I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 RepliesI am trying to write a function that finds and breaks a cell about the first space.
Worksheet is:
=LEFT(name,FIND(" ",name)-1)
Have tried...
Function Firstname(name)
Dim Space As Integer
Set Space = .Find(" ", name)
Firstname = Left(name, Space)
End Function
and also...
Function Firstname(name)
firstname = left(name,find(" ",name)-1))
End Function
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
EX.
Cell A1{ 1 2 4 5 3 5 TITLE1 1 2 3 6 7 4 5 TITLE2 3 4 5 2 4 5 TITLE 4 }
Cell A2{ 1 2 4 5 3 5 TITLE2 1 2 3 6 7 4 5 TITLE3 3 4 5 2 4 5 TITLE 4 }
I would like to be able to search each cell for the "TitleX" then parse data out to the left of that title (and if not found, return "").
There are too many different Titles to use IF statements and I cannot change that the data comes to the left of the title.
Cell R2 contains this value: " Forecast Time: 240 Index A forecast = 9078.314". I want to extract the characters "9078.314" and put them in a different cell. The cell that it should be affected to depends on the characters "240". I believe I should use the MID() and VLOOKUP() functions but I get stuck at the very first step of extracting my data.
View 3 Replies View RelatedHow can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
I have two words of differing character lengths separated by a space.
How can I remove the first word... essentially, all the charcters to the left of the space AND the space itself?
I've created a user form that has a list box populated with a fairly standardized format - a product ID or model number followed by a dash ( - ) then followed by a description. Based on the users selection of an item in the listbox, certain rows will be copied over from another tab in the excel file.
An error occurs when a Model Number list box item is selected but not when a product ID is selected.
The difference between the two are AlphaNumeric vs only numeric.
USBLT15CMB - Product Description 1
1121 - Product Description 2
the code is:
Private Sub CommandButton1_Click()
Dim ID As Long
Dim Row As Long
Dim Cnt As Long
[Code]...
The macro stops on the ID = line
How do I return the Nth Character in a cell starting from the left.
For example, cell A1 has the word "Baseball". What formula will give me the 6th character to the right, which would be "a"?
Could someone tell me if the following formula is valid?
=AND(F15="R*", I15>0)
I want to know if F15 contains 'R' or 'RW' but using a wildcard always returns false whether this correct or not.
Using VBA, how can I determine if a cell contains only white spaces and NO valid characters?
View 2 Replies View RelatedI am looking to write a formula in an excell cell to veiw some of the wording in another cell. I know how to say that i want to see the first or last "x" characters in a cell.. But how do i say that i want to see all the info/wording in a cell except the last "x" characters..
View 4 Replies View RelatedI'm trying to figure out why i'm getting this error: "Object variable or With block variable not set" for this
Sub Macro3()
Dim cel As Range
Dim str1 As String
Dim SearchThing As Range
Set SearchThing = ActiveSheet.Range("I34")
str1 = Left(SearchThing.Value, Len(SearchThing) - 4)
cel.Value = str1
End Sub
The error is specifically with this line
cel.Value = str1....................
I am blanking out. I want to pull the data out until a space (one formula from the left and one from the right). Ithink it's a mid function but not sure.
Example
John, Doe
I would like to get:
John,
and
Doe
Sub GetThatstring()
Dim strMonth As String
Dim iYear As Integer
Dim StrMnthYear As String
strMonth = Trim(Left( Range("A1"), _
InStr(1, Range("A1"), " ", vbTextCompare)))
MsgBox strMonth
iYear = Mid(Range("A1"), _
InStr(1, Range("A1"), " ", vbTextCompare) + 1, 4)
MsgBox iYear
StrMnthYear = Trim(Left(Range("A1"), _
InStr(1, Range("A1"), " ", vbTextCompare) + 4))
MsgBox StrMnthYear
End Sub
I have a column of cells likes:
5/5058 Jack Daniels
5/29AA Crown Royal
I want to delete everything to the left of the first space.
So it will look like:
Jack Daniels
Crown Royal
It has to be vba though. I have done alot of trim in just formulas but this is first time in VBA. The above code is one I found by searching but not sure what to do to modify it.
This will be for range AM2:AM2000
I'm looking for a formula that pulls the text from a cell unti it hits a space. I'm using the formula below but keep getting #VALUE results. B1: =LEFT(A1,FIND(",",A1,1)). I know it's not that hard but can't figure it out.
View 4 Replies View RelatedThis is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
=LOOKUP(9.99E+307,--MID(C4,MIN(FIND({1,2,3,4,5,6,7,8,9,0},C4&1234567890)),ROW(INDIRECT("1:"&LEN(C4)))))
is the solution, but I'm struggling with making the correct alterations.
I need composing a formula that will add a space after every 4th Number in a 16 digit Character Set.
ex. 0101 0101 0101 0101
I was able to get rid of the weird character [] with the =CLEAN(E11), where E11 had the problem character. but now where the [] used to be between to words the 2 words just show as 1. Example If the bad cell was just[]test the clean cell has justtest without a space between the 2 words. Since the spreadsheet is about 8,000 cells and has random [] characters is it possible to not just clean the bad characters, but add a space where they used to be all in one command?
View 9 Replies View RelatedI have the following in Column A
28VNC
JR2KL
29C9O
PQS11
I'd like have this result
28
2
299
11
How would I achieve this.
I'm looking for a way to split a cell with text into two cells. The first cell can only contain up to 40 characters, the rest needs to go in the second cell. However, I don't want the text to be split in the middle of a word. So basically, if the text is in cell A1, I need to find the closest space to the left of position 40 in A1, and move anything to the right of this position to B1. Example:
Original text:
A1: One green apple and a bucket of small onions that smell nice
I want to avoid this:
A1: One green apple and a bucket of small on
B1: ions that smell nice
I want to achieve this:
A1: One green apple and a bucket of small
B1: onions that smell nice
I have special character that I removed with =CLEAN formula.
It was only one character which represents carriage return. It looks like one little square with question mark inside.
After I applied =CLEAN formula it disappeared, but now I don't have space between these two words.
How could I replace this special character with space?
Automatically format a textbox on a userform so that it puts a space immediately before the last 3 characters, regardless of how many characters are put in?
View 9 Replies View RelatedI have following kinds of texts in a column.
MISCELLANEOUS
EQUIPMENT
JBKU348597-3
T-225
75984
I want to convert above texts with space between every character as follows:
M I S C E L L A N E O U S
E Q U I P M E N T
J B K U 3 4 8 5 9 7 - 3
T - 2 2 5
7 5 9 8 4
I am trying to find numbers before a space character.
For example...
In column 1..................to return in column 2
23 cars................................................. 23
5 trucks................................................. 5
150 vans.............................................. 150
I can't use MID Function as it can be 4 numers long...
Sub TrimSlashesToRight()
Dim cell As Range
For Each cell In Range("AN2:AN2000")
cell = Left(cell, InStr(cell, "//") -1)
Next
End Sub
I cannot get it to run this, it always crashes on
cell = Left(cell, InStr(cell, "//") -1)
It will work fine like:
cell = Left(cell, InStr(cell, "//") + 0)
but then it leaves the first / in place, i want it to start deleteing before both //.
I am looking a macro which should perform below activities
I have a lists of suppliers which needs to cleansed....
1.replace all the special characters with a space
2.replace Corporation with Corp
Incorporation with Inc
Limited with Ltd
Limited partnership/ltd partnership with LP
Company with Co
ASSC/ASSOC with ASSOCIATION/ASSOCIATES (SEARCH SUPPLIER IN GOOGLE FOR THE CORRECT ONE)
MGNT with MANAGEMENT
SVCS with SERVICES
DEPT with DEPARTMENT
Unltd with UNLIMITED
Ctr with CENTER
UNIV with UNIVERSITY
3. Remove any text, Special characters and numbers after INC,CO, LTD, CORP,LLP, LLC
The macro should when I select any particular column... not restricted to column A
I've a column of data as below:
ROACH (#21)
SHARK (#11)
SHARK (#13)
UNICORN (#26)
ROACH (#20)
TRIGGER (#09)
UNICORN (#06)
UNICORN (#09)
UNICORN (#11)
VIMBA (#03)
VIMBA (#04)
TRIGGER (#06)
ROACH (#07)
ROACH (#08)
ROACH (#10), UNICORN (#24)
What I need to do it to strip off all the characters after the first space.
I assume I can use FIND and then LEFT, but how to I put this into a Macro?
I need to add spaces to a string of characters so that it is readable, the database is huge so I cannot do it manually:
For example,
123456John Doe 3456Adam Sharp I need it to apperar as:
123456 John Doe 3456 Adam Sharp
but still remains at the same column. Is there a quick way to do this ?
I want to write a macro that will check every selected cell. It should detect if there is a space after the fourth character. If there is a space, go to the next selected cell. If there is no space, add a space and go to the next selected cell.
View 5 Replies View RelatedPretty sure this has been asked but have searched the forum to no avail, but I need to extract the numbers from a value which has a letter on the end.
eg. 1000x I need to get out the 1000
or 2p I need the 2
I have sooooo many values ranging in numbers of digits, so just basic left(A1,2) won't work, I'm sure I've seen a search or find function but don't know how to use them!