Loop Column & Display Variable In Other Column

Dec 6, 2006

on the syntax of things in VBA. here's a description of what i'm trying to do:

1) loop through a particular column ("N"), and compare the values (if not blank) with corresponding cells in another column ("V"). i.e. - comparing N1 to V1, N2 to V2, etc...

2) run If, ElseIf statements to display appropriate values in different column ("O"), but on the row that corresponds to the row the values in Step 1 are compared. i.e. - if N1 > V1 then cell O1 = value; if N2 > V2 then cell O2 = value; etc...

here's an example (but obviously not in proper syntax). hopefully someone can help me convert it to Excel VBA:

Function CalculateFR()

Dim Col1 As Column = ColumnN
Dim Col2 As Column = ColumnV
Dim Col3 As Column = ColumnO
Dim Cell As Cell
Dim IndexValue As Integer

For Each Cell In Col1
If Col1 > Col 2 Then
IndexValue = 5
Else If Col1 < Col2 Then
IndexValue = 4
End If
Next Cell

If Not IsEmpty(Cell) Then Col3 = IndexValue

End Sub

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Excel 2013 :: Formula To Subtract 7th Column Values From Column Before 1st Loop?

Feb 21, 2014

I have a code that inserts a new column after every 7th column. I want to include a formula where every 7th column value is subtracted from the values present in the column before the 1st, or you can think of it as subtracting 7th column of the present group from the 7th column of the previous group. Example: The range of my data starts from col F, then

F (7th) New Column (G) H (1st) I (2nd) J (3rd) K (4th) L (5th) M (6th) N (7th) New Column (O) P (1st) Q (2nd) R (3rd)

So, New Column (O) = N - F
and the next New Column (W) = V-N ...

NOTE: Column G can be ignored.

I want to add a looping function to this so that it will continue to subtract for the other respective columns as well. How do I incorporate this into the following code?


I'm using Excel 2013.

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I started the formula in P2 of the GL Detail-2012 tab. File attached.

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I would like to display the column header of the row in which a value other than 0 exists in a cell for each instance that value exists in an array spanning 3 columns. So the result cell could be any of the three column headers.

I started the formula in P2 of the GL Detail-2012 tab. (FILE TOO BIG)


Resin Sand Eliminated Segment
- (12,896.65)-
- (6,570.85) -
- (11,503.80) -
- (13,188.50) -

If there is any value other than 0 in Resin, Sand or Eliminated columns, return that column's header under Segment.

Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,)))

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