Finding Duplicates - Variation On Previous Threads

Jul 9, 2013

I have a list of text values in column X. I need to come up with a formula in column Y.

X
Y (RESULTS OF REQUIRED FORMULA)
Comment
1
HAT
1
First HAT in column
2

[Code]....

I can't play about with the natural order of the spreadsheet, so there's no chance I can re-sort the data into column X and (easily) identify the duplicates that way. So, it could be that the duplicated value(s) will appear in any cell within that column.

I need to identify whether the item is a duplicate in the unsorted list. Ideally, the first entry of a set of duplicates will be given 1, then the subsequent duplicates themselves given a 0 (zero). It's to subsequently do some counts on.

I guess that as long as the one of the entries in the duplicates is marked with a 1, while the others are 0 (zero), that's all that's important.

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The basis of my needs is to be able to find in a list of names, a duplicate name from previous list and then grab and populate a number from that row. Here is an example

A B C D
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Smith,John $700 $100 $600
Wilson,Alan $1500 $1500 $0

I update the list, some names are added and others taken away. When I add the new list, column C of every name is $0. I want the formula to find names from the previous list and populate Column C with the value of Column C + D of the corresponding name. Also I have a separate formula that simply is D=(B-C) The result of what I would want this to look like is this...

A B C D
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Doe,John $500 $0 $500
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As you can see there was a new name added to the list (Doe,John) and a name taken away from the list (Wilson,Alan). Column C is the only Column that I am wanting to auto populate. The Value in Column B is a variable that is managed by another program so you don't have to worry about that.

Keep in mind there will be multiple instances of this list and the same name will occur more than once in the spreadsheet. There are not duplicate names that are different customers though as my other program takes care of that. eg. "Doe,John" and "Doe,John #2". I only want it to grab the information from the previous list not ones previous to that list(if that makes sense) third example...

A B C D
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Doe,John $500 $500 $0
Miller,Joe $700 $0 $700
Smith, John $1300 $1000 $300

My current method of accomplishing this is to select the previous list and print it. I then go down the new list and cross reference it with the old one keying in the values by hand. This would be a huge time saver as the list is 250 names and growing. I hope I have given enough information but undoubtedly I have not. So feel free to ask me any questions and for more details. I did not want to go to in depth for fear of my post being to long.

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-19
etc.

The "Increase" is a simple =B4-B3 etc. But, there is a problem...

Say for example a member of staff is ill one day and therefore doesn't take any calls, I end up with a 'blank' cell in column 'B'...

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IDUTCDepth (FT)
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315:56:285
415:56:285.4
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I have a workbook that I want to find if I have any duplicate numbers in a specific area.

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I am checking for numbers between 95 and 800. These are all ID# of individuals and not all the numbers between 95 and 800 are used. IE: 97 through 100 are not used ect.

I have already written a macro that does something else and I can use it to check each number as it comes up. However, once the number comes up I don't know how to use it to check the area.

If I can check all the area at one time to find duplicates it would be easier.

I do not know how to do either way but I can adapt my macro to whatever way is possible.

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way to wrap or format anything in this post. I dont think the text I put here is code, but I want to be sure, after receiving a moderators infraction for failing to properly wrap code in a previous post.

Now:

I have a wks in which the first column is a list account #'s and the folowing columns are specifics of transactions or interactions.

Lets say it is a movie rental customer list that lists each rental, and column "A" is the customer number, column "B" declares if it was returned late.

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SV10000000@@1
SV10000000@@2
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This should be an easy one, it has slipped my mind.

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[code]...

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