Finding The Position Of A Value In An Array
Jun 4, 2009I am aware that you can use Match to find the position of an entry in an array, and the following code works as expected, returning an index of 4:
View 2 RepliesI am aware that you can use Match to find the position of an entry in an array, and the following code works as expected, returning an index of 4:
View 2 RepliesI have an array that I want to go through several times. I want to try something like this:
[Code] ......
I cant just say "If Val < 7 Then" because it will spit out the string where "Val" is.
I know that I could create another variable like so:
[Code] .....
but this doesnt seem like an elegent solution...
Possible to find the position of the 1st number value inbetween text??
example : GBB_5600_OPP_WNN
1-Using the Date-Time data in cell “T3” find the cell in column “A” that has the same Date and time.
2-Position the cursor in column I of the same Row.
3-End
In the example giving the Date-Time in “T3” is: 07/03/2008 17:15:00. The Cell in column “A” that has this same Date-Time is: “A97”. The cursor should then be positioned in Cell “I97”.
Title should read: Finding the nth Occurrence of a character within a text string
I have a very long text string that is delimited by about 50 "/" to segment certain values within the text string. I want to be able to extract the text between the 33rd and 34th occurrence of "/". How to do this?
if i have an array myarray=array("MA","PA","CA")
is it possible to go down a row and if it said "MA" then return 0 or if it said CA return a 3 the number of the array position
The list at the left is the data (A1:F1900) in the middle the table (is like a parking lot - place number), and in the right is the swap results, I mean if I put the table in front of the list, and want to know what place number 2 was before, I can see was in the position 7 in the table, next #6 was in 8 and so on, see the example:
Code:
2
6
25
31
37
50
1
2
3
4
5
6
[Code]...
when I go to swap the second line I mean 2-6-11-18-etc. the table has to move one cell down like this.
Code:
2
6
25
31
37
50
[Code]...
and for the next number, the same thing, the tabe go down one place and according from the new position swap the numbers.
The position talbe is on H:M from 1 to 500, I don't write H1:M500 because remember this table go down one row every time, and the results in O:T; well at least I don't find another way to explain.
find a formula that would act as a vlookup but would look up and return a value even if it is not on the first position within the array. I have an SAP export that has on Column A the batch number and on column B the item description. The thing is that within the multiple batch number arrays it allocates on column B the item description only for one row and randomly (sometimes first, last or in the middle).
View 6 Replies View RelatedIs there a function that returns the position (numberical order) of a cell within an array?
View 9 Replies View RelatedWhat I'm trying to do is generate a 2D array of values in VBA from data in a spreadsheet. (Array is not pulled from sheet)
What I would like to do next is look at each row or column of the 2D array and find the max value. I've tried using the worksheetfunction.MAX to no avail.
How do i find the length of an array, which has been declared as
VB : Dim abcarray() As Variant
i have a sheet in template i use in preparing bid packages for electrical installations.it relates to locating in a (building) grid the locations of the motor control (mcp) and power panels (cdp).my desire at this point is to find a way to local a unique value (mcp or cdp) in a 2d grid and then return the column and row names from the same grid. eventually this information will populate a table of all the mcp's and cdp's with their locations.
my sticking point appears to be finding a unique value in a 2d table. this value can be anywhere in the table, not just the first column.
i've tried the lookups and index/match. match fails when i extend the lookup_array beyond the first column.
not sure if this is even possible.
Very simple problem. I need the second highest value in an array. Max gives me highest. Min gives me lowest. I need a kind of a MAX2 function.
View 3 Replies View RelatedI have list of strings to be searched in column A2 to A150 (A1 has column title). The array that needs to be searched is in B2 to AG1000 (B1 to AG1 has column title). I want each string in column A to be searched in the full array. If match is found the corresponding column title (B1 or C1 and so.) and cell address needs to written to a new result columns in AY and AZ. it should work for duplicates as well i.e. the string can be in all the columns of array from B to AG. and all of them needs to be written to result column.
View 9 Replies View RelatedI have been trying to set up a macro to find the Minimum and Maximum values from an array of temperatures for painting... so far, partially successful.
The problems I am having are that the values have 1 decimal place and can be anywhere between 22.7 to -1.4. When they come they are put on the spreadsheet, the MinTemp can be 10.0 and MaxTemp 9.9, totally reversed.
Dim Info(2000, 2) As String
Dim MonthValue(31, 9) As Variant
Dim Working1 As Date
Dim I As Integer
Dim J As Integer
Dim Tot As Integer
[code]....
Is there a way to find data in an array similar to the way match, index or vlookup is used for data in cells of the spreadsheet?
Example, if I have a 2 dimensional array:
1 apple
2 orange
3 pear
4 banana
5 grape
and I want to know if the word "banana" exists in the second column of the array, is there code that would determine if it was in there at all, and is there code that would determine that it was item 4 in that array?
I'd like to know if exist a procedure/ function to find a argument in an array and return the index/address of the argument at the array.
For example, I have a array contaning a list of products. i'd to create a function that finds the index of a particular/list of products, feeded as arguments, and returns the indexes locations.
I'm setting up an Excel (2000) sheet to record the results of a competition at my local photographic society. I'm trying to make it as simple as possible to fill out by the people using it, so have shaded the cells that require the user to put data in. I'll post a screenshot of the sheet, which is named "DPI", to make it easier:
(EDIT) screenshot removed - see attached file in post #3 below instead
I use one row for each member entering the competition. Each member can submit up to three photographs for judging. The names in B5:B30 are tied to the member number in A5:A30, and pulled in with VLOOKUP from a separate sheet containing all the club's members. The names in this example are, obviously, fakes. ;-)
The three blocks are to enter the image titles and associated scores. I have a range called "scores" which is defined as =DPI!$D$5:$D$30,DPI!$G$5:$G$30,DPI!$J$5:$J$30
The rank columns are simply calculated using the RANK function. E.g. the formula in E5 is =IF(ISBLANK(A5),"",RANK(D5,scores,0))
The cells at the top are calculated using the LARGE function upon the defined range "scores" (although they could equally use the SMALL function on the rank columsn instead).
The bit I'm stuck at is what I want it to say along the top. eg: "Leg 1 Winner: 30 is {insert image title} by {insert member name}"
Using the winner as an example, I want to take the winning score shown in D1, find it in the named array "scores", and return the image title to the left of it. Obviously I can't use VLOOKUP as the data is to the left of the lookup value as well as being in multiple columns. I wanted to use OFFSET to return the value of the column to the left, but to do that I need to pick up the reference of the cell containing "30" i.e. the winning score shown in cell D1.
How can I find this cell reference? Or is there a better way? I thought about the old MATCH/INDEX function, but INDEX doesn't seem to work very well with data in non-contiguous arrays as I'd have to specify which block to look in.
Once I can get the image title returned I hopefully sholdn't have any bother extending it to return the member name from a fixed column, but I can't figure out how to get the reference of the cells in the "scores" array that contain the winning scores shown in D1, D2 and D3.
I've defined a string array and would want to use it as a basis for a vlookup. Is it possible to find the elements of the array directly in the worksheet ?So far I've got :
[Code] .....
I have an array that is 60x100 (column x row).
I'm trying to search for a value in that array and return the value on the same row, but shifted to the right one column.
Example: If my value is found in D63, I want to return the value in E63.
I've been messing with Index, Match, and Offset, but I can't get anything working.
I am using VLOOKUP with the not_exact_match set to True, however instead of finding the next largest value that is less than value, I want to find a way of returning the next largest value that is greater than value. I have looked at using MATCH and OFFSET to try and increment the returned value by 1.
View 9 Replies View RelatedI am trying to find an item within an array and then VBA could execute code.
Here is an example:
[Code]....
LookupItems =("text", "value", "book") or should I acutally be using Split("text,value,book",",")
For Each sht in ThisWorkbook
If sht.name = array(LookupItems) Then.....execute code
[Code] ....
So basically in this example I want to loop through all the sheet names in the workbook and if any of the names in the arrary are found it will execute the code for those particular sheet names.
I know alternatives are the select case or write an if statement for each value I am looking up or even use an OR for each value to lookup; but I just wanted to see if this method was even possible as it would be less coding.
I have a column array with various cells in that array populated. In every subsequent cell in that array I want a formula that finds the previously populated cell and that value added a cell that is in the same row but two columns to the left.
I have a table with three columns, column 1 is a list of names, column 2 is where I want my result to appear, and column 3 has my array of search values. Column 1 and 2 could have any number of rows with values, but column 3 will have less values. It looks like this if it's working right:
Item List
Result
Search List
[Code].....
What I am trying to do is for each cell in column 1, I want to see if there is a matching value in column 3 - it has to be either an exact match or a partial match (i.e. the string appears somewhere in the values of column 1).
I have been trying to use MATCH like this:
=ISNUMBER(MATCH($A2,$C:$C,0))
but it does not return true unless the match is exact.
way to get these partial string matches to work?
Is it possible to position a predetermined cell (e.g. A42) in the top left corner of the screen. (Not every screen users use has the same size)
View 3 Replies View RelatedI need to do a vlookup that takes a string from one cell and then tries to find that string (embedded in a larger string) in the table array
Essentially I imagine this involves the FIND function at some point.
Attached is an incredibly simplified example of what I'm looking for.
I have been trying to write two formulas in one cell. I have been able to write them both separately but have been unable to join them both together. What I am trying to do if first search name them how many reoccurring numbers appear. I have provided an example below
a b c d
1 Tom 333
2 Sam 22
3 Sam 22
4 John 5
5 Sam 22
6 Sam 1
7 Tom 3
8 Tom 333
So the answer would be
Tom = 2
Sam = 2
John = 1
I have some cells with some spaces and then text where I want to find the position of the first letter. Do any of you know about any function I can use?
The example below contain 5 spaces and then my name. It should give me the answer 6.
" Magne"
Here is example... Explanation is in the title
Book2.xls
I would like to end a macro with a specific cell (e.g. E50) in the first cell in the upper left hand corner of the screen. How might I accomplish this?
View 3 Replies View Related