Remove Comma In The First Character
Nov 22, 2009How to remove the first charcter that contains comma, like this :
,001,003,005 and i want the result is --> 001,003,005.
How to remove the first charcter that contains comma, like this :
,001,003,005 and i want the result is --> 001,003,005.
I need to remove the last character in a cell if it is a comma. I can't remove all commas because there are other commas in the text.
View 2 Replies View RelatedTo all sifus out there, how can i transfer from these:
NAS517-3-2
-41353913
NAS517-3-5
NAS517-3-4
-42MS27253-2
-43353908
-44357182
To these:
NAS517-3-2
353913
NAS517-3-5
NAS517-3-4
MS27253-2
353908
357182
I'm doing data clean up for a client & have run across data that contains a comma at the end. They've supplied it to me this way & from what I can see it just ends (there is no space after the final comma) IE:
Cheerful, Chipper, Convivial, Delighted, Ecstatic, Elated, Exultant, Pleasant, Pleased, Sparkling, Sunny, Tranquil, Unadorned, Symphony,
The next row may be similar in descriptors but not contain the extraneous comma at the end. IE:
Compassionate, Tender, Calm, Countrified, Priestly, Tranquil, Unadorned, Symphony, Pastoral
Is there a way to remove the final comma in the fields where it's just "dangling" at the end but not remove it from the fields that don't contain the extraneous comma?
Obviously Find & Replace doesn't work because I need the commas to remain throughout the rest of the data. I've searched the boards & have not found a formula that works... I'm going a bit cross eyed at the moment & with thousands of rows to go through, I'd hate to have to remove the ending comma's one at a time!
The below function concats a range of cells by csv. How can I get it to remove the last comma in the string when it's finished?
Function SpecialConcatenate(rnge As Range) As String
Dim r As Long, col As Integer
For c = 1 To rnge.Columns.Count
For r = 1 To rnge.Rows.Count
If rnge.Cells(r, c) "" Then
SpecialConcatenate = SpecialConcatenate & _
rnge.Cells(r, c).Value & ","
End If
Next r
Next c
End Function
I currently have a macro that imports data from a web-based query then deletes column A from the query. I do this because I am using a VLOOKUP on the data and the VLOOKUP value would be in column B if I didn't.
The website has changed the format and now once column A is deleted, I'm left with a format of FirstName LastName, POS TEAM (i.e. Tom Brady, QB NEP). My VLOOKUP looks for FirstName LastName so I'm getting the "N/A" error now. I need to remove the "," and "POS" and "TEAM" from the imported data. This would be easy enough if the number of characters right of and including the comma was consistent, but it isn't. (Also, text to columns then CONCATENATE won't work because VLOOKUP looks at values, not formula results...)
Now I know the formula =LEFT(A1,FIND(",",A1)-1) works, but how would I incorporate this into the worksheet to keep the values in column A and not add additional columns to throw off my VLOOKUP.
Ideally I'd like a simple macro to add to my current macro to use the above formula, but I'm not sure of the wording.
I need a simple way to extract the comma in 14,656 imported text so I can do a vlookup against 14656.
Is it possible to take a list that is alphabetized in the following manner--Jones, Mary--, convert it to Mary Jones while also removing the comma after the name?
The =TRIM and =MID formulas that I saw in another thread both seem to convert the text, but they also leave the comma at the end.
This is a delima I cannot figure out. I had to create passwords for a website we are building. I have 3000 employee numbers has to be used. So what i did was took the first initial and middle initial and last initial and first 5 of the ID number. I did a comma delimiter to obtain all of the letters and numbers. example: ABC12345
My problem is none of the passwords work because when I imported the letters and numbers into the sheet it looks just like the above. However on review I cut and pasted back to notepad and the data looks like this:
"A B C 12345"
So its adding a tab in the password thats thats a problem, How do I remove this extra white space between each comma delimited digit? without having to manually delete it ?
I'm trying to write a UDF that takes the text in a cell and returns text with a list of forbidden characters removed from it. At the moment I have the following:
View 8 Replies View RelatedI have a column and each cell in that column has information that ends with a comma "," I would like to remove that comma.
View 4 Replies View RelatedI am trying to remove the last character from some text with:
Application.SendKeys "{F2}"
Application.SendKeys "{BS}"
Application.SendKeys "{Enter}"
But when I do this, it is giving me the object browser in VBE . . .
I would like to take a value in a cell and remove the second and third characters in that cell.
For example: "V0010" would become "V10."
I've found formulas for removing the beginning and ending characters, but not a way to remove from the middle.
I need a VB script to remove a character.
The character is the SECOND . in the following strings
1.07.66
0.59.53
1.08.99
1.10.1
0.58.6
Basically, 1.07.66 represents 1 min and 7.66 sec, but I cant use the data until excel can recognise it as 1.0766
A vb sript would be nice, but a formula is also acceptable.
I have data in a column and each cell has an extra character at the end of it-
house;
farm%
school bus>
football-
trip to europe"
I once saw someone remove the characters with either a =LEFT( or =RIGHT( formula with a comma after the reference cell and some kind of FIND" " statement.
I have sentences which contains special characters (mentioned below) in a single column. I need to remove all special characters other than space. Could anyone help me on this...
!@#$%^&*()-_=+{}[]|~`?/,:;"
1) In any cell, I would like to remove "Area#xxxxxxxxx" (where x are random numbers).
Example : "INFO Log - [sys] Area#541185471Character#46545"
2) I would like to remove x characters before a word.
Example : 2013-08-28.txt@INFO
I would need to remove 14 characters before the character "@".
I tried to play with the LEN and RIGHT/LEFT formula but so far, I can't get it to work... The idea is to parse some text and remove the part in red (I was thinking about using SUBSTITUTE).
I managed to produce the following code. It removes the the last character in a cell if it is a slash But most of the time there are more than one slashes at the end. How can I take care of these?
Code:
For Each cell In Range("G2:G71")
If Right(cell, 1) = "/" Then
cell.Value = Left(cell, Len(cell) - 1)
End If
Next cell
How do I search for and remove the vertical lines in the above example from the column D? These things came when I imported a data file into Excel....
View 9 Replies View RelatedI'm trying to write to text file a HTML page that is in string variable sFullPage.
So far my code is like this:
Sub wrtHTML()
Dim sFName As String ' Path and name of text file
Dim iFNumber As Integer ' File Number
sFName = "c: est.html"
'Get an unused file number
iFNumber = FreeFile
'Create new file or overwrite existing file
Open sFName For Output As #iFNumber
'Write data to file....
How do I remove those first and last two marks (a double quote on each side + square mark from the end)? Do I use somehow wrong data types or wrong printing methods?
i need a formula that will remove the first 2 characters and the last character from the below, so below the result should be R0131644, the number of characters vary from row to row, they are not always 11
EUR01316441
I have data in cell A1 and A2 which looks like below
SECTOR - 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30-15-171 DABA GARDENS, NEAR SARASWATI PARK,-530020,
In cell A1 the number of hypens (-) are 2
In cell A2 the number of - are 3
What I am looking for is a formula which can remove all additional - except the last one. Therefore the result of the formula should be
SECTOR 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30 15 171 DABA GARDENS, NEAR SARASWATI PARK,-530020
I am trying to remove the last 6 character from a variable. I worked out how to do it using formula's in XL, but want to move this in to VBA. Currently I have this
Mid(ActiveSheet. Name, 1, Find(" Intrdy", LookIn:=ActiveSheet.Name))
however it does not like the find function. Does it exist? am I using it correctly?
I have the function below from http://www.ozgrid.com/VBA/extract-words-function.htm
and have it working exactly as it's supposed to. Is it possible to adapt this to remove the last character of the text string, specifically the commas? My problem is that the raw data in one cell is like this (including commas) 0.333, 5.8874, 6.85423, 0.025. I separate each text string into separate cells but am left with the commas. I'm not using the "Data Text to Columns" option as I need the results in specific cells so they can then be used in calculations.
Function Get_Word(text_string As String, nth_word) As String
Dim lWordCount As Long
With Application.WorksheetFunction
lWordCount = Len(text_string) - Len(.Substitute(text_string, " ", "")) + 1
If IsNumeric(nth_word) Then
nth_word = nth_word - 1
Get_Word = Mid(Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _
. Find("^", .Substitute(text_string, " ", "^", nth_word)), 256), 2, _
.Find(" ", Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _ ............................
I want to change the character ~ with . in order to be able to make them numeric values to be feeded to other functions. But REPLACE seems not doing the job so I've been checking out other options such as seperating after and before the character ~. Details are below. I've been trying to use this formula to extract values from a delimited database which I open with excel. The formula that has brought me close is =IF(ISNUMBER(E51)=FALSE,LEFT(E51,LEN(E51)- FIND("~",E51)),E51)
14010~000
3210~0000
When I import the database, the figures above have originals as 14010.00000 & 3210.00000 but transfer to excel as above. As far as I have observed 9 character spaces are displayed & the DOT transfers to ~ for some reason. I need the LEFT section of the ~
I need to remove the first character in each row of a column, but only its first occurrence in each row. For instance:
Say, column 2 has following data (lots of rows, by the way):
First Text" - "blabla"
=SomeText2 = "blabla"
SomeText3 = "blabla"
=SomeText4 = "blabla"
-SomeText5 --- "blabla"
........
....
I would like to use the VBA code to remove ONLY the FIRST occurrence of the FIRST character specified (either "=" or "-") in each row in that column, so that I get:
First Text" - "blabla"
SomeText2 = "blabla"
SomeText3 = "blabla"
SomeText4 = "blabla"
SomeText5 --- "blabla"
......
...and so on...
I tried to use this:
Code:
Columns(2).Cells.Replace What:="-", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
Columns(2).Cells.Replace What:="=", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
but it replaces ALL occurrences of "=" and "-" and that is not what I need.
I also tried this code:
Code:
With Range("B:B")
.Value = Replace(.Value, "=", "", 1, 1)
End With
But It doesn't work either.
I have a spreadsheet with a column that containts UNSPSC codes that can be in any of the four following formats:-
10
77/11
78/10/22
44/12/19/04
I basically want ta formula that will find and remove any / leaving me with
7711
781222
44121904
I have a column of text where I need to remove all the characters to the right of the last occurance of a special character.
I think a process like reading from right to left, look for the first occurance of the special character, and return the characters to the left of this position.
If I can determine the position of the last occurance of the special character, I could use the LEFT function.
The SEARCH function is close. It finds the position of the first occurance of text inside text but it reads from left to right. I need to read from right to left.
Another approach is to examine each character one by one from right to left. If the character is not the special character, delete it. When the character is the special character, delete it and stop the process.
There is no consistency in the text. The total lengths vary. The number of times the special character occurs in the text vary. The number of characters to the right or left of the last special character vary.
I much prefer not to have the solution be some VBA because I need to share it with others who are even less capable than I am. We are using Excel 2003.
i am trying to remove the unknown character and extra space from the name. Though i use formula as trim or proper(trim), it is not removing the Unknown character / extra space. I have attached the few name as sample. Formula to remove these Unknown character / extra space, double space, special character from selected cell?
Note : I am using ms office 2013
I have a string of text in cell A2. In cell B2 of my spreadsheet is a formula that calculates a number based on the text string in cell A2.
I want to write a VBA loop that removes a single character from the cell A2 string, then calculate the new value in cell B2. I want this loop to continue until the value in B2 falls below a set value (in this case 60).
My code so far
Sub trim_text()
Dim mytext As String
Dim myanswer As Integer
mytext = Range("A2")
myanswer = Range("B2")
Do While myanswer > 60
mytext = (Right(mytext, Len(mytext) - 1))
Loop
End Sub
This obviously does not work. In my excel table I have a formula in cell B2 to calculate "myanswer" will this work, or does that code have to be placed into the VBA code?