Filter Last 9 Digits From 16 Digit Number Within Text
Nov 20, 2012
I have a large file with cells filled with text (converted from a database, imported into Excel). The text is in rows of column A and always contains a 16 digit number, which is what I need. I am able to clean up this text and show only this number, but then Excel shows the last digit as a '0'.
An example of the text I need to filter the 16-digit number from: GIRO 6838657 K MAHMODBETALINGSKENM. 7062542158461684 STORNOADMINISTRATIEVE REDEN 1 ZIE DE TOEGEZONDEN KENNISGEVINGVAN VERHAAL OF CJIC.NL/VZD
I've altered some of the information in here so this is fake. The text is messy but all I need is the number.
This is the macro I use to clean up the text and leave only the 16 digit number:
Sub CleanUp
Dim e As Variant
With CreateObject("VBScript.RegExp")
[Code].....
It sort of works, but when I run it, I get this number as a result: 7062542158461680 (last digit is changed into a zero).
I've been trying to insert this line into the macro but it doesn't work: Columns("A:A").NumberFormat = "@"
How do I change the outcome of this macro into the actual number?
If this is impossible to do, I can also manage if there is a way to filter only the last 9 digits from the 16 digit number. I can work with that, too.
I have 4 and 5 digit numbers. For the 4 digit numbers, I want to be able to distinguish between the numbers by the last digit. For the 5 digit numbers, I want to be able to distinguish between the numbers by the last two digits.
Example: For 4 digit numbers, I would like to do something with all numbers ending in 1, 2, 3, 4, 5, 6, 7, and 8. For 5 digit numbers, I would like to do something with numbers ending in 10, 11, 12, 20, 21, etc.
The first step in being able to do this, I guess is distiguishing between 4 and 5 digit numbers, which I know can be done by the number lenght. However, the second part of looking at the last digit or the two last digits I don't know how to do.
The values in columns b:d range from 000-999. I need a formula that will count the number of digits in B:D that match the 3 values in H1 without counting a digit twice. The existing formula counts a digit twice, like the value in H4.
I have a macro which will import data to the worksheet, then perform some formatting on the data, then assign the month & job description based on the lookup table. The problem is that when I import in the data, the data in column B&C will be store as text instead of number and the date in column E will store a 2 digit year instead on 4 digit year which cause error to my macro. I have try to preset the column format to number, i even try to change the column format to number when i run the format macro data. But the problem is still there.
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I am using following formulae to convert 16 digit number to with validation that number is not exceeding 16 digits and should always start with "1" else it should give Error with 11 blank spaces
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I am wanting to create a VB script that will take a number (in general format) of two or three digits, convert it to text, then make sure that there are enough zeros preceeding the number to make exactly 6 digits. Examples of the initial number (before the macro is run) and the final number (after it is run): ..
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How to calculate a check digit in excel. The details to calculate this are as follows:
All variables in the calculation are positive integers.
We take each integer of the pro number and multiply it by a value and sum them to get a total.
An Example: 8 Digit Pro Number: 66988757 Pro Number: 6 6 9 8 8 7 5 7 Position in the Pro Number: 1 2 3 4 5 6 7 8 Multiply each digit in the pro number by (10-position) in the number, to achieve a sum.
Using our example pro again: 6*(10-1) + 6*(10-2) + 9*(10-3) + 8*(10-4) + 8*(10-5) + 7*(10-6) + 5*(10-7) + 7*(10-8) 6*9 + 6*8 + 9*7 + 8*6 + 8*5 + 7*4 + 5*3 + 7*2 54+ 48+ 63+48+40+28+15+14 = 310 Take the Sum of the previous calculation and divide it by 11 310/11 = 28
(Actually, it's 28.181818, but since we're working with integers, we truncate everything behind the decimal).
Figure a remainder by multiplying the quotient by 11 and subtracting from the sum. Remainder = 310 - (28*11) ---> Remainder = 310 - 308 ----> Remainder = 2 Check Digit = 11- Remainder Check Digit = 11 - 2 ---> Check Digit = 9 Note: if the check digit is 10 or 11, need to subtract 10 from the Check Digit.
This has got to be simpler than I'm making it out to be, but I'm stuck. I have a column that is created by a formula that counts the number of times a name appears in a list and prepends the number to the beginning of the name. The result is something like:
There's got to be an easy way to do this, but I can't figure how to account for the variable number of digits (1 or 2 digits) at the beginning. It would probably work to set up an advanced filter for cells that begin with a number less than 2, but I don't know how to do that.
I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)
I've tried everything I know (which isnt that much to be honest. lol). Ive tried the frequency formula but that doesn't work the way I want it - I think its probably the wrong formula to use. I've also tried a pivot table but they always vex me. If a pivot table IS the way to go, could someone talk me through it step by step? (*the wizard is just as confusing as doing it yourself I find) ....
I wrote an excel program in Excel'03 for a dental office to manage state assistance patients and one of the table columns is the state assistance number. The problem is that the program defaults to a number format when it is entered instead of a text format, which is what I want. The issue is that state assistance numbers are always 8 digits and when it defaults to a number field the program drops the required preceeding zeros.
For example the number 00123456 will sometimes show up as 123456, which is wrong. It's like sometimes it will show up right and other times it gets a butterfly in its brain and deletes those zeros irritating the receptionist here. So, how do I get the table to either stay in text format or set up a number format that keeps the preceeding zeros?
how you can determine if a cel value is a number or a digit
It is actually for a column to determine if it has a heading or not and acordingly y have to count the rows off that "current region" and put some values with a formula next to this column.
Y was testing an expression with this
msg = IIf(target.End(xlUp).Value = "X", "is this a LETTER", "is this a DIGIT")
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or whatever the number is after A1D, but when AK8 = a value of 1 or 2 or 3...... It comes back as A1D1 or A1D2... How ca I keep the two digits in AK8 to stay and put the value the way I want in AE5 ...
I'm trying to figure out how to setup a worksheet to find the most common 2 digit numbers going vertically from the bottom(cold) to the top(hot) it would consist of 90 digits 0 thru 9
each vertical line would be considered weeks 9 thru 1. week 9 would be the first vertical line of digits on the left. it could also contain the most common 2 digits horizontally. Both 2 digit values would be color coded ex. blue equals most common 2 digit horizontally and green equals vertically. I would also like to color code the most common 2 digit value diagonally as long as it is the most common of either the vertical or horizontal 2 digit. Each number is seperate on the worksheet they would not be pairs. im using excell 2003.
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I have a cell with a number which is a result of several previous sums. It's a number with 8 to 11 digits. For example: 878567663.
I need to add each digit of the number, and then add again the result until I end up with a single digit. In the above example it'd be (8+7+8+5+6+7+6+6+3=56), then (5+6=11), then (1+1=2) and put the end result (2) in a cell
My main doubt is that I don't know how to use a simple "do while" type structure in Excel to achieve the above.
Questions:
1.) How do I create a formula to do that?. I have seen solutions in this board that let me add each digit but that's it... I need to "reduce" it until only one digit is left...
2.) What about if the lenght of the number is not always the same (fe. in one cell is 8, in another is 11, the next one is again 8...)?
I am trying to get a formula to return the last digit from a number in a cell as a number.
If the cell (B3) contains a number such as 164 or 34 I want to return a value of 4 and have it be formated as a number.
I have tried =RIGHT(B3,1) and it returns a 4 but I cannot get another formula to recognize it as a number. It shows up in the cell on the left side as text would and if I format it as a number nothing happens it is still on the left and the formula does not work.
I'm trying to search a column that has cells with various length strings. Included in the strange (at random locations) could be possibly be a 7 digit number starting with 4. I want a formula that counts the number of cells with contain that 7 digit number. Is this possible?
