Code To Find In A String And Return

Jul 3, 2009

I am trying to search a string for the first instance of "#" and return everything to the left of it and right of the word "where".

Example String -

Where 11# is greater then 10#

I want to just return 11

11 is left of the # and right of "Where"

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Find And Return 10-digit Number From String

Nov 3, 2011

I am working with data where I need to extract a 10-digit number from a string. Where the 10-digit number is in the string varies, so I can't use a simple left/len combination. Here's an example below:

Something and email@me.com 1234567890 stuff thingsThe formula I am using now is this:

=MID(F4,MIN(FIND({0,1,2,3,4,5,6,7,8,9},F4&"0123456789")),10)

This finds the first number in a string and returns that number and the next 9 digits for a total of a 10-digit string (so it would return 1234567890). However, I run into an issue when I have a string that has numbers in the email address.

So this:

number in email123@me.com 1234567890 exampleWould return this:

123@me.comIs there a way to modify the formula above so that it searches for 10 consecutive numbers and not just the first number in a string?

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Jun 27, 2013

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I need to extract the userid protion, the part between "=" and "'target...." and then

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Jun 9, 2009

Have problems using find and the Dictionary
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Jan 31, 2008

Find a short text string in a column of longer text strings and when that short text string is found return the longer text string that matches.

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May 23, 2006

I am having trouble getting my IF statement to test if the cell contains the text "sale" return "X" if not "Y". I need it to search through the text string in that cell and find a certain word, and if it finds that word, retrn a value. I am really having difficulty with is what symbol or function do I use for the logical test? (i.e. =, <>, MATCH, INDEX?)

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Is there a way with the following formula to tell it that if value return is = to value of cell above then find return next value?

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Mar 31, 2014

I am trying to do a sort of index match thing using VBA. What I am attempting to do is to use the prefix of a long number and try to find that exact prefix in a string array, and output that string array value. So this is what I have so far as a test:

[Code].....

So I can match the text exactly so if I put PREFIXB in cell A1 in this example, i will get the msg box saying "YES", but if I make it PREFIXB1231k4j3jj1kj32cj, it will display "NO". I want to get it so that PREFIXB will be displayed in the cell that I put the formula in. So if A1 = "PREFIX1AAA100CF" and cell B1 = "=ABC(A1)", cell B1 will display "PREFIX1AAA".

Now the thing is that these prefixes can have different lengths, but will never encompass the exact prefix of another. So if I had a prefix of: PRE1AB, I won't have a prefix of PRE1A.

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Mar 18, 2009

how do return the cell address of a certain string?

I'm seraching in a named range called "positions" for the string "GK"?

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Feb 4, 2010

Can you please assist in helping with a formula that will return the value of the characters (no matter the length) between the "."?

123456.B.78.C.321
12345.B.78.C.321

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Mar 15, 2007


TX_jhfft_DATA.05-32_65 TGIF

I need to take out the number in the middle, from the period to the space. The number varies in length so just using the mid function doesn't work. Does anyone know how to modify the mid function to return all chars between the period and the space or is there some other function that may work?

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Jan 9, 2009

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I have 3 columns containing data:

column A has text in it,
example: A2="red", A3="green", A4="blue"

column B has 3 letter month in it and they could have repeats
example: B2="Jan", B3="Feb", B4="Jan"

C2="Jan"

in D2 list anything column A that matches C2
example: D2="red, blue"

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Jun 24, 2013

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For example:
A1 B1 C1:to whatever cell needed, to be autofilled with day, date, month, year, weekdays only.
Start Date 2013/07/04 Monday, July 1, 2013

It would be really nice if it highlights the local holidays too.

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Jan 8, 2014

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I have over a 1000 records broken down by Leaders of which each is roughly 50 records. in those records, answers are either : 4 hours, 8 hours, 24 hours or 48 hours. I need to have a formula return of the 4 choices, which had the greatest value.

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Nov 16, 2004

I want a formula or function that will return a count value if a cell contains a string rather than returning a value if the cell equals a value. For example, =COUNTIF(A$1:A$19703,F1) returns a value to cells in column G if the value in column F equals any exactly matching value in A. I need a formula that works like the filter option "contains" so that if any cells in col A merely contain a string rather than exactly match or equal a string from column F I can get a count value returned.

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Feb 11, 2008

I have made this function that returns the string value for a column based on it's number but it starts getting more complicated after I've been thru the alphabet once and have to return two string values to move across the chart.

PHP
Function colnum_string(ByVal num As Integer) As String    colnum_string = "IV"    If num = 1 Then        colnum_string = "A"    End If    If num = 2 Then        colnum_string = "B"    End If    If num = 3 Then        colnum_string = "C"    End If    If num = 4 Then        colnum_string = "D"    End If    If num = 5 Then        colnum_string = "E"    End If    If num = 6 Then        colnum_string = "F"    End If    If num = 7 Then        colnum_string = "G"    End If    If num = 8 Then        colnum_string = "H"    End If    If num = 9 Then        colnum_string = "I"    End If    If num = 10 Then        colnum_string = "J"    End If    If num = 11 Then        colnum_string = "K"    End If    If num = 12 Then        colnum_string = "L"    End If    If num = 13 Then        colnum_string = "M"    End If    If num = 14 Then        colnum_string = "N"    End If    If num = 15 Then        colnum_string = "O"    End If    If num = 16 Then        colnum_string = "P"    End If    If num = 17 Then        colnum_string = "Q"    End If    If num = 18 Then        colnum_string = "R"    End If    If num = 19 Then        colnum_string = "S"    End If    If num = 20 Then        colnum_string = "T"    End If    If num = 21 Then        colnum_string = "U"    End If    If num = 22 Then        colnum_string = "V"    End If    If num = 23 Then        colnum_string = "W"    End If    If num = 24 Then        colnum_string = "X"    End If    If num = 25 Then        colnum_string = "Y"    End If    If num = 26 Then        colnum_string = "Z"    End IfEnd Function 

Is there a better, more simple way to return the string value for a column from it's number reference?

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Jul 30, 2008

I have the following formula that returns the most frequently occuring string in a range. what I would like to do is return the 2nd, 3rd 4th and 5th most common occourance as well. I am not sure if I can do this by adjusting this formula or whether that would be a completely diffent formula or worst case senario it is not possible at all.

=INDEX(B2:B1537,MATCH(MAX(COUNTIF(B2:B1537,B2:B1537)),COUNTIF(B2:B1537,B2:B1537),0))

obviously this is an array.

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Jul 13, 2009

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Mar 14, 2007

I have multiple automatically updating data sets and I need to extract certain data to perform calculations on, this is the format of the data

SPLIT AB H 2B 3B
HOME 20 6 1 0
AWAY 20 7 2 0
SPLIT R HR RBI
HOME 2 0 1
AWAY 3 1 4

basically, what I need is to extract the data for home and away, and put them each on one line, no problem if this is always the format, but there are other lines of data that I don't need thrown in there at times which shift the data up or down
a simple vlookup will extract the first occurance of home, but I need another formula to extract the second occurance so I can have them all on one line and have the data as:

SPLIT AB H 2B 3B R HR RBI
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I need to look within column A (which contains text strings), match label in column c (which contains text for label), and return result within column B (titled category label).

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I have attached an excel file that shows the current problem. Nested if(isnumber(search( statements can perform this, but I yield too many arguments error after three labels?

Isn't there a way to do this with Vlookup or Hlookup?

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Jan 28, 2014

I'm trying to come up with a VBA function that would return cell values based on another cell value.

I can do this by comparing a range (column of cells) with the cell value to match and then return the value of the cell next to it.

For instance,

The function should search a column for partial text, as follows:

TS ID
PDT ID

TS 1.1
PDT 1

TS 1.2
PDT 2

TS 1.3
PDT 3

TS 2.1
PDT 4

TS 2.2
PDT 5

TS 3.1
PDT 6

TS 3.2
PDT 7

In the above table, the function should for partial text and return string as follows:

TS covered
PDTs

TS 1.1, TS 1.2, TS 1.3
PDT 1, PDT 2, PDT 3

TS 2.1, TS 2.2
PDT 4, PDT 5

TS 3.1, TS 3.2
PDT 6, PDT 7

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I am trying to use ADO via VB6 to find a specific input in row A of my excel sheet.

I then want it to return the Column and Row to me separately.

I have a code I already use for returning specific values from cells:

Code:
Function Look(ClosedWorkbookFullName As String, _
SheetName As String, RangeAddress As String) As Variant

Dim conn As Object, rs As Object, SQL As String
Set conn = CreateObject("ADODB.Connection")
Set rs = CreateObject("ADODB.Recordset")

[Code] ......

Now I want something like this I can use as a function, but it obviously needs tweaks.

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What I'd like to do is from Right2Left return the 5 characters immediately to the right of (before) the 11th "," comma (i.e. 22.59 for the 1st string on Excel Cell A2) OR from the Left2Right return the 5 characters immediately after the 9th comma "," comma, which is also 22.59

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I know this seems pretty easy, but there's a small problem. The word "BENT PIPE," could be in Column D, in which case, I would want it to return "EA" instead of "LF".

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Table E6 to F9 contains the desired result (The result wont be more than 3 at any point of time

Search.xlsx

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D2:Adv Costs (27a) - would return "27a"
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