Extract The First 5 Characters In A String, And Convert Them To A Number
Nov 7, 2008Say I have a string "09800EBHR052708"
How would I take the first 5 characters and get a number out of them?
Say I have a string "09800EBHR052708"
How would I take the first 5 characters and get a number out of them?
I have the following type of info in A1,A2,A3...
Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50
My goal is to get as close as possible to this,so it will be easier to sort and manage
Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one
Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Code:
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",3))+1,LEN(A1)),"_",REPT(" ",LEN(A1))),LEN(A1)))
I have a problem that I just don’t seem to have the brain power to solve right now. I have a list of websites and I need to extract all characters after the last “/” in the URL. URL example:.....
I have been using the find function in conjunction with LEN and RIGHT etc but the multiple instances of “/” is causing headaches for me. Also, the trailing string of characters that I want to extract can be both text or numeric and are of differing lenths.
Having trouble with this one. Searches seem to bring up every other variation of extracting info from strings except this.
I have cells which contain alphanumeric strings as below and, using a formula, I want to extract everything from and including the last letter to give A 2-3, B 3 and C 3-4 in the examples below.
Sub-base A 2-3
Sub-base B 3
Paving C 3-4
How can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
I'm working with a large list of items of varying length. A sample worksheet is attached. I need to do the following:
1) If the characters after the final forward slash from the right are of the pattern "tttxxx" (where "t" is text and "x" is a number/digit), then return all characters to the right of the final slash, including the slash itself:
Y:/Series/hun/hun109 ----> /hun109
2) if the characters after the final slash from the right are not of the pattern "tttxxx", then return all characters after the second slash from the right, including the slash:
Z:/Series/crd/crd409/editorial ----> /crd409/editorial
3) if there are less than 3 backslashes in the item, return a blank.
If for example, I have a set of IDs like:
Bellen-234-B25R
Carlota-345-C20RDF
Quad-765-Q20LP
How would I return just the first 4 characters after the second dash? The closest I can get is ALL the characters after the second dash.
If 'a' is a string that contains x number of characters, how do I find out what x is (in VBA)?
View 2 Replies View RelatedI wanted to return the second number in a string such as this:"0 of 0 jobs ... View all jobs"
The following worked perfectly:=MID(U3,FIND("f", U3)+1,LEN(U3)-FIND("f", U3)-23)
Until this line came up:"1 of 1 job ... View all jobs"
Obviously the "jobs" changed to "job" because of there being only 1, so the "-23" no longer worked. I need this to get the second number out of the string and it can change because the data is being refreshed from a website so it could easily change from one line to another.
It's for listing items to eBay. Ink Toners to be precise, the macro I have creates everything I need for a listing with a few msg prompts and importing data from another sheet. Saves me hours of work. Each cartridge has a Black, Cyan, Magenta, Yellow. The macro works fine for cartridge sets that go under one name. E.g: Brother TN325 Black, TN325 Cyan, TN325 Yellow... etc.
I've run into an issue with some cartridges which have different names: HP C530a Black, C531a Cyan, C532a Yellow...
I set the macro up to deal with different number, by removing the last character of the "tonername" string "C530", then replacing it with "C531".. etc.
What I haven't factored in is the ones with an A on the end. I need a way to tell it to ignore the a if there is one.
To make it clear, I will be inputting the text: C530a From this, I need to create 3 more strings: C531a, c532a and C533a
Here's the snippet of code I'm using to achieve what I'm already doing.
Code:
Selection.Replace What:=A, Replacement:=Left(y, Len(y) - 1) & "1"
Selection.Replace What:=b, Replacement:=Left(y, Len(y) - 1) & "2"
Selection.Replace What:=c, Replacement:=Left(y, Len(y) - 1) & "3"
[Code]....
Below is a sample of data I need to extract the 8 digit number:
WO_32092_56228491_575482-113476-WP55
WO_32092_56228491_115130-WP55
WO_32092_56228491_115116-115118/115117-WP55
WO_32092_56228491_291881-318903-WP55
WO_259_56748761
WO_13895_52245652COUNTYRDN-30
WO_17368_51421730-A-ADDPOLEINFIELD
WO_17368_50885431-A-ADDMISSINGPOLE
WO_11021_52350485brock3377
In a spreadsheet, I had set up three columns where:
A: removed first three characters. WO_32092_56228491_115130-WP55 to 32092_56228491_115130-WP55
B: removed up to the _ . 32092_56228491_115130-WP55 to 56228491_115130-WP55
C: captured the first 8 characters left. 56228491_115130-WP55 to 56228491
I am pulling the data into Excel via an ODBC where there is thousands of rows of data. The three column process puts a tremendous strain on the processor.
Is there a formula that will extract the 8 character number without a three step process?
I would like to parse a part number.
ab24s-12-g4a
if there is a "-#-" in the string, that is the value I want. If the "-#-" is not present, I would like to take the first number. Currently, as written in your first example, I am getting the first number - excellent and thank you!
In the sku, the first digit reprepresents capacity. If a second number is present after the capacity portion of the sku (i.e. "-#-"), that means that they want to order it filled with less than capacity. For instance, a carton of eggs and they want 6 eggs instead of the max capacity of 12. (i.e. egg12-6-z2z). Numbers after the second octet (i.e. z2z) do not matter.
It would be a number only in the second octet. If there are characters with it, the equation should disregard it.
Here are the scenarios, and what the formula should accomplish
1) egg12 --> currently returns 12
2) egg12-6 --> would return 6
3) egg12-6-g2c --> would return 6
4) egg12-g2c --> would return 12
Have many rows of alphanumeric strings. 2-4 letters followed by a variety of numbers, some spaces, and some additional letters. What I need is to return the first number after the initial 2-4 letters, everything after that first digit is junk. Thus, I would like a formula that takes me from:
AB23400 12 -> 2
CET25800 1 -> 2
NYT67300 H01 -> 6
HSRF49900 1 -> 4
I need to extract a set of 5 numbers from a string of characters. The number set I need is always 5 digits long, always starts with a 1, and always begins after a period. But the number I need can occur in different parts of the string:
In each example below I would want to extract only the 10572 portion.
5194003.10572.N
5194003.10572.R
5194003.1.0010785.10572
7500008.N.5999900.10572
Additionally (if possible) if the cell is blank I don't want anything to show up, and if the string begins with a letter then I don't want anything to show up either.
My knowledge of functions is pretty limited, or negligible to be honest. I require a function to extract numbers from each cell in a selected range.
Eg.
cells contain the following data:
cell 1: xxxxxx 45,59
cell 2: x xxxxx xx 6,45,27
cell 3: x xxxx 28
were x represents text
I need to loop through each cell and extract each of the numbers and list them in a separate range. If applied to the above range of cells the function would show the below in the ouput range. Each number in its own cell.
6
27
28
45
45
59
What is the formula to be used to extract number from a alphanumeric string located at different row?
example:
test123test128test131
test124test129test132
test125test130test133
test126test131test134
test127test132test135
test128test133test136
result: ....
I am trying to extract a 7-consecutive-digit number from a mixed string (letters and numbers). The only condition is that the number has to start with a "7" or "6" and be exactly 7 consecutive numbers long. My function only evaluates for one and one within the other but not both. It's faulted because it only looks for the occurrance of "6". rCell is the string range.
Function ExtractNumber(rCell As Range)
If Len(Mid(rCell, InStr(1, rCell, "6"))) > 6 Then
ExtractInvoice = Mid(rCell, InStr(1, rCell, "6"), 7)
ElseIf Len(Mid(rCell, InStr(1, rCell, "7"))) > 6 Then
ExtractInvoice = Mid(rCell, InStr(1, rCell, "7"), 7)
End If
End Function
I am using a regular expression in a function to extract numbers from strings. the code I am using is below.
Function ExtractNumber(rCell As String)
Set RegEx = CreateObject("vbscript.regexp")
RegEx.Pattern = "d*.d*"
If RegEx.Test(rCell) Then
ExtractNumber = CDbl(RegEx.Execute(rCell)(0))
Else
ExtractNumber = vbNullString
End If
End Function...
The following function reads many worksheets in one workbook and put the information into one worksheet. F22 to Q22 is dates in the format of mmm-yy on the many worksheets. On the one worksheet B1, C1, D1, etc... is dates also formatted mmm-yy. Now the many sheets only have a 12 month period but could be any date within 60 months. In the many worksheets the beginning date in F22 is based on the date that is entered into G8 of the many worksheets. The function is:
Code:
Function HrsByMonth(strField As String, MonthNum As Integer) As Long
Dim sht As Worksheet, i As Long, j As Integer
HrsByMonth = 0
[Code].....
I am trying to convert a number string date that has been stored in a database to a readable date time in an excel pivot table.
1260983366 needs to look like Wednesday, December 16, 2009, 10:09 AM.
The converted date could also look like Wed, Dec 16, 09, 10:09 AM.
Imagine that I have this list of thousands of customers, who are listed in column B in the format "customer no+space+customer name".
Now I want to extract ONLY the customer no from the text string in column B and insert it as number value in column A on the same row.
Would have been easy with "Left" command, but as the customer numbers have variable length, I have a problem.
I'm trying to extract all the numbers from the left of the delimiter ":" . They can occur once or more.
E.g. cell F2 contains BP2.2.1:40 BP2.2.1:50 BP2.2.1:60 BP2.2.1:70 BP2.4.1:80
and what i want as a result is : BP2.2.1 BP2.2.1 BP2.2.1 BP2.2.1 BP2.4.1.
I've tried =IFERROR(LEFT(F2,FIND(":",F2)-2), " ") but only displays 1 out of a possible 4 in the cell.
I need a VBA function to extract number sequences from a string and separate them with hyphens In the example below cell A1 has the value 'xx2 yyy34 zz515' The code must produce the value '2-34-515' from the above example I have the following function that extracts the numbers but need a way to separate the groups with a hyphen
Code:
Function parseNum(strSearch As String) As String
Dim i As Integer, tempVal As String
For i = 1 To Len(strSearch)
[Code]....
I have something like the following:
If Worksheets("RawData"). Cells(1, nColumn).Value = Worksheets("RawData").Cells(12, 16).Value Then
..do code (I know the cell location of interest at this point)
End If
Then I End up needing To Do something Like the following
ActiveChart.SeriesCollection(1).XValues = _
Worksheets("RawData").Range("L1:N1")
“L1:N1” above is a sample. Given the code above it I have the cell location in question but it is in the format such as .Cells(12,16). That doesn’t do me much good when range wants something like “L1”. I don’t know how to convert that (12,16) to a L16 for example.
I am working with flight numbers and want to split out the letters from the digits. Examples,
BA1234A
BA123
EZY4566H
BE7893B
In column A I need the first two or three letters only,
BA
BA
EZY
BE
In column B I need everything to the right of what appears in column A
1234A
123
4566H
893B
etc.
I have a problems here. The problems is attached in the file. I wanna extract alpha/char from a string. Example: I wanna extract the words "(M)" with the bracket from the string "Toothbrush (M)" in column A. After extracting the (M) out, I wanna do a validation to compare the (M) in column B with another data in column C, if the (M) is same as the data called "Medium" in column c, the validation will return "Match" in the column d!
View 9 Replies View RelatedI would like to extract any numerals between the comma and colon. (Format is text)
Example: 8 Dec, 1:52PM (1 to show in another cell)
Format is always the same but date/day & hour may change. (Hence changing number of characters depending on day and time.)
Example: 11 Dec, 10:49AM (10 to show in another cell.)
In column M I have data that lists a number, then number of metres between brackets. For instance
Column M
11 (79m)
1 (5m)
22 (123m)
Basically what I want to do is to always return the number of metres without m, so the data between "(" and "m".
I tried to do this using the find and mid formulas, but I either haven't got it quite right. I'm only after a spreadsheet solution (not VBA).
Data in field A1 currently appears as below.
8/10
I want to extract everything to the right of the "/" in a new field.
The formula that I am using is =RIGHT(A1,FIND("/",A1)-1)
For some reason, I am only receiving a 0 in the new field and not the 10 that I expect.
What's odd is that the formula is working as intended on every other field except this one.
I have a column contains Postal Adress in more than 5000 rows. Column contains Door Number, Area, City and Zip code. I need to separate "Zip code" alone in next coulmn. Zip code (of India) will be in six digits like "600083" also some cases contain space in middle of zip code like "600 083" (after 3 digits). Is there any way to do this without doing cut & paste?
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