I am wanting to replace part of a cell ( the first two digits) with nothing - blank
eg cell contains 441298871657 and i want it to read 1298871657
I am looking for a function to do this, i have tried using the finf and replace function but if 44 appears somewhere else in the value this will also be replaced.
I have a work problem where my spreadsheets have the following structure due to faulty optical character recognition:
Ringholm 8 G R hem.ag Bavik Postl 115 O Amtervik
Rinman K H B dir Johannebergsg 34 Goteborg S
Risberg L kass Mitandersfors Bogen
In some cases the letters in the beginning of the cells have been misread as a number (above S as 8), so I want to search and replace those numbers with the correct letter without changing the correct numbers at the end of the cells to letters too. Is there any way to write a search-and-replace code in VBA that will only implement the search-and-replace in (for example) the first five letter-spaces of the cell?
As part of a macro i do a find and replace on a range cells that replaces "/1" with nothing (""). Therefore 2/1 becomes 2, what i don't want though is if the de-nominator includes a 1 but not only 1 to keep the whole of the de-nominator, say 8/11 does not want to become 8/1.
View 4 Replies View RelatedI have a worksheet - sheet 1 like below:
00001 - $2000
00002 - $3150
00004 - $2010
00001 - $1011
I would like to look up customer number (such as 00001) and replace to Peter
sheet2 like:
00001 Peter
00002 Marry
00003 John
00004 Mac
Expect Output:
Peter - $2000
Marry - $3150
Mac - $2010
Peter - $1011
I have a formula in cell J2:
='H:Folder[CI10001G.xlsm]Sheet'!$C$5
I need a macro that will change the part of the formula that is "CI10001G" to the value of cell A2 which would basically be something along the lines of "CI10004D" so the formula would change to the following:
='H:Folder[CI10004D.xlsm]Sheet'!$C$5
And then this formula will then successfully look in the newly directly file path.
Can you cut out part of a number and replace it in another cell. For example
A1 come in as ###+### and it will not always be a three digts all the time but I would like to keep the number in front of the "+" in A1 and the number behind the "+" into A2 cell.
Can you do this my a SEARCH("+",A1)LEFT("+)
Here is the code I'm working on:
I want this code to replace the value of s with the value of a cell.
sub Macro2()
Dim s As String
s= value of (cell F2)
Range("I8").Select
ActiveCell.FormulaR1C1 = "='[(s).xlsm]Payroll Computation '!R8C11"
End Sub
I need to find the "x" in range C2:C44 and replace it with a value (variable) specified in cell I2
The catch is that I then need to be ablt to change that character when I2 changes.
Coloum C
*VER
*T’x’STATUS
*ON
*OFF
*T’x’BANDS
EG
I2 - Variable = B
*T’x’STATUS will become *T’B’STATUS
I2 - Variable = A
*T’x’STATUS will become *T’A’STATUS
But " *OFF " should not change.
I can change *T’x’STATUS to *T’B’STATUS but then I can change *T’B’STATUS to *T’A’STATUS
Please see attached example file as it shows it better than I can explain it.
I've recorded a macro to replace the Australian telephone number area codes (at the beginning of each phone number) with international dialling codes. I also need to replace the first two digits ONLY of mobile ( cell) phone numbers which, in Australia, all begin with "04" (see last part of macro code below - column L:L).
With the code the way I've recorded it, if it finds "04" in another part of the number (e.g. 0411 104 111), the second occurrence of the "04" will automatically be replaced with "614" as well which I don't want. So I need some code to add so that the macro only searches and replaces those first two digits in that column. I hope I'm making sense?!
Sub ConvPhNo()
'
' ConvPhNo Macro
' Macro recorded 12/12/2007 by xxxxxxxxx
'
'
Columns("C:C").Select
Selection.Replace What:="(", Replacement:="", LookAt:=xlPart, _ ...........
I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)
View 2 Replies View RelatedI am looping in Excel to find "NUMBER OF EMPLOYEES". IF found I want to go up one row and replace the first 4 digits with " 9ZZ". The Line 1 data will alway be different so I just want to replace the first 4 digits. I don't want it to effect the rest of the line.
Example:
Line 1 - 100 6300 BRCH TOTALS
Line 2 - NUMBER OF EMPLOYEES
RESULTS NEEDED:
Line 1 - 9ZZ 6300 BRCH TOTALS
Line 2 - NUMBE OF EMPLOYEES
I want to replace a part of a formula with its value.
eg say I have a formula =vlookup($a55,$a$2:$e$50,column(),false).
I want to replace column() with its value. There will be plenty of cells with this formula What can be the best way of achieving this.
I am trying to modify a cell formula with the Replace function.
Code:
The Formula in the target cell =
='C:Documents and SettingsHoliday macro[Holiday2011.xls]Year 2011'!C5
I am using the below code but it returns just the end portion ='Year 2012'!C5
where I expect just the year to change
='C:Documents and SettingsHoliday macro[Holiday2012.xls]Year 2012'!C5
Where last year = 2011
Yr=2012
Range("C3").Formula = Replace(Range("C3").Formula, LastYr, Yr)
I'm trying to replace text in formulas with text that is gathered from a macro. For example:
Cells.Replace What:="RangeX", Replacement:=Data1, LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False
Where RangeX is the text currently in the formula, and Data1 is a string that references a range in another workbook. Data1 is defined before the replace function.
I am working with a lot of data and have been making a table of statistical analysis for several rock types. I have it worked out to where i can filter the data and with the use of a bunch of IF functions, below, and it keeps everything the way I want.
{=MAX(IF($H$2:$H$22="sedimentary rocks",$W$2:$W$22))}
The problem is I have to introduce new rock types, but if I just copy the formulas over i then have to go through hundreds of cells and switch sedimentary rocks to volcanic or whatever new class i have.
How this can be done faster. Maybe some way to say "find "text" within this range and replace" i can do it for actual values but when its embedded in a function im not sure.
I'm trying to 'find and replace' part of a filepath which is buried in hundreds of formula, but when I hit 'Replace All' a file navigation window appears. Hitting cancel simply bring up another window, and again and again, each time a replace is executed.
View 3 Replies View RelatedI'm trying to create a macro to replace a link on a formula.
The formula is as below
='[Players Report 31121999.xls]Player1'!$AK$23
Where 31121999 is the date. there's a workbook everyday with different sheets for every player
I want to have a macro that gets the date I inputed in another cell and changes the date in the formula I displayed above (just changing the date).
I've got a problem with my workbook.
It gets datas from another workbooks and contains cells with formulas like these:
='C:YEAR[2006-ab.xls]'!A12
='C:YEAR[2006-bc.xls]'!C18
et.c.
Is it possible to write a code in VBA to replace a part of formulas above?
I would like to use some vba code to search range T3 to U500
and search for the word "all out" which will appear within the text of some cells - in the format :-
64 all out(36 overs)
and replace it to
64 all out(50 overs)
the two digit total at the beginning of the line can be 1-3 digits and the number of overs can only be 1 or 2.
Is there a formula where it will find all that reads 07-06 and be able to change it to 08-06? Below are samples of formulas where I am looking to change 07-06 to 08-06 without having to go into each cell and manually changing 07-06 to 08-06:
= SUM(IF('07-06 data'!$C$2:$C$103="CAM",IF('07-06 data'!$I$2:$I$103="INCOMING - NEW",1,0)))
=SUM(IF('07-06 data'!$C$2:$C$103="MSP",IF('07-06 data'!$I$2:$I$103="INCOMING - NEW",1,0)))
=SUM(IF(('07-06 data'!$C$2:$C$103="CAM")*('07-06 data'!$I$2:$I$103="INCOMING - NEW"),'07-06 data'!$J$2:$J$103))
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
Structure:
I have a worksheet with the cells in one of the columns having html tags inside of each cell.
The tags vary by location within the cell and there are anywhere from 0-10 tags per cell.
Column A is the text string. Inside these cells are the tags. The tags are of form
<A href="/mortgagecenter/article_alias">
The
<A href="/mortgagecenter/
and
">
parts are true for every instance of this string....
....article_alias is a variable per each string. I have columns B and C which are the aricle_alias names and article_ID's, respectively.
What I am trying to do:
From the [quote]<A href="/mortgagecenter/article_alias">[quote]
I would need to replace the
article_alias
portion with
ArticleID&"-"&article_alias
I am trying to create a macro where it finds a a certain word in a column for example C. What i want it to do is find anything that says FWD_EUR and then replace that cell (e.g C2) with CASH_EUR_FWD and after it has done that it replaces the adjacent cell (e.g. D2) with EUR_FWD. I then want this to do the same with FWD_USD to CASH_USD_FWD and adjacent cell to USD_FWD.
View 2 Replies View RelatedI have over 16000 cells with different information in them, each cell is unique. There are parts of these cells that have similar information.
I am looking to search part of the cell, and replace the whole cell with my new description, so I can run pivot tables on it.
I was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
View 5 Replies View Relatedadding the sum of digits in a cell using VBA. For eg: in A1 if I have 12345 I need the sum of 12345 (15) in cell B1.
View 3 Replies View RelatedI found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:
12345 45
26548 48
21854 54
211ae ae
I thought it was a =right or something.