I have a columb of positions which at the moment have a decimal place, I want to substitute the first decimal with a degree ie. S27.01.050 for S27°01.050 This has to apply to all cells in that columb.
View 9 RepliesI'm trying to convert degree minutes and second latitude and longitude to decimal lat and long in excel (I have 100s of such conversion to undertake). When trying out dividing the minutes and second by 60 and checking my calculation on Google Maps lat/long finder or Latlong.net my calculations are not correct. However the equation to other way around - converting from decimal lat long to DMS (*60) works.
View 2 Replies View RelatedI am having problems applying custom format to numbers that need to be formatted.
custom format use is 0",00". When I apply the custom format above to whole numbers, I achieve the results I want:
0.00
20.00
40.00
becomes
0,00
20,00
40,00
However, when I apply to numbers with decimal places
0.20.......
how I can change the custom format so that the period is replaced with a comma but the decimal values are preserved?
I have this data:
x y
310 516
320 526
325 535
330 587
335 640
340 715
345 857
350 1040
When I perform a third degree polynomial curve fit I get this equation:
y = 0.0106x3 - 10.0266x2 + 3152.3381x - 329943.8370
R2 = 0.9987
Which isnt right. On a calculator, I get negative numbers. Does excel have problems with 3rd degree polynomials?
I'm logging temperatures and I want to add the degree symbol "°" to the end of the numbers, how do I do that? It's easy if I just use one number (#°), but how do I do it when adding the lowest and highest in the same cell, e.g. 33-35?
View 9 Replies View RelatedHave written all the code to remove various words,numbers, etc from cells but this one symbol...I can not figure it out.
It looks like this:
Its the degree symbol, however using that symbol in VBA has proved to fail me. I have a large data set that is created for import but it will continue to fail until I remove this, Find(Replace) should work right? But using a search in VBA it deletes the entire cell.
i have a function in a cell (that works) to extract coefficients from a range of cells in a workbook:
VB: =INDEX(LINEST(CP25:CP27,CQ25:CQ27^{1,2}),1)}
i have variables for cp25:cp27 and cq25:cq27 already defined in my vba code. the values for these in the case i am working on are as follows (returns 110.5):
cp25 = 560
cp26 = 570
cp27 = 580
cq25 = .414
cq26 = .479
cq27 = .536
1) how to do this function in VBA only - this is part of a UDF and cannot have any helper cells
2) how to refer to 560,570,580 as a 'range'. is there a way to put these six variables into my ranges for later processing?
All of the google searches i have deal only with linear regression, taking from existing graphs, or say to just use the function i have above.
I have tried
VB:
Var = Application.WorksheetFunction.LinEst(Sheets("references").Range("CP25:CP27"), Sheets("references").Range("CQ25:CQ27^{1,2}"), 1)
[COLOR=#333333][/COLOR]
but return #value! errors. when i remove the ^{1,2} portion, i do return a value but it is incorrect (returns 160), what is the correct syntax for adding in the ^{1,2}? if you do that would be fantastic, but brings me back to issue #2 in that i need to refer to my variables in the vba code and not this range (as they will eventually be going away).
=IF(H29=>70,"1st",IF(H29>=60AND>=69,"2:1",IF(H29>=50AND>=59,"2:2",IF(H29>=40AND<=49,"3rd"))))
The formula is to work out the class of an honours degree for a certain student.
I have quite a number of 4th degree polynomials and attempting to extract the variables from every equation. I used the formula below (from another thread);
=LOOKUP(99^99,--("0"&MID(A1,MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A1&"0 123456789")),ROW($1:$10000))))
but it only extracts the first variable.
4th degree polynomial function: f(x) = ax^4 + bx^3 + cx^2 + dx + e
Example of one of the equations: Y = -42.4276 + 319.989 X - 809.094 X^2 + 942.247 X ^3 - 397.587 X^4
I'll like to have the final result like below (Based on the Example equation above)
edcba-42.4276319.989-809.094942.247-397.587
I have a vba macro that takes data from one workbook and pastes it into another workbook. In doing this I have declared a few variables of type single (I only need two decimal precision). However, when I copy the values from the cells on the source workbook and paste them into the target workbook, the numbers end up having 12 decimal places. Ultimately, this extra precision causes my totals to be off by .01 or more after a while. I have tried rounding the number as I pull it off the source workbook into the variable, but that didn't matter. How do I solve this problem? Code for pulling data from source workbook:...
View 2 Replies View RelatedBasically, I want to format a group of cells to display 1 decimal figure if the number is not a whole number. If the number is a whole number (or if the rounded first decimal place is 0) I want it to display no decimal.
View 9 Replies View RelatedI need to convert a column of numbers currently formatted with 2 decimal places e.g. 112.12 to 4 decimal places (without the decimal point). I need the end result to be 1121200. I've tried a few different suggestions given on the forum previously but can't seem to retain the 4 decimal places that I require.
View 4 Replies View RelatedI have to make a excel document in which I have length and width in feet and inch format.
E.g. 10.01 in which 10 is feet and .01 is inch
I have all the length and width values in the above format. And what I want to do is convert the inch value (10.01) to feet value (.01=.08 feet) .
Just like the calculator here does.. [URL] ........
Like
10.01=10.08
10.02=10.16
10..03=10.25
...and so on...
Here is table of conversions from inches to decimal feet. But I don't know how to get a formula for this in excel...????
Inch Decimal of a Foot
1 inch 0.0833
2 inches 0.167
3 inches 0.250
4 inches 0.333
5 inches 0.417
6 inches 0.500
7 inches 0.583
8 inches 0.667
9 inches 0.750
10 inches 0.833
11 inches 0.917
12 inches 1.000
I am trying to create a unique sample code by putting together the values of other cells that a user will input. It's all working well apart from the last part, where I am trying to include a decimal number. I want the decimal number to appear without the central "." and in a four digit format. e.g. 2.5 would appear as 0250, 14.25 would appear as 1425. This is the formlua I am using currently:
=IF(ISBLANK(B4),"",IF(LEFT(C4,1)="w",(B4&"-"&TEXT(F4,"YYMMDD")&C4&TEXT(G4,"HHMM")),(B4&"-"&TEXT(F4,"YYMMDD")&C4&LEFT(TEXT(H4,"00"),2)&RIGHT(TEXT(H4,"00"),2))))
However, where the value of H4 is 2.5, I am getting a result of 0303 (I've put this part in bold). I have attached a small spreadsheet to aid understanding.
I need a formula to multiply only the decimal number in a cell and not the integer. For example: the number in the cell is 57.3615. I want to multiply .3615 only.
View 2 Replies View RelatedThis problem has come up fairly frequently lately, and I'm not sure how to fix it, or if this is by design...but in Excel 2003 I can't seem to do a "Find and Replace" based on the value of a cell. I can do a find, based on cell value, but the moment I change to the replace tab, the "values" and "comments" are missing from the "look in" dropdown.
I've only noticed this when I'm trying to replace on a filtered list, so I'm not sure if that is part of the issue.
Perhaps an alternative way of arriving at the same goal. Basically I have a worksheet with a number of filtered columns. They are filtered just right, using custom filtering, and so I do not want to undo the filters. In some columns I have formulas that are returning #VALUE! errors. I'd like to replace all of these cells with NA.
I recently became owner of a spreadsheet with some issues, and I am trying to make it useful. Each row has a URL of a blog post, and I want to extract the date from it (which is present in each URL) while getting rid of the rest of the URL. I was able to get rid of everything up to the year (which comes first), but then the URL continues, for example, 2013/05/16/the-rest-of-the-url/ and I would like to just have 2013/05/16 remain.
I am trying to use find and replace with the find box reading 2013/??/??/*/ and replacing it with 2013/??/?? which effectively erases everything else in the url, but leaves ?? instead of the numbers. Is there any way to have it so that it keeps whatever was in the original box?
[Code] .....
Trying to repeat a 550 or so character statement with a find/replace however I am getting type mismatch errors. When I use a smaller message in the "replace" it works.
I need it to post a message exactly as long as what I have in there. How do I get it to work?
Need assistance with the code for catching errors when using the find / replace function in excel? In particular, I am trying to write code to break to an error message when the value or string searched for isn't found in the find / replace. At the minute I have just copied the standard code using a macro and all this does is return a message box saying X entries replaced.
View 3 Replies View RelatedI have values in row A and I have values in row C. I want to create a loop to look up xxx and replace it with the values consecutively in row C. Look at example for a better Idea. I found a way to find and replace, but I not sure how to use it with qoutes. I was thinking maybe I dont even need row A and just supply a list and excel could have the chunk of data in the code itself.
View 2 Replies View RelatedI am trying to convert Degrees Minutes & Decimals of a minute (12° 34.567') to Degrees and decimals of a degree (12.57611°). I have the formula to convert latitude, that is two digits, but it doesn't want to work with longitudes, three digits. (see attachment). This is the formula that I am using:
=IF(A2="","",(INT((LEFT(A2,3)+MID(A2,4,6)/60)*100000)/100000)&"d")
I need a formula to take a number with several decimal places and round it up to two decimal places to either .33, .66 or, .00 if its above .66.
For example, 4.23423423423423 will be 4.33
4.43453453533434 will be 4.66
4.8353453453 will be 5.00
Lets say the number is in cell A1. What formula would do this?
I am trying to create a macro where it finds a a certain word in a column for example C. What i want it to do is find anything that says FWD_EUR and then replace that cell (e.g C2) with CASH_EUR_FWD and after it has done that it replaces the adjacent cell (e.g. D2) with EUR_FWD. I then want this to do the same with FWD_USD to CASH_USD_FWD and adjacent cell to USD_FWD.
View 2 Replies View RelatedI'm wanting to use Excel's built in replace function to replace ANY date with "Call:"
I'm not going to go into details about why, but I cannot use a code, as I only want to change them at specific times.
The dates are currently formatted as 12/09/2009. So I need to change the 12/09/2009 and any other date there may be to "call:" without having to go through every possible date.
I have over 16000 cells with different information in them, each cell is unique. There are parts of these cells that have similar information.
I am looking to search part of the cell, and replace the whole cell with my new description, so I can run pivot tables on it.
I used the following code to replace " characters to !%. Then I copy the selected cells, and replace the !% back to "-es. The copied cells contain the "-es. When I comment the second replace, the function is working correctly, the copied cells contain the !%. What's the problem of my code?
Selection.Replace _
What:="""", Replacement:="!%"
Selection.Copy
'Selection.Replace _
' What:="!%", Replacement:=""""
i try to convert several decimal values into Days Hours:Minutes:Seconds my problem is the following. If i user the format DD hh:mm:ss values over 32 will start counting the days from 0 (like a new month). and if i format it like M D h:m:s values < 32 days gets displayed with a 1 (for the month) before the days.
[Code] ......
is there a way to get only the count of days displayed without the summarization to months?
I need to create a formula in a spreadsheet so that when KWD or BHD is entered into a cell then another cell changes to 8 decimal places if neither of these are in the box then it needs to be 7 decimals! But the box that is changing needs to be alterable.
I have posted this on a non excel specialised forums and i got this answer:
in cell x you have "kwd"
in cell y you put: =IF(cell X="kwd",TEXT(cell Z,"#,##0.00000000"),TEXT(CELL z,"#,##0.0000000"))
in cell Z you put the value that you want to be alterable
Extract 2 digits to the right of a decimal when it ends in 0, AND keep it a value.
Ex: .69 .75 .50 .70 = 69 75 50 70.
Text to columns won't work because it has to calculate from other cells' data. This value is then used in an IF function.
I actually have time entered as a number and decimal.
10.29 means 10 minutes and 29 seconds. How can I get that to only seconds 629?