Pretty sure this has been asked but have searched the forum to no avail, but I need to extract the numbers from a value which has a letter on the end.
eg. 1000x I need to get out the 1000
or 2p I need the 2
I have sooooo many values ranging in numbers of digits, so just basic left(A1,2) won't work, I'm sure I've seen a search or find function but don't know how to use them!
So, I need to keep adding together all the numbers from cell row 0 upto and including the row number of the cell with the result. The column with the results is to the right of the column with numbers to add. So, if the numbers are positive, to the right of each should be an ever increasing number as a result. In the column with the numbers to add is a function which as a result gives either numbers or blank cells. It sounds simple but it is frustrating me. Why can't I use the function SUMIF with a ROW function inside the condition field? It always gives me 0 as the result. I use excel 2003.
I probably do't understand the SUMIF function but why isn't =SUMIF(A:A;"1>0") equivalent to =SUM(A:A). This too gives the result of 0. Why don't I get an error instead.
I want to multiply a number say, 1551 by 5%, 6%, 7%, 8% and 9% and round each result to 0 decimal places. Then the sum of these results (544)should be equal to 35% of 1551 rounded to 0 decimal places (543). How do I create an if function for rounding so that the sum equals 543.
View 6 Replies View RelatedBasically I have a phone number in column A:
123-456-1234
In column B, I want it to show me the first 3 numbers from the left, (so 123)
So I do =LEFT(A2,3)
Which gives me 123, but it's displayed as text, which ruins my whole formula that looks up the area code and displays the state.
I googled the problem and found http://exceltip.com/st/Make_LEFT_Fun...umber/778.html
which tells me to do:
=IF(LEFT(A1,1)=1,"Ignore",A1) [sees 1 as a number]
=IF(LEFT(A1,1)+0=1,"Ignore",A1) [sees 1 as a number]
=IF(LEFT(A1,1)="1","Ignore",A1) [sees 1 as text]
but when i try that it just displays the ENTIRE phone number: 123-456-1234
I need to make a list of Part Numbers in quotation marks. If a number of digits of a P/N is less than 13 a number of space characters has to be added to make the string 13 characters long.
We have example P/N:
1234567890123
12345678
123456
should become:
"1234567890123(no extra space characters should be filled-13chars)"
"12345678(5 extra space characters here)"
"123456(7 extra space characters)"
Is there a function that inputs a cerain number of a specific character ("space" in this example)?
Sub TrimSlashesToRight()
Dim cell As Range
For Each cell In Range("AN2:AN2000")
cell = Left(cell, InStr(cell, "//") -1)
Next
End Sub
I cannot get it to run this, it always crashes on
cell = Left(cell, InStr(cell, "//") -1)
It will work fine like:
cell = Left(cell, InStr(cell, "//") + 0)
but then it leaves the first / in place, i want it to start deleteing before both //.
I've created a user form that has a list box populated with a fairly standardized format - a product ID or model number followed by a dash ( - ) then followed by a description. Based on the users selection of an item in the listbox, certain rows will be copied over from another tab in the excel file.
An error occurs when a Model Number list box item is selected but not when a product ID is selected.
The difference between the two are AlphaNumeric vs only numeric.
USBLT15CMB - Product Description 1
1121 - Product Description 2
the code is:
Private Sub CommandButton1_Click()
Dim ID As Long
Dim Row As Long
Dim Cnt As Long
[Code]...
The macro stops on the ID = line
How do I return the Nth Character in a cell starting from the left.
For example, cell A1 has the word "Baseball". What formula will give me the 6th character to the right, which would be "a"?
Could someone tell me if the following formula is valid?
=AND(F15="R*", I15>0)
I want to know if F15 contains 'R' or 'RW' but using a wildcard always returns false whether this correct or not.
I want to select email addresses in a particular cell. Since every email address will contain @ so I want to extract the email address from the cell on the basis os all the characters to be selected on the left & right of the '@' before a space is encountered.
Eg
If the cell contains the below values:
91 121 5158123 / 5159123, 011 5103710
91 999 999 1123
info@designs.com
I only want the email address to extracted to the next cell. i.e. info@designs.com
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 Replies View RelatedI'm trying to use logic to identify trends...in each of the strings below, I want to count the occurrences of the left most character appearing consecutively. The answer is to the left
I'm trying to do this via a formula vs. vba if possible
BBBBBBBBBBBBBBBBBBB - 19
BBBDUDUUUUDDBBBBBBB - 3
UUDUDDUUUDUDBBBBBBB - 2
UDUDDUDUUUDDBBBBBBB - 1
[Code] .....
Items in Column A1 are calculated by (B2/4+5)*1.4 Items located under the columns 2000, 3000, 4000, etc... 10,000 are calculated by taking the top number, eg 2000/(A1 cell value)+the column B number. 2000/7+0 = 286 (rounded numbers)
I need to find an way to look up for x number (2000,3000,4000, etc...) find the smallest number in that column and then return the value in column A1.
Cell
A1 Number >2000300040005000600070008000900010000
70 2864295717148571000114312861429
84 24236148059971883795610751194
[Code].....
I received a request from a coworker regarding custom formatting some numbers in his spreadsheet. Those numbers are serial numbers of 20 characters long. Sometimes in my files I use this custom number formatting ###0 and its enough for the data I handle. But when I tried to use it in his spreadsheet, the following shows:
8456891070060510000
The cell must look like this: 08456891070060510302
The reason to have it like this is due to a Delivery Program requirement to deliver Set-top Units for repair. The Delivery Program do not recognize other format than the above. My coworker takes the data from a spreadsheet, and the spreadsheet needs a custom number format to display the correct number.
find a custom number format to be able to display as my coworker need it??
I am trying to use the left function to include only the first account number, for example if a cell has "120122 280000" (there may be many spaces between the two numbers), I only want 120122.
So far my programming only returns the 280000 into the cell.
I am working with cell values in column "K".
Every day i have to pull of a text document from a server and import it into excel so i can change the format of certain columns. Then import the data into a database. I am trying to create a macro that will enable me to make these changes instantly without having to spend minutes on them.
There is once column that has the format 2009-03-12-10:02:09 which indicates date and time however there is a - inbetween them. I know that i can use =DateValue(left(a1,10))+ Time alue(right(a1,8)) and then format the cells to date and time to remove the -. My issue is that i only want to use the formula upto the last row of data otherwise i end up importing blank rows into my database.
When we give formulas say for eg
cell A5/Cel d4*30/365
we format for two digits so i get in my spread sheet cell as
60423.28
but it is actually
60423.28302
so over a period of time my figures posted in accounts dont match to excel spreadsheet.
How can i get the excel spreadsheet to not only show two digits but calculate to two digits as well So say if my calculation result is
60423.276 it should not only show 60423.28 but also be that way and not 60423.276
I need to move characters from the end of a string to the beginning.
I have a list of Exact stings that are allowed. I need to move this allowed string to the beginning.
JAN
JANS
JANTX
JANTXV
If "TR" or "T/R" are at the end of the allowed Exact string, I need that removed completely.
i.e.
JANTR = JAN
JANT/R = JAN
JANTXT/R = JANTX
PN
Desired result
1N3595UR-1JANTX = JANTX1N3595UR-1
1N4992JAN = JAN1N4992
2N1711JANS = JANS2N1711
1N4148UR-1JANTXVTR = JANTXV1N4148UR-1
Function sequence giving me "N/A": =VLOOKUP(LEFT(C6,5),H:I,2,FALSE)
Basically, I have numbers that each start with a unique sequence. The first 5 numbers of that sequence represent a certain cell carrier.
What I want to do is have the function look up the first 5 characters of a cell and depending on the 5 characters, I want it to return a certain value.
My idea with the vlookup was to have the lookup value be the first 5 digits and then in my table, it would take only those 5 digits and return a value I have specified in the second column.
I need to return the text from a string, in a similar way to they way LEFT/ RIGHT would do.
I have some text in a cell, say A1 that looks like this ->
TEXT BEGIN --- TEXT NOW ENDS
I want to return everything before / after the --- symbols.
I have the below line in a macro but the left function is not working, will not sum everything.
Range("g" & x).Value = "=SUMPRODUCT(--(Data!a2:a65536 = """ & val1 & """)*(data!t2:t65536=left(g1,2)))"
have this formula..
=SUMIFS(Sheet2!$D$2847:$D$3065;Sheet2!$I$2847:$I$3065;$B$6;Sheet2!$G$2847:$G$3065;$C$6;Sheet2!$B$2847:$B$3065;A14)
D2847 - D3065
includes Numbers..
lets say.. i want every cell counted which has in these range the first two numbers..
every cell has..
5052
5053
5054
4060
4050
so i count the entries which has 50.. so in total it gives a result of 3. Not summing them, just count the entries that has the first two numbers "50" in every row..
The Red Markings can be replaced, the rest should stay.. it is needed due different criteria.....
I keep seeing Right$(arg,arg) in VBA examples, but I am not sure what the dollar sign is doing.
Is it acting like a string declaration?
I have a spreadsheet where I extract the last 3 digits of a five digit string by using the "=Right(...)" command.
Column A 71500
Column B =right(column a,3)
Column C 500
Column D = lookup(Column C,toc_desc)
Column E #N/A (if it worked, this would read Labor)
I want to take the result of that command (Column C) and use the "Lookup(...) command to translate type of cost as a name rather than the three digit number (Column D). Excel doesn't recognize the result of the "=Right(...)" command. I am getting #N/A as a result. (Column E). How can I get Excel to read that number and give me the results I need?
I've got a little application in excel using macros.
It worked perfectly with Excel 2000, but with Excel 2003 shows an error for every formula I've used in the macro -right, left, mid, date...
Sub buscar_libros_datos()
On Error Resume Next
Dim libro As Variant
Dim ruta As Variant
Dim libroruta As Variant
Dim tabcol As Variant
Dim tabfil As Variant
Dim posguion As Variant
Dim posparen1 As Variant
Dim posparen2 As Variant
Dim categoria As Variant
Dim categant As Variant
Dim tipo_info As Variant
Dim fecha_carga As Variant
Dim i As Variant
Got the following formula:-
=LEFT(L5, FIND("(",L5)-1)
I need to add the SUBSTITUTE function to this but can't figure out where it goes if somebody could point me in the right direction please? My substitute formula is SUBSTITUTE(L5,"car","train").
I have several property codes in column E e.g THA 134,THB 224, C 122, 223 AD. The letters A, B, C, D denote a type of property but do not always appear in the same place in the cell (sometimes 3rd character, sometimes first character etc). I want to put in a formula in column F, so that if the character A, B, C or D is in column E then the result in column F will be "A type", "B Type" etc....
View 9 Replies View RelatedI have random descriptions that have the case dimentions within the text
The descriptions are NOT standard length.
the only thing I can think of is the dimensions in ALL descriptions have this in common:
Length ( x ) Width ( x ) Height
I am looking for the Height value
How can I use the =mid function based on the 2nd ( x ) character?
i want to copy a cell value to rest of the cells in the same column upto the last value in that column has the value of "FIN"
View 2 Replies View RelatedWhat I would like to do is output the first 4 characters of a cell into another cell. eg Cell A1 has "1234 Sydney". If I just use the manual formula "=left(A1,4)" it would give me the correct output "1234" in say cell B2, but as a formula. As I need to automate this in a macro, how could you code this in VBA to output the String "1234" into cell B2(ie the actual output rather than a formula)?
View 2 Replies View Related