Adjustment To Remove FALSE Result

Feb 1, 2009

Im having alot of difficulty preventing the result FALSE when one or more of my >20 count within an index table doesnt have a result to display.

Is there anyone able to understand the following? That can perhaps provide a solution that returns no FALSE word??

=IF(ISERROR((VLOOKUP($A22,'C Number'!$A:$N,B$1,0)))=FALSE,VLOOKUP($A22,'C Number'!$A:$N,B$1,0))

Ive tried ISNA but I always get an error appear when i try to use it, perhaps you could edit the command above so that ISNA works whenever FALSE is the result?

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Formula Shows Result As FALSE?

Feb 15, 2014

I have following formula:

Why does this formula show result as "FALSE"?

If cell B56 is empty, then I need a result of "". i.e. blank result, but it shows FALSE word.

IF(LEFT(B56,2)="on",

then you go straight to the TRUE nested IFs

IF(LEFT(B56,2)="on",
IF(LEFT(B$52,3)="Pla",RIGHT(Table!AN4,2)&"% Discount",
IF(LEFT(B$52,3)="Gol",RIGHT(Table!AO4,2)&"% Discount",
IF(LEFT(B$52,3)="Sil",RIGHT(Table!AP4,2)&"% Discount",""))), "need something here" )

so to get ""

IF(LEFT(B56,2)="on",IF(LEFT(B$52,3)="Pla",RIGHT(Table!AN4,2)&"% Discount",IF(LEFT(B$52,3)="Gol",
RIGHT(Table!AO4,2)&"% Discount",IF(LEFT(B$52,3)="Sil",RIGHT(Table!AP4,2)&"% Discount",""))), "" )

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If instead of qualifying this full string, I try to Search for the "-QS" string in that cell as the criteria:

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I'm guessing it may be because SEARCH isn't actually returning a TRUE/FALSE response, but rather, a numeric one based on the position of "-QS". I tried using a numeric approach also, but this didn't help:

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| ID X
| +------+------+------+--->
| | 1999 | 2000 | 2001 |
+------+------+------+------+--->
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+------+------+------+------+--->
| Feb | $200 | $300 | $200 |
+------+------+------+------+--->
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+------+------+------+------+--->
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| +------+------+------+--->

| ID Y
| +------+------+------+--->
| | 1999 | 2000 | 2001 |
+------+------+------+------+--->
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+------+------+------+------+--->
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+------+------+------+------+--->
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+------+------+------+------+--->
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Option Explicit

Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
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For intLoopCounter = 1 To intStringLength
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End If
Next intLoopCounter
End Function

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1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?

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