Macro To Open File Saved In Same Location But File Name Changes With Each Date

Feb 8, 2013

I do routine tasks every day which involves opening 3 different files and pasting data into my main file. The data is always in the same format, and the 3 files are saved in the same location (3 different folders through). The 3 files are saved each day and the naming convention is constant, with only the date changing. For example, the files are always saved in C:My Documents and the files are called test_05.02.2013.xls. Tomorrow the file will be called test_06.02.2013.xls and so on.

So each day I will be rolling a file forward and I want to bring in the info from each of these files based on the new day.

How to do 1, and I will do the others (because the concept will be the same).

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I'm looking for a code which is checking the file name first before opening and operating on it. File name format is filenameyyyymmdd.xls but the problem is files in that directory are saved irregularly (couple times a week) and I need to open the newest saved file.

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I'm working on the following
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ActiveWindow.Close

Date: 2009-06-03

What I'm trying too do is open a file, make an exact copy and save it under a new file name.

My problem is in the date formula the day is not always the same. In the sample case it's 03 at other times the day will change.

is there a way too get this too work irregardles of what the day might be?

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VB:
Private Sub Commandbutton1_Click()
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[Code]....

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I have a VBA routine that asks the user to load an existing file on startup.

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The workbook to run the code will always be located on this same share at a fixed location.

My present code builds the path to the desired opening folder by collecting the drive letter from the current working directory (which has to be done as everybody maps there shares to different letters here, its not guaranteed to be the same! )

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ootafolderanother arget

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Code:
Sub Test()
Dim Rng As Range
Dim wb As Workbook
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[code]....

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Dim wb As Workbook
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Sub Macro1()
'
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VB:
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