I have several property codes in column E e.g THA 134,THB 224, C 122, 223 AD. The letters A, B, C, D denote a type of property but do not always appear in the same place in the cell (sometimes 3rd character, sometimes first character etc). I want to put in a formula in column F, so that if the character A, B, C or D is in column E then the result in column F will be "A type", "B Type" etc....
View 9 RepliesIs there a function in VBA that is similar to either the FIND function or SEARCH function in Excel? The arguments for the FIND function in Excel are FIND(find_text, within_text, [position]).
I have a text string in VBA ("$A1:$D$13") that I want to be able to identify the first "$" and then later the ":". I'm getting tripped up on the 3rd line of code. Thanks a million.
Sub page_set_print_area()
ActiveSheet.PageSetup.PrintArea = "$A$1:$D$13"
x = ActiveSheet.PageSetup.PrintArea
Position$ = Search("$", x, 0)
End Sub
Let's say I have numeric nonzero and zero data in A2:X2. How do I find the first, second, third, second-to-last, last occurrence of a nonzero or zero value. I am able to find the first nonzero value by using Match(true, A2:X20, 0) to find the relative position, and then using index to find the value. This method also works with the first zero value, but I can't seem to find how to do the second, third, nth occurrence.
View 3 Replies View RelatedI am trying to solve problem with finding cells (all searching cells are in 1 column ) witch contains only recurring characters like : 00, aaaaa, 444444444 , etc.
View 3 Replies View RelatedI have a cell that has approx 22000 characters. I'm trying to remove a specific character string from a cell by doing a find and replace with "". It works for characters in the first part of the cell but not for characters in the last part of the cell.
Example: I do a find/replace for the characters 21242 to "" in column A and I get the expected results. I do a find/replace on 69294 to "", again I get the expected results, but if I do a find/replace on 85203 to "", I get "Excel cannot find what I am searching for" (but its there!)
My cell size is within the max size of 32,767 characters so not sure why its not working.
Attached a sample worksheet.
For a given cell, I need to count the number of times a given character (e.g., the letter "a") appears. Is there a worksheet function or formula?
View 9 Replies View RelatedI have two lists of numbers.
The first list contains site numbers of people who havent responded to me.
The second list is the master list of site numbers along with a column showing the date they responded.
Now, a site number is built like this:
123456/0001
123456/0002
So it is possible for the same 6 digits to appear more than once in the master list.
What I need to do is to compare the first 6 digits in the non responder list against the master list, because some sites, like the example above, may have more than one '0001' tag and so if they have responded to me from site '0002' I dont want to spam their other sites with emails.
I've tried using match and various formulas I've found from google etc, but nothing seems to work!
The goal of this is to get a list of non respondents that have not responded from any of their sites listed in the master list.
Non Responses
Master List
Date of Response
203289/0001
201162/0003
06/06/12
[code]...
Title should read: Finding the nth Occurrence of a character within a text string
I have a very long text string that is delimited by about 50 "/" to segment certain values within the text string. I want to be able to extract the text between the 33rd and 34th occurrence of "/". How to do this?
want a way to find out any special character in text file (.txt).
The .txt file I use is very large about 100 mb to 1GB. I need to find a way to write vba code that asks for input text file and the validates it and gives the message that following special characters are present in the file. Also, it gives their column number and row no's, where they are located.
The characters which needs not treated as special characters are numbers (0-9), alpha (A-Z) and special characters (@,-,%,$,+,=).
I have random descriptions that have the case dimentions within the text
The descriptions are NOT standard length.
the only thing I can think of is the dimensions in ALL descriptions have this in common:
Length ( x ) Width ( x ) Height
I am looking for the Height value
How can I use the =mid function based on the 2nd ( x ) character?
if a cell contains "usable characters". By usable characters i mean i want something to check if a cell contains a number or letter.
cell = AAAAA formula returns true
cell = A123 formula = true
cell = 123 formula = true
cell = ----- formula = false
I am trying to build a formula that return what is after ":" For example, in a cell, I have NASDAQ:MSFT and I want another cell to return MSFT. I tried to use the function FIND combined with a LEFT or RIGHT but I could not have it work.
View 2 Replies View RelatedPretty sure this has been asked but have searched the forum to no avail, but I need to extract the numbers from a value which has a letter on the end.
eg. 1000x I need to get out the 1000
or 2p I need the 2
I have sooooo many values ranging in numbers of digits, so just basic left(A1,2) won't work, I'm sure I've seen a search or find function but don't know how to use them!
I need to make a list of Part Numbers in quotation marks. If a number of digits of a P/N is less than 13 a number of space characters has to be added to make the string 13 characters long.
We have example P/N:
1234567890123
12345678
123456
should become:
"1234567890123(no extra space characters should be filled-13chars)"
"12345678(5 extra space characters here)"
"123456(7 extra space characters)"
Is there a function that inputs a cerain number of a specific character ("space" in this example)?
Does such function exist in Excel?
View 9 Replies View RelatedI have special character that I removed with =CLEAN formula.
It was only one character which represents carriage return. It looks like one little square with question mark inside.
After I applied =CLEAN formula it disappeared, but now I don't have space between these two words.
How could I replace this special character with space?
I have a few thousand products codes (i.e ABCD123BLA08 or SHU267BLA) They are non standardised in length or structure. I wish to pull out everything upto the end of the third numeric digit.( ie ABCD123 and SHU267) I cannot use left as they are all different lengths. Ideally i would serach for a non numeric char after the number then use left up to that point. Search can't do this, FIND can't do this.
Summary
ABCD123BLA08 would be ABCD123
SHU246BLU would be SHU246
I147ORT08-12 would be I147
I want to use the find function on a range and search for a "," character. If I get a "," I want to return a True otherwise false.
I tried just recording a macro using the find function but no code shows up.
how to use the find feature in a macro, can this be done?
excel 2010
I've written this code to find a value in the worksheet chosen from the combo box (I think it works as its doesnt error), but I now need too write some code to pull out the row number from my code and put data into the same row (but different columns). This is my code so far:
Code:
Private Sub BookButton_Click()
Dim rFound As Range[code].....
I am having a problem finding the right javascript function(s) to use in my macros. Use Google homepage as an example. The line
.Navigate "javascript:_dlsetp('ss=2')"
will open the page for customizing your Google page. But what is the function you fire on in the macro to execute the general search? I can send text to the search input box, but I can't find the function that runs the search.
Is there some way to quickly identify the function and the correct syntax without having to learn how all the source code in the web page works? Finding the right URLs, links, and input boxes is fairly straight forward. But not the functions.
I have a table as follows: [URL] - note: cells containing times and temperatures are numeric values, I've used custom formatting to add " mins" and "°C" on the end
In one cell, a user can input a time period (in mins), and in another cell, I would like to output the start and end columns (in letter/s) for the chosen time.
For example, in the link above, if the value inputted '30' then the start column is 'C' and the end column is 'G'. If the user had inputted '60', then the results would be 'H' and 'K', etc.
I am able to find the start column with the following equation:
=SUBSTITUTE(ADDRESS(1,MATCH(VALUE,C2:P2,0)+2,4),"1","")
I am struggling, however, to find the end column for the chosen time.
If each time had the same number of temperatures then it would be a simple case of adding the number of temperatures per time, minus 1, after the "+2".
My first idea was to copy the above function, but to change the "0" in the MATCH function to "-1", in order to find the next greatest time value. However, it appears that using "-1" in the MATCH function only works if the range is in descending order - my times are always in ascending order.
I have a further problem in that the time periods are not always the same values (i.e. it won't always be 30-60-90-120, it could for example be 30-45-60-75). So as far as I know, there is no way in advance of knowing the next time period up (and then subsequently taking one column to the left).
One possible workaround I have considered involves the following:
- Add a new row between rows 2 and 3, which has the time values in each cell (i.e. from column C, values of 30-30-30-30-30-60-60-60-60-90-90-90-120-120) - effectively duplicating the time row, but not merging cells
- Use the COUNTIF function to find the number of cells in that row containing the chosen time
- Add this value, minus 1, after the "+2" in the above formula, i.e. =SUBSTITUTE(ADDRESS(1,MATCH(VALUE,C2:P2,0)+2+COUNTIF(C3:P3,"="&VALUE")-1,4),"1","")
I know you can't use the SUMIFS function in 2003 but give alternative in 2003
=SUMIFS($D$3:$D$30000,$C$3:$C$30000,"IOP",$E$3:$E$30000,">=01/03/2011",,"
Any function in Excel, that would allow me to have a unit cost price (for example: 0.5432) and then for a table of figures containing the pack sizes to determine the correct unit price that would allow all pack costs to be at 2 decimal places. I have included an example below:
My spreadsheet would look like the following:
Cell A1 (Unit Cost Price) = .5814
Cell A3 (Pack of 75 units) = .5814*75 = 43.605
Cell A4 (Pack of 80 units) = .5814*80 = 46.512
Cell A5 (Pack of 100 units) = .5814*100 = 58.14
and so on
I need some way of making cell A1 change to a value that will cause all cells A3 to A5 to be 2 decimal places or less.
To all sifus out there, how can i transfer from these:
NAS517-3-2
-41353913
NAS517-3-5
NAS517-3-4
-42MS27253-2
-43353908
-44357182
To these:
NAS517-3-2
353913
NAS517-3-5
NAS517-3-4
MS27253-2
353908
357182
I have got a list of numeric abbreviations, for instance 10739011/21/31/41. What it should really display are the numbers 10739011, 10739021, 10739031 and 10739041 (the first six figures stay the same). All the numbers in my list are 8 figures long. I want to change the list from the list seperated by the backward slash to the complete numbers. I have uploaded an example of the list with backward slash between the numbers. Is there a way that Excel can automatically change these numbers to the full numbers?
Because all the numbers are 8 figures long, I thought the first 6 figures of the 1st number can be copied and those 6 figures pasted before the other two figures after the backslash. Auto Merged Post Until 24 Hrs Passes;sorry, pressed OK too quickly. The problem is that there are sometimes 4 numbers in the cell, sometimes 6 and once three. I would like Excel to complete all the numbers in the cell and then move on to the cell underneath it and so on. Also, I would like each number to have it's own cell.
I have a cell which will contain SER01+SER02+SER03
and what i need it to contain is [SER01]+[SER02]+[SER03]
and shocker is i've got this to work for the first instance but not the other two
code as below... be grateful for your help
Sub measure1()
Dim list As String, pos As Integer, refl As String, refr As String, newlist As String
list = Cells(1472, 16).Value
pos = InStr(list, "+")
refl = Left(list, pos - 1)
refr = Right(list, pos + 1)
newlist = "[" & refl & "]"
Cells(1472, 17) = newlist
End Sub
Need a formula/code that will determine what the corrected part number should be (insert dashes if they are missing) by comparing to other values in the list.
Original A1:A5 = {452, a-bc, 123, 4-52, abc}
Corrected C1:C5 = {4-52, a-bc, 123, 4-52, a-bc}
I can do this using an intermediate working column, but can this be done all in one formula, or via VBA?
My formulaic solution is thus: .....
I have been trying to write two formulas in one cell. I have been able to write them both separately but have been unable to join them both together. What I am trying to do if first search name them how many reoccurring numbers appear. I have provided an example below
a b c d
1 Tom 333
2 Sam 22
3 Sam 22
4 John 5
5 Sam 22
6 Sam 1
7 Tom 3
8 Tom 333
So the answer would be
Tom = 2
Sam = 2
John = 1
I would like to create an If Then statement in which the condition is based on if a string is a simple text or a formula. Some of my cells contain a formula and some contain simple text...and I would like to cycle through all of them- only do something different to them based on what the cell contains.
View 18 Replies View RelatedI have some cells with some spaces and then text where I want to find the position of the first letter. Do any of you know about any function I can use?
The example below contain 5 spaces and then my name. It should give me the answer 6.
" Magne"