More Digits From Polynomial Regressions?

Nov 21, 2008

The functions of trend lines in charts are nice, but the coefficients of the output equations are all with only one-digit for the polynomial fits. The single-digit fits by the fitting equations often result in higher deviations from what we have seen in the charts.

I also tried to use the statistical functions but it seams that I cannot get any outputs of these coefficients except for the slope of LINEST, which is not sufficient for polynomials.

I also use addins such as as regressions but cannot get anything either to help for these coefficients.

May someone tell me how to make such outputs with more digits so the equations can be more precisely fitting please?

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Number Formatting: The First Three Digits Will Be Separated And Then Subsequently 2 Digits

Oct 31, 2008

i need to format my numbers in the following format

10,00,000.00

the first three digits will be separated and then subsequently 2 digits

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VLookup Only Right Most 4 Digits Of The 6 Digits Sequential Numbers

Apr 30, 2014

I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.

=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)

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Feb 9, 2010

I have plotted a graph which compares the miles done with the petrol used.

I'm trying find a formula which allows me to apply the petrol and would give me the miles covered.

From excel I have applied the tread line of polynomial and obtained the following formula...

y = 1E-06x5 - 0.0002x4 + 0.0161x3 - 0.4893x2 + 7.5295x - 20.87

Rē = 0.9989

When is it applied to excel with the value of petrol it does not give me the miles.
I'm working out the formula in a incorrect manner?

I have attached the excel file.

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May 14, 2006

y = 1.083333333x4 - 7.3333333x3 + 16.416667x2 - 6.16667x + 4

Above is the polynomial equation of a trend line as shown on my chart, I have extracted the numbers into separate cells using LINEST, so now I have in cells A20 to E20 the numbers 1.083333333, -7.333333, 16.416667, -6.16667 and 4 respectively.With a "y" value of 25 how do I go about solving for a value of "x".

I've been stubbornly struggling with this on and off for a couple of weeks now and I'm not getting any closer to working it out and the websites I've found explaining the procedure all seem to go over my head by the time I get into the fourth or fifth paragraph.

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Jul 31, 2008

I have this data:

x y
310 516
320 526
325 535
330 587
335 640
340 715
345 857
350 1040

When I perform a third degree polynomial curve fit I get this equation:
y = 0.0106x3 - 10.0266x2 + 3152.3381x - 329943.8370
R2 = 0.9987

Which isnt right. On a calculator, I get negative numbers. Does excel have problems with 3rd degree polynomials?

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Sep 7, 2009

For Excel 2007 -

I am looking for a function [or method] to calculate a polynomial curve fit. I can do it on a graph with the existing graph and chart tools, but I need to calculate it myself. Does such software exist somewhere in my Excel 2007 package, or can anyone recommend a freeware program? I am hesitant to download an unknown, un-recommended add-in.

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Feb 16, 2007

I don't actually own Excel as yet - but I'm wondering if someone could tell me whether Excel is capable of solving what I'm told are 'polynomial equations'. An example of the sort of equation I hope to solve is: d/(1.18 + d) + d/(1.86 + d) + d/(9 + d) + d/(8.8 + d) = 2
d=? {I happen to know d = 3.65(approx) in this example btw}

Often there will be many more than four terms...

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Create A Polynomial Equation Of Z From The X And Y Inputs?

Jan 20, 2014

I'm familiar with 2d graphs, trendlines, and regression equations. Now I have some tabular data that has 2 input variables and a result. As with my 2d data, I would like Excel to create a polynomial equation of z from the x and y inputs. Can Excel do this, or do I need a plug-in or another software package?

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Multivariate Polynomial Regression In Excel?

Feb 8, 2010

I am trying to do multivariate polynomial regression in excel, trying to correlate data of the form y=f(x1,x2) with second order polynomials:

Y = c + a1*x1 + a2*x1^2 + a3^x1^3 + b1*x2 + b2*x2^2 + b3*x2^3

Using the following command, I have achieved this:

=LINEST(A2:A10,B2:B10^{1,2,3,0,0,0}*C2:C10^{0,0,0, 1,2,3},TRUE,TRUE)

theory Excel uses for this kind of regression?

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VBA Array Function For Polynomial Coefficients

Mar 9, 2007

I have a VBA function that calculates polynomial coefficients for a series of data pairs. One selects the range of cells that the coefficients are to be stored in, and enters the polynomial formula:

{POLFIT(Xa, Ya, N)}

Where Xa is the array of ordinate values, Ya is the array of data values, and N is the polynomial order to be fit.

It is obvious that one needs to select at least N+1 cells when the array funtion is typed in. But, it is easy to select too few cells.

I am looking for a way to test whether enough cells were selected for the range formula: The function declaration is

Function POLFIT(Xa, Ya, N As Integer) As Variant

Various means I have tried to count POLFIT do not return the correct value.

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Remove First X Digits And Last Y Digits From A Cell

Sep 25, 2009

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))

As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

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How To Remove First X Digits And Last Y Digits From A Cell

Sep 25, 2009

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.

Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).

Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

Does anyone have an idea on how to help with this?

Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.

However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.

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Calculate 2nd Degree Polynomial Trendline Coefficients In VBA Without Using Cells

Jul 17, 2014

i have a function in a cell (that works) to extract coefficients from a range of cells in a workbook:

VB: =INDEX(LINEST(CP25:CP27,CQ25:CQ27^{1,2}),1)}

i have variables for cp25:cp27 and cq25:cq27 already defined in my vba code. the values for these in the case i am working on are as follows (returns 110.5):

cp25 = 560
cp26 = 570
cp27 = 580
cq25 = .414
cq26 = .479
cq27 = .536

1) how to do this function in VBA only - this is part of a UDF and cannot have any helper cells
2) how to refer to 560,570,580 as a 'range'. is there a way to put these six variables into my ranges for later processing?

All of the google searches i have deal only with linear regression, taking from existing graphs, or say to just use the function i have above.

I have tried

VB:

Var = Application.WorksheetFunction.LinEst(Sheets("references").Range("CP25:CP27"), Sheets("references").Range("CQ25:CQ27^{1,2}"), 1)
[COLOR=#333333][/COLOR]

but return #value! errors. when i remove the ^{1,2} portion, i do return a value but it is incorrect (returns 160), what is the correct syntax for adding in the ^{1,2}? if you do that would be fantastic, but brings me back to issue #2 in that i need to refer to my variables in the vba code and not this range (as they will eventually be going away).

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Apr 10, 2012

I have quite a number of 4th degree polynomials and attempting to extract the variables from every equation. I used the formula below (from another thread);

=LOOKUP(99^99,--("0"&MID(A1,MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A1&"0 123456789")),ROW($1:$10000))))

but it only extracts the first variable.

4th degree polynomial function: f(x) = ax^4 + bx^3 + cx^2 + dx + e

Example of one of the equations: Y = -42.4276 + 319.989 X - 809.094 X^2 + 942.247 X ^3 - 397.587 X^4

I'll like to have the final result like below (Based on the Example equation above)

edcba-42.4276319.989-809.094942.247-397.587

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Jul 12, 2014

I can't seem to find a way to find the max of only the last four digits of a cell, matching the first 8. As an example:

I have thousands of cells in a column like this, (and I can't add any columns to the sheet), and I have a cell with the first three digits and the second three digits. So, out of all these numbers, I want the MAX of ONLY the numbers with the first 8 digits of "800-123-". Also, the decimal on the end is how many times the number was called, and any the decimal and any number after it is to be ignored. The answer would be "800-123-0024", or "0024", I just need a faster way to find it without searching for it.

888-555-0099.2
800-123-0022.3
555-333-0474

[Code]....

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Nov 11, 2008

I have a long list of 4 digit numbers:

e.g.

0234
2434
6566
4566
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But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:

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Nov 24, 2009

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Apr 13, 2007

I have 2 columns, A and B. The data looks like this:

0040005A2002868000PMTo 164.40
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002000002000015000PMTn 104.35
001000002000298000PMTn 92.80
001000004001042000PMTo 78.00
001000004001050000PMTo 78.00
003000001002100000PMTo 97.10
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I want to have column J with values from column A grouped by the first 9 digits and column J with the totals for these groups. It would look something like this:

002000002 250
002000004 300
003000027 100
003000050 70
004000002 90
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Jun 24, 2009

I have a formula now that is =right(C2,5)+0 that is working well. However the data has grown and sometimes there is also 6 digits now instead of 5. So I need it to pick up either one 5 or 6. When I change the formula to 6 it works but picks up a / which happens to be before the 5 digit # sequence when there is only 5 digits. It works great for the 6. Is there another way around this so I only get the numbre digits if there are 5 or 6 and not the /. Maybe an if statement. I've tried several ways but none work right. The only other thing I can think of is to get it as above with the =right(C2,6)+0 and then afterwards to a find and replace and remove the / from the data. I was just tryign not to add an extra step to the process. Any ideas please?

Example of the data in coloumn C2 is:
15/2000/4567/NA/NA/97305or with 6 digits at the end15/2000/4567/NA/NA/973052there is always just 5 or 6 digits at the end that I need.

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Oct 8, 2009

1. Remove the first 4 digits from each "Appeal ID"

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3. Run a v-lookup down the new column against a file that is stored on my desktop. The v-lookup will cross check the Appeal ID against the file to identify the Chapter

4. Sort the data alphabetically by Chapter

5. Create seperate Excel files for each Chapter ...

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Jul 8, 2003

I tried every filter function I know of, to no avail, and am yielding my stupidity to the forum. I have this series of numbers as an example:

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how can i do this in excel 2002?

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mod(95000000922019182020281000,97)=24

but in excel im getting the value as 0
also when i type the 24 digits its show like ..... # NUM!

if i put the function like =A1-FLOOR(A1,B1) its working for 13 digits but not for 24 digits.

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