How To Select Number Not Already Used

Aug 4, 2013

I have a competition in bowls format where mats are selected each round so that players do not play on the same mat twice. I was hoping to find through search, where the number selected was never repeated not so far.

I have 32 mats to chose from in one comp, but others can vary from 4 to 24. how to start via vba or formula would be welcome.

if 2 players have played on mats 2,4,8,6 and 12,14,16,18 can a formula check the numbers used and select one that has not been used so far?

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I have a multiselect listbox with values that gets populated from a sql statement, and I would like to get is the first or second index from the selected item. I know how to get the listindex from a combobox by using:

VB:
cbnumber.List(.ListIndex, 0)

How can I loop through and get the 1st index number for the selected items only from the listbox? I want to pass this index number to another sql statement.

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Feb 14, 2014

[Code] ......

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Apr 1, 2014

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[Code] ......

Instead of (Works):

[Code] ....

Rows can be selected according to:

[Code] ....

I have written this code that works. But there must be an easier way:

[Code] ....

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Jan 5, 2012

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Code:

Sub LoadUnits()
Dim oRs As Recordset
Set oFSObj = CreateObject("SCRIPTING.FILESYSTEMOBJECT")
'Open an ADO connection to the folder specified
Set oConn = CreateObject("ADODB.CONNECTION")
oConn.Open "Provider=Microsoft.Jet.OLEDB.4.0;" & _
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[code]...

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an equivalent to the code

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Aug 16, 2008

I'm trying to write a macro that will validate data in variable amount of rows but will always be in a specific column. what i'd like to do is count the amount of row entries in Column A to give me "iRows." Then validate data in column E from E1-E"iRows." Currently my data validation runs for the entire column which means i can not validate blank entries. Once I can limit the validation process from E1 to E "iRows" then I can consider blank fields and mark them as invalid.

Columns("E:E").Select
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.Delete
.Add Type:=xlValidateDecimal, AlertStyle:=xlValidAlertStop, Operator _
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Jul 3, 2014

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Formula:

[Code] .....

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Jan 24, 2013

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Jun 19, 2009

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Code:

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[URL]

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