I am trying to remove the last character from some text with:
Application.SendKeys "{F2}"
Application.SendKeys "{BS}"
Application.SendKeys "{Enter}"
But when I do this, it is giving me the object browser in VBE . . .
1) In any cell, I would like to remove "Area#xxxxxxxxx" (where x are random numbers).
Example : "INFO Log - [sys] Area#541185471Character#46545"
2) I would like to remove x characters before a word.
Example : 2013-08-28.txt@INFO
I would need to remove 14 characters before the character "@".
I tried to play with the LEN and RIGHT/LEFT formula but so far, I can't get it to work... The idea is to parse some text and remove the part in red (I was thinking about using SUBSTITUTE).
I'm trying to write to text file a HTML page that is in string variable sFullPage.
So far my code is like this:
Sub wrtHTML()
Dim sFName As String ' Path and name of text file
Dim iFNumber As Integer ' File Number
sFName = "c: est.html"
'Get an unused file number
iFNumber = FreeFile
'Create new file or overwrite existing file
Open sFName For Output As #iFNumber
'Write data to file....
How do I remove those first and last two marks (a double quote on each side + square mark from the end)? Do I use somehow wrong data types or wrong printing methods?
I want to change the character ~ with . in order to be able to make them numeric values to be feeded to other functions. But REPLACE seems not doing the job so I've been checking out other options such as seperating after and before the character ~. Details are below. I've been trying to use this formula to extract values from a delimited database which I open with excel. The formula that has brought me close is =IF(ISNUMBER(E51)=FALSE,LEFT(E51,LEN(E51)- FIND("~",E51)),E51)
14010~000
3210~0000
When I import the database, the figures above have originals as 14010.00000 & 3210.00000 but transfer to excel as above. As far as I have observed 9 character spaces are displayed & the DOT transfers to ~ for some reason. I need the LEFT section of the ~
To all sifus out there, how can i transfer from these:
NAS517-3-2
-41353913
NAS517-3-5
NAS517-3-4
-42MS27253-2
-43353908
-44357182
To these:
NAS517-3-2
353913
NAS517-3-5
NAS517-3-4
MS27253-2
353908
357182
How to remove the first charcter that contains comma, like this :
,001,003,005 and i want the result is --> 001,003,005.
I'm trying to write a UDF that takes the text in a cell and returns text with a list of forbidden characters removed from it. At the moment I have the following:
View 8 Replies View RelatedI have a column and each cell in that column has information that ends with a comma "," I would like to remove that comma.
View 4 Replies View RelatedI would like to take a value in a cell and remove the second and third characters in that cell.
For example: "V0010" would become "V10."
I've found formulas for removing the beginning and ending characters, but not a way to remove from the middle.
I need a VB script to remove a character.
The character is the SECOND . in the following strings
1.07.66
0.59.53
1.08.99
1.10.1
0.58.6
Basically, 1.07.66 represents 1 min and 7.66 sec, but I cant use the data until excel can recognise it as 1.0766
A vb sript would be nice, but a formula is also acceptable.
I have data in a column and each cell has an extra character at the end of it-
house;
farm%
school bus>
football-
trip to europe"
I once saw someone remove the characters with either a =LEFT( or =RIGHT( formula with a comma after the reference cell and some kind of FIND" " statement.
I have sentences which contains special characters (mentioned below) in a single column. I need to remove all special characters other than space. Could anyone help me on this...
!@#$%^&*()-_=+{}[]|~`?/,:;"
I need to remove the last character in a cell if it is a comma. I can't remove all commas because there are other commas in the text.
View 2 Replies View RelatedI managed to produce the following code. It removes the the last character in a cell if it is a slash But most of the time there are more than one slashes at the end. How can I take care of these?
Code:
For Each cell In Range("G2:G71")
If Right(cell, 1) = "/" Then
cell.Value = Left(cell, Len(cell) - 1)
End If
Next cell
How do I search for and remove the vertical lines in the above example from the column D? These things came when I imported a data file into Excel....
View 9 Replies View Relatedi need a formula that will remove the first 2 characters and the last character from the below, so below the result should be R0131644, the number of characters vary from row to row, they are not always 11
EUR01316441
I have data in cell A1 and A2 which looks like below
SECTOR - 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30-15-171 DABA GARDENS, NEAR SARASWATI PARK,-530020,
In cell A1 the number of hypens (-) are 2
In cell A2 the number of - are 3
What I am looking for is a formula which can remove all additional - except the last one. Therefore the result of the formula should be
SECTOR 11, HIRAN MAGRI, - 313001
MAIN BRANCH, 30 15 171 DABA GARDENS, NEAR SARASWATI PARK,-530020
I am trying to remove the last 6 character from a variable. I worked out how to do it using formula's in XL, but want to move this in to VBA. Currently I have this
Mid(ActiveSheet. Name, 1, Find(" Intrdy", LookIn:=ActiveSheet.Name))
however it does not like the find function. Does it exist? am I using it correctly?
I have the function below from http://www.ozgrid.com/VBA/extract-words-function.htm
and have it working exactly as it's supposed to. Is it possible to adapt this to remove the last character of the text string, specifically the commas? My problem is that the raw data in one cell is like this (including commas) 0.333, 5.8874, 6.85423, 0.025. I separate each text string into separate cells but am left with the commas. I'm not using the "Data Text to Columns" option as I need the results in specific cells so they can then be used in calculations.
Function Get_Word(text_string As String, nth_word) As String
Dim lWordCount As Long
With Application.WorksheetFunction
lWordCount = Len(text_string) - Len(.Substitute(text_string, " ", "")) + 1
If IsNumeric(nth_word) Then
nth_word = nth_word - 1
Get_Word = Mid(Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _
. Find("^", .Substitute(text_string, " ", "^", nth_word)), 256), 2, _
.Find(" ", Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _ ............................
I need to remove the first character in each row of a column, but only its first occurrence in each row. For instance:
Say, column 2 has following data (lots of rows, by the way):
First Text" - "blabla"
=SomeText2 = "blabla"
SomeText3 = "blabla"
=SomeText4 = "blabla"
-SomeText5 --- "blabla"
........
....
I would like to use the VBA code to remove ONLY the FIRST occurrence of the FIRST character specified (either "=" or "-") in each row in that column, so that I get:
First Text" - "blabla"
SomeText2 = "blabla"
SomeText3 = "blabla"
SomeText4 = "blabla"
SomeText5 --- "blabla"
......
...and so on...
I tried to use this:
Code:
Columns(2).Cells.Replace What:="-", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
Columns(2).Cells.Replace What:="=", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
but it replaces ALL occurrences of "=" and "-" and that is not what I need.
I also tried this code:
Code:
With Range("B:B")
.Value = Replace(.Value, "=", "", 1, 1)
End With
But It doesn't work either.
I have a spreadsheet with a column that containts UNSPSC codes that can be in any of the four following formats:-
10
77/11
78/10/22
44/12/19/04
I basically want ta formula that will find and remove any / leaving me with
7711
781222
44121904
I have a column of text where I need to remove all the characters to the right of the last occurance of a special character.
I think a process like reading from right to left, look for the first occurance of the special character, and return the characters to the left of this position.
If I can determine the position of the last occurance of the special character, I could use the LEFT function.
The SEARCH function is close. It finds the position of the first occurance of text inside text but it reads from left to right. I need to read from right to left.
Another approach is to examine each character one by one from right to left. If the character is not the special character, delete it. When the character is the special character, delete it and stop the process.
There is no consistency in the text. The total lengths vary. The number of times the special character occurs in the text vary. The number of characters to the right or left of the last special character vary.
I much prefer not to have the solution be some VBA because I need to share it with others who are even less capable than I am. We are using Excel 2003.
i am trying to remove the unknown character and extra space from the name. Though i use formula as trim or proper(trim), it is not removing the Unknown character / extra space. I have attached the few name as sample. Formula to remove these Unknown character / extra space, double space, special character from selected cell?
Note : I am using ms office 2013
I have a string of text in cell A2. In cell B2 of my spreadsheet is a formula that calculates a number based on the text string in cell A2.
I want to write a VBA loop that removes a single character from the cell A2 string, then calculate the new value in cell B2. I want this loop to continue until the value in B2 falls below a set value (in this case 60).
My code so far
Sub trim_text()
Dim mytext As String
Dim myanswer As Integer
mytext = Range("A2")
myanswer = Range("B2")
Do While myanswer > 60
mytext = (Right(mytext, Len(mytext) - 1))
Loop
End Sub
This obviously does not work. In my excel table I have a formula in cell B2 to calculate "myanswer" will this work, or does that code have to be placed into the VBA code?
get the function to get the text in the middle of long text
i have text like this 125/565/797/7222/222/2122
how i put the formula to get text after multiple "/" example the text : 125/565/797/7222/222/2122 in cell A1 i want to get after third char "/ " value 7222 Before the fourth "/"in cell A2 and after the last "/" in cell a3 or value 2122
I have a cell in my worksheet with a fully qualified filename like 'D:abcDefGHIJklxyz123.app
I would like to extract only the xyz123.app. Obviously, the number of characters is going to vary based on the filename. The find and search functions appear to locate the cell but not the substring in the text. The right and left appear to work based on number of characters and in my case these are varying. Also, there does not appear to be any function that can do a search a string from right to left.
The following code reads text one character at a time, and each character is determined either to be a blank space or to be any other character. If it's determined to be any other character, then the character is added to the active cell. If it's determined to be a blank space, then the active cell becomes the cell one column over. The idea is to have different words written in columns next to each other.
The sample text file I'm reading from reads: "text file". The file has only those two words. One space between them. No space before the first word, and no space after the second word. The following code compiles and runs. BUT the result is that the word "text" is in column k, not A. And the word "file" is in column J, not b.
I have a list of over 300+ email addresses. If there is a way that I could pull out the ".com" (Find & Replace: Which is not working in any format, Text, Custom, General.) then pull out the text from the right to left until I get to the "@" into another cell and drag that down that would make it so much easier. Is there a formula that will pull data and then stop at a CHAR code? @ =CHAR(64) These email addresses are all different lengths. (personal to corporate email addresses.)
Example: moe10134@hotmail.com
Looking for something like this: Replace ".com", =LEFT(9) or whatever will take out the "moe10134@" and the ".com" leaving only hotmail.
I have list like the below. I need to pull out everything before the space for each of these and after the _ which is after the CRN_, SA_ or MA_
CRN_212141 JRDC 7402-01_ICT-ICM IT Services Basel PDiv 3702 POPEnd 01/31/2015
MA_7500007822 JRDC
SA_GS-35F-4461G No Alias Determined
CRN_179764 Director of Administration and Managem PDiv 3799 POPEnd 06/30/2014
MA_N00189-09-D-Z044 USJFCOM Projects
SA_GS-35F-4461G No Alias Determined
Desired Results:
212141
7500007822
GS-35F-4461G
179764
N00189-09-D-Z044
GS-35F-4461G
I have a column list that I need to seperate. The Text has both a title and location separated by an = sign. The cells look like this...
BlahBlahBlah = Location1
I would like to take the text after the = sign and place it in the next column so that all that is in it is...
Location1
The Location varies so the RIGHT function won't work.
