Find The Next NULL Value And Delete Remaining Column
Feb 4, 2010
I am paste valuing from one sheet to another. The size of the data changes each time so to manually delete all Null cells is a pain.
If I do not delete them it sucks up 3 megs of space. I have searched the board several times looking for a solution, lots of discussions but no solutions.
It would be great if I could find that first cell that contains the Null string and then delete the cells remaining in the column. Any suggestions would be greatly appreciated.
In the code below I find rows containing "$$ #" at the far left and process it. For all the remaining rows I want to delete the entire row, my macro only deletes some rows. Obviously I am not grasping something about looping throught the rows to delete unwanted data.
So I want to add some VBA Code that deletes specified columns and then insert Bolded Column headers to the remaining columns. The columns I want deleted are D,F,I,J,K. For simplicity purposes, the column headers would be A,B,C,D,E,F,G.
I tried using Columns("D,F,I,J,K").delete but I kept on getting 13 error.
I am building a template ("Table") that will import data from 4 other spreadsheets and then format the data once its all in the template. I need to delete all rows where a name didn't import. The names are landing in column B (starting with B22), so I set up my code using an active cell loop macro to examine each cell to see if it was empty, and then to delete the row if it were. I've tried 4-5 iterations of code but nothing is working correctly.
Apparently when the fields are copied over from the other spreadsheets, some empty cells actually have something in them such that they are not completely blank. What syntax I can use so that I capture every instance of a blank/empty cell and delete that corresponding row? Some of the code I've tried is below.
I need a macro to find the last cell in the column, then copy the formula to the next blank cell. Then, it goes back to the last cell (above) and paste's values. Then, go to the next column and repeat the process. I can do this but have to call each cell separatly...however, I would like to do it in a loop to simplify things. It would be great to even be able to just set the start and ending columns. Here is my current code:
Dim rng As Range, aCell As Range Set rng = Range("C8, D8, E8, F8, G8, H8, J8, K8, L8, M8, N8, O8, P8, Q8, R8, S8, T8, U8") For Each aCell In rng Selection.End(xlDown).Select Application.CutCopyMode = False
[Code] .......
It does not go to the next column, instead it stays in the same column and repeats the process.
I am looking for a method which would delete empty cells in a row, and then shift the remaining data to the left (filling the cells with data). I know that this could be done manually, but I need it completed for 3000 rows! I have attached a simple sheet to show what I'm Looking for.
The code should go through each worksheet and if the row in column A has a null value or 0, then delete the row. The count is based off of column T. The row deletion portion of the code works, but something is wrong with my worksheet looping structure.
1. Find the last row (cell) of data in the "Customer Number" column. This search should be by the name "Customer Number" rather than by column letter because the column that "Customer Number" will be in can change.
2. Find the column named "Purple" (also by name for same reason)
3. If the "Purple" column has no blank cells in those same number of rows as the "Customer Number" column, delete the whole "Purple" column.
A column (A1:A60) is being progressively filled in with numbers, and occasionally some blank cells are between.
I need a formula to work out the number of the remaining cells (that are yet to be filled in) from the last entry till the last cell (A60) of the column.
I have searched high and low for a more efficient macro than the current loop i have. I have a range that varies in size but always follows the same format. After i reach a certain value output from a formula, "4", I want to delete all lines below that line. So I want to find value "4" then move one row down and delete all lines to line 2004. I have attached the macro that i compiled but it takes a couple of minutes to run.
Sub manual() Dim Firstrow As Long Dim Lastrow As Long Dim Lrow As Long Dim CalcMode As Long Dim ViewMode As Long With Application CalcMode = .Calculation .Calculation = xlCalculationManual . ScreenUpdating = False End With With ActiveSheet .Select ViewMode = ActiveWindow.View ActiveWindow.View = xlNormalView.................
The idea is that i have several monthly data in columns. I also have a subtotal column that can be a "Total Trim I", "Total Trim II", "Total Trim III" or "Total Trim IV". I also have a yearly total: Jan Feb Mar Total Trim I Apr May Jun Total Trim II Total 2005
I wanna cut the "Total Trim I" column, paste it after the Yearly Total and cut and paste the "Total Trim II" after the "Total Trim I" column for every year... It'll look like this: Jan Feb Mar Apr May Jun Total Trim I Total Trim II Total 2005. But not every trimester has 3 months... I've been thinking about a find function but i have troubles with the implementation.
I have a file here included which has 8 + columns. I normally have to go through each column and find when the references start and delete everything below it. If i could have a macro find where the references start in each column and delete on down that would be a huge time saver.
#REF! #REF! #REF! #REF!
Thats the example of the reference i run into, i was thinking of a macro to find where the REF starts and delete that cell and everything on down.
My code is always failing on the findnext method. I'm thinking that the findnext method fails because it loses it's cell reference when the row gets deleted.
Sub findwbs() Dim rngFind As Range Dim strFirstAddress As String
I need a quick macro I can run to hide the columns if the formula result for cells B1:AA1 is "" (null) instead of text. This runs explicitly on Sheet2. Array VBA is still geek to me.
I am finding that I am using the 'go to' option frequently in my macros, but I feel very limited by the options that I have (I need to learn VB-I know) I would like primarily to discover how to select the last cell containing anything (not including blanks like the 'last cell' option in the edit>go to) within a selected row. Ideally, I would like a formula to fill downward a given amount of rows so as to prevent myself from having to fill them all the way down to the end of the spreadsheet (therebye making the file to large). Also, If anyone could guide me to a resource at which I can find similar commands.
I want to search a range set in column a. from a1 to a200. When it finds a cell that has some sort of value in it (for example cell a29) i want it to take what is in cell a29 and set sell z1 = to whats in a29 and then continue searching for other cells that are not null in column A.
See attached doc "Find and Delete.xlsx". Inside, the value in F12 is a very important cell. Using the text value from F12, I first want to use visual basic code to find the range in column B because it will vary. This means the 'text words' column might have 50 words or it might have 2000. I have racked my brain trying to find a universal way to find a variable range.
Then I would like to search for the exact text value within this range in column B. For example, in F12 is the text word 'windows xp registry cleaner' and you can see that this value is in B9. There will only be one exact match in column B.
I then would like the vb script to delete and remove this found value, then move left one space in column A to also delete the ID number associated with the text word. Then shift both rows up to fill the empty gap. I have tried numerous different codes but to be honest, I'm not really sure what I'm looking for. I've tinkered with find and replace, vlookup, match, find, search, and many more.
I am trying to move through the worksheets and delete all columns with "Accession" in contained in them. I have to do this with an external macro as the spreadsheet with the data is created from another program. I tried this and get an 'Object or With block variable not set' error and the debug highlights the Cells. Find line of the code.
Also, the number of columns could be variable within the spreadsheet as it is compiled by the other program.
Sub DelAccessionNum() Dim Wrkst As Worksheet For Each Wrkst In ActiveWorkbook.Worksheets Cells.Find(What:="Accession", After:=ActiveCell, LookIn:=xlFormulas, LookAt:= _ xlPart, SearchOrder:=xlByRows, SearchDirection:=xlPrevious, MatchCase:=False _ , SearchFormat:=False).Activate On Error Goto Completed: Selection.EntireColumn.Delete Shift:=xlToLeft Completed: Next End Sub
Why my code is not working. I am working with Excel 2010. It will only delete the column on the active spreadsheet and not go to next worksheet. Not all worksheets contain the word "Broker".
[Code] ......
Not sure if its something to do with Activecell, try After:=ws.cells(1,1) or passing it in as the active cell stays the same i think.
I am not the best at this, but we recorded a macro and we want to delete whole rows after we 'control' find something from a specific column. WHen we recorded our macro, it finds the first instance and we hightlight the whole row and 'control' 'shift' 'end' and delete all of the rows. We did this because we sorted and made sure the information we wanted to delete was at the bottom of the worksheet. we realized that each day the spreadsheet we pull from an ip address gets bigger and the row that we started from to delete starts on a different row each day. How do we get all the information to delete everyday, even when the row that Owned starts on changes? ...
I want to do, is search column A for claim numbers that match. When I do have a matching claim number, I want to concatenate the original cells ownership field with the said matching cells ownership field (or move into a column in the same row, I can always concatenate later). Once that is complete, I want to delete the row I took the information out of.
I want to join this data in ArcGIS, but as of right now, it's not a 1-to-1 relationship, so only a relate works. That doesn't help me as I want to display claims by ownership, and this can vary per claim. Company A may have 100% on one claim, and then split another claim 50% with Company B.
This causes a double entry on the claim field in this current spreadsheet I have, which requires me to clean it up by making multiple columns of ownership vs. an additional row for shared ownership.
My problem:
Column A Column B 1235555 Company A (50%) 1235555 Company B (50%) 1235556 Company A (100%) 1235557 Company A (33%) 1235557 Company B (33%) 1235557 Company C (33%)
What I would like to see
Column A Column B Column C Column D 1235555 Company A (50%) Company B (50%) 1235556 Company A (100%) 1235557 Company A (33%) Company B (33%) Company C (33%)
There are groups of similar ID numbers in Column J. For a group of similar ID numbers in consecutive rows there is only one row that has a number greater than 0 in its Column L cell and the rest of the cells of Column L for that set of similar IDs is filled with 0s.
First for that unique ID group I need to find out which row is it that has a value greater than zero in its Column L cell.
Then I need to use that value to fill the rest of the 0s in Column L corresponding to that set of Unique IDs.
The process continues with identifying similar IDs in Column J and this time doing the same thing for their Column M. I have attached a sample file that shows the data and how the results need to look like.
I would like a macro to find the columns named "apple" and "peach" and delete them. These would always be in row 1 but would always be in different column letters which is why I want the macro to simply find these columns by their name and not by their column letter.
And yes, I do mean the entire column altogether, shifting entire columns to the left. Wipe it off the face of the earth
