Starting in cell F3, if Column F is greater than or equal to zero, delete the entire row and continue deleting rows until Column A has contents in it. Then go to Column F in that same row that had contents in Column A, if the contents in that row of Column F are greater than or equal to zero, delete the entire row and continue deleting rows until Column A has contents in it. Persist with this pattern until every row in Column F has been checked.
I have a sheet where i want to delete duplicate rows where column A and column B combined are equal, i.e. range(Ax:Bx) where x is the current row. I am using the macro below but cant seem to get it working as I keep getting a type mismatch error and Im not sure why.
I need an easy code that searches all of column A and deletes the entire row if the cell has the value "-". It needs to find the last row of data using something like LastRow = Range("A" & Rows.Count).End(xlUp).Row
Located in column W are amounts. if this amount is les than or equal to zero, I want to look at column A to see what account number is associated with that amount. then delete any row with that account number and also any empty row that may be directly above it.
Macro to delete a row if it contains a particular value in a column. Say for example I have the following:
a b c d 1 x 2 x 3 4 x
I want to be able to put into my macro code that says delete all rows that contain an X in column B. So this would leave just Row 3 remaining.
I could also sort this data so that I get: a b c d 1 x 2 x 3 x 4
That way I just have to delete all the rows less than and equal to 3. Ultimately I'm trying to get a way for the macro to copy the rows that DONT have a value in a particular column. But I figured it might be easier to find a macro which would delete.
I need some assistance with a simple macro. Im clueless when it comes to macros.
Heres what I have:
column "e" contains the year built for homes. Some of the fields contain "9999" or "0000" or blank. I need to delete these entire rows. If the year is between 1900 and 2020 I would consider it valid and keep the row.
So I need a macro that says something like this:
if column "e" is not between 1900 and 2020 delete the entire row.
I have a excel file which contains dublicate rows. The duplicate rows can be identified based on few cell/column values. I need a macro to delete the duplicate rows when the below condition is satisfied: let us consider row 5 and row 6:
If column 7,12,13,16,17,18,19,23,24,27,28,29,30 in row 5 = row 6 then row 6 has to be deleted. This condition has to be followed for all other rows in the excel used range. Have attached the sample workbook.
Each day I am going to have a list of about 300 different ID numbers, which i have already got a macro for creating, that outputs them into a single column on a sheet.
The next challenge Ill face now, is that I'll have a list of maybe 500 ID numbers in another spreadsheet.... I need a way to basically tell excel to keep rows that contain the numbers in 1 column on the list of 500, that correspond with those on the list of 300.
Numbers that are not found on the list of 300 ID numbers, must be deleted, along with the entire row.
I essentially need a macro that runs something like this that i found online, but instead of it just looking for the word "apple" as rows to delete, i would need it to check to see if the number is one of the 300 on my list.... and delete the row if it is not on the list
Sub Delete_Rows()Dim rng As Range, cell As Range, del As RangeSet rng = Intersect(Range("A1:C20"), ActiveSheet.UsedRange)For Each cell In rngIf (cell.Value) = "Apple" _ThenIf del Is Nothing ThenSet del = cell Else: Set del = Union(del, cell)End IfEnd IfNext cellOn Error Resume Nextdel.EntireRow.DeleteEnd Sub
How to create a macro to search a value and delete the row but I'm having trouble trying to get this to search multiple values. Keep in mind I'm really new at attempting to create a macro so this may look terrible ;-)
I have a list of 20 numbers (changes from time to time) and I need to filter any row containing any one of these numbers out of my results each day. I am currently able to filter a single group of numbers but get an end error every time I attempt to string a group of numbers.
This is what I have so far and is an example. We'll use three numbers as an example.
"12345","12346","12347" are the numbers that we'll use for the example that I need to filter. The code that I have is:
I want to create a Macro to be used on the Active Sheet that FIRST deletes all the rows that contain the following values in Column E. Here are the values contained in Column E that will result in deleting the whole row: PT, JK, BH.
Here is a data sample, the real data will have thousands of rows:
ROW 1 COLUMN E ROW 2 Work Code ROW 3 BN ROW 4 KL ROW 5 PT ROW 6 JK ROW 7 AL ROW 8 BH ROW 9 PT ROW 10 JK ROW 11 TU ROW 12 PT
Second, I would like the Macro to DELETE the ENTIRE Column E Not just the values in Column E.
Hi, I'm very new to writing Excel Macro's and wanted to know if I could do the following. Conceptually, I understand what I need done and think it should be fairly straightforward.
There's 2 main events in this loop (I hope that's the correct terminology):
Input 1) User defines the beginning cell to start the loop. In this case, A2.
Input 2) User defines the range of columns/rows to display. The formula for rows that I've thought of is 4r. So if a user wants 20 rows below cells A2, they simply input 5 for r. The number of columns is a constant 5. So if r=5, then I'd want the range to be A2:E22......
I am not the best at this, but we recorded a macro and we want to delete whole rows after we 'control' find something from a specific column. WHen we recorded our macro, it finds the first instance and we hightlight the whole row and 'control' 'shift' 'end' and delete all of the rows. We did this because we sorted and made sure the information we wanted to delete was at the bottom of the worksheet. we realized that each day the spreadsheet we pull from an ip address gets bigger and the row that we started from to delete starts on a different row each day. How do we get all the information to delete everyday, even when the row that Owned starts on changes? ...
I have a spreadsheeet with values in columns F:K from row 10 onwards
I need VBA code that will delete the rows where there are values opposite and equal in columns F:K from row 10 owards for eg if F10 is 10000 and K10 is -10000, F 25 is 150000 and G25 is -10000, G29 is -175000 and H29 is 175000, then rowa 10,25 & 29 must be deleted
I need to group all records where the values in column A are equal. BUT I needed them sorted by another column (the whole sheet, not just within each group). Currently, all of the values in column A are listed in random order. Is there any way to do this manually?
to elaborate a bit further, consider the following:
Columns: A-B-C-etc. 1-Z... 1-X... 4-X 3-Y 4-Y 2-Z
Basically, I need to group all of the "1"'s and all of the "4"'s so that the extra values will show underneath the other. HOWEVER, I need them to be sorted such that the order in which they appear are XYZ. So the goal would be:
I have cells that they're values should be equal B6=B11, B7=B12, B8=B13, E6=B14, E7=B15, E8=B16, I want a macro that if the values are not equal then the background should be RED and a pop up message "The values should be equal".
I have a sheet in Excel 2004 for Mac that is a patient list with over 2000 patients. I need a rule that will compare values (patient IDs and responsible party ID) in two adjacent cells, if the values are different, to delete the entire row. The goal is to get rid of patients (rows) that are not the responsible party (responsible party ID).
Is there an easy to use macro or VBA function to delete the rows with "position" column value of a zero? I have both positive and negative values in the column. I tried to put on filter but am not sure how to make it a rule based function: i.e. show only < 0 <.
Date Type NamePosition 2006/09/20CRGJacob11167 2006/09/20CRGTom 0 2006/09/20CRGMark 58371 2006/09/20CRGSue0 2006/09/20CRGDawn0
I'm having trouble with a small vba macro. At the end of the macro I test to see if two variables are equal and then print out true or false. However, for some reason even though the variables are equal vba is not treating them that way. I have put the values that represent the variables on a spreadsheet and used the if(x1=x2) formula and it says it is true, also, when I debug the macro and watch the values when it comes to test the logical expression the numbers are the same. I don't understand why vba does not say that the two variables are equal. I have attached a screenshot of the breakpoint where I double check the values are equal.
I am copying a price list from a worksheet. I currently have a script that deletes unwanted rows (products) but these products' header rows' are left. I also want to delete these text based headers. One solution might be a script that reads a columns cell value in the row(s) below and if values are missing the header row should be deleted.
Code: Sub DeleteAllBlankColumns() Dim LastRow As Long LastRow = Cells.Find(What:="*", SearchOrder:=xlRows, SearchDirection:=xlPrevious, LookIn:=xlFormulas).Row On Error Resume Next
I want it to ALSO delete entire rows in the worksheet that do not have any values across the entire row. Currently the worksheet prints rows that have borders but no values. This would eliminate that problem.
But if there is a value in any cell of the entire row it keeps that row.
I have a long list of IP addresses in an excel column, they all either end with .1 or .3, i want to be able to get rid of any ip address in the list that ends with .1 but when i select the column and choose filter by ends with and put the value (i have tried .1, 1 *1 ".1" and "1") and all it does is remove every value, the column looks like this
i figured the ends with filter would work but i dont know why its not doing what i expected it to, there are several thousand cells and it will be impossible to delete them one by one, how i can just get rid of any cell that ends with .1