I have a spreadsheet with a column that containts UNSPSC codes that can be in any of the four following formats:-
10
77/11
78/10/22
44/12/19/04
I basically want ta formula that will find and remove any / leaving me with
7711
781222
44121904
I want to change the character ~ with . in order to be able to make them numeric values to be feeded to other functions. But REPLACE seems not doing the job so I've been checking out other options such as seperating after and before the character ~. Details are below. I've been trying to use this formula to extract values from a delimited database which I open with excel. The formula that has brought me close is =IF(ISNUMBER(E51)=FALSE,LEFT(E51,LEN(E51)- FIND("~",E51)),E51)
14010~000
3210~0000
When I import the database, the figures above have originals as 14010.00000 & 3210.00000 but transfer to excel as above. As far as I have observed 9 character spaces are displayed & the DOT transfers to ~ for some reason. I need the LEFT section of the ~
To all sifus out there, how can i transfer from these:
NAS517-3-2
-41353913
NAS517-3-5
NAS517-3-4
-42MS27253-2
-43353908
-44357182
To these:
NAS517-3-2
353913
NAS517-3-5
NAS517-3-4
MS27253-2
353908
357182
I have a code which displays the values of R2, S2, T2, and U2 in one cell (J2). R2, S2 and U2 are all letters, but T2 is a 2 digit number. If there is a leading zero in T2, then in the display of J2, the leading zero is gone. so if the value of R2 is K, S2 is M, T2 is 01 and U2 is S, then I would want it to display KM01S, but it is only displaying KM1S.
View 1 Replies View RelatedI have got a list of numeric abbreviations, for instance 10739011/21/31/41. What it should really display are the numbers 10739011, 10739021, 10739031 and 10739041 (the first six figures stay the same). All the numbers in my list are 8 figures long. I want to change the list from the list seperated by the backward slash to the complete numbers. I have uploaded an example of the list with backward slash between the numbers. Is there a way that Excel can automatically change these numbers to the full numbers?
Because all the numbers are 8 figures long, I thought the first 6 figures of the 1st number can be copied and those 6 figures pasted before the other two figures after the backslash. Auto Merged Post Until 24 Hrs Passes;sorry, pressed OK too quickly. The problem is that there are sometimes 4 numbers in the cell, sometimes 6 and once three. I would like Excel to complete all the numbers in the cell and then move on to the cell underneath it and so on. Also, I would like each number to have it's own cell.
i have numbers like:
00012334
00122434
00000344
00003432
i need:
12334
122434
344
3432
i cant use formulas because its in text and for some reason if i try to use a formula the formula shows but not the answer.
vba would be prefered.
Can anyone suggest a formula that will take a number (a variable amount of placeholders), and remove any trailing zeros.
eg. 6000 = 6, , 23 = 23, 230 = 23, 2300 = 23, 23000 = 23
Also looking for a similar forumla that will strip off any numeric characters from a text string of variable length.
eg ACA2343 = ACA, GNVC23 = GNVC, DAL12 = DAL, CGHJ = CGHJ, CGHJ5002 = CGHJ
Now I have a decimal column and I would like to remove all of the trailing zeros. It is using the number format. How do I accomplish this?
View 10 Replies View Relatedi have a number formate 0000001 and another formate 0000123005
i would like to move only all the zeros on the left side of the number .
i got this code from Dave before:
Sub KillZeros()
'*Note: Column B must be the Entry No one
Range("B:B").Replace What:="000", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByColumns, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
End Sub
I have a list of about 1,400 numbers ranging in different lengths. What I'm trying to accomplish with a formula is to remove the single letter at the end of each number (not all numbers have them) and in addition to removing all zeros at the beginning of the number (again not all numbers have them).
Here is an example...say I have the following 5 numbers:
8014554
45678456
87451245
0008014554b
0008014554c
And what I need my formula to do provide is the following results instead:
8014554
45678456
87451245
8014554
8014554
So far I have started with the following =LEFT(A1,LEN(A1)-1), but that will always remove the last character (number and letter).
I have a array which includes zero's and based on this array I would like to create a new (almost identical) array, where the cells with zero's are omitted.
To illustrate, I would like to make some code which will bring me from OldArray to NewArray:
OldArray
(10)
(0)
(5)
(12)
(0)
(30)
(0)
NewArray
(10)
(5)
(12)
(30)
I am importing a csv file and each field in this file is imported with an apostrophe
eg: '01
I need to remove the apostrophes but leave the information as text thereby keeping my leading 0's
have tried formatting as text
data text to columns
nothing I do works.
I want to remove the front zero(s) from the front and put a space before the last two letters for the following column of data in Excel:
0001MG
0020MG
0100MG
1000MG
Final result will have this format and the data are right aligned.
1 MG
20 MG
100 MG
1000 MG
The numbers can vary (e.g. 0150MG, 0025MG,etc.) but the arrangement is always the same: four figures for the first 4 characters and two letters for the last two characters.
The format of the cells containing the data is: “General”
My table has 7 columns and these data are in the 5th column in a worksheet called “ProductSummary”. The number of rows for the records can vary from 10 to over a couple of hundred.
How can I use VBA to: 1) automatically select the table range in that worksheet and reformat all the data in the 5th column.
I have a lot of record that contain number like shown below:
0000082181
0000005465
0000028997
I want to remove all 0 in front of this number in excel.. I use excel 2007..
I already try using formula
Code:
=IF( LEFT(A1) = "0" , RIGHT(A1, LEN(A1)-5), A1)
but it only remove 5 character in front what about the number that have 6 '0'......
How to remove the first charcter that contains comma, like this :
,001,003,005 and i want the result is --> 001,003,005.
I'm trying to write a UDF that takes the text in a cell and returns text with a list of forbidden characters removed from it. At the moment I have the following:
View 8 Replies View RelatedI have a column and each cell in that column has information that ends with a comma "," I would like to remove that comma.
View 4 Replies View RelatedI am trying to remove the last character from some text with:
Application.SendKeys "{F2}"
Application.SendKeys "{BS}"
Application.SendKeys "{Enter}"
But when I do this, it is giving me the object browser in VBE . . .
I would like to take a value in a cell and remove the second and third characters in that cell.
For example: "V0010" would become "V10."
I've found formulas for removing the beginning and ending characters, but not a way to remove from the middle.
I need a VB script to remove a character.
The character is the SECOND . in the following strings
1.07.66
0.59.53
1.08.99
1.10.1
0.58.6
Basically, 1.07.66 represents 1 min and 7.66 sec, but I cant use the data until excel can recognise it as 1.0766
A vb sript would be nice, but a formula is also acceptable.
I have data in a column and each cell has an extra character at the end of it-
house;
farm%
school bus>
football-
trip to europe"
I once saw someone remove the characters with either a =LEFT( or =RIGHT( formula with a comma after the reference cell and some kind of FIND" " statement.
I have sentences which contains special characters (mentioned below) in a single column. I need to remove all special characters other than space. Could anyone help me on this...
!@#$%^&*()-_=+{}[]|~`?/,:;"
1) In any cell, I would like to remove "Area#xxxxxxxxx" (where x are random numbers).
Example : "INFO Log - [sys] Area#541185471Character#46545"
2) I would like to remove x characters before a word.
Example : 2013-08-28.txt@INFO
I would need to remove 14 characters before the character "@".
I tried to play with the LEN and RIGHT/LEFT formula but so far, I can't get it to work... The idea is to parse some text and remove the part in red (I was thinking about using SUBSTITUTE).
I need to remove the last character in a cell if it is a comma. I can't remove all commas because there are other commas in the text.
View 2 Replies View RelatedI managed to produce the following code. It removes the the last character in a cell if it is a slash But most of the time there are more than one slashes at the end. How can I take care of these?
Code:
For Each cell In Range("G2:G71")
If Right(cell, 1) = "/" Then
cell.Value = Left(cell, Len(cell) - 1)
End If
Next cell
How do I search for and remove the vertical lines in the above example from the column D? These things came when I imported a data file into Excel....
View 9 Replies View RelatedI'm trying to write to text file a HTML page that is in string variable sFullPage.
So far my code is like this:
Sub wrtHTML()
Dim sFName As String ' Path and name of text file
Dim iFNumber As Integer ' File Number
sFName = "c: est.html"
'Get an unused file number
iFNumber = FreeFile
'Create new file or overwrite existing file
Open sFName For Output As #iFNumber
'Write data to file....
How do I remove those first and last two marks (a double quote on each side + square mark from the end)? Do I use somehow wrong data types or wrong printing methods?
i need a formula that will remove the first 2 characters and the last character from the below, so below the result should be R0131644, the number of characters vary from row to row, they are not always 11
EUR01316441
I have data in cell A1 and A2 which looks like below
SECTOR - 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30-15-171 DABA GARDENS, NEAR SARASWATI PARK,-530020,
In cell A1 the number of hypens (-) are 2
In cell A2 the number of - are 3
What I am looking for is a formula which can remove all additional - except the last one. Therefore the result of the formula should be
SECTOR 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30 15 171 DABA GARDENS, NEAR SARASWATI PARK,-530020
I am trying to remove the last 6 character from a variable. I worked out how to do it using formula's in XL, but want to move this in to VBA. Currently I have this
Mid(ActiveSheet. Name, 1, Find(" Intrdy", LookIn:=ActiveSheet.Name))
however it does not like the find function. Does it exist? am I using it correctly?