I am trying to remove the last 6 character from a variable. I worked out how to do it using formula's in XL, but want to move this in to VBA. Currently I have this
Mid(ActiveSheet. Name, 1, Find(" Intrdy", LookIn:=ActiveSheet.Name))
however it does not like the find function. Does it exist? am I using it correctly?
To all sifus out there, how can i transfer from these:
NAS517-3-2
-41353913
NAS517-3-5
NAS517-3-4
-42MS27253-2
-43353908
-44357182
To these:
NAS517-3-2
353913
NAS517-3-5
NAS517-3-4
MS27253-2
353908
357182
How to remove the first charcter that contains comma, like this :
,001,003,005 and i want the result is --> 001,003,005.
I'm trying to write a UDF that takes the text in a cell and returns text with a list of forbidden characters removed from it. At the moment I have the following:
View 8 Replies View RelatedI have a column and each cell in that column has information that ends with a comma "," I would like to remove that comma.
View 4 Replies View RelatedI am trying to remove the last character from some text with:
Application.SendKeys "{F2}"
Application.SendKeys "{BS}"
Application.SendKeys "{Enter}"
But when I do this, it is giving me the object browser in VBE . . .
I would like to take a value in a cell and remove the second and third characters in that cell.
For example: "V0010" would become "V10."
I've found formulas for removing the beginning and ending characters, but not a way to remove from the middle.
I need a VB script to remove a character.
The character is the SECOND . in the following strings
1.07.66
0.59.53
1.08.99
1.10.1
0.58.6
Basically, 1.07.66 represents 1 min and 7.66 sec, but I cant use the data until excel can recognise it as 1.0766
A vb sript would be nice, but a formula is also acceptable.
I have data in a column and each cell has an extra character at the end of it-
house;
farm%
school bus>
football-
trip to europe"
I once saw someone remove the characters with either a =LEFT( or =RIGHT( formula with a comma after the reference cell and some kind of FIND" " statement.
I have sentences which contains special characters (mentioned below) in a single column. I need to remove all special characters other than space. Could anyone help me on this...
!@#$%^&*()-_=+{}[]|~`?/,:;"
1) In any cell, I would like to remove "Area#xxxxxxxxx" (where x are random numbers).
Example : "INFO Log - [sys] Area#541185471Character#46545"
2) I would like to remove x characters before a word.
Example : 2013-08-28.txt@INFO
I would need to remove 14 characters before the character "@".
I tried to play with the LEN and RIGHT/LEFT formula but so far, I can't get it to work... The idea is to parse some text and remove the part in red (I was thinking about using SUBSTITUTE).
I need to remove the last character in a cell if it is a comma. I can't remove all commas because there are other commas in the text.
View 2 Replies View RelatedI managed to produce the following code. It removes the the last character in a cell if it is a slash But most of the time there are more than one slashes at the end. How can I take care of these?
Code:
For Each cell In Range("G2:G71")
If Right(cell, 1) = "/" Then
cell.Value = Left(cell, Len(cell) - 1)
End If
Next cell
How do I search for and remove the vertical lines in the above example from the column D? These things came when I imported a data file into Excel....
View 9 Replies View RelatedI'm trying to write to text file a HTML page that is in string variable sFullPage.
So far my code is like this:
Sub wrtHTML()
Dim sFName As String ' Path and name of text file
Dim iFNumber As Integer ' File Number
sFName = "c: est.html"
'Get an unused file number
iFNumber = FreeFile
'Create new file or overwrite existing file
Open sFName For Output As #iFNumber
'Write data to file....
How do I remove those first and last two marks (a double quote on each side + square mark from the end)? Do I use somehow wrong data types or wrong printing methods?
i need a formula that will remove the first 2 characters and the last character from the below, so below the result should be R0131644, the number of characters vary from row to row, they are not always 11
EUR01316441
I have data in cell A1 and A2 which looks like below
SECTOR - 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30-15-171 DABA GARDENS, NEAR SARASWATI PARK,-530020,
In cell A1 the number of hypens (-) are 2
In cell A2 the number of - are 3
What I am looking for is a formula which can remove all additional - except the last one. Therefore the result of the formula should be
SECTOR 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30 15 171 DABA GARDENS, NEAR SARASWATI PARK,-530020
I have the function below from http://www.ozgrid.com/VBA/extract-words-function.htm
and have it working exactly as it's supposed to. Is it possible to adapt this to remove the last character of the text string, specifically the commas? My problem is that the raw data in one cell is like this (including commas) 0.333, 5.8874, 6.85423, 0.025. I separate each text string into separate cells but am left with the commas. I'm not using the "Data Text to Columns" option as I need the results in specific cells so they can then be used in calculations.
Function Get_Word(text_string As String, nth_word) As String
Dim lWordCount As Long
With Application.WorksheetFunction
lWordCount = Len(text_string) - Len(.Substitute(text_string, " ", "")) + 1
If IsNumeric(nth_word) Then
nth_word = nth_word - 1
Get_Word = Mid(Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _
. Find("^", .Substitute(text_string, " ", "^", nth_word)), 256), 2, _
.Find(" ", Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _ ............................
I want to change the character ~ with . in order to be able to make them numeric values to be feeded to other functions. But REPLACE seems not doing the job so I've been checking out other options such as seperating after and before the character ~. Details are below. I've been trying to use this formula to extract values from a delimited database which I open with excel. The formula that has brought me close is =IF(ISNUMBER(E51)=FALSE,LEFT(E51,LEN(E51)- FIND("~",E51)),E51)
14010~000
3210~0000
When I import the database, the figures above have originals as 14010.00000 & 3210.00000 but transfer to excel as above. As far as I have observed 9 character spaces are displayed & the DOT transfers to ~ for some reason. I need the LEFT section of the ~
I need to remove the first character in each row of a column, but only its first occurrence in each row. For instance:
Say, column 2 has following data (lots of rows, by the way):
First Text" - "blabla"
=SomeText2 = "blabla"
SomeText3 = "blabla"
=SomeText4 = "blabla"
-SomeText5 --- "blabla"
........
....
I would like to use the VBA code to remove ONLY the FIRST occurrence of the FIRST character specified (either "=" or "-") in each row in that column, so that I get:
First Text" - "blabla"
SomeText2 = "blabla"
SomeText3 = "blabla"
SomeText4 = "blabla"
SomeText5 --- "blabla"
......
...and so on...
I tried to use this:
Code:
Columns(2).Cells.Replace What:="-", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
Columns(2).Cells.Replace What:="=", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
but it replaces ALL occurrences of "=" and "-" and that is not what I need.
I also tried this code:
Code:
With Range("B:B")
.Value = Replace(.Value, "=", "", 1, 1)
End With
But It doesn't work either.
I have a spreadsheet with a column that containts UNSPSC codes that can be in any of the four following formats:-
10
77/11
78/10/22
44/12/19/04
I basically want ta formula that will find and remove any / leaving me with
7711
781222
44121904
I have a column of text where I need to remove all the characters to the right of the last occurance of a special character.
I think a process like reading from right to left, look for the first occurance of the special character, and return the characters to the left of this position.
If I can determine the position of the last occurance of the special character, I could use the LEFT function.
The SEARCH function is close. It finds the position of the first occurance of text inside text but it reads from left to right. I need to read from right to left.
Another approach is to examine each character one by one from right to left. If the character is not the special character, delete it. When the character is the special character, delete it and stop the process.
There is no consistency in the text. The total lengths vary. The number of times the special character occurs in the text vary. The number of characters to the right or left of the last special character vary.
I much prefer not to have the solution be some VBA because I need to share it with others who are even less capable than I am. We are using Excel 2003.
I've spent way too much time trying to figure out this simple thing. Doh! I have a text string that may have one or more CR and/or LF characters on the right. Unfortunately, RTrim doesn't remove CR/LF characters.
Is there an easy way to do something similar to the following that will remove the CR/LF characters?
[Code] .....
After doing a search, I need to ask an Excel 2003 question. I'm creating a tool to open three sparate workbooks. One is the driver and I need to use it to pull data from the second and then to place that data along with additional data into the third.
My driver data may consist of a single value or multiple values separated by semi-colons in a cell. A single value works fine. The first value in a multi-value condition works fine. the second find, however, gives me an object error. I'm using the " split" verb to separate the values. Here's my code. Have you any idea why the second find is throwing up this error when the first find works correctly?
varData = Split(strRef, ";", -1)
For J = 0 To UBound(varData)
varSrchVlu = Trim(varData(J))
' do the ARIS Exrtact matching
Workbooks(strManualFile).Activate
Workbooks(strARISExtract).Activate ' Activate ARIS Extract
Sheets("Processes").Cells(2, 1).Activate
Workbooks(strARISExtract).Sheets("Processes").Range("A2").Select
Workbooks(strARISExtract).Sheets("Processes").Columns("A:A").Select
i am trying to remove the unknown character and extra space from the name. Though i use formula as trim or proper(trim), it is not removing the Unknown character / extra space. I have attached the few name as sample. Formula to remove these Unknown character / extra space, double space, special character from selected cell?
Note : I am using ms office 2013
I need my program to:
- find the cell containing the string "Datum/Tid"
- record the column and the row of the found cell in two variables lCol and lRow
Here is my
Sub test()
Dim rFoundCell As Range
Dim lRow As Long
Dim lCol As Long
'Find method of VBA
Set rFoundCell = Range("A1")
Set rFoundCell = Worksheets("Sheet1").Range("A1:Z50").Find(What:="Datum/Tid", After:=rFoundCell, _
LookIn:=xlValues, LookAt:=xlPart, SearchOrder:=xlByRows, _
SearchDirection:=xlNext, MatchCase:=False)
'for anyof the two lines down I get the message "object variable OR block variable not set"
lRow = rFoundCell.Row
lCol = rFoundCell.Column
End Sub
I found this nice little bit of code for a date range search in column A but it will not work. Apparently i have not set a variable or something.
Private Sub Worksheet_SelectionChange(ByVal Target As Range)
Dim startDate As String
Dim stopDate As String
Dim startRow As Integer
Dim stopRow As Integer
startDate = InputBox("Enter the Start Date: (dd/mm/yyyy)")
If startDate = "" Then End
stopDate = InputBox("Enter the Stop Date: (dd/mm/yyyy)")
If stopDate = "" Then End
startDate = Format(startDate, "dd/mm/yyyy")
stopDate = Format(stopDate, "dd/mm/yyyy")
startRow = Worksheets("sheet1").Columns("A").Find(startDate, _
LookIn:=xlValues, lookat:=xlWhole).Row
stopRow = Worksheets("sheet1").Columns("A").Find(stopDate, _
LookIn:=xlValues, lookat:=xlWhole).Row
Worksheets("Sheet1").Range("A" & startRow & ":A" & stopRow).Select
End Sub
I have a spreadsheet form with all kind of values and what I want to do is to find a data in a worksheet named "Config" based on the spreadsheet activecell value. With the find row adress I return data of another column but same row (in the worksheet) in two diferent label captions. If the spreadsheet activecell value it was found in the worksheet everything is ok but if the value is not found I'm getting the message "Object variable or with block variable not set"....
View 7 Replies View RelatedI have following kind of sting in the cell.
<Abc_desc><to_location>10102535</to_location><from_location>100</from_location><abc_nbr>00000000009882203100</abc_nbr><abc_type>C</abc_type><con_qty>113</con_qty><bcd_nbr>00000000009882203</bcd_nbr>
I want to extract the number between <abc_nbr> and </abc_nbr>. i.e., "00000000009882203100".
The starting number of the string may varies.
Macro should pick the number and paste it into the next cell.
I have loads of dates but I only want to change the first 0 to 0
01/01/2010 after replace 01/01/2010 how can I do this with find and replace?