The Formula bar shows: ="01/01/2009"
The cell presents: 01/01/2009
I need to remove the equation sign as well the two inverted-commas.
I am familiar with the "Text to Column" feature, the use of SUBSTITUTE Function, a short macro and also the Find&Replace is also a good idea but, as far as I understand,
it must be run Twice(!)
I am looking for a way to use Find&Replace in "One! shot" - meaning, to put the TWO different(!) characters [ the '=' and the " ] in the 'find what' window,
leaving the 'replace with' window empty.
I know that something similar to that can be done in a "Word" document - but can it be accomplished in Excel?
This problem has come up fairly frequently lately, and I'm not sure how to fix it, or if this is by design...but in Excel 2003 I can't seem to do a "Find and Replace" based on the value of a cell. I can do a find, based on cell value, but the moment I change to the replace tab, the "values" and "comments" are missing from the "look in" dropdown.
I've only noticed this when I'm trying to replace on a filtered list, so I'm not sure if that is part of the issue.
Perhaps an alternative way of arriving at the same goal. Basically I have a worksheet with a number of filtered columns. They are filtered just right, using custom filtering, and so I do not want to undo the filters. In some columns I have formulas that are returning #VALUE! errors. I'd like to replace all of these cells with NA.
I recently became owner of a spreadsheet with some issues, and I am trying to make it useful. Each row has a URL of a blog post, and I want to extract the date from it (which is present in each URL) while getting rid of the rest of the URL. I was able to get rid of everything up to the year (which comes first), but then the URL continues, for example, 2013/05/16/the-rest-of-the-url/ and I would like to just have 2013/05/16 remain.
I am trying to use find and replace with the find box reading 2013/??/??/*/ and replacing it with 2013/??/?? which effectively erases everything else in the url, but leaves ?? instead of the numbers. Is there any way to have it so that it keeps whatever was in the original box?
Trying to repeat a 550 or so character statement with a find/replace however I am getting type mismatch errors. When I use a smaller message in the "replace" it works.
I need it to post a message exactly as long as what I have in there. How do I get it to work?
Need assistance with the code for catching errors when using the find / replace function in excel? In particular, I am trying to write code to break to an error message when the value or string searched for isn't found in the find / replace. At the minute I have just copied the standard code using a macro and all this does is return a message box saying X entries replaced.
I am trying to create a macro where it finds a a certain word in a column for example C. What i want it to do is find anything that says FWD_EUR and then replace that cell (e.g C2) with CASH_EUR_FWD and after it has done that it replaces the adjacent cell (e.g. D2) with EUR_FWD. I then want this to do the same with FWD_USD to CASH_USD_FWD and adjacent cell to USD_FWD.
Range B3:B1000 is text strings. Column C2:C50 is a list of words that I would like to "Find" in Column B and replace with it's lowercase values unless they start off the string.
Example
Find all occurences of And or AND and replace with and Find all occurences of With or WITH and replace with with. Find all occurences of Or or OR and replace with or
I believe I should use the INSTR function, but I simply dont understand its use very well. I have a string in a cell, "MEAS/SPHERE,F(QUA_1),5", the characters I need start at the "(" and end at the closing ")", ref: (QUA_1). The start and end will always be the same, the length of characters and the spelling of characters be anything. Thus, QUA_1 can be CAL_1, CAL_2, SOMEOTHERTEXT_1 or 187bgo_199, etc, always enclosed in "( )". I wish to place the characters and the closing "( )" into a variable as a string.
This one has two sets of quotes, with the information from the noted post I can retrieve the string "S5a09b-90", now that I have a double set of brackets "( )" how do I get the value for the second set of brackets, "CAL_15"?
In the quoted string, CALIB/SENS,S, is constant. The first set of brackets are constant (string length is not), the second set of brackets are constant (string length is not).
I made in a macros this formula :LEFT(RC[-1],(LEN(RC[-1])-2)) is removing from left side an index , like in this example ' 9117 - 570-65CE49D-B4-7 to obtain 9117 - 570-65CE49D-B4
so here is my code,
is with an userform, but it gaves me an error, that my procedure is invalid
I need to some spaces to the end of a string to make it up to 36 chars.
The original string can vary in size based on the courier name. i.e. : business direct invoice 40617 = 29 chars i.e. : TNT post invoice 4061755 = 24 chars
Can someone point me in the right direction to be able to concat' some spaces on the end to make it up to 36 chars.
I want to remove varying amounts of periods that appear at the end of my strings. For instance, ABCEDFGH......., DEFGH.., FG.... etc. Do I have to test each char to see if it's a period, and then use that count of chars to LEFT out the string that I want? Or is there an easier, quicker way to do this?
I'm looking for a formula which returns the longest consecutive series of occurrences of 2 chars in a text string.
In the case I'm trying to count the longest consecutive number of nine-spares (9/) in a bowling game.
For example:
|7/|X|9/|9/|9-|9/|9/|9/|9/|X8/|longest series of 9/ would be 4. |9/|9-|9/|9/|7/|9-|(8)/|X|7/|9-|longest series of 9/ would be 2. |9/|(8)1|X|X|72|63|7/|8/|8/|9/9|longest series of 9/ would be 1.
I have a file of names that has some undisplayable characters. I am trying to match against a different file. It works if I overtype the "blank" fields with a space. How can remove these trailing problem characters whatever they are? I tried CLEAN and TRIM and the mystery characters are still there.
I am having problems with a macro I am writing and I need some guidance on where I am going wrong (I am still a noob at VBA).
I have pasted the code below (not the most efficient use of code I know).
I have a list of departments and codes from the Intranet at Work. Now this contains a Department Code, Department Description and within the Description is a number in brackets showing how high up the organisation hierarchy they are....
I'm using excel 2003 and I have have a dynamic string of data separated by 19 commas ",". I think 19 (the # of commas) is one of the few fix numbers...
What I'd like to do is from Right2Left return the 5 characters immediately to the right of (before) the 11th "," comma (i.e. 22.59 for the 1st string on Excel Cell A2) OR from the Left2Right return the 5 characters immediately after the 9th comma "," comma, which is also 22.59
Example of some of the strings I've been trying to work with...the list is much longer...but for example sake I've limited to 4...
I was wondering if it is possible to do this unique find and replace that is explained below.
I have many columns with data from our database. I have one column that has my html layout in it. I want to find within the html text data and replace it with data from another column for that row.
Example: We have [[manufacturer]] in the html area that we want to replace with data from our column called Manufacturer. So, it will replace the text in the html named [[Manufacturer]] with that rows Manufacturer data we have.
I have around 10 names which I want to replace with their code names. For Example, "Alan Richard" needs to be replaced with AR001. Problem is I don't know cell range and this name might appear more than once in the data.
I am trying to find and replace #N/A from a formula (link to another sheet) with nothing in the cell, using VBA.
Using this code it will do the first "find" Cells.Find(What:="#N/A", After:=ActiveCell, LookIn:=xlValues, LookAt _ :=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:= _ True, SearchFormat:=False).Activate ActiveCell.ClearContents Trying this Cells.Replace What:="#N/A", Replacement:=" ", LookIn:=xlValues, LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=True, SearchFormat:=True, _ ReplaceFormat:=False LookIn:= is highlighted and I get a "named argument not found" Don't understand that because LookIn:=xlValues works in the first code.
I did try and place After:=ActiveCell,before this, but that does not work. I Get the same error.
I have more then one cell with the #N/A which I would like to get rid of. I want this to work only on this one sheet. The other sheet that the formula is pulling from does have #N/A, and that is okay, I need it there.
I have a list of sales associates that are assigned numbers. For example, John Doe is 1022. The data I have to work with only shows his number 1022 but for my reports management wants the name John Doe. I have about 60 sales associates and have a VB code that 'finds and replaces'. The code is huge. It has slowly grown out of hand, with more sales associates added daily. I also have 22 sheets in one workbook with specific columns to search for the numbers to replace with the names.
This is what I would like to do. Have a sheet named associates, as more associates are added I would just have to add their name and number. Have two columns with headers column A - Associates column B Associate #. Name ranges for the two columns and write a code that says look in the sheet associate, at named range 'numbertoname' and if the current sheet 'total sales' I am in has the number 1022 in column C replace it with the name John Doe. It seems like it should be easy but.......I have tried and tried today.
I am facing a strange problem with Find and Replace function of Excel. I converted a PDF document into a Word document. I copied the tables in the Word document to an Excel document. As the data had many ‘*’ characters, which I did not want, I used Find and Replace function to get rid of them. However, to my surprise, two things were happening.
1.When I tried to replace ‘*’ in a cell with ‘ Construction revenue ********************** ’, it was deleting all the contents of the cell. 2.When I tried to find all the cells with ‘*’ , it was selecting cells even without ‘*’
I tried various things like changing the format, pasting only values..etc, but nothing worked. Finally I had to use the Replace function of VBA to do the task. For further analysis I am attaching my Excel file with that data.
In the attached file I want to do a Find/Replace for 599 --> 599.0 and 428 --> 428.0. When I do a F/R for each it tells me it has made 3 and 5 replacements respectively but the data is not changed?
HOWEVER when I do the find & replace I don't want it to change whatever the current value is to D3 I want it to stay as whatever it was already....so how do I exempt the "D" value from the search?
I'm using Excel 2007 and trying to replace about 2000 commas with full stops. I want to use find and replace but keep getting a message saying that Excel cannot find the data I'm searching for.
Excel help suggests I haven't clicked on "find" before clicking "replace" but I did. I've tried highlighting the column in which I want to make the replacements, but same message.
Also tried highlighting nothing, same message.
Tried copying and pasting the whole thing into a new file, but same message.
I have two groups of numbers. The first group is x amount of rows and each row has 6 numbers. The second group is x amount of rows and each row is 7 numbers.
Each number from the first group needs to check to see if it exists in the second group. If it does exist, the cell should change to a highlighted cell, or switch to an 'X' or something else that identifies it has been matched. Note: Numbers may be duplicated in both groups. Is there an easy way to do this, or will it involve programming? I'm attaching an example of the "group" setup.
I have various formulas (such as: =(D3-$E$3)/$E$3 ) which continues for each row (IE next row 3 is replaced with 4 etc)
I have made som errors when I made the formulas and therefore I have the following questions:
1. Is it possible to find and replace all E's with another letter (F in my case). I haven't been able to resolve this, when it has to be done inside formulas? The optimal would be if I could set 'Display formulas' under tools, and find and replace in the formulas displayed.
2. Is there a smart way of swapping D3 with E3 for all formulas? (So the result will be: =($E$3-D3)/$E$3 and etc for all formulas)
