How can I count the number of gaps (spaces) of a string? (Adding one we have number of words!). I need to save the position of each gap (space) on a array. How can I do it? With InStr()? The variable (string) that i'm working is GlbTargetRange.Value
View 4 RepliesSpaces after entries keep messing up my VLOOKUPS. I get a lot of data from other people and when they have entered the information in some of the entries have a space after the word which mess up the results of my vlookups. Is there an easy way of going through and removing spaces after a word? Not all the words have spaces after them.
View 4 Replies View RelatedI'm trying to find a formula to add spaces in between capitalized words
example :
cell A1 = MtVernonRoad
trying to make it say..
Mt Vernon Road
If I have ABC DEF in a1, is there a formula I can put in a2 to remove the space and display ABCDEF
View 2 Replies View RelatedI am trying to parse a formatted text file. I am using the SPLIT function as
arr() = split(cline," ")
where cline is an input line. if the line input(cline) has multiple spaces between two words, how would it split that.
Eg :
abcd defg fefdcs fasdfasdsa
would the output of above be
arr(0) = abcd
arr(1) = defg
arr(2) = fefdcs
arr(3) = fasdfasdsa
I want to count words given two criteria.
So I basically want to combine the COUNTA function and the COUNTIFS function.
I have attached a sample spreadsheet in the post.
Test Excel.xlsx
I'm trying to speed up the creation of an input file that has a set character length but the inputs have variable lengths. For instance the identifier can have a string length of 7 or 8 depending upon the type.
BTW I've also tried using space(1) as opposed to " " in the loop.
However I have survey data results and in one of the cells it has multiple values which are separated between ; and some are not separated at all e.g B&Q; The Range; Wicks The Garden Shop
Also there are spelling mistakes everywhere and variation of the word B&Q e.g b+q, B n Q
I need to add count up all of the B&Q, Wicks etc...
Is there a formula that can count the number of words in a cell?
View 3 Replies View RelatedI have a column filled dates in the format 01 January 2013 and I want a formula to count all the cells containing "January" for example.
View 3 Replies View RelatedI currently have this code for counting commas in each cell in range giving me the total number of different points in the entire row. Here's the link to the original question as well.
Code:
Sub Totals()
Dim X As Long, Count As Variant
Sheets("App Communication").Select
For X = 3 To 59
Count = UBound(Split(Application.Trim(Replace(Replace(Application.Trim(Join(Application. _
Index(Cells(X, "E").Resize(, 57).Value, 1, 0), ",")), " ", "X"), ",", " ")))) + 1
Cells(X, "BJ").Value = Left(Count, CLng(Count))
Next
End Sub
Now I am looking for a way to count the number of points that have been turned blue. Some times the text in the whole cell is turned blue, others just one or two of the points is turned blue.
I need to some spaces to the end of a string to make it up to 36 chars.
The original string can vary in size based on the courier name.
i.e. : business direct invoice 40617 = 29 chars
i.e. : TNT post invoice 4061755 = 24 chars
Can someone point me in the right direction to be able to concat' some spaces on the end to make it up to 36 chars.
Would this be easier done using VB?
I am trying to replace all spaces in a string with an underscore.
I'll be applying a loop to cycle through the whole column in that file. Should be pretty easy..
I need to take 12ABC1234512345 and turn it into 12A BC 12345 12345 with a vba macro. I've made a formula that works but in this situation a macro would be more ideal.
View 5 Replies View RelatedI am looking for this for some time. Is there any formula (not vba) to count that how many occurances of spaces are in a text string, spaces could be more than one between the words.
I am trying to get rid of the spaces at the beginning of text that is the result of a download from a reporting software package. I am using the Trim function but it does not work. It seems that it has something to do with the formatting. The first set of data of the download looks as follows:
SalesSales BreakdownSolenaceousCucurbitsLargeSeedIf I overtype the text in exactly the same way (thus keeping the spaces at the beginning), the trim function works. But this is not a practical solution.
The type of the cells is "2". I have tried copying the data as values to a different workbook but this does not help either.
I'm trying to build a function, but I haven't been able to successfully navigate some of the eccentricities of Excel formula-building.
Right now I am working on counting all of the cells that contain numbers (so likely just a =COUNT function), but will be eventually getting other descriptive stats as well. My problem is that I would like to create a formula that will perform the counting/mean calculation, etc., but only on a specific column that has the header cell that contains several specific words. Rather than having to type in the target words for each column, I would like to have the target words in the function be imported from multiple designated cells.
For example,
I want to find how many numbered cells are found in column E headed as "dog brown," but I also have columns headed as "cat brown" "dog black" etc. (which I will be using the formula on later) to paint a small picture, in my descriptive table, "dog" is in B31 and "brown" is in C30, then "cat" in B32 and "black" in D30.
I've found several posts about returning variable substrings that dealt with one or two spaces, but I have not been able to find anything that is for multiple spaces. The number of characters before the substring will remain constant.
For example:
Income from transmission agreement - 83 subs @ $0.44
In this case I need to extract: 83
Income from transmission agreement - 10,312 subs @ $0.50
Need: 10,312
I'm attempting to extract the Street Names from an Address.
For Example, if given "123 Very Big Street" I'd want to extract "Very Big".
If given, "123 Very Big" I'd want the same answer.
I've written code to do this, with a simple IF statement to identify mathcing last words like "Street" and "Drive".
How can I efficiently do this with a large list of last words? I'm drawing a blank on how to query against an array that would contain all these values.
Take a look at the attached workbook.
Tab 'Internal' is an example of our internal customers and how much they spent with us.
Tab 'External' is a list of companies in our area that we could do business with, it came from a marketing firm. Columns B:J contain my formulas. B is my lookup.
I need to match the two sheets together and pull the dollars spent from Internal to External. The problem is that the marketing firm did not use the same naming conventions that are in our systems. This means a simple Vlookup will not work.
Here is what I did so far: used VBA and formulas to break apart the company names in External, then using a modified Vlookup to match the words to the names in Internal. My accuracy rate is less than 1%.
I have a conditional formula which populates a string depending on the value selected by user.
E.G of formula is:- =IF($B$1=0,"CONTACT PERSON - OPTIONAL",IF($B$1=5,"CONTACT PERSON - MANDATORY",""))
Where the result is "CONTACT PERSON - MANDATORY" then I want the word MANDATORY (not the whole string) to be displayed in RED.
I am trying to search words that are in column A (5 letter combinations of sequences) within the text in column B (amino acid sequence).
So I am stumbling upon 2 questions:
- what is the function that would do this search.
- how to acchieve to reverse the text in B1 cell (eg. abcde --> edcba , but with 600 letters),
sample file: test.xlsx
I have a sheet of about 10k rows that I need to switch some things around on. The string is below:
Acura|TL|1995^^Acura|TL|1996^^Acura|TL|1997^^Acura|TL|1998^^Acura|TL|1999
It needs to say:
1995|Acura|TL^^1996|Acura|TL^^1997|Acura|TL^^1998|Acura|TL^^1999|Acura|TL
How to fix this with a macro or formula. The Make Model and Year on each string will be different. Basically I need the format to be Make|Model|Year.
Let's say i do have words : cow, dog, giraffe, elephant, parrot.
The rest will try to explain in the excel file.
What I am trying to do isn't very complicated. I started on some code, but it's just not good enough to do all of what needs to happen.
A
B
C
1
Cupcake Monster
Aisle 5
Shelf H
2
The Cupcake Ghoul
Aisle 2
Shelf P
3
Fred Baxter's Diary
Aisle 1
Shelf X
4
Angry Cupcake Beast
Aisle 3
Shelf A
5
Everyone Loves Cake
Aisle 4
Shelf R
So I have a list of titles that I want to search for a particular string. The title in this list is the "proper" title,whereas the rest of my workbook typically uses a shortened version of the title. Sometimes the two will match 100%, but usually, they will be close.
If the string in the table above has more than 2 words, I want to use the first 2 words to check for a match. If the string has 2 words (will never have fewer), I want to match the first word. I want to do this IF there is no 100% match (if possible or reasonable). I will settle for just matching 1 or 2 words. I want to copy the values to another sheet and then delete the row that I originally got the data from.
What I want to do is search the list for "Angry Cupcake" and return the Aisle and Shelf location of Angry Cupcake Beast. There will never be any other "Angry Cupcake", so I am not worried about mismatches there.
Code:
Dim SearchRow As Integer
Dim StoryTitle As String[code]....
how to do and can get to work without issues is an exact match. This still leaves out all of the shortened titles though.
I can not get this to work:
Code:
Sub SplitApart()
Dim data As String
data = Sheets(1).Cells(20, 1).Text
For Each EachSplit in Split(data)
n = n + 1
Sheets(1).Cells(20, n + 1) = EachSplit
Next
End Sub
Error code when Debugging on "Split":
"Wrong Number of arguments or invalid property assignment"
How can i find the first 15 letters or numbers in a text string "material change:"
or find ":" then display everything to the left of that symbol ?
assume formula in a1 and test string in b1.
I wish there was a class you could take on this stuff.
I need to compare a list of keywords (stored in a string variable) with the content of a cell in order to see if any of the keywords do appear in the cell. I have to work with many such lists which can grow over time. What I'm doing is using InStr(cell with content, keyword) for each keyword. My goal is to have a macro which can automatically create the long formula from any list. My actual problem is that the formula I've build and stored acts more like a string. I'd like it to say either true or false. Anyway, here's a sample of what I came up with so far.
Sub build_formula()
Dim i As Integer, j As Integer, m(20) As Integer, n As Integer, z As Integer
Dim List As String, f(2) As String, s(20) As String, sp As String, Source As String
Dim Formula As Variant
List = "black, blue, green, red, yellow, white, z"
Source = Cells(3, 1).Value
z = InStr(1, List, "z")
i = 1
n = 1
Do
i = InStr(i + 1, List, ",")
m(n) = i ..........................
I have uploaded my spreadsheet.
I have a column of text strings on Sheet1, Column A, which I need to check for the presence of keywords listed on Sheet2, Column A
So if any word from the keyword list on Sheet2, Column A is found in, say, cell A2 of Sheet1, the cell to its right (B1) should have a formula to display the count of keywords found in A2. I also would like to see each keyword identified either through a highlight or a list. I need the formula to NOT be case sensitive and the match does not have to be for whole words).
I need to extract all instances of words that have format xnnnnnn, where x is an alpha character (letter of alphabet, to be precise) and nnnnnn are numbers. The words could something like u435586. The problem is I do not know how many instances of these words are in the string. The entire string is contained in a cell. A sample string could be something like:
SMNTv922970;#1283;#SMNT 433925;#1284;#SQRS 003417;#1285;#SQRSp047683;#1286;#SMNT 6132451;#1287;#SQRSw3145627;#1288
and the end result should be
v922970 t433925 t003417 p047683 t6132451 w3145627
The words are preceded by the character "" which might facilitate the search.