Title should read: Finding the nth Occurrence of a character within a text string
I have a very long text string that is delimited by about 50 "/" to segment certain values within the text string. I want to be able to extract the text between the 33rd and 34th occurrence of "/". How to do this?
Is there a function in VBA that is similar to either the FIND function or SEARCH function in Excel? The arguments for the FIND function in Excel are FIND(find_text, within_text, [position]).
I have a text string in VBA ("$A1:$D$13") that I want to be able to identify the first "$" and then later the ":". I'm getting tripped up on the 3rd line of code. Thanks a million.
Sub page_set_print_area()
ActiveSheet.PageSetup.PrintArea = "$A$1:$D$13"
x = ActiveSheet.PageSetup.PrintArea
Position$ = Search("$", x, 0)
End Sub
I am trying to work out how to get nth position of a character in a string. For example in this
Code:
kjishdfiuayigdscka
if I use the formula
Code:
=FIND("i",I$1),
it will give me answer 3. But I want the position of 3rd "i" in the string. The answer should be 12. How can I change this formula to get the correct result?
In cell A1 contains a string, how do I get the number of position of the last numeric character from right to left (this value will be in cell B1).
Example: 12543AR3372C31WWW (In Cell A1)
4 (In Cell B1)
on the web I've found this formula, which returns the postion of the last occurrence of the character in cell B1 in the string in cell A1:
=MAX((MID(A1,ROW(INDIRECT("A1:A"&LEN(A1))),1)=B1)*ROW(INDIRECT("A1:A"&LEN(A1))))
How do I turn this into a VBA function?
I have a cell that has approx 22000 characters. I'm trying to remove a specific character string from a cell by doing a find and replace with "". It works for characters in the first part of the cell but not for characters in the last part of the cell.
Example: I do a find/replace for the characters 21242 to "" in column A and I get the expected results. I do a find/replace on 69294 to "", again I get the expected results, but if I do a find/replace on 85203 to "", I get "Excel cannot find what I am searching for" (but its there!)
My cell size is within the max size of 32,767 characters so not sure why its not working.
Attached a sample worksheet.
Possible to find the position of the 1st number value inbetween text??
example : GBB_5600_OPP_WNN
i want to extract a value from a column into another column in excel.
this first column contains text and i want to extract a value that in located between the characters 'FOR' and 'MTHS'.
how do i do that?
the situation is the same for all the rows; the value that i want is just located between these characters.
is there a simpler way other than using the MID functn? because everytime i use it i need to count the no. of characters and its quite difficult to keep up with the numbers.
I am reading lines from a textfile. Each line in the textfile has the identical format: textstring1:textstring2. The two strings are always separated by the : character. I have the code to get textstring1, but because I'm a rookie, I can't figure out how to get textstring2. See the code in bold, this is the line I need to get textstring2.
View 4 Replies View RelatedThere is a method to use ROW(1:10) within an array formula to strip a string into individual elements e.g.
HELLO > {"H","E","L","L","O"}
I cannot find it anywhere, thought it was something like =MID(A1,ROW(1:10),1) but not yielding results.
I am trying to return the first occurrence of a variable text string with-in brackets for all data on the spreadsheet using the "RIGHT" excel function, the text to search is in column D.
Example for cells D2 & D3 reads:
D2:Adv Costs (27a) - would return "27a"
D3:Designer Unit (60) (Base) (50abc) - would return "50abc"
I have a spreadsheet that has a column of text that is always 10 characters long. There are 10 rows of text so there could be 100 text characters if all rows are filled. The rows usually will not all be filled. There will probably be blank rows between used rows. I have been able to capture the text and put it into one cell as one long text which is ok but I want to be able to break it up into the 10 character strings again, separated with a comma and space between each 10 characters.
This is the code I used to collect the 10 character text strings and put them all together as the variable "result". I used & ", " after ... Cells(r,17) which worked fine unless there was a blank row. If the row was blank it put in a comma and space anyway so I ended up with duplicate(triplicate) commas and spaces.
Private Sub test_Click()
result = ""
For r = 5 To 32 Step 3
'If Cells(r, 17) "" Then
result = result & Cells(r, 17)
Next r
Range("r5") = result
End Sub
I need to create a macro to do the following:
Search the activecell for a text string (a), and then either paste in text string (b) at the end of the cell if (a) is found, or text string (c) if (a) is not found.
For example, if the activecell has "AA/" in it, I want the cell to become "AA/01" (pasting in "01" at the end), and if the cell has just "AA" in it, I want it to still become "AA/01" (pasting "/01" at the end). The macro will be linked to a commandbutton.
i have a device that produce its data as following:
NTFLog_D2013-02-12_T104016.csv
I need to divide the single column to 7 column as separated by semicolon ";"
On my spreadsheet I have a column entitled: "Item Title", and the data within this column can look like the following;
View 3 Replies View RelatedIn a data report i have a column which contains a mix of text and may contain an 8 digit number which could start in 0.
for example
in column A i could have "Hello how are you 01237232 I am fine"
I wish to extract the number into a seperate column, and would ordinarilly use a mid or left/ right function, however the text infront and behind the number will vary in length, which means i cannot do this.
The number will always be 8 digits, could start in 0 but will not always, and it may not be present in all the cells in this column.
How I an achieve this?
I want to find a number within a text string, then count the letters in the same string, then add the number to the number of letters.
For example, if I have 9RR in a cell, I want to add 9 + 2 = 11.
The data will always be arranged with the number on the left side of the string.
So, if the number is a single digit, I know I can use left(A1) + len(A1) -1 to get my desired result. But, the trouble I am having is what if there is a double digit number like 10RR...I'm not quite sure how to create a formula (without using VBA) to give me a result of 12 for this cell.
I have a mass of text in a cell. I would ideally like to search the text to format in a different font colour so it can be easily seen where the specific text is.
My current way is to use SEARCH in conditional formatting but this changes the whole cell not the specific text I am interested in.
EG. - I interested in the text PETER in my cell so would like PETER to be in red font.
A peck of pickled peppers Peter Piper picked; If Peter Piper picked a peck of pickled peppers, Where's the peck of pickled peppers Peter Piper picked?
i need help with 2 formulas to return text within a longer string.
the first result i need is a style #. this will always start at the 5th character, but the length is variable. it will always end right before the last "/" or "" in the string (there may or may not be a / or within the style number)
the 2nd result i need is a description of the style. this will always be after the last "/" or "" in the string and end before a ".", but there may not always be a period in the string.
Text string: ABC123123BASIC TEE.black
Style # result: 123123
Description result: BASIC TEE
Text string: DEF/4567LEAH/FLORAL TANK DRESS
Style # result: 4567LEAH
Description result: FLORAL TANK DRESS
I have some cells with some spaces and then text where I want to find the position of the first letter. Do any of you know about any function I can use?
The example below contain 5 spaces and then my name. It should give me the answer 6.
" Magne"
I have a report that in column BX has a large string of text (html information). Within this text there is a phrase called "| Hear = Education Website |" The phrase Education Website can be a variety of things though (Up to 9 choices). What is a formula I could use to just pull out the text after "Hear =" but before |""?
View 8 Replies View RelatedI'm trying to restructure a list of files at work into a format that makes some sort of sense and can be filtered into useful information.
Part of what I need to do, is match up all the drawing numbers that a certain project references. The numbers are formatted like "####A##" ex. 1234A01,1234A02,5678A01, etc. The cells that I need to extract drawing numbers from contain some description or other text (not just the drawing number) so I need to extract the drawing number from that cells value. (Ex. I need to get the drawing number 1234A01 from a cell whose value is "blah blah 1234A01 blah blah blah")
I was thinking I could just search the string for "####A##" but I'm not really sure how....I tried instr, but I think its searching for the literal value of "####A##" rather than treating the # characters as wildcards...
I tried:
Code:
if rngNames.Cells(intx, 2).Value Like ("*####A##*") then
set intStart = instr(1,rngnames.Cells(intx,2).value,"####A##")
'....
end if
but intStart remains 0, so this method is not working...
Let's say we have a text string in the excel cell: 12.123.12.1
Is there any way to get the latest dot's position using excel's functions?
How to find and show position number? I try merged two function, but doesn't work
1ΒΊ=FIND("0";B2)
2ΒΊ=FIND(CHAR(1);SUBSTITUTE(B2;"0";CHAR(1);2))
Number
Position
[Code].....
I have an array that I want to go through several times. I want to try something like this:
[Code] ......
I cant just say "If Val < 7 Then" because it will spit out the string where "Val" is.
I know that I could create another variable like so:
[Code] .....
but this doesnt seem like an elegent solution...
I am aware that you can use Match to find the position of an entry in an array, and the following code works as expected, returning an index of 4:
View 2 Replies View Related1-Using the Date-Time data in cell T3 find the cell in column A that has the same Date and time.
2-Position the cursor in column I of the same Row.
3-End
In the example giving the Date-Time in T3 is: 07/03/2008 17:15:00. The Cell in column A that has this same Date-Time is: A97. The cursor should then be positioned in Cell I97.
Let's say I have numeric nonzero and zero data in A2:X2. How do I find the first, second, third, second-to-last, last occurrence of a nonzero or zero value. I am able to find the first nonzero value by using Match(true, A2:X20, 0) to find the relative position, and then using index to find the value. This method also works with the first zero value, but I can't seem to find how to do the second, third, nth occurrence.
View 3 Replies View RelatedI have several property codes in column E e.g THA 134,THB 224, C 122, 223 AD. The letters A, B, C, D denote a type of property but do not always appear in the same place in the cell (sometimes 3rd character, sometimes first character etc). I want to put in a formula in column F, so that if the character A, B, C or D is in column E then the result in column F will be "A type", "B Type" etc....
View 9 Replies View RelatedIs it possible to find the location of different characters in a string (using VBA)? Normally I would use InStr of InStrRev option in VBA but my situation is a little more complicated.
The character I am looking for is not always the same, sometimes it is a , or a . or a : or a "blank" etc
I tried to do it like:
dim strChar as string
strChar = "[,.? /]"
SearchPosition = InStr ("cell location", strChar) (searchposition is the name of the function I am trying to make)
This works if I define only 1 character, this way it gives me a 0 as outcome
I have tried to change it to strChar = "[,]" or strChar = "[.]" or strChar = "[ ]" but this doesn't work.