I am looking for a formula that will calculate the number after the decimal point, for example: A1=0.4656162 I want to multiple the number after the decimal point by A2=60, is there a simple formula to enable me to do this as I have to perform this across a large number of cells.
View 2 RepliesI need to add a decimal point to a column of numbers. For example, where it says 126 needs to be changed to 1.26, 3035 changed to 30.35, 13593 to 135.93 and so on. Can this be done automatically or with a formula?
View 2 Replies View Relateda1 -> 2.333.33 "i want this to return as 2,333.33"
a2 -> 33.33 "i want this to retun 33.33"
a3 -> 45.555.55 "i want this to return 45,555.55"
i already asked this question and someone gave me this code -> substitute(a1,".","",1) which return to 2333.33 but the problem is for the a2 if i use the code it will return as "3333" which read as "3,333".
Is there any way that we can determine if the values have two decimal point before it will run the command?
I have a column that has values ranging anywhere from 1 to 999,999 and I need a way in vba to take whatever value is in the specified cell and place a decimal point at the far left. Example:
change 175526.34 to .17552634
change 376.1 to .3761
change 22987.254 to .22978254
when the code is run I need the selected number to begin with the decimal point.
See, the tricky part is that the length of the number varies and I cant just divide by X to shift so many places to the left..
I need a formula to multiply only the decimal number in a cell and not the integer. For example: the number in the cell is 57.3615. I want to multiply .3615 only.
View 2 Replies View RelatedI need to convert a column of numbers currently formatted with 2 decimal places e.g. 112.12 to 4 decimal places (without the decimal point). I need the end result to be 1121200. I've tried a few different suggestions given on the forum previously but can't seem to retain the 4 decimal places that I require.
View 4 Replies View RelatedI am trying to create a unique sample code by putting together the values of other cells that a user will input. It's all working well apart from the last part, where I am trying to include a decimal number. I want the decimal number to appear without the central "." and in a four digit format. e.g. 2.5 would appear as 0250, 14.25 would appear as 1425. This is the formlua I am using currently:
=IF(ISBLANK(B4),"",IF(LEFT(C4,1)="w",(B4&"-"&TEXT(F4,"YYMMDD")&C4&TEXT(G4,"HHMM")),(B4&"-"&TEXT(F4,"YYMMDD")&C4&LEFT(TEXT(H4,"00"),2)&RIGHT(TEXT(H4,"00"),2))))
However, where the value of H4 is 2.5, I am getting a result of 0303 (I've put this part in bold). I have attached a small spreadsheet to aid understanding.
is there any way to use the right function to return any data to the right of the decimal point?
eg 117.22 would be .22
108.1225 would be .1225
102.358 would be .358 etc
Would like to do the following for our school,
In cell A1 there is a number, for instance: 12.12345
Based on that number, the 3rd number after the decimal is important.
If the 3rd number after the decimal is “x” then the contents returned in b2 is a text value ( like high school ) .........
During finalization I have to convert the numbers into millions. But due to rounding factor, the total doesnot match with the displayed fig. how can I sum only upto two digits of the fig? A sample file is attached.
View 9 Replies View RelatedThis problem just appeared recently, as if out of the blue, and it seems to affect all of my old work sheets as well as new ones. I am using 2002 version. When I input any number in any cell the program automatically inserts a decimal point. Thus 1 becomes .1, 12 becomes 1.2, 123 becomes 12.3 etc. I have tried formatting the cells to "general" and to to "number" with no change. The thing that really gets me is that old saved worksheets exhibit this behavior as well. I can work around the problem by inputting 1. or 12. which then gives me the entry I am after but I've never needed to do this before.
View 2 Replies View RelatedI've just imported a file into a UK version of Excel from a German made datalogger. The decimal points (which should look like this 0.0) all appear as comas (0,0) with the result that Excel can't read them.
View 5 Replies View RelatedI need to allow only in textbox1 Numbers & decimal Point.
View 4 Replies View RelatedI have one problem in my data
In the amount Column, the amount looks like
10000, 10025, 20025 and so on
The amount should be
100.00, 100.25, 200.25
The decimal point is missing,
Any formula for the decimal point to appear in every last two digits
Is it possible to enter a number into a cel as: 12345 and have it display as 123.45.
View 10 Replies View RelatedI have just started a job and given a task to input some timesheets that were done manually. The problem is that I used decimal point instead of the colon. When I try and format the cells I do not get the real time.
Here is an example: ....
How to make calculation in excel without decimal point automatically. I use this formula =MIN(360,30*F42/360) . Total displayed 144. By right 142
DAY
FORMULA
RESULT
BY RIGHT
361
=F12/360*30
30.08
30
365
=F13/360*30
30.00
30
365
=F14/360*30
30.00
30
366
=F15/360*30
30.08
30
269
=F16/360*30
22.11
22
=MIN(360,30*F42/360)
144
142
So how can it be that Excel calculates Pi()/90*90=Pi(); but Pi()/90+Pi()/90+Pi()/90......90 times is 0.000000000000033527. And why is the number zero out to 14 decimal places not being returned as 0?
I need to know exactly when a series of sequentially increasing radians = Pi(). The length of the series is dynamic and can be as few as 6 and as many as 120. And right now Excel is not cooperating.
Here is what excel thinks Pi()/90+Pi()/90+....90 times =
3.14159265358980000000
3.14159265358979000000 (this is how excel displays Pi() out to 20 decimal places)
So Excel thinks the two numbers are not equal to each other, and what could be more interesting is that Excel thinks the difference is
0.00000000000000355271
Even after copying and pasting both numbers as values out to 20 decimals. Excel still thinks the difference is 0.00000000000000355271
How is that possible?
I have Excel 2013. Is there some sort of bug here? I had posted earlier about major headaches when using natural log. Random cells keep getting forced to 14, 15, sometimes 16 or 17 decimals. No rhyme no reason. I can custom format every cell in worksheet to 2 decimals, and as soon as I hit F9... ############# all over the place. At least with Pi() the decimals are under control, but the math is not right. Pi()/x + Pi()/x.....x times = Pi().
Is there anyway to be able to bring decimal point forward without affecting the numbers using any formatting, which will still be there even after refreshing the query.
For example, 0.0531 to 53.1
Is it possible to Conditionally Format using the (Custom) Data Validation Tool one or both of the following conditions:-
1. Force the user to enter the correct decimal point position for a given currency :-
The are 3 different decimal point locations location's - 0.87624 / 123.123 / 1273.00 There are always 6 numerals We have a table to lookup which specifies where the decimal point is on all currencies
CURRENCY AUDUSD< List is linked to a table
Price - High 0.87744< Decimal point dependant on chosen currency pair chosen
Price - Low 0.86596
Price - Close 0.86823
2. As above but numbers once entered will be formatted accordingly to the correct decimal place to the corresponding currency
I have a vba macro that takes data from one workbook and pastes it into another workbook. In doing this I have declared a few variables of type single (I only need two decimal precision). However, when I copy the values from the cells on the source workbook and paste them into the target workbook, the numbers end up having 12 decimal places. Ultimately, this extra precision causes my totals to be off by .01 or more after a while. I have tried rounding the number as I pull it off the source workbook into the variable, but that didn't matter. How do I solve this problem? Code for pulling data from source workbook:...
View 2 Replies View RelatedI want to know if it's possible to calculate the probability that a certain range of values, reach to a certain point.....
The range is this (example):
4
3
9
7
14
22
15
20
42
46.....
What I want to know is if this tendency will reach to 1000. Or how many steps more will be need to reach 1000.
Like I said, and don't know if this is in the right place, but if you put this values in a graphic you will see that the tendency is growing. I assume that this tendency will reach to 1000. But will be in the next 10 steps or in the next 30.
I have put my values into a XY scatter graph but need to find the maximum point i.e when the gradient is zero. I am using visual basic to obtain my data and draw my graph.
View 7 Replies View RelatedI am trying to found or create a formula that will display cell width to the decimal place.
I can use the formula Cell("width"), but it rounds to the nearest integer. I need to display the decimals. For instance, if the actual column width is 8.43, the Cell("Width") formula will display 8. I need it to show 8.43.
I have a problem that when I try to convert text to number and format the number without 2 decimal places as seen on the link I have given below, Instead of 1607.947, I get 1607947. I have Excel 2010 loaded. The details are in below picture.
[URL]
I need to create a formula to calculate monthly hours worked (144.20) by hourly rate (£14.25). So far everything ive tried has given me awrong answer. I cant seem to make the total right. From what ive come up with (Not good) the total accepts the hours-just not the minutes.
View 8 Replies View RelatedHow can I drop the whole number part of a number and leaving only the decimal part of the number. Then multiply the decimal part of the number with a number. Then repeat this in a sequence. The object is to convert Lat and Long decimals to Hr. Min. Sec.
eg. 53.535663 .535663*60=32.13978 .13978*60=8 53 32 8
eg. 113.352640 .352640*60=21.1584 .1584*60=9 113 21 9
eg. 113.306579 .306579*60=18.39474 .39474*60=23 113 18 23
I need a formula to take a number with several decimal places and round it up to two decimal places to either .33, .66 or, .00 if its above .66.
For example, 4.23423423423423 will be 4.33
4.43453453533434 will be 4.66
4.8353453453 will be 5.00
Lets say the number is in cell A1. What formula would do this?
convert a decimal number entered into a cell into its hex representation? 32-bit floating point representation.
View 10 Replies View RelatedI am trying to determine whether or not 26 blanks occur in succession in a row. Two example rows of data are listed below, where "_" refers to a blank cell:
2 _ _ 3 _ _ _ _ _ _ _ 4 5 6 3 4 _ _ _ _ _ 4
_ _ _ _ _ _ 7 8 13 2 3 _ _ _ _4 5 6 11 10 2
Hopefully you can picture the data from above. Anyway, there are multiple locations where a string of blanks occur. I'm looking for a formula that can test as to whether or not a certain number of blanks occur in succession during any part of the row.