1. Remove the first 4 digits from each "Appeal ID"
2. Insert a new column (first column) called "Chapter"
3. Run a v-lookup down the new column against a file that is stored on my desktop. The v-lookup will cross check the Appeal ID against the file to identify the Chapter
4. Sort the data alphabetically by Chapter
5. Create seperate Excel files for each Chapter ...
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
I have a excel file, I need to remove the first two digits if they are certain numbers, such as 12. For example, if the number is 12987654, then I need remove 12, and it will be "987654" , but if it is not 12 in the first two digits, then keep it no change, for example if it is 345678, then keep it.
I barely work with Excel formulas, now I need connect the excel file with my Database table. I need to make the file matches the DB.
I know how to remove the first part of a text, but not the end. I have a very large amount of data in which the first column contains a product description and then the UPC code. I need to isolate the product name from the UPC code into 2 columns. I used =RIGHT(B2,14) to isolate the UPC, but since the length of the product name varies, I'm not sure how to isolate the product name. I have looked at using the TRIM and TRUNC functions without any luck. 'Text to columns' doesn't work because I have multiple spaces, 'Text to columns' would work if I could used 2 digits as the delimiter, but the function doesn't allow that.
Can someone please suggest a function or formula for this?
Here is an examples of how the text appears in the field. (Note: I only need to cut off the UPC code, I need the measure information to stay).
some really long product name 12 oz 5 bag 09-99999-99999
another shorter name 2 oz 09-99999-99998
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I have found a very useful UDF for removing non-alpha characters from strings. (See below, Credit for posting to Stanley D Grom - Ozgrid post ´Removing Non-alpha Characters From Text´).
Option Explicit
Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
intStringLength = Len(InString)
InString = LCase(InString)
For intLoopCounter = 1 To intStringLength
intASCIIVal = Asc(Mid(InString, intLoopCounter, 1))
If intASCIIVal >= 97 And intASCIIVal <= 122 Then
RemoveCharacters = RemoveCharacters + Mid(InString, intLoopCounter, 1)
End If
Next intLoopCounter
End Function
Two requests:
1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?
2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"
I can't seem to find a way to find the max of only the last four digits of a cell, matching the first 8. As an example:
I have thousands of cells in a column like this, (and I can't add any columns to the sheet), and I have a cell with the first three digits and the second three digits. So, out of all these numbers, I want the MAX of ONLY the numbers with the first 8 digits of "800-123-". Also, the decimal on the end is how many times the number was called, and any the decimal and any number after it is to be ignored. The answer would be "800-123-0024", or "0024", I just need a faster way to find it without searching for it.
888-555-0099.2
800-123-0022.3
555-333-0474
[Code]....
I have a long list of 4 digit numbers:
e.g.
0234
2434
6566
4566
6785
But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:
02
24
65
45
67
I would like to take the first three digits of column A and do a lookup of column B that would return the corresponding number from column C. For example, if I entered the formula for 103PH, the lookup would find the 103 in column B and return "2775.00" from column C...........
View 4 Replies View RelatedI was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
View 5 Replies View Relatedadding the sum of digits in a cell using VBA. For eg: in A1 if I have 12345 I need the sum of 12345 (15) in cell B1.
View 3 Replies View RelatedI have a number 53.30242 in a cell a1. How can I just make it 53.302? I don't want to round it to 3 decimal place, just keep the first 3 digits.
View 6 Replies View RelatedI have a column with social security numbers, i.e. 555-33-2222 and I need to change to show only the last four digits, i.e. xxx-xx-2222. Can this be done in excel?
View 4 Replies View RelatedI have 2 columns, A and B. The data looks like this:
0040005A2002868000PMTo 164.40
003000005000037000PMTo 104.40
001000002002090000PMTn 188.35
002000002000015000PMTn 104.35
001000002000298000PMTn 92.80
001000004001042000PMTo 78.00
001000004001050000PMTo 78.00
003000001002100000PMTo 97.10
001000004002115000PMTn 92.75
I want to have column J with values from column A grouped by the first 9 digits and column J with the totals for these groups. It would look something like this:
002000002 250
002000004 300
003000027 100
003000050 70
004000002 90
etc
I have a column of numbers, all with varying numbers of digits. I want to make them all have only 4 DIGITS in total (regardless of where the decimal is located... so there could be 4,3, 2, 1,or, 0 decimal places). I just want to make everything the same number of digits.
View 9 Replies View RelatedIn this worksheet , in Columns B4:F2615, there are rows of digits that range from 1-36, I have a need to find the 10 digits that were drawn togather the most. I have no idea how to do this in Excel or can it be done? ....
View 9 Replies View RelatedI have a pair of digits in col B, that I would like to match with the digits in in col D, and display those matches in col E. If possible I would delete the duplicates in col E, and show results in col F.
View 9 Replies View RelatedI have a formula now that is =right(C2,5)+0 that is working well. However the data has grown and sometimes there is also 6 digits now instead of 5. So I need it to pick up either one 5 or 6. When I change the formula to 6 it works but picks up a / which happens to be before the 5 digit # sequence when there is only 5 digits. It works great for the 6. Is there another way around this so I only get the numbre digits if there are 5 or 6 and not the /. Maybe an if statement. I've tried several ways but none work right. The only other thing I can think of is to get it as above with the =right(C2,6)+0 and then afterwards to a find and replace and remove the / from the data. I was just tryign not to add an extra step to the process. Any ideas please?
Example of the data in coloumn C2 is:
15/2000/4567/NA/NA/97305or with 6 digits at the end15/2000/4567/NA/NA/973052there is always just 5 or 6 digits at the end that I need.
I tried every filter function I know of, to no avail, and am yielding my stupidity to the forum. I have this series of numbers as an example:
456912
789547
785171
658712
968712
369874
258741
127812
All I want to filter is all values ending with 12.
how can i do this in excel 2002?
for example.....
mod(95000000922019182020281000,97)=24
but in excel im getting the value as 0
also when i type the 24 digits its show like ..... # NUM!
if i put the function like =A1-FLOOR(A1,B1) its working for 13 digits but not for 24 digits.
I've recorded a macro to replace the Australian telephone number area codes (at the beginning of each phone number) with international dialling codes. I also need to replace the first two digits ONLY of mobile ( cell) phone numbers which, in Australia, all begin with "04" (see last part of macro code below - column L:L).
With the code the way I've recorded it, if it finds "04" in another part of the number (e.g. 0411 104 111), the second occurrence of the "04" will automatically be replaced with "614" as well which I don't want. So I need some code to add so that the macro only searches and replaces those first two digits in that column. I hope I'm making sense?!
Sub ConvPhNo()
'
' ConvPhNo Macro
' Macro recorded 12/12/2007 by xxxxxxxxx
'
'
Columns("C:C").Select
Selection.Replace What:="(", Replacement:="", LookAt:=xlPart, _ ...........
I found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:
12345 45
26548 48
21854 54
211ae ae
I thought it was a =right or something.
I did post a problem where I have a number like 123456 and I need to have Excel change it so that it puts a comma before the last two digits .. like so: 1234,56
I got a reply where I got the solution to use 0","00 and this works in Excel (using the custom format)
The only problem is that although the number changes in the cell to 1234,56 it doesn´t do so in the FX window and thus when I use the number to multiply it is actually 123456 instead of 1234,56 like it want it to be.
is there some way to conditionally change the last digit into something else entirely? 1222 should be 122.25, 1224 should be 122.50, and 1226 should be 122.75.
View 3 Replies View RelatedI am looking for a formula to sum up all the digit(s) within a range of cells, e.g.
View 7 Replies View RelatedI have a text field (description) and in the description i have a product code S followed by 7 digits and then in the process of pasting into excel i have lost the space after this code and before the next text. E.g. "Ballpoint pen S1234567With Free Delivery" should be "Ballpoint pen S1234567 With Free Delivery".
I dont know how to say =if("S" followed by 7 numbers,subsitute ..... etc)
I understand how to use IF and substitute. its the 7 numbers part i am stuck on.
I could do it in access with the wildcards but excel is different.
Example numbers:
21130 & 21065
I want to check each number if EITHER of the two conditions is true:
1. if the third digit from the right (the hundreth place) is greater than zero;
or
2. if the second digit from the right (the tens place) is >=6.
If either is true I want to add a particular number to the original number.
My example numbers meet questions 1 & 2, respectively.
Can a vba macro be provided for splitting a number into digits? The number will be in Sheet 1 but splitted number will be on sheet 2. Splitting of numbers means a number entered into a cell will be splitted into different column/cells with one digit per cell.
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