I have put my values into a XY scatter graph but need to find the maximum point i.e when the gradient is zero. I am using visual basic to obtain my data and draw my graph.
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I am supposed to make an xy scatter graph like the one drawn of paper. The average point need to have a "cross" around it. So far I can just plot the points. I have added the average point as secondary series. I just need to put the "+ sign or cross around" it.
View 1 Replies View RelatedI would like to make a scatter graph that will graph the attached. The score would be on the Y axis and the birth date would be on the X axis. This is simple to do by itself but what I would like to do in addition to this is to have the top 25% of the scores a single color, the middle 50% of the scores a second color and then the bottom 25% of the scores to be a third color. And if it is possible to have the ID visible when you move your cursor over a given dot in the graph. Currently when I make a scatter graph the X,Y coordinates show when I hoover the cursor over a dot.
View 7 Replies View RelatedI'm trying to graph a bell curve chart using the following data
Hotels per state
Total
AK
4
NH
5
[Code] ......
As you can see I have states and the number of hotels per state what I need not for statistical purposes but more for "pretyness" is to sort this data in a way that what you get is a somewhat of a bell shape curve graph.
I now have a XY scatter graph with 109 individual points (representing schools) and a macro that tells you the plot details when you hover over. It's ok if you want to know which school is down the bottom but if you don't know where the desired school is in the first place, it's a lot of trial and error before you find it.
What could I look to add that gives the user the option to have a single data point highlighted (on selection?) so they don't have to manually look for it?
I have to create a chart XY Scatter plot in excel. I have to differentiate the data points color based on the another column "category". Now I can change the data points color manually. Since the number of points is huge, is it possible to color the data points based on a column?
View 5 Replies View RelatedWe have a special testing machine in the lab I work in, and it measures reflectivity from reflective vests etc. A special instrument takes a reflective reading and reports back a X and Y value which is used then as a co-ordinate and gets plotted on a graph.
The machine measures for 8 colours, and takes four readings, so for example the first color will be Flourescent Yellow. and then it produces 4 "X,Y" readings, which get plotted onto a graph, and joins all 4 points to create a box as shown in the link >> Graph with joined plots
This is a small capture of the spreadsheet with the values >> spreadsheet
Basically, I need to know how to take the values in columns X and Y, and then make it plot onto a graph as one point, and then join the four points for that one colour,
end result being the grapgh will have upto 8 boxes on it.
I have the following data points:
A
B
1
X
Y
2
0.18
0.52
[Code] ......
And can create a scatter diagram fine. However, I've been asked if it's possible to show on the graph, for each point a line to it's respective X and Y co-ordinate. For example, for row 4 (in red), on the same scatter graph, I'd like there to be two lines for this point,
Line1 drawn from (0.1, 0) to (0.1, 0.26) and
Line2 drawn from (0,0.26) to (0.1,0.26)
I know it's possible to overlap graphs in Excel, but I can't find how to achieve this with scatter plots
Given 100 samples, to calculate: numbers of hours spent on study is dependent on numbers of hours spent on social networking site.
x (social networking site)
y (study)
x^2
xy
6
4
36
16
24
[Code] .......
SUMMARY OUTPUT
SUMMARY OUTPUT
Regression Statistics
Regression Statistics
Multiple R
0.571423290877713
[Code] ....
So, I've got the coefficient of correlation equals to 0.57, how can I plot my scatter graph?
I would like to graph the data shown below using a scatter graph. However, when I use the cart wizard it assigns numerical values to each data point and then plots the data accordingly. How can I get the scatter graph to group the assets with the same ratings together? Note, I don't want to have to assign values to assets with the same rating each time. I have attached the spreadsheet so you an see the problem.
View 5 Replies View RelatedFor Excel 2007 -
I am looking for a function [or method] to calculate a polynomial curve fit. I can do it on a graph with the existing graph and chart tools, but I need to calculate it myself. Does such software exist somewhere in my Excel 2007 package, or can anyone recommend a freeware program? I am hesitant to download an unknown, un-recommended add-in.
i am getting some data via RS 232 port and plotting it straight to excel, which comes out to be in forms of waves you can say sine waves, now i need to calculate area under the curve, say like if i highlight some area it will automatically calculate the area, or if i select two points on the curve it will calculate the area. please help me out i am really stuck at this part.
View 9 Replies View RelatedI am trying to calculate the equation of a curve which best fits some data. On the x-axis is date and y-axis the readings. The curve is quadratic, so on the chart I am fitting a 2nd order polyomial and displaying the equation. To prove that the equation the trendline gives me is reasonable, I am applying the equation on the x parameter to get the y parameter estimate and looking to see the error between predicted and actual - see attached.
The equation and the output from it are clearly rubbish, even though on the graph the trendline is a reasonable fit - see attached. Has anyone any ideas why? I think it has something to do with using a date on the x-axis but no idea why. Is there a way to correct for this? I also tried using the following I to calculate the coefficients which came up with a reasonable forecast (although linest should only be used for linear data): =LINEST(C3:C15,B3:B15^{1,2,3})
I have an XY scatter with 40 or so different lines displayed.I want to change the thickness of all of the lines. I dont want to have to try and select them individually and change them. Is there any way to do this? Perhaps changing the default thickness of lines for this type of graph?
View 1 Replies View RelatedI am trying to plot a scattered line graph that contains nearly 4000 points on the y axis. The points represent a day. The x axis is the percentage belonging to that day. The problem that I am having is that the graph looks squashed together and the line is very thick because of this. One of the reasons for this is that a lot of the 4000 points have similar percentages so the line just moves a tiny bit. Is there a way that I can make the graph look more presentable?
The following is a picture of how it looks. You may need to enlarge it to see it properly.
I am reporting on the amount of certificates issued over a period of time. Basically the government stopped released data on the amount of one type of certificate being issued during this period and started releasing data on another type. I am having trouble displaying this other data which starts around half way into the time period. So all the data starts in June 2010... but this other data starts in June 2012.
View 3 Replies View Relatedafter spending hours searching the forum, I begin to seriously doubt my ability to even formulate a suitable search question. My problem SHOULD be a known one, but I am unable to find any clues. Here we go:
I have made a pretty stright-forward forecasting model. It is used to calculate economics of a coal fuelled power plant (even though that shouldn't matter). The outcome is, among other things, a single number for Profit / MWh in Euros. There are several input data, such as fuel price, price for CO2 emission rights, operational expenditure, capex, etc.
My idea, then, is to lock all in-data parameters except ONE, then let this variable vary incrementally and then produce a new small table with a) the variable data (example: price for CO2 rights ranging from 10 to 50 Euro in 2 euro steps), and b) the resulting net profit in each case. Ideally, I wish to be able to chose which indata to lock and which to vary, i.e. solution need to have certain flexibility.
NB: The calculations are not that simple, i.e. I cannot use a simple formula - I need to use the exising output cell(s) to feed data.
How do I do this?
The outcome should be basically two rows with a suitable number of columns (or the other way around, two columns in X number of rows). The table will then be used to produce illustrative graphs.
I guess I could hard code a table by simply enter data, but heck, that's not the way to use Excel!
I have a set of data which I need to plot both unordered and ranked.
For the unordered (as is) data, a line graph is fine, as it gives the category labels along the x axis.
For the ordered data, i have a row with the ranking in, and then plot an xy scatter graph, so the values increase.
This obviously has the rank numbers along the x axis, not the corresponding category labels.
Is there anyway to force this? I know there are chart labelling add-ins on here, but our IT dept blocks the download.
The attched file is a very small example.
I have 5 different groups for that i have to make XY scatter graphs and my data looks like this
XY
125
13
156
145
134
234
248
260
2102
2105
3125
3148
3198
3298
3245
4386
4369
4234
4465
4898
5902
5907
5345
5234
5209
now i want to make 5 different graphs one per each group. Now i am making them manually in excel but it is taking lot of time to format each graphs to get unique graphs. I am attching sample file and graph for better understanding.
I want to insert a text box into a line graph. I want the box locked onto a data point in this graph. The problem I am having is the graph is updated daily with more data so the point moves so I have to drag the box daily. Is there a way to fix this so it works automatically?
View 1 Replies View RelatedI have a data set (Set#1) that consists of a positional rank (1-240) and a dollar value ($46-$1) for each positional rank. It's not a straight line set.
DataSet.JPG
What I need to do is take that curve and apply it to another data set (Set#2) (1-240) and assign a dollar value ($46-$1) to each positional rank.
A "corner cutting" way of doing it would be an Index/Match to simply carry over the dollar value from (for example) #45 from my Set#1 to #45 in my Set#2. This could work reasonably well with data sets of the same size, but mine aren't always the same size, so I need to apply the curve itself. I
I would like combine (overlay) a bubble chart with a connected point scatter chart. I understand that, without VBA, this is not possible. However, I understand that, by using VBA, the markers of a scatter chart can be configured as circles with their size proportional to values in a specified column. This pseudo-bubble chart can then easily be combined with a connected point scatter chart.
My question is: does anyone have any VBA code to share that shows how to configure a scatter chart as the type of pseudo-bubble chart described above.
If I have a graph with 2 series of data plotted, how can I display the x-axis' value when these 2 curves intersect each other?
View 9 Replies View Relatedfinding a function/formula for determining the breaking point (Yvalue) in a graph, that doesn't necessarely equals the maximum value of that curve!
So the curve in the sample is a stress strain curve (tensile test) of a fibre and at the end it breaks and the Y value returns to 0. I would like to determine that Y value before it is 0, so the last Y value before it returns to zero.
I thought of a formula like:
display last y value before it drops with 90%...
but I don't have a clue how to write it in maths...
Ok, so here's the trick:
I know how to create combo or mixed graphs with line/bars on single axis, and secondary axis. I even know how to do mixed stacked and unstacked columnar charts...
But how do you depict in single view graph
a single bar (1 datapoint) with a single line (upper control limit e.g. target).?
And I don't want to to use shapes to draw the target line.
I want the target line to be automatically plotted by Excel...
i have created a xlColumnStacked chart using VBA in excel 2000. i would like to place a line in the center of one of the Points(). How can i locate a specific point, for example Points(1), so what i can then "draw" a line in the center
View 7 Replies View Relatedhow to get a line in a graph to become a curved line between 2 data points in 10 point chart. I the pictuer attached I am trying to get the line to curve at the second data point 5(ms) and the third data point at 80(ms). The aftr 80 the line become staright again.[IMG][/IMG]
View 3 Replies View RelatedI have two different data sets that I have plotted using XY(Scatter) w/ smooth lines. Is there a macro or sub that will calculate the volume or area between where the two data sets cross?
View 3 Replies View RelatedI am trying to manually format a few graphs in my sheet. I, however, leave the major units of the axes to be automatically calculated. The code that I use is given below:
ActiveChart.Axes(xlValue).Select
With ActiveChart.Axes(xlValue)
.MinimumScale = Range("Min").Value
.MaximumScale = Range("Max").Value
End With
Now what this does is that it sets the maximum of the scale exactly equal to maximum of the range being plotted and hence a few parts of my graph overlap with the border of the plot area. Is there any way in which I can round the max and min scale of y-axis to the next highest and lowest major unit respectively or may be add and subtract a value proportional to the major unit of the y-axis. I cannot add a constant in the code given above since I that does not suite my requirements.
I want to know if it's possible to calculate the probability that a certain range of values, reach to a certain point.....
The range is this (example):
4
3
9
7
14
22
15
20
42
46.....
What I want to know is if this tendency will reach to 1000. Or how many steps more will be need to reach 1000.
Like I said, and don't know if this is in the right place, but if you put this values in a graphic you will see that the tendency is growing. I assume that this tendency will reach to 1000. But will be in the next 10 steps or in the next 30.
