Filter Last 9 Digits From 16 Digit Number Within Text
Nov 20, 2012
I have a large file with cells filled with text (converted from a database, imported into Excel). The text is in rows of column A and always contains a 16 digit number, which is what I need. I am able to clean up this text and show only this number, but then Excel shows the last digit as a '0'.
An example of the text I need to filter the 16-digit number from: GIRO 6838657 K MAHMODBETALINGSKENM. 7062542158461684 STORNOADMINISTRATIEVE REDEN 1 ZIE DE TOEGEZONDEN KENNISGEVINGVAN VERHAAL OF CJIC.NL/VZD
I've altered some of the information in here so this is fake. The text is messy but all I need is the number.
This is the macro I use to clean up the text and leave only the 16 digit number:
Sub CleanUp
Dim e As Variant
With CreateObject("VBScript.RegExp")
[Code].....
It sort of works, but when I run it, I get this number as a result: 7062542158461680 (last digit is changed into a zero).
I've been trying to insert this line into the macro but it doesn't work: Columns("A:A").NumberFormat = "@"
How do I change the outcome of this macro into the actual number?
If this is impossible to do, I can also manage if there is a way to filter only the last 9 digits from the 16 digit number. I can work with that, too.
I use Excel XP (2002) at work.
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May 26, 2006
I have 4 and 5 digit numbers. For the 4 digit numbers, I want to be able to distinguish between the numbers by the last digit. For the 5 digit numbers, I want to be able to distinguish between the numbers by the last two digits.
Example: For 4 digit numbers, I would like to do something with all numbers ending in 1, 2, 3, 4, 5, 6, 7, and 8. For 5 digit numbers, I would like to do something with numbers ending in 10, 11, 12, 20, 21, etc.
The first step in being able to do this, I guess is distiguishing between 4 and 5 digit numbers, which I know can be done by the number lenght. However, the second part of looking at the last digit or the two last digits I don't know how to do.
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Sep 10, 2013
The values in columns b:d range from 000-999. I need a formula that will count the number of digits in B:D that match the 3 values in H1 without counting a digit twice. The existing formula counts a digit twice, like the value in H4.
DIGIT HITSABCDEFGH10,1,2209/09/132192191222309/09/134824821441409/08/131191191112509/08/139799792550609/07/137177171551709/07/138668662000
Excel 2007Worksheet FormulasCellFormulaE2=B2&C2&D2F2=SUM(B2:D2)G2=MOD(F2,10)H2=SUMPRODUCT(--ISNUMBER(FIND(","&$B2:$D2&",",","&H$1&",")))E3=B3&C3&D3F3=SUM(B3:D3)G3=MOD(F3,10)H3=SUMPRODUCT(--ISNUMBER(FIND(","&$B3:$D3&",",","&H$1&",")))E4=B4&
[Code] ......
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Dec 23, 2008
I have a macro which will import data to the worksheet, then perform some formatting on the data, then assign the month & job description based on the lookup table. The problem is that when I import in the data, the data in column B&C will be store as text instead of number and the date in column E will store a 2 digit year instead on 4 digit year which cause error to my macro. I have try to preset the column format to number, i even try to change the column format to number when i run the format macro data. But the problem is still there.
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Jul 16, 2008
I need a way to display all 8 digit numbers that have the digits 1-8 in them. (ie. 12345678 but NOT 12345679 OR 12345677) Also If I could somehow divide by 13 then check for whole numbers
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Nov 25, 2011
I am using following formulae to convert 16 digit number to with validation that number is not exceeding 16 digits and should always start with "1" else it should give Error with 11 blank spaces
(IF(LEN(L2)+LEFT(L2)=17,TEXT(L2,"0000000000000000"),"ERROR"&REPT(" ",11))))
but when I input any number which has a value other than zero e.g. 1009510010000059 its returning result as 1009510010000050 I need validation also in the same formulae
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Feb 26, 2011
I need creating a tool for numerology.
Every alphabet from a to z has a number associated with it.
A = 1, b 2 , c = 3 etc
Numeric Values for Each Numeral
A1N5
B2O7
C3P8
D4Q1
E5R2
F8S3
G3T4
H5U6
I1V6
J1W6
K2X5
L3Y1
M4Z7
I can either use excel or access or write this.
Example 1 , r = 2 , I = 1, L = 3. .
If I write RIL in column 1 , column 2 should say 213 and column 3 should add 2+1+3 and display 7.
Example 2:
Col 1 = Infosys Ltd
Col 2 should say 1587313 344
Col 3 = 1 + 5 + 8+ 7+ 3+1+3 3+4+4 = 39 , 3+ 9 = 12 , add 1+2 = 3
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Jun 22, 2014
I have a column that has section numbers like 001.002.006.003.010.011.002.
I would like to divide that single column into seven columns with only the single or double digit in it, ie
1 in a cell
2 in a cell
6 in a cell
3 in a cell
10 in a cell
11 in a cell
2 in a cell
Have been using MID and FIND togther, but when I get to the double digits like 10 an 11 I run into problems.
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Apr 3, 2008
I know you can take a number from one cell and combine it with number from another cell and make it one number. What I need to do is the reverse. Take a two digit number in a cell and separate it into single digits in two cells. If you have the number 50 in a cell, then is there a formula that will take the 5 and put it in cell and take the 0 and put it in the cell beside it?
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Mar 4, 2009
I am wanting to create a VB script that will take a number (in general format) of two or three digits, convert it to text, then make sure that there are enough zeros preceeding the number to make exactly 6 digits. Examples of the initial number (before the macro is run) and the final number (after it is run): ..
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Mar 2, 2009
I have a column of 6 digit numbers in excel, and I need to remove the last digit from each number, turning it into a 5 digit number. No rounding, just simply remove the last digit. Each number is different. Does anyone know how to quickly and efficiently remove the last digit from each number? I can convert to alphanumeric string if need be...
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Oct 31, 2008
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
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Jun 13, 2014
How to calculate a check digit in excel. The details to calculate this are as follows:
All variables in the calculation are positive integers.
We take each integer of the pro number and multiply it by a value and sum them to get a total.
An Example: 8 Digit Pro Number: 66988757
Pro Number: 6 6 9 8 8 7 5 7
Position in the Pro Number: 1 2 3 4 5 6 7 8
Multiply each digit in the pro number by (10-position) in the number, to achieve a sum.
Using our example pro again:
6*(10-1) + 6*(10-2) + 9*(10-3) + 8*(10-4) + 8*(10-5) + 7*(10-6) + 5*(10-7) + 7*(10-8)
6*9 + 6*8 + 9*7 + 8*6 + 8*5 + 7*4 + 5*3 + 7*2
54+ 48+ 63+48+40+28+15+14 = 310
Take the Sum of the previous calculation and divide it by 11
310/11 = 28
(Actually, it's 28.181818, but since we're working with integers, we truncate everything behind the decimal).
Figure a remainder by multiplying the quotient by 11 and subtracting from the sum.
Remainder = 310 - (28*11) ---> Remainder = 310 - 308 ----> Remainder = 2
Check Digit = 11- Remainder
Check Digit = 11 - 2 ---> Check Digit = 9
Note: if the check digit is 10 or 11, need to subtract 10 from the Check Digit.
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Jul 8, 2003
I tried every filter function I know of, to no avail, and am yielding my stupidity to the forum. I have this series of numbers as an example:
456912
789547
785171
658712
968712
369874
258741
127812
All I want to filter is all values ending with 12.
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Jan 15, 2014
This has got to be simpler than I'm making it out to be, but I'm stuck. I have a column that is created by a formula that counts the number of times a name appears in a list and prepends the number to the beginning of the name. The result is something like:
A1:
1JohnSmith021488
2JohnSmith021488
1JaneDoe102187
2JaneDoe102187
3JaneDoe102187
4JaneDoe102187
5JaneDoe102187
6JaneDoe102187
7JaneDoe102187
8JaneDoe102187
9JaneDoe102187
10JaneDoe102187
11JaneDoe102187
I need a filter that results in a list of names preceded by "1" (but not 10, 11, 12, etc.) The correctly filtered result of the above list would be:
DESIRED:
1JohnSmith021488
1JaneDoe102187
My autofilter searches for data that begin with "1", so instead of the above result, I get:
UNDESIRED:
1JohnSmith021488
1JaneDoe102187
10JaneDoe102187
11JaneDoe102187
There's got to be an easy way to do this, but I can't figure how to account for the variable number of digits (1 or 2 digits) at the beginning. It would probably work to set up an advanced filter for cells that begin with a number less than 2, but I don't know how to do that.
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Jul 16, 2009
I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)
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I've tried everything I know (which isnt that much to be honest. lol). Ive tried the frequency formula but that doesn't work the way I want it - I think its probably the wrong formula to use. I've also tried a pivot table but they always vex me. If a pivot table IS the way to go, could someone talk me through it step by step? (*the wizard is just as confusing as doing it yourself I find) ....
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Feb 12, 2009
I wrote an excel program in Excel'03 for a dental office to manage state assistance patients and one of the table columns is the state assistance number. The problem is that the program defaults to a number format when it is entered instead of a text format, which is what I want. The issue is that state assistance numbers are always 8 digits and when it defaults to a number field the program drops the required preceeding zeros.
For example the number 00123456 will sometimes show up as 123456, which is wrong. It's like sometimes it will show up right and other times it gets a butterfly in its brain and deletes those zeros irritating the receptionist here. So, how do I get the table to either stay in text format or set up a number format that keeps the preceeding zeros?
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Feb 6, 2013
I have a number, eg, 1234567 and rounded to prepare the shrink of the size of the number like
= Round(a1, -3). I have, say now, 1234000.
I need to strip "000" from the number and place 1234 to a cell.
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Jun 22, 2006
how you can determine if a cel value is a number or a digit
It is actually for a column to determine if it has a heading or not and acordingly y have to count the rows off that "current region" and put some values with a formula next to this column.
Y was testing an expression with this
msg = IIf(target.End(xlUp).Value = "X", "is this a LETTER", "is this a DIGIT")
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Jun 9, 2014
Well I want to add few numbers in a few number for example I have ten columns containing few cell numbers and i want to add 92 my country code with it. I have tried this by using replace formula but in result it comes in text format from which i cannot use another formula unless text format is removed and for that i have to do it one by on in every single cell. I have attached a sample sheet.
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Dec 13, 2013
I have the following dates in a column and need to convert them to the short date format:
91113 (Sept 11, 2013)
100713 (Oct 07, 2013)
122612 (Dec 26, 2012)
40413 (April 04, 2013)
Those are just some examples. When I convert these as is I get dates that are really far in the future. Some dates are 5 digit and some are 6.
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Aug 19, 2014
I have the following
[Code] .....
AK5 value will be 2 - 21.
I need it to display
A1D05
or
A1D21
or whatever the number is after A1D, but when AK8 = a value of 1 or 2 or 3...... It comes back as A1D1 or A1D2... How ca I keep the two digits in AK8 to stay and put the value the way I want in AE5 ...
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Jan 26, 2009
I'm trying to figure out how to setup a worksheet to find the most common 2 digit numbers going vertically from the bottom(cold) to the top(hot) it would consist of 90 digits 0 thru 9
it would look like this
4 0 3 9 0 4 3 3 2
9 2 5 6 5 6 9 6 6
8 9 9 3 1 0 2 9 8
1 6 7 5 9 9 8 2 5
2 7 2 2 2 8 5 1 3
0 1 4 7 4 7 6 0 9
3 5 6 4 3 3 0 4 4
7 8 8 1 8 5 7 8 7
5 4 1 8 6 1 1 5 1
6 3 0 0 7 2 4 7 0
each vertical line would be considered weeks 9 thru 1. week 9 would be the first vertical line of digits on the left. it could also contain the most common 2 digits horizontally. Both 2 digit values would be color coded ex. blue equals most common 2 digit horizontally and green equals vertically. I would also like to color code the most common 2 digit value diagonally as long as it is the most common of either the vertical or horizontal 2 digit. Each number is seperate on the worksheet they would not be pairs. im using excell 2003.
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Jun 26, 2009
The last digit of a number (can be any demonination but always an integer). I know that you can check the last digit of a number with =RIGHT(A1,1) but I would like to check whether the last digit in number is 1,2,3,4,5 and if so change the whole number to a number ending in 5. If the original number ends in 0,9,8,7,6 then I want it to be changed to end in 9. Is this possible and if so is there an excel function that I could use??
e.g. 143 -> 145
e.g. 1037 -> 1039
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Oct 17, 2006
I have a cell with a number which is a result of several previous sums. It's a number with 8 to 11 digits. For example: 878567663.
I need to add each digit of the number, and then add again the result until I end up with a single digit. In the above example it'd be (8+7+8+5+6+7+6+6+3=56), then (5+6=11), then (1+1=2) and put the end result (2) in a cell
My main doubt is that I don't know how to use a simple "do while" type structure in Excel to achieve the above.
Questions:
1.) How do I create a formula to do that?. I have seen solutions in this board that let me add each digit but that's it... I need to "reduce" it until only one digit is left...
2.) What about if the lenght of the number is not always the same (fe. in one cell is 8, in another is 11, the next one is again 8...)?
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Feb 4, 2010
I need composing a formula that will add a space after every 4th Number in a 16 digit Character Set.
ex. 0101 0101 0101 0101
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Jul 13, 2009
="autECLSession.autECLPS.SendKeys """&B4*100&""""
B4 is 3.00% and I need it to be 03 no %, 3.00%*100= 3 but I need anything less then 10 to be two digits still (1-9)
This would be the perfect end result:
autECLSession.autECLPS.SendKeys "03"
and for over 10
autECLSession.autECLPS.SendKeys "10"
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Feb 20, 2010
I am trying to get a formula to return the last digit from a number in a cell as a number.
If the cell (B3) contains a number such as 164 or 34 I want to return a value of 4 and have it be formated as a number.
I have tried =RIGHT(B3,1) and it returns a 4 but I cannot get another formula to recognize it as a number.
It shows up in the cell on the left side as text would and if I format it as a number nothing happens it is still on the left and the formula does not work.
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Oct 14, 2013
I'm trying to search a column that has cells with various length strings. Included in the strange (at random locations) could be possibly be a 7 digit number starting with 4. I want a formula that counts the number of cells with contain that 7 digit number. Is this possible?
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