I am wanting to replace part of a cell ( the first two digits) with nothing - blank

eg cell contains 441298871657 and i want it to read 1298871657
I am looking for a function to do this, i have tried using the finf and replace function but if 44 appears somewhere else in the value this will also be replaced.

I have a work problem where my spreadsheets have the following structure due to faulty optical character recognition:

Ringholm 8 G R hem.ag Bavik Postl 115 O Amtervik Rinman K H B dir Johannebergsg 34 Goteborg S Risberg L kass Mitandersfors Bogen

In some cases the letters in the beginning of the cells have been misread as a number (above S as 8), so I want to search and replace those numbers with the correct letter without changing the correct numbers at the end of the cells to letters too. Is there any way to write a search-and-replace code in VBA that will only implement the search-and-replace in (for example) the first five letter-spaces of the cell?

As part of a macro i do a find and replace on a range cells that replaces "/1" with nothing (""). Therefore 2/1 becomes 2, what i don't want though is if the de-nominator includes a 1 but not only 1 to keep the whole of the de-nominator, say 8/11 does not want to become 8/1.

I need a macro that will change the part of the formula that is "CI10001G" to the value of cell A2 which would basically be something along the lines of "CI10004D" so the formula would change to the following:

='H:Folder[CI10004D.xlsm]Sheet'!$C$5

And then this formula will then successfully look in the newly directly file path.

Can you cut out part of a number and replace it in another cell. For example

A1 come in as ###+### and it will not always be a three digts all the time but I would like to keep the number in front of the "+" in A1 and the number behind the "+" into A2 cell.

I've recorded a macro to replace the Australian telephone number area codes (at the beginning of each phone number) with international dialling codes. I also need to replace the first two digits ONLY of mobile ( cell) phone numbers which, in Australia, all begin with "04" (see last part of macro code below - column L:L).

With the code the way I've recorded it, if it finds "04" in another part of the number (e.g. 0411 104 111), the second occurrence of the "04" will automatically be replaced with "614" as well which I don't want. So I need some code to add so that the macro only searches and replaces those first two digits in that column. I hope I'm making sense?!

Sub ConvPhNo() ' ' ConvPhNo Macro ' Macro recorded 12/12/2007 by xxxxxxxxx '

I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)

I am looping in Excel to find "NUMBER OF EMPLOYEES". IF found I want to go up one row and replace the first 4 digits with " 9ZZ". The Line 1 data will alway be different so I just want to replace the first 4 digits. I don't want it to effect the rest of the line.

Example: Line 1 - 100 6300 BRCH TOTALS Line 2 - NUMBER OF EMPLOYEES

RESULTS NEEDED:

Line 1 - 9ZZ 6300 BRCH TOTALS Line 2 - NUMBE OF EMPLOYEES

Where RangeX is the text currently in the formula, and Data1 is a string that references a range in another workbook. Data1 is defined before the replace function.

I am working with a lot of data and have been making a table of statistical analysis for several rock types. I have it worked out to where i can filter the data and with the use of a bunch of IF functions, below, and it keeps everything the way I want.

The problem is I have to introduce new rock types, but if I just copy the formulas over i then have to go through hundreds of cells and switch sedimentary rocks to volcanic or whatever new class i have.

How this can be done faster. Maybe some way to say "find "text" within this range and replace" i can do it for actual values but when its embedded in a function im not sure.

I'm trying to 'find and replace' part of a filepath which is buried in hundreds of formula, but when I hit 'Replace All' a file navigation window appears. Hitting cancel simply bring up another window, and again and again, each time a replace is executed.

Is there a formula where it will find all that reads 07-06 and be able to change it to 08-06? Below are samples of formulas where I am looking to change 07-06 to 08-06 without having to go into each cell and manually changing 07-06 to 08-06:

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...). Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05 DuToitskloof Pinotage/Merlot/Ruby Cabernet 1999 Tradition Juracon 375ml

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))

As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.

Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).

Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 2003 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2))) As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

Does anyone have an idea on how to help with this?

Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.

However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.

I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.

=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)

I am trying to create a macro where it finds a a certain word in a column for example C. What i want it to do is find anything that says FWD_EUR and then replace that cell (e.g C2) with CASH_EUR_FWD and after it has done that it replaces the adjacent cell (e.g. D2) with EUR_FWD. I then want this to do the same with FWD_USD to CASH_USD_FWD and adjacent cell to USD_FWD.

I was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits

I found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:

I have pasted over 1300 numbers in a list, all of which need to have 5 digits. However, when I pasted the 5 digit number (ie 00003) into the cell, it omits the leading 0's.

Is there any way to get these numbers back to having 5 digits....and if it omitted the 0's, can I put them back all in one fell swoop?

I have a sheet with column A. This column A contains numbers from 1 number to 6 numbers.

So, one cell can have a '1' or a '999999' or any combination between them. Now this is the problem.

I want a formula that will fill those cells that don't contain a number up to 6 digits. So if a cell contains '254' I will like this formula to fill the cell like this: 000254.

This should happen with any number that don't have a number with six digits.

78 should be 000078, 78652 should be 078652 and so on.

find a formula or function where i can remove the last 4 digits from cells. I have a spreadsheet where there was might have been concatenation do where 4 digits were added to the end of part numbers in a cell. I need to remove just the last 4 digits so that I can do matches later on. Each cell has a different number of characters and i just need to remove the last for Example 154758NE20 or NFD148574DE11. Need to remove the NE20 and DE11 respectively.

During work this thing stuck me that i have a column A1 an amount like 12345663..now what i want in column B1 the same amount but except first 3 digits..for example instead of 12345663 i want only 45663 in column b..

i have attachmed excel file. in that file total 8 colums among them i kept 8th colum empty .

but i want name racks in that file. i knw..it will confuses u. but once u see my attachemts u will realize.

eg: if G2 =XA06-G-001 I2 will be XA only..(XA is rack Name) if G2 =XB06-G-001 I2 will be XB only if G2 =XC06-G-001 I2 will be XC only if G2 =XD06-G-001 I2 will be XD only

i mean to say..i want only first two alpabatics of G2 in I2..

I'm struggling to find a good formula or code produce the below. I have a column that contains a text string followed by spaces then a number. I need to sparate these into two separate cells.

OldNew NewD-EUROBANK PROPERTIES REAL E 4D-EUROBANK PROPERTIES REAL E4D-ACTIVE INVESTMENT SA 12-SYNT 567D-ACTIVE INVESTMENT SA 12-SYNT567RSK HYDRO-NWKR 25(NORWAY REG 1RSK HYDRO-NWKR 25(NORWAY REG1ADRILL LTD 1ADRILL LTD 1OFFSHORE LIMITED 1OFFSHORE LIMITED 1TRATA PLC 2TRATA PLC 2