2"
Selection.Replace What:=c, Replacement:=Left(y, Len(y) - 1) & "3"

[Code]....

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Apr 28, 2014

Below is a sample of data I need to extract the 8 digit number:

WO_32092_56228491_575482-113476-WP55
WO_32092_56228491_115130-WP55
WO_32092_56228491_115116-115118/115117-WP55
WO_32092_56228491_291881-318903-WP55
WO_259_56748761
WO_13895_52245652COUNTYRDN-30
WO_17368_51421730-A-ADDPOLEINFIELD
WO_17368_50885431-A-ADDMISSINGPOLE
WO_11021_52350485brock3377
In a spreadsheet, I had set up three columns where:

A: removed first three characters. WO_32092_56228491_115130-WP55 to 32092_56228491_115130-WP55
B: removed up to the _ . 32092_56228491_115130-WP55 to 56228491_115130-WP55
C: captured the first 8 characters left. 56228491_115130-WP55 to 56228491

I am pulling the data into Excel via an ODBC where there is thousands of rows of data. The three column process puts a tremendous strain on the processor.

Is there a formula that will extract the 8 character number without a three step process?

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Dec 16, 2008

I would like to parse a part number.

ab24s-12-g4a

if there is a "-#-" in the string, that is the value I want. If the "-#-" is not present, I would like to take the first number. Currently, as written in your first example, I am getting the first number - excellent and thank you!

In the sku, the first digit reprepresents capacity. If a second number is present after the capacity portion of the sku (i.e. "-#-"), that means that they want to order it filled with less than capacity. For instance, a carton of eggs and they want 6 eggs instead of the max capacity of 12. (i.e. egg12-6-z2z). Numbers after the second octet (i.e. z2z) do not matter.

It would be a number only in the second octet. If there are characters with it, the equation should disregard it.

Here are the scenarios, and what the formula should accomplish

1) egg12 --> currently returns 12
2) egg12-6 --> would return 6
3) egg12-6-g2c --> would return 6
4) egg12-g2c --> would return 12

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Oct 11, 2011

Have many rows of alphanumeric strings. 2-4 letters followed by a variety of numbers, some spaces, and some additional letters. What I need is to return the first number after the initial 2-4 letters, everything after that first digit is junk. Thus, I would like a formula that takes me from:

AB23400 12 -> 2
CET25800 1 -> 2
NYT67300 H01 -> 6
HSRF49900 1 -> 4

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Jan 12, 2009

I need to extract a set of 5 numbers from a string of characters. The number set I need is always 5 digits long, always starts with a 1, and always begins after a period. But the number I need can occur in different parts of the string:

In each example below I would want to extract only the 10572 portion.

5194003.10572.N
5194003.10572.R
5194003.1.0010785.10572
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Additionally (if possible) if the cell is blank I don't want anything to show up, and if the string begins with a letter then I don't want anything to show up either.

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Dec 3, 2009

My knowledge of functions is pretty limited, or negligible to be honest. I require a function to extract numbers from each cell in a selected range.

Eg.

cells contain the following data:

cell 1: xxxxxx 45,59
cell 2: x xxxxx xx 6,45,27
cell 3: x xxxx 28

were x represents text

I need to loop through each cell and extract each of the numbers and list them in a separate range. If applied to the above range of cells the function would show the below in the ouput range. Each number in its own cell.

6
27
28
45
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Nov 7, 2008

Say I have a string "09800EBHR052708"

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Jan 20, 2008

What is the formula to be used to extract number from a alphanumeric string located at different row?

example:
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test124test129test132
test125test130test133
test126test131test134
test127test132test135
test128test133test136

result: ....

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Sep 26, 2009

I am trying to extract a 7-consecutive-digit number from a mixed string (letters and numbers). The only condition is that the number has to start with a "7" or "6" and be exactly 7 consecutive numbers long. My function only evaluates for one and one within the other but not both. It's faulted because it only looks for the occurrance of "6". rCell is the string range.

Function ExtractNumber(rCell As Range)

If Len(Mid(rCell, InStr(1, rCell, "6"))) > 6 Then
ExtractInvoice = Mid(rCell, InStr(1, rCell, "6"), 7)
ElseIf Len(Mid(rCell, InStr(1, rCell, "7"))) > 6 Then
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End Function

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Jan 15, 2008

I am using a regular expression in a function to extract numbers from strings. the code I am using is below.

Function ExtractNumber(rCell As String)

Set RegEx = CreateObject("vbscript.regexp")
RegEx.Pattern = "d*.d*"
If RegEx.Test(rCell) Then
ExtractNumber = CDbl(RegEx.Execute(rCell)(0))
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Jan 25, 2007

Imagine that I have this list of thousands of customers, who are listed in column B in the format "customer no+space+customer name".

Now I want to extract ONLY the customer no from the text string in column B and insert it as number value in column A on the same row.

Would have been easy with "Left" command, but as the customer numbers have variable length, I have a problem.

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Aug 14, 2014

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E.g. cell F2 contains BP2.2.1:40 BP2.2.1:50 BP2.2.1:60 BP2.2.1:70 BP2.4.1:80

and what i want as a result is : BP2.2.1 BP2.2.1 BP2.2.1 BP2.2.1 BP2.4.1.

I've tried =IFERROR(LEFT(F2,FIND(":",F2)-2), " ") but only displays 1 out of a possible 4 in the cell.

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Code:
Function parseNum(strSearch As String) As String
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[Code]....

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BA123
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BE7893B

In column A I need the first two or three letters only,

BA
BA
EZY
BE

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1234A
123
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893B
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Dec 22, 2013

I have the following type of info in A1,A2,A3...

Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50

My goal is to get as close as possible to this,so it will be easier to sort and manage

Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180

I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180

I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.

My question is somewhat similar to this one
Extract A String Between Two Characters

Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?

Code:
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