I want to remove varying amounts of periods that appear at the end of my strings. For instance, ABCEDFGH......., DEFGH.., FG.... etc. Do I have to test each char to see if it's a period, and then use that count of chars to LEFT out the string that I want? Or is there an easier, quicker way to do this?
View 3 RepliesI believe I should use the INSTR function, but I simply dont understand its use very well. I have a string in a cell, "MEAS/SPHERE,F(QUA_1),5", the characters I need start at the "(" and end at the closing ")", ref: (QUA_1). The start and end will always be the same, the length of characters and the spelling of characters be anything. Thus, QUA_1 can be CAL_1, CAL_2, SOMEOTHERTEXT_1 or 187bgo_199, etc, always enclosed in "( )". I wish to place the characters and the closing "( )" into a variable as a string.
View 5 Replies View RelatedCALIB/SENS,S(S5a90b-90),FA(CAL_15)
This one has two sets of quotes, with the information from the noted post I can retrieve the string "S5a09b-90", now that I have a double set of brackets "( )" how do I get the value for the second set of brackets, "CAL_15"?
In the quoted string, CALIB/SENS,S, is constant. The first set of brackets are constant (string length is not), the second set of brackets are constant (string length is not).
I made in a macros this formula :LEFT(RC[-1],(LEN(RC[-1])-2))
is removing from left side an index , like in this example '
9117 - 570-65CE49D-B4-7 to obtain 9117 - 570-65CE49D-B4
so here is my code,
is with an userform, but it gaves me an error, that my procedure is invalid
I need to some spaces to the end of a string to make it up to 36 chars.
The original string can vary in size based on the courier name.
i.e. : business direct invoice 40617 = 29 chars
i.e. : TNT post invoice 4061755 = 24 chars
Can someone point me in the right direction to be able to concat' some spaces on the end to make it up to 36 chars.
Would this be easier done using VB?
I'm looking for a formula which returns the longest consecutive series of occurrences of 2 chars in a text string.
In the case I'm trying to count the longest consecutive number of nine-spares (9/) in a bowling game.
For example:
|7/|X|9/|9/|9-|9/|9/|9/|9/|X8/|longest series of 9/ would be 4.
|9/|9-|9/|9/|7/|9-|(8)/|X|7/|9-|longest series of 9/ would be 2.
|9/|(8)1|X|X|72|63|7/|8/|8/|9/9|longest series of 9/ would be 1.
I'm using excel 2003 and I have have a dynamic string of data separated by 19 commas ",". I think 19 (the # of commas) is one of the few fix numbers...
What I'd like to do is from Right2Left return the 5 characters immediately to the right of (before) the 11th "," comma (i.e. 22.59 for the 1st string on Excel Cell A2) OR from the Left2Right return the 5 characters immediately after the 9th comma "," comma, which is also 22.59
Example of some of the strings I've been trying to work with...the list is much longer...but for example sake I've limited to 4...
I would like to query your knowledge database (too much VBA I guess ) as I have a predicament that I cannot seem to solve.
Here is the thing: I am trying to write a sub that would enable me to automatically put in place extensible name ranges (the Offset worksheet function).
The problem is that, despite everything seems to go well, the reference in the name box displays : ="DECALER($C$2;0;0;5-1;1)" (the string comes from a variable and Decaler is Offset in French). These quotation marks are the culprits for sure, as taken off the formula works beautifully.
I've tried everything I've found on the internet, that is to say: Replace(String, Chr$(34), "") so on and so forth, but these marks are not recognized a part of the string so they escape the replacement.
I am trying to develope a "goto" page macro where the page value maybe 1,34,7A, 256C etc. I am not clear on how an inputbox value can be compared to a string variable or a numeric variable at the same time. This is what I have done, but when the texboxvalue is "7A" it doesn't work.
View 3 Replies View RelatedSay you define a public range variable called Inputworksheet and you set it to refer to the worksheet called Inputworksheet. You have a separate string variable with the value Inputworksheet. How do you get this string variable value to call/control the range variable Inputworksheet?
I am getting an excel worksheet value from a lookup function that corresponds to the name of a VBA range variable. Once I have this worksheet value, I would like to use the range variable that has the same name as the worksheet value.
I'm using a userform to create a new sheet. The form already creates the sheet and names it what was typed into the userform. Now I want it to place that variable in a cell along with a string. the following code will place the variable from the form (tbname) into cell b5.
View 2 Replies View RelatedI'm trying to remove everything after a specific character in a string.
I.e. change a website address to the hostname
http://www.excelforum.com/newthread.php
http://usa.excelforum.com/forum/new
to
excelforum.com
usa.excelforum.com
I'm using this formula, which strips the http:// and the www., but does not replace the characters after the first remaining "/" as the wildcard is not recognized.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A2,"www.",""), A2,"http://",""), A2, "/*", "")
I'm attempting to extract the Street Names from an Address.
For Example, if given "123 Very Big Street" I'd want to extract "Very Big".
If given, "123 Very Big" I'd want the same answer.
I've written code to do this, with a simple IF statement to identify mathcing last words like "Street" and "Drive".
How can I efficiently do this with a large list of last words? I'm drawing a blank on how to query against an array that would contain all these values.
How can I remove everything to the left of the first space in a String? For exapmle - 'Mr Adam Bill' should become 'Adam Bill'
If someone enters "1,000" in a TextBox, Isnumeric(TextBoxEntry) says True
If I convert it to a value with something like x = TextBoxEntry * 0, the 1,000 becomes 1
I would prefer it to be 1000. Just removing commas would do the trick. How to do it.
The below function concats a range of cells by csv. How can I get it to remove the last comma in the string when it's finished?
Function SpecialConcatenate(rnge As Range) As String
Dim r As Long, col As Integer
For c = 1 To rnge.Columns.Count
For r = 1 To rnge.Rows.Count
If rnge.Cells(r, c) "" Then
SpecialConcatenate = SpecialConcatenate & _
rnge.Cells(r, c).Value & ","
End If
Next r
Next c
End Function
I have a list of data that populates B2:B2900
This data is often prefixed by a 'reference code' that I wish to be removed.
Now rater than perform this manually aprox 3000 times is there a formula or some VB code that will complete this for me....
eg
The list of data is shown like:
SC7547-05 - Payne, Freda
SC8706-08 - Rungren, Todd
SC8714-05 - Travis, Randy
SC7517-03 - Beach Boys, The
Love Song
Now You're Gone
SC7512-01 - Horton, Johnny
SC8721-15 - Journey
So I wish for the SC7547-05 - to be removed from the first example to just leave Payne, Freda and continue this throughout the list
However if the data is found not to include this code (as in the 5th/6th examples above) leave it alone
So if the code of formula is run for the above the outcome would be....
Payne, Freda
Rungren, Todd
Travis, Randy
Beach Boys, The
Love Song
Now You're Gone
Horton, Johnny
Journey
i would like to remove string "Total" from a list in col A,
Sheet1 AB5How do I remove total Excel tables to the web >> Excel Jeanie HTML 4
I have a string like: AAJDGYE030000460. How can I remove the first character in a macro? I need to look at the second,third, and forth character
View 3 Replies View RelatedI have a set of data in column a that consists of email addresses. These email addresses all have underscores after them, ie "abc@hotmail.com_______". It will be a different amount of underscores everytime and I don't want underscores to be removed that are actually part of the address. I had been using the find replace function through vba, ie
Range("A:A").Select
Selection.Replace What:="_", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
however this ofcourse removes from actual parts of the email address. Is there a way to do this?
I've come across multiple times where I have to do this same sort of task, and I don't think I am doing it the most efficient way.
What I need to do is take a variable which holds a string and remove the last 9 characters from it. Don't need to know what the last 9 characters are, all I care about is knowing what the other characters are in the string. I know this can be done through thingslike susbstrings, but I don't think VBA has a substring function.
I am trying to remove all characters that aren't letters or numbers from a string. Is there any way to differentiate between a non-alphanumeric characters and alphanumeric characters? I'm thinking of something like "ISTEXT()" that I could use on one character at a time. Or are there any wildcards I could use in the Replace function?
View 9 Replies View Relatedmake equation to remove alphabet characters from a text mixed with alphanumeric characters like below.
eg.
1.ASD000234234-1RST to 00234234-1
2.ZYXW2343WE to 2343
3.abcde2023820eiwls to 2023820
like this
I have a list (SIC Codes) and I want to remove the numbers. The numbers range from 2 to 8 deep. The list exists in column B and I want the new list in column C.
01 Agricultural Production Crops
011 Cash Grains
0111 Wheat
0112 Rice
0115 Corn
0116 Soybeans
0119 Cash grains, nec
011901 Pea and bean farms (legumes)
01190101 Bean (dry field and seed) farm
01190102 Cowpea farm
01190103 Lentil farm
01190104 Mustard seed farm
I am using this code to remove a row if string is found, however, I would like to know how can I set it to do the same for all the worksheet in the same excel?
[Code] ....
I'm using excel 2007 and windows vista. I have 2 cells, A1 contains (01,) and B1 contains (01, 08). I want the result in cell C1 to be (01, 08) by calling function trim_sort($A1&$B1). The code gives me an error "invalid qualifier" for s.length & more.
View 4 Replies View RelatedI have a list of about 1,400 numbers ranging in different lengths. What I'm trying to accomplish with a formula is to remove the single letter at the end of each number (not all numbers have them) and in addition to removing all zeros at the beginning of the number (again not all numbers have them).
Here is an example...say I have the following 5 numbers:
8014554
45678456
87451245
0008014554b
0008014554c
And what I need my formula to do provide is the following results instead:
8014554
45678456
87451245
8014554
8014554
So far I have started with the following =LEFT(A1,LEN(A1)-1), but that will always remove the last character (number and letter).
provide a vba script to replace characters from a string.
I have the following script which has the cell address as the string and want to remove the dollar signs.
Code:
Dim C1 as string
C1 = ActiveCell.Address
With C1
.Replace "$", "", xlPart
End With
I want to remove a string of text from the front and rear of a cell value and would like to do it with one formula. I have tried using LEFT,RIGHT and LEN. I would Like to use the SUBSTITUTE formula as the user can define the actual string to be removed.
I can achieve want i want using two columns i would just like to be able to consolidate down to one.I have tried nesting the formulas but i always seem to get an error.
Characters to remove
Raw data
Output
Front
dog
dogcatmouse
cat
Rear
mouse
dogratmouse
rat
Assume that the table uses stadard naming conventions for Columns(a,b,c...) and Rows(1,2,3...)
A string contain a number like AB12345 or B7845 How could I remove the alphabetic characters and keep only the number.
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