Display All 8 Digit Numbers That Have The Digits 1-8 In Them
Jul 16, 2008
I need a way to display all 8 digit numbers that have the digits 1-8 in them. (ie. 12345678 but NOT 12345679 OR 12345677) Also If I could somehow divide by 13 then check for whole numbers
I know you can take a number from one cell and combine it with number from another cell and make it one number. What I need to do is the reverse. Take a two digit number in a cell and separate it into single digits in two cells. If you have the number 50 in a cell, then is there a formula that will take the 5 and put it in cell and take the 0 and put it in the cell beside it?
I have a large file with cells filled with text (converted from a database, imported into Excel). The text is in rows of column A and always contains a 16 digit number, which is what I need. I am able to clean up this text and show only this number, but then Excel shows the last digit as a '0'.
An example of the text I need to filter the 16-digit number from: GIRO 6838657 K MAHMODBETALINGSKENM. 7062542158461684 STORNOADMINISTRATIEVE REDEN 1 ZIE DE TOEGEZONDEN KENNISGEVINGVAN VERHAAL OF CJIC.NL/VZD
I've altered some of the information in here so this is fake. The text is messy but all I need is the number.
This is the macro I use to clean up the text and leave only the 16 digit number:
Sub CleanUp Dim e As Variant With CreateObject("VBScript.RegExp")
[Code].....
It sort of works, but when I run it, I get this number as a result: 7062542158461680 (last digit is changed into a zero).
I've been trying to insert this line into the macro but it doesn't work: Columns("A:A").NumberFormat = "@"
How do I change the outcome of this macro into the actual number?
If this is impossible to do, I can also manage if there is a way to filter only the last 9 digits from the 16 digit number. I can work with that, too.
I have 4 and 5 digit numbers. For the 4 digit numbers, I want to be able to distinguish between the numbers by the last digit. For the 5 digit numbers, I want to be able to distinguish between the numbers by the last two digits.
Example: For 4 digit numbers, I would like to do something with all numbers ending in 1, 2, 3, 4, 5, 6, 7, and 8. For 5 digit numbers, I would like to do something with numbers ending in 10, 11, 12, 20, 21, etc.
The first step in being able to do this, I guess is distiguishing between 4 and 5 digit numbers, which I know can be done by the number lenght. However, the second part of looking at the last digit or the two last digits I don't know how to do.
The values in columns b:d range from 000-999. I need a formula that will count the number of digits in B:D that match the 3 values in H1 without counting a digit twice. The existing formula counts a digit twice, like the value in H4.
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I work in a finance department and we have MANY numbers consisting of 7 digits. Is there a way to enter in the entire number, but only display the first 4 digits?
i have 2 coulmns in a listbox. The columns cant display more than 11 digits. So basically it would look like this 1.23456789E+12. I even tried playing with the Columnwidth but that didnt work.
I am trying to display the results that i get in excel sheet in a userform using textboxes; I need to round off the digits in these textboxes so as to display 2 digits after decimal point! I would like to have the code to solve this problem!
Need to display time in total minutes but with a space after every 3 digits.
For instance, I can display 0.833333 as total minutes by using the custom number format [m] which displays 1200. But I need it to display as 1 200. I know with a standard number, I could use # ##0 but I don't know how to get both of these custom attributes to work simultaneously.
I have a column that contains 4 digit numbers that I want to convert to a text value. Here is my example
Number Text Value 7004 RBPA 7002 DCVA 7001 PVBA .....etc.
There is a total of 10 different number values. I want to include the conversion vba into an existing macro that is performing other functions on the spreadsheet.
using Excel 2007, windowsXP, and am trying to find the right formula for the following problem.
I have a column of 3 digit numbers, and want to determine how many times a number occurs in the first position ie: 123 the second position ie: 123 and the third position ie: 123 in the entire column of figures?
I wanna create a buildin check digit for container numbers
so it will exists out of 11 cells. ( GATU 021097-9 )
is it possible when u type any letter/number in the first cell on a row it automaticly jumps to the next cell, repeating this for the full container number ?
I have a spreadsheet, with about 1,500 lines. In column A is a list of numbers that I need to remove the last digit from each number, for example in A22 is 02602726521 - I need this to be 0260272652. The numbers are all uniqe.
How can I remove the last digit from every number, without going in manually to do so?
Is there any way changing general four digit number into hours and minutes?
I have almost 31000 rows of imported data, showing arrival and departure times with four digits (dep 2130, arr 0130) without colons and I need to subtract dep from arr to get block hours. Is there a way to add colon to multiple cells or some other solution to my problem?
Adding colon to 62000 cells one by one does not sound that good to me.
I have a excel file, I need to remove the first two digits if they are certain numbers, such as 12. For example, if the number is 12987654, then I need remove 12, and it will be "987654" , but if it is not 12 in the first two digits, then keep it no change, for example if it is 345678, then keep it.
I barely work with Excel formulas, now I need connect the excel file with my Database table. I need to make the file matches the DB.
I have a unique 6 digit number in a column. I have 2500 rows. I need to cut the first three numbers only leaving the last 3 numbers in the column for each row.
Example: 112345 234325
I would need 112, and 234 deleted. Checked the forum and cannot get quite what I want.
I have a column with numbers in about 500 rows. The entries are 5 numbers long and others 8. So I thought i could use one of the following: A macro code to tell a cell to delete the first 3 numbers if the entry is 8 numbers long?
OR
A macro code to tell a cell to reduce itself to 5 digits long starting from the right? Attached is a small example
given the number set how many times does the number 5 show up in the 4th digit. I know its 3 but for the data size I need to run it on, it is impossible to count.
What function would count how many times a certain number shows up in the same spot?
I have a userform for keeping records and would love to incorporate a new feature. I would want to generate a random serial number for each entry made with the userform.
I've modified this macro I found on this forum, all it does is compares 2 lists of 6 digit serial numbers and and then tells me which numbers are in list 1 that are not in list 2.
However, I want to modify it so that it also gives me the numbers in list 2 that are not in list 1 (put into column F). I then need it to cut the matching serial numbers (in columns A and B) from sheet 1 and paste them into sheet 2.
modifying the following VBA code; this code auto-generates 4-digit unique numbers, using zero as one of the starting digit as well. I need the 4-digit numbers NOT to begin with a zero, the 4-digit numbers should only begin with numbers 1-9.
Private Sub Worksheet_Change(ByVal Target As Range) Dim Cell As Range Dim Test As Integer
I have a large list of phone numbers & some of the numbers do not have area codes. The area code is the same for all numbers. Is there a way to add the area codes to all of these numbers without keying all in manually