Format SSN To Last 4 Digits
May 2, 2013I have a column with social security numbers, i.e. 555-33-2222 and I need to change to show only the last four digits, i.e. xxx-xx-2222. Can this be done in excel?
View 4 RepliesI have a column with social security numbers, i.e. 555-33-2222 and I need to change to show only the last four digits, i.e. xxx-xx-2222. Can this be done in excel?
View 4 RepliesIf I enter 2.5 into a cell, and then change the format so that there are no digits after the decimal, the number changes to a 3.
2.4 correctly rounds to 2, but shouldn't 2.5 round to 2???
I thought that even numbers were supposed to round down, and odd numbers round up when there is a 5 right after the decimal.
I need to list 4 digit numbers in each section followed by commas, but whatever I do it goes to 3digits (e.g. I need "1234,5678,9123" and as soon as I hit Enter it goes to "123,456,789,123"). It wont work to format as text because I have a whole bunch of 12 digit numbers to break up into 4.
View 9 Replies View RelatedI have a calculated field which is essentially two concatenated values (DDMMYY and sequential numbers starting from 1). I want it so that any single digits will automatically have a zero in front (e.g. 01, 02, 03 etc). The concatenating takes place in VBA so it has to be coded...
View 3 Replies View Relatedin A1 I have a drop down list with unit numbers and descriptions
example - 123456 - 30 to 150 lots
I want to see if when I pick from the drop down list the right unit and description that the cell will only show the first 5 digits.
example I pick 123456 - 30 to 150 lots in cell A1 would say 123456
I am inserting data into my spreadsheet using VBA code to read a file and insert the data into the relevant cells. My problem arises when I have a string such as 80830410205724044. The actual code that inserts the data is as shown (temp is dimmed as string)....
View 9 Replies View RelatedHow to convert any types format into Text with 5 digits in selection?
For instance, the content I select is "234", and I want it to convert to "00234". Just like the function "TEXT" in excel. How can I realize it promptly in VBA?
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I am trying to create a unique sample code by putting together the values of other cells that a user will input. It's all working well apart from the last part, where I am trying to include a decimal number. I want the decimal number to appear without the central "." and in a four digit format. e.g. 2.5 would appear as 0250, 14.25 would appear as 1425. This is the formlua I am using currently:
=IF(ISBLANK(B4),"",IF(LEFT(C4,1)="w",(B4&"-"&TEXT(F4,"YYMMDD")&C4&TEXT(G4,"HHMM")),(B4&"-"&TEXT(F4,"YYMMDD")&C4&LEFT(TEXT(H4,"00"),2)&RIGHT(TEXT(H4,"00"),2))))
However, where the value of H4 is 2.5, I am getting a result of 0303 (I've put this part in bold). I have attached a small spreadsheet to aid understanding.
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
I am having trouble with formating a to date. I have ~5,000 lines of data that are formatted as follows: the last 6 digits refer to date. For example, below line should be date 09/24/09. PRIVATEBANK 3.65%09PRIVATE 3.65%09 PRIVATEBK&TR 3.65 092409. I am using the right function to isolate the date. In cell A2:
View 2 Replies View RelatedI can't seem to find a way to find the max of only the last four digits of a cell, matching the first 8. As an example:
I have thousands of cells in a column like this, (and I can't add any columns to the sheet), and I have a cell with the first three digits and the second three digits. So, out of all these numbers, I want the MAX of ONLY the numbers with the first 8 digits of "800-123-". Also, the decimal on the end is how many times the number was called, and any the decimal and any number after it is to be ignored. The answer would be "800-123-0024", or "0024", I just need a faster way to find it without searching for it.
888-555-0099.2
800-123-0022.3
555-333-0474
[Code]....
I have a long list of 4 digit numbers:
e.g.
0234
2434
6566
4566
6785
But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:
02
24
65
45
67
I would like to take the first three digits of column A and do a lookup of column B that would return the corresponding number from column C. For example, if I entered the formula for 103PH, the lookup would find the 103 in column B and return "2775.00" from column C...........
View 4 Replies View RelatedI was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
View 5 Replies View Relatedadding the sum of digits in a cell using VBA. For eg: in A1 if I have 12345 I need the sum of 12345 (15) in cell B1.
View 3 Replies View RelatedI have a number 53.30242 in a cell a1. How can I just make it 53.302? I don't want to round it to 3 decimal place, just keep the first 3 digits.
View 6 Replies View RelatedI have 2 columns, A and B. The data looks like this:
0040005A2002868000PMTo 164.40
003000005000037000PMTo 104.40
001000002002090000PMTn 188.35
002000002000015000PMTn 104.35
001000002000298000PMTn 92.80
001000004001042000PMTo 78.00
001000004001050000PMTo 78.00
003000001002100000PMTo 97.10
001000004002115000PMTn 92.75
I want to have column J with values from column A grouped by the first 9 digits and column J with the totals for these groups. It would look something like this:
002000002 250
002000004 300
003000027 100
003000050 70
004000002 90
etc
I have a column of numbers, all with varying numbers of digits. I want to make them all have only 4 DIGITS in total (regardless of where the decimal is located... so there could be 4,3, 2, 1,or, 0 decimal places). I just want to make everything the same number of digits.
View 9 Replies View RelatedIn this worksheet , in Columns B4:F2615, there are rows of digits that range from 1-36, I have a need to find the 10 digits that were drawn togather the most. I have no idea how to do this in Excel or can it be done? ....
View 9 Replies View RelatedI have a pair of digits in col B, that I would like to match with the digits in in col D, and display those matches in col E. If possible I would delete the duplicates in col E, and show results in col F.
View 9 Replies View RelatedI have a formula now that is =right(C2,5)+0 that is working well. However the data has grown and sometimes there is also 6 digits now instead of 5. So I need it to pick up either one 5 or 6. When I change the formula to 6 it works but picks up a / which happens to be before the 5 digit # sequence when there is only 5 digits. It works great for the 6. Is there another way around this so I only get the numbre digits if there are 5 or 6 and not the /. Maybe an if statement. I've tried several ways but none work right. The only other thing I can think of is to get it as above with the =right(C2,6)+0 and then afterwards to a find and replace and remove the / from the data. I was just tryign not to add an extra step to the process. Any ideas please?
Example of the data in coloumn C2 is:
15/2000/4567/NA/NA/97305or with 6 digits at the end15/2000/4567/NA/NA/973052there is always just 5 or 6 digits at the end that I need.
1. Remove the first 4 digits from each "Appeal ID"
2. Insert a new column (first column) called "Chapter"
3. Run a v-lookup down the new column against a file that is stored on my desktop. The v-lookup will cross check the Appeal ID against the file to identify the Chapter
4. Sort the data alphabetically by Chapter
5. Create seperate Excel files for each Chapter ...
I tried every filter function I know of, to no avail, and am yielding my stupidity to the forum. I have this series of numbers as an example:
456912
789547
785171
658712
968712
369874
258741
127812
All I want to filter is all values ending with 12.
how can i do this in excel 2002?
for example.....
mod(95000000922019182020281000,97)=24
but in excel im getting the value as 0
also when i type the 24 digits its show like ..... # NUM!
if i put the function like =A1-FLOOR(A1,B1) its working for 13 digits but not for 24 digits.
I've recorded a macro to replace the Australian telephone number area codes (at the beginning of each phone number) with international dialling codes. I also need to replace the first two digits ONLY of mobile ( cell) phone numbers which, in Australia, all begin with "04" (see last part of macro code below - column L:L).
With the code the way I've recorded it, if it finds "04" in another part of the number (e.g. 0411 104 111), the second occurrence of the "04" will automatically be replaced with "614" as well which I don't want. So I need some code to add so that the macro only searches and replaces those first two digits in that column. I hope I'm making sense?!
Sub ConvPhNo()
'
' ConvPhNo Macro
' Macro recorded 12/12/2007 by xxxxxxxxx
'
'
Columns("C:C").Select
Selection.Replace What:="(", Replacement:="", LookAt:=xlPart, _ ...........
I found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:
12345 45
26548 48
21854 54
211ae ae
I thought it was a =right or something.
I have a excel file, I need to remove the first two digits if they are certain numbers, such as 12. For example, if the number is 12987654, then I need remove 12, and it will be "987654" , but if it is not 12 in the first two digits, then keep it no change, for example if it is 345678, then keep it.
I barely work with Excel formulas, now I need connect the excel file with my Database table. I need to make the file matches the DB.