Finding Two Patterns In Column And Doing Calculations Depending On Pattern Order Found

Apr 30, 2013

I'm attempting to do work on pattern detection and actions based on how said patterns occur in a column. Here is what I would like excel to do for me:

Code:
Pattern W1

Example A1=A , A2=A , A3=B

Pattern L1 Consecutive "A" 3 or more

Example A4=A , A5=A , A6=A

Triggers on specific events:

While L1 tracking variable = 0 -- If L1 is found, mark a variable to -2 then set the corresponding cell in the column over to the value of the variable (-2)

While L1 tracking variable < 0 -- If consecutive L1s are found one after another, then (on each consecutive occurence) multiply the variable by 3, then set the corresponding cell in the column over to the value of the variable

If W1 is found while L1's variable is < 0, then multiply the value of the L1 tracking variable by -1 and add 1, then set the corresponding cell in the column over to the value of the L1 variable, then set L1's tracking variable to 0

If W1 is found while L1's variable is = 0, then set the corresponding cell in the column over to the value of 1

All data is in one column.

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Fill Handle Pattern (not Finding My Pattern)

Jan 31, 2007

Pre-requisite: I would consider myself to be very poor with excel, based on what I've read on this forum and found on my web-searches. I have a worksheet that has a list of data on the left going vertically, then a summary of this data going horizontally across the top. It is not arranged in such a way that transposing the data will do what I want. I am pulling the 5th word out of the title of each block of the vertical data and need to show this word on the horizontal section.

When I use this formula to pull the 5th word: =MID(MID(MID(SUBSTITUTE(A2," ","^",4),1,256), FIND("^",SUBSTITUTE(A2," ","^",4)),256),2,FIND(" ",MID(MID(SUBSTITUTE(A2," ","^",4),1,256),FIND("^",SUBSTITUTE(A2," ","^",4)),256))-2)

I need to increase A2 to A30, then A58 (up by 28 every time) in every instance in that formula. The fill handle increases the values by 1, instead of 28 (even if I do 3 or 4 instances manually) How do I do this? I've run into this problem in other scenarios, and there HAS to be a way to get around it.

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Jun 18, 2014

I have a string and a pattern. If a substring of the string is found in the pattern, the string is no longer valid. I would like to return a message stating which substring was found in the pattern.

String: K22+L09+P88+Q12+J56
Pattern: (N75|X02|A21|U67|L09|...)
Output Should Be: "J56 is an invalid code. Blah-Blah"

Code to test string against pattern:

Code:
Function Test_OPC(sCode, sPattern) As Boolean
Dim RegX As Object
Dim RegMC

[Code]....

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Apr 22, 2009

I have a VBA method that goes thru and calculates a bunch of stuff and puts this calculated info into a static data structure. This method is called 'setProjectInfo()'. This method is reliant on values on my worksheets, So as the user makes changes to the worksheet, I want setProjectInfo() to get called so it refreshes the data structure with updated information. I then have a bunch of helper methods to access different parts of this data structure. These helper methods are used in the formulae of a bunch of cells on a worksheet (ie '=getPercentComplete(period)', etc, etc).

This is all working well except for one thing. Sometimes the helper methods get called BEFORE setProjectInfo() gets called.. So, the helper methods return stale information. I can only get around this by manually recalculating the spreadsheet again. setProjectInfo() does enough stuff and takes a long enough time that I don't want to have to call it at the top of each helper method.

I've put the call to setProjectInfo() in a cell formula at the top of the my spreadsheet in hopes that Excel would know enough to call it first.. But that does not seem to work. Net, how can I get VBA to always call setProjectInfo() BEFORE it calls any other VBA methods?

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Jul 6, 2006

I have a list of two columns. Here’s an example. The left most column provides the row number.

_ A B
1 1 0
2 2 1
3 2 1
4 3 2
5 4 2.5
6 5 4
7 1 0
8 1 0
9 2 2

Whenever there are two repeating numbers in column one, I want to reduce certain numbers in column 2 by a certain amount. The amount is determined by half the difference between the number in column B corresponding to the second repeated number and the number in column B corresponding to the row after the second repeating number. The range of numbers that are to be reduced begins with the row after the second repeating number and ends with the last row before number one appears in column A. The values in column A are integers, always starting with one. For example, 1, 2, 3, 4, 1, 2, 3, 1, 2, 3, 4, 5.

For the above example, after finding the repeating number two’s at A2 and A3, it would reduce B4 through B6 by half the difference between B3 and B4 (1/2). The values for B4 through B6 would be updated in column B. The same for the next repeated numbers, which is one at A7 and A8. Half the difference between B8 and B9 is 1.

Here’s what the updated list would look like:

1 1 0
2 2 1
3 2 1
4 3 1.5
5 4 2
6 5 3.5
7 1 0
8 1 0
9 2 1

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If there is more same numbersthat small function returns... It need to give me all of them, no matter 5 is limit. how to get back values of rank function that are duplicated. Book1.xls

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Mar 1, 2008

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Data is extracted from a database into excel however users can configure the columns in the initial system. to how they like This causes problems when the data is copied into an excel spreadsheet I have created as the data copied will not be in the same column order as is required.

How can i reorder the columns without physically having to cut and paste the columns to match?

I have attached a sample spreadsheet.

You will see on the spreadsheet that 'fixed columns' is the order that i require the data however 'variable columns' is not in the same order.

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Eg.
18-MAY-2007 600
01-JUN-2007 500
02-JUN-2007 400
28-JUN-2007 600
12-JUL-2007 700
17-JUL-2007 200

I need formula that will give me "600" if the month I want is June. Ideally I would not want to have to filter the data, so SUBTOTAL would probably not work for me.

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Apr 10, 2014

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=IF('Label Calculations'!$A1="","",'Label Calculations'!$A1)

This way, it won't return 0s for blank cells from the "calculations" worksheet. I dragged down the formula to cell A10, but would like to continue the pattern so that cell C1 would be:

=IF('Label Calculations'!$A11="","",'Label Calculations'!$A11)

and cell E1 would be:

=IF('Label Calculations'!$A21="","",'Label Calculations'!$A21)

and the pattern would continue with cell A11 with the formula:

=IF('Label Calculations'!$A31="","",'Label Calculations'!$A31)

Then cell B11 would be 41, C11 would be 51, A21 would be 61, etc.

I can do it manually by adding the function in the top row of each "page" (A1,C1,E1 then A11,C11,E11...) and dragging them down each "page." However, I may end up with 20 some pages of labels. I feel like there should be an easier way I can do this.

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Jul 30, 2014

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=MAX($D$2:$D$61)
=MAX($E$62:$E$121)
=MAX($F$122:$F$181)

and so on...

[Code] .....

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CartonNo1

ProductNo1

LotNo1

LotNo2

CartonNo2

ProductNo1

LotNo3

LotNo4

In the above (repeating for say, 50 or more cartons), is there a way with a macro(I know nothing about) or pivot table(see macro) to get the following format/result?

CartonNo1
ProductNo1
LotNo1

CartonNo1
ProductNo1
LotNo2

[code].....

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Jun 1, 2014

I need to find and match patterns of strings in a column and fetch data from the adjacent column. I've attached a sample workbook with my sample data.

How can I find the appropriate matching pattern and fetch and fill data from the adjacent column from my source table to destination? I tried the string functions available and used SEARCH function to match the pattern and check whether it is available. However, when the pattern is found, how can I fetch the adjacent column ?

My attempt to code a formula using SUBSTITUTE, MID and SEARCH functions. Below is the monster formula I wrote - it works and returns 1 when the pattern is found.

Formula:

I need to return the matching pattern that is found. And with it the corresponding adjacent cell's value.

Attached File : Find_Pattern_Match_and_Fetch.xlsx

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Column A---------Column B-------Column C

5230400----------81,50----------1660000
3275500----------78,00----------6245700
2856300----------47,50----------5230400
1879800----------62,50----------2497900
2124300----------99,00----------1879800
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4826900----------77,50
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6245700----------61,50
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Column B represents 600 prices. (different for each material)

Column C represents 107 materials that are present in column A and have to be removed along with their prices in column B.

Now i want to remove the materials that are in column A and C along with their prices, so i won't damage the order in the file.Meaning if i delete a row in A and shift the other materials up or down, and in the same time column B remains unchanged, the remaining materials will have different prices...and that's not good.

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[URL]

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In the last line item Computer is recorded for the third time.

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I have the following code for identifying the 1,3,2 patterns from sheet1 and it copy pastes those rows into sheet2. I was wondering if there is a way to modify this code to delete those patterns once it has identified them instead of pasting them into sheet2. In other word,s sheet2 needs to contain every other data except those identified patterns.

VB:

Sub test()
Dim myPtn As String, txt As String, m As Object, n As Long, LastR As Range
Dim ws1 As Worksheet, ws2 As Worksheet, myStep As Long, i As Long, t As Long
myStep = 10000 '<- change here if needed.
Set ws1 = Sheets("sheet1")
Set ws2 = Sheets("sheet2")

[Code]...

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2 6
4
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0000-2400 [weekend]

I got the first 3 blocks working but got stuck with the 4th one.

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I have tried a few other examples in previous threads that use COUNTIF and ISERROR but I just can't get it right.

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Please find attached a daily copy of a spreadsheet that is used to monitor train running times.

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DAILY TRAIN RUNNING.xlsx‎

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