I have a cell which holds text with a maximum number of characters of 6. Let´s say I want this cell to hold a word which is bigger, and trim it till it has 6 characters.
Example: word "Hippopotamus" (longer than 6 characters) should be trimmed so its displayed as "Hippop"(6 characters)
is there a way to specify how i want to trim, either right or left?
Example "Hippop"(6 characters trim right) or "otamus" (6 characters trim left)
I want to trim text into 10 characters.I am new to excel.
Attached is the sample sheet.
TRIM.xls‎
I'm having difficulty figuring out how i can Trim the last 3 characters from this string
Code:
FeatureCode1 = Split(errorChecker.lstErrorMessage.List(0), " [")(0))
I tried
Code:
FeatureCode1 = Left(Split(errorChecker.lstErrorMessage.List(0), " [")(0)), 3)
But that only SHOWS the last 3 characters... how i can just cut off the last 3 characters?
I'm guessing something to do with TRIM, but not sure how to implement it?
I have something simple (i think) but i cant think it through. I have a range of cells that are populated by a link and so even though the value shows #,### It really shows #,###.########
I would like to trim everything after the decimal point without having to adjust format of the range since some cells are general format and others are Percentage format but they all suffer from .####### HOWEVER, the last digits are variable and never the exact same amount of characters.
for each cell in range("C4:J9")
if cell.value "" then
Trim(Left(cell,4))
end if
next cell
This formula I want to apply it in another workbook. It split in different columns the content of a cell.
The formula is below:
[Code] .....
In cell A2 I have the following data:
|516582-001-99|414816-001-99|414816-003-99|516582-001-99|
If I apply the formula above in cells B2 to E2 it returns a blank cells. But if I delete the first "|" sign in the left side manually the formula works perfectly by splitting the cell into columns from B2 to E2. The issue here is that I have more than 300,000 records. Just imagine the amount of time invested in just deleting the first "|" at the left side.
I need a variation of the formula above that in first place delete the first "|" at the left side and after that continue with the proper work of the formula.
I have come up with this to Trim all of the data from rows 2:30 removing any trailing spaces after the last word in each cell. The macro takes a couple of minutes to run have I got something wrong that is making it run slowly or does the Trim process just take longer?
Sub TRIM_RANGE()
Dim myRange As Range
Dim myRow As Range
Sheets("CAMPAIGNS_2007").Select
Set myRange = Range("2:30")
If myRange Is Nothing Then Exit Sub
Application. ScreenUpdating = False
myRange.Replace What:=Chr(160), Replacement:=Chr(32), _
LookAt:=xlPart, SearchOrder:=xlByRows, MatchCase:=False
For Each myRow In myRange.Columns
If Application. CountA(myRow) > 0 Then
myRow.TextToColumns Destination:=myRow(1), _
DataType:=xlFixedWidth, FieldInfo:=Array(0, 1)
End If
Next myRow
Application.ScreenUpdating = True
End Sub
I have this code that trims cells and I would like to implement in it a way to remove line returns in cells (new lines created with alt+enter).
Below is the code I used so far:
I have a small Excel VBA program that pulls data from our company database. I use this to collect information about orders that have been placed. The decriptions of our inventory within our accounting software usually go something like this: [
2/24] Small Red Rose
The [2/24] stands for 24 pieces per case and 2 pieces per inner pack.
My question is... can I trim off the text '[2/24]' within VBA?
I need to create quotes, labels and other things that use these descriptions and don't need to include the information with the brackets.
Obviously within VBA everything is done with variables, such as strDESC for the description.
I would like to trim text based on the character .
For example i have a code FGH45679.A How do I keep only the characters before .A without the dot?
Any idea how you would remove all text strings that are red, I want to leave any text within the cells that are not red.
e.g
A1 contains
15245, 1535554, 17548789, erg, rtree, bf5256s
Would become
15245, erg, bf5256s
I want to put text after firsr 15 chars to new row.
View 5 Replies View RelatedI am writing to a text file and only want to allow 10,000 lines. There is only one value on each line. How can I trim the top of this text file to allow for more entries to be appended to it and still keep it at no more that 10,000 entries?
The lines look like
"1001-1"
"1002-3"
"1003-3"
"1004-4"
"1005-5"
"1002-6"
"1001-10"
"1004-7"
"1015-5"
"0002-6"
i have a device that produce its data as following:
NTFLog_D2013-02-12_T104016.csv
I need to divide the single column to 7 column as separated by semicolon ";"
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View 6 Replies View RelatedI have a cell (B2) I would like to apply multiple data validations to.
I know I need to use the custom formula option but don't know how to write the formula.
I don't even know if it is possible, but here is what I'm after
I need to make sure the cell is 4 digits long
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I frequently need to extract email addresses from huge amounts of text, like 40+ pages long, etc... I was wondering if a macro could be developed somehow to leave me with a stack of email addresses. I suppose the macro would have to test each piece of text for an "@" and a ".com" and then stack only those terms in a column somewhere. Any ideas on how to do this? I am not macro savvy AT ALL...
View 9 Replies View RelatedI've searched Excel's Help but still unsure how to do this. I hope excel experts here can lend me a hand...
I have literally thousands of words in a single columns column which looks like this:
absah
absen
absenan
absensi
abses
absis
absolusi
absolut
absolutisme
...
...
...
etc
My question is what formula if i'd have to enter to add three spaces between characters and five characters at every end of the word so it should look like this?:
a b s a h .
a b s e n .
a b s e n a n .
....
....
etc
Note i have entered a full stop at the end of the example above to make the five spaces visible in this demonstration (I dont need the period character inserted at all).
In my worksheet, column C contains a list of part numbers of various lengths.
How do I copy the part number without the last 3 characters & paste in col D?
I don't mind if this is achieved using VBA code or excel function.
How do I add special characters in-between text? I know how to include a registered sign by using =CHAR(174) but what I do not know is how to include text before and after the sign itself.
ie timeware *registered sign* community
I am submitting a book CSV file to my website. However, the website will not accept any cell that contains more than 80 characters. The error states the following. "WARNING: Title should be less than or equal to 80 chars; your Title was truncated to 80 chars" repeated 13 times.
View 2 Replies View Related"Is there some VBA code which could delete all first, second or third
characters of a text? Could it be done to the three last characters
from this same text and these be displayed on reverse order?"
Example:
AAAASAHDASK
AAASAHDASK
AASAHDASK
ASAHDASK
SADHASAAAA
ADHASAAAA
DHASAAAA
From the names listed in column A, in the table listed below, I wish to delete everything
to the right of the first two characters.
So the new column A would look this.
A
1
E HAZARD
2
F LAMPARD
3
F MALOUDA
[code].....
I have a textbox in a form and i need to check if the text posted there begins with zero or if it contains spaces. Ex:
05E 9050 01
if this is the text then it shoud warn me becouse there is a zero in the begining and it contain spaces
4P 565001
if this is the text then it shoud warn me becouse there is a space
if there is maximum number of characters in a cell, above which wrapping and the row height auto-fit functions will not work? I typed a paragraph into a cell and have the cell set to wrap and the row height to auto-fit but it does not display on print preview or on actual printing past a certain character in the cell. Even when I manually increase the row height, it still does not display.
View 4 Replies View RelatedI have a spreadsheet that uses sql to gather data from our servers. From this data, I use concatenate function to put the data into one cell ready to copy/paste into our sms program. The program will only take 160 characters at a time..
Result I need:
For the cell to split into two/three cells if over 160 characters (and to break after the last complete word), and if appropriate, it needs to say 1of2 at the beginning of the 1st message for example, and 2of2 at the beginning of the second.
In order to compare strings I have to remove a special character from imported text.
It is character F008 from Unicode(hex).
This charcter is not on my keyboard.
I find it under Insert - Symbol but I can't copy and paste it to the find/replace window.
how can I key in this character so that I can use it for find and replace?
I pasted in 1369 characters (including spaces) to a cell, and NO MATTER what I try, all characters will not print.
If I have the cell up for formatting on the function line, all text can be seen, but for some reason it cuts off the last sentance or more and will not show it in print preview.
I've tried all kinds of cell text formatting, cell merging, etc. with no luck. The only work around I found is to just have the "missing text" on the following row.
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
=LOOKUP(9.99E+307,--MID(C4,MIN(FIND({1,2,3,4,5,6,7,8,9,0},C4&1234567890)),ROW(INDIRECT("1:"&LEN(C4)))))
is the solution, but I'm struggling with making the correct alterations.
I am trying to extract text from stings that appear in the following format XXX-XXX-XXX and XXX-XXX-XXX-XXX.
I have figured out how to extract the first and second sets of data, what I am stuck on is getting the third and (if present) fourth sections.
Is there a function that can remove all text and other characters from cell and only keep the numbers? The numbers can be randomly in the cell so not only in the end or beginning.
See attached file.