Removing Columns With No Data

Aug 7, 2012

I am working on importing contacts from Zimbra to Outlook/Exchange.

Outlook is not properly importing the contacts and is consistently importing only some of the data for each contact. So, I played around a lot with the import file and have found that if I delete out all the columns that have no data in them for any contact record, that Outlook imports no problem, perfectly.

So...here's my issue. I have multiple contact lists for each user that I am importing. We're talking about 100 different CSV files to sort through, some of which have at least 500 records (rows) in them. It is a lot of scrolling up and down left and right to find columns manually/visually that have no data in them.

Any manner in which I could add a row at the top of each CSV/excel file, input a formula, drag it across all columns that will tell me if there is data within that row? I tried using a filter, but because a lot of the data columns have no data in the first row across multiple columns, it doesn't seem to be accurate.

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I have a list of about 85,000 addresses and I know that there are about 35,000 duplicates in it.

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AAAA
500135500136
500136500135
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500138500137
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A B ....... J K
Prop1 Prop1Address Rent 100
Prop2 Prop2Address Rent 150
Prop3 Prop3Address Gas 70
Prop4 Prop4Address Water 60
Prop4 Prop4Address Rent 200
Prop4 Prop4Address Elec 80
Prop5 Prop5Address Service 90

I want the sheet to display a property on a single row so would look like as follows ...

A B ....... Rent Gas Water Elec Service Total
Prop1 Prop1Address 100 100
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Prop3 Prop3Address 70 70
Prop4 Prop4Address 200 60 80 340
Prop5 Prop5Address 90 90

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I have a list A2...A11

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Rvec is defined in NAME MANAGER as: =ROW(Sheet1!$A$2:$A$11)-ROW(Sheet1!$A$2)+1

In cells B2...B11 is this formula: =IF(ROWS($B$2:B2)

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Formula:

[Code] .....

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Private Sub CommandButton1_Click()
Dim shDest As Worksheet
Dim shSource As Worksheet
Dim Rw As Long

Set shDest = Sheets("BLOCKTIMES")
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With shDest
'B2 to column B; D4 to Column C; C3 to Column D...........

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Apr 3, 2014

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Data Currently: Solution should be:
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Nov 13, 2009

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A B
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gap
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charlie
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how would I get,

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also is it possible to have an if statement in 1 cell change the value of another cell?

e.g.
in a1
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removing empty rows from my set of data.

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I've made an example for you to try and explain it better - attached.

remove all of the rows that are completely empty, but leave any row that has any data in it (at any point), that would be awesome!

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Feb 17, 2014

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What modifications I need to make to my macro to be able to delete data/ranges from sheet "Form" and sheet "Training Cost" ? so if I delete range A5:D5 in sheet Form it will also delete range A5:D5 in Training Cost.

[Code] ......

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Mar 12, 2014

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I require only the non duplicate values to appear in the final cell, each separated with ';'.

My data is in row 2 of a spreadsheet and in every other column (A,C,E,G,I,K,M...for 45 instances in total).

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Oct 10, 2011

Currently trying to solve a niggling issue with removing duplicate row data from competition entry databases using the following code...

Code:
Sub remove_duplicates()

Dim lastrow As Long
Dim i As Long, j As Long

On Error GoTo errhandler

Columns("A:G").Sort Key1:=Range("A2"), Order1:=xlAscending, Key2:=Range("B2") _

[Code] ......

errhandler:
'MsgBox Err.Description
End Sub

What I need to happen is for duplicates to be based on both the name and email matching (columns A + B) and then remove all duplicate rows, whilst ignoring but preserving the content in columns C,D,E and F on those rows that remain. Column G contains either "Yes" or "No" depending on a users membership status. Sometimes duplicated data will contain identical name and email address but have different membership status in column G where someone was logged in when submitting a form the first time, and then logged out the next (potentially a mixture of the two over multiple times). Therefore I need any duplicate users who have different values in the G column throughout the database to be detected by the macro and we must ensure that the single row retained in the final non-duplicated list displays "Yes" in column G for that user.

Duplicate users who are always "yes" or always "no" work fine, its only the ones with mixed values for column G that need to be analysed and their return forced as Yes in the final list.

The final list should preserve the original column structure and thus be only one row per unique user.

The above code appeared to work the first time with a sample file, but when running the macro on one of my full size lists (3k - 5k rows) it returns 2 rows for each user who started off as a mixture of Yes/No... ?

Both rows will say yes in column G (so that part is correct!) but I have to re-run the macro again on the same dataset for it to remove the duplicate yes rows to get the list as it finally should be!

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Feb 9, 2012

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An example source file is found here: [URL]...

As you can see, there are many students who have received an award in all 3 terms, however there are also some students that only received standing for 1 or 2 terms.

I need to manipulate the data so that there are no duplicate names and all the data regarding Honour Roll standings and which term it occured in are all laid out in one row per student.

IDEAL COLUMN HEADINGS:

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I have an excel sheet with approx 30,000 rows of data.

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I have some software which basically pulls in keyword phrases from search engines and meta tags etc, including misspelled keyword phrases.

My problem;

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