Select Column Of Unknown Length Using VBA
Jul 14, 2014I have a column that begins in the same place all of the time (Cell C6) however the length of this column can vary. How can I copy the column using VBA?
View 2 RepliesI have a column that begins in the same place all of the time (Cell C6) however the length of this column can vary. How can I copy the column using VBA?
View 2 RepliesTrying to sum up a column that has an unknown length. This is a canned Excel form that is saved within a software system and is used to create customized documents. Usually, I would enter the table name.field name in a cell to pull the data from various parts of the system.
In this case, that data resides in AA234 of my customized Excel sheet. When the user retrieves this doc from the system, the data could run several rows, starting from AA30 to AA255. So, in my "Total" cell, I've entered =SUM(AA1:AA255), so it will just add up whatever is in the column, regardless of how long it runs upon document generation. When I try to pull the document, I get "=SUM(#REF!)" in that field instead.
I need to write a spread sheet that will calculate the length of 2 unknown sides of a right triangle using the following information.
Here is what I know
1. I have a right triangle
2. I know the length of the hypotenuses
3. I know the ratio between the length of the other 2 sides
I need to write and Excel file that will solve for the length of the other two sides
The math look like a^2+b^2=c^2
with c being known and the ratio between a and b known
so I have been googling to figure out how to write a macro that will select every other column on my workbook. All that keeps coming up is conditional formatting, which I do not want. I am not trying to highlight the columns in alternating colors, I just want to select them.
I am starting at column F and I would like it to search until the end of the columns and select every other column ending with the last column with data in it.
I know I could search by a specific row and tell it to find the first blank cell then offset it, but there is no particular row that will always have data in it, so I guess it needs to check by column until it finds the first column without any data in all rows and then offset it.
Anyone know what I am talking about here?
I know it should be fairly simple but I couldn't seem to find any answers anywhere else.
Also, anyone know any good websites that have definitions for some basic macros? I'd love to start learning how to write this stuff on my own.
I am having difficulty with creating an IF formula that will only show 9 digit numbers. If the cell the formula is looking at has less or more than a 9 digit number in it, or the cell ha no value, the result will be blank.
View 6 Replies View RelatedI've been working on a spreadsheet and these forums have been a great help. I'm now at the very last section and, surprise surprise, it's also the hardest!
I'm creating a stock trade recording sheet. I have a userform ask the user to enter a date, a time, the number of stock purchased, and the price of the stock. These are then entered in a new row.
Now what I want to do is have summary cells which say how many stocks were purchased and the total profit made for each day. Since each time is given its own row, I can't know in advance which rows to sum over. I also don't know on which days a trade was made. So a summary cell should only exist if a trade was made that day.
Could I do something like.... check if the date matches then sum over all the values for that date? So if column A has the dates, can I say "Search which rows in column A have this date" then "for those rows, sum column C"?
Also, how would I create a a row for each traded date's summary cell and enter the date in it? I've attached a spreadsheets which manually demonstrates what I want to do (no macros) and a spreadsheet with what I have so far (basic macros).
Any and all help much appreciated, I just need to get my head around creating and dealing with variable ranges. Is that a really advanced task? I don't think this is a one line solution so please bear with me while I make mistakes!
I'm trying to define the last row in a column which is determined from a find command. It's quite a large sub, and the rest is working properly, so I'll just post the (still rather large) troubling section.
'startingPoint is declared as a range. Destbook, reporttarget and FullControlName all exist.
'this sets StartingPoint to a one cell range in a sheet named from a custom class in a workbook named from variable destbook
Set StartingPoint = DestBook.Sheets(ReportTarget.Name).Cells.Find(what:=FullControlName, searchorder:=xlByColumns)
WriteCol = StartingPoint.Column
'this changes the range to include the whole column of the existing range
Set StartingPoint = Range(StartingPoint.EntireColumn.Address).....................
In the code below, a formula is placed in column F to compute the total of that column. I first find the number of rows and place the formula in the cell below it. I'm dividing the sum by 2 since there are subtotals in the column.
Sub AddColumn()
Dim NumRows As Long
NumRows = Range("A65536").End(xlUp).Row 'get the row count
NumRows = NumRows + 1
Worksheets("Report").Cells(NumRows, "F").Value = "=SUM(F9:F308) / 2"
End Sub
The problem with the code is that I don't really know that the last row in the column is F308. I need to replace that part with a variable. It will be something like this (which I know is incorrect):
Worksheets("Report").Cells(NumRows, "F").Value = "=SUM(F9:NumRows) / 2"
How would I use a variable in the SUM function in place of the cell names? Should I even be placing the formula in a cell, or should I compute the sum in the macro and place the value in the cell?
i can't seem to figure this one out.
I attached a file showing how i am trying to format data (the second tab).
The big issue is the counting to format. (the formatting itself is obviously easy.)
The number of columns is not always standard so i need to count for it.
the number of rows in each "room number" is also not always standard, which means i also need to count for those.
If anyone has had experience trying to do something like this i would appreciate the help.
i know it is possible because i had one that someone had given me years ago, unfortunately i lost it in a hard drive failure...also years ago.
if it isn't obvious what i am trying to do, let me know and i will try to be clearer.
im trying to find and delete records within a column if they occur twice. this works great right now but I want it to exclude the top 8 rows... i think it might have something to do with the LookAt:=xlPart constraint ...
View 4 Replies View Relatedi have a sheet for monitoring sickness. i have used a macro before which automatically selects a range and emails it to recipients when i press a button. what i would like to do is have excel automatically choose the range for me based on today's day. in the attached example i would like column "A" copied along with the 5 columns before today's date, today's date column and also the 5 columns after today's date. paste the lot into an email and send. (i have highlghted the parts i would like copied and pasted into an email based on today's date (21st july).
View 4 Replies View RelatedI've set up a filing system which saves sheets/ workbooks based on the value of a cell - Range("B1") Everything works great apart from when ThisFile String length exceeds 31 characters which you may know is the max useable character length for a sheet name - I had no idea! 8-0
Is there a way i can check if string length exceeds 31 characters then, if it does, shorten it to 31 characters?
[Code] .....
How to create a code formula to calculate the arc length from a given chord length?
If you know the radius of the major circle.
Say the chord is 50mm and major circle dia is 72mm (radius 36mm)
arc from chord.jpg
My worksheet contains data with the reaction times on a psychological test. Each respondent in the test has 280 rows in my excel sheet.
The 'perfect' length of the row, is from A to M. When an error is made in the test, the length of the row will increase. So the error length can be A to AA.
For me it is important to analyse the error. So I would like to give a perfect row length, the value 1, and an error row length a value 2.
So, in conclusion:
If:
Cell length = A1 - M1? --> Copy A1 B1 C1 (A B Cof that row) to Sheet3, and give D1 in sheet 3 the value 1
Cell length >= A1 - M1? --> Copy A1 B1 C1 (A B C of that row) to Sheet3, and give D1 in sheet 3 the value 2
I have two columns, one with an account number (call it A) and another with a vendor id (call it B). I need the length of the number in column A to be truncated to 10 characters by just deleting any additional characters after 10. That should be based on whether or not the corresponding cell in column B equals the following number "147212336". Right now, my code edits the ENTIRE column A, not just the cell in the same row.
I know it's because I'm using a "FOR EACH CELL" argument but I don't what else would work.
Code:
Set acctlengthrange = Range("N2", Cells(LastRowB, "N"))
Set dplrange = Range("P2", Cells(LastRowB, "P"))
With dplrange
If cell.Value = "147212336" Then
For Each cell In acctlengthrange
cell.Value = Left(cell.Value, 10)
Next
End If
Next
I have a worksheet which already has some built in formulas which take the data in columns V and W, and use them to build other coding in column P. The trick is that the coding created in column P will be six times as long as the source data in columns V and W.
I.e., a single row containing "Sample1" and "Sample 2" in columns V and W respectively create the six following rows in column P:
Row 1:
Row 2: TMUnknown
Row 3: tested1
Row 4: Sample1
Row 5: Sample2
Row 6:
I want to be able to select the accurate length of Column P, which should be 6x as long as columns V or W. Any dynamic way to do this? (Since the amount of data pasted into columns V and W will change each time I use this worksheet.) I know how to select set ranges, but not how to adjust them as multiples of the length of another column
I have a range of text data in a column and need to get the text lengths to no longer than 60 characters.
The remaining data then need to be copied in a cell inserted below the original.
I have been playing with the following code…
Hello All:
I have the following type information in thousands of cells. I need too isolate the Width and Length from these cells. The width and the length are the two numbers on each side of the "X".
RAPITONE C2 10 X 10 100
RAPITONE M2 10 X 10 250
RAPITONE M2 10 X 10 250
RAPITONE M2 10 X 10 250
RAPITONE M2 10 X 10 250
RAPITONE M2 10 X 10 250
RAPITONE M2 10 X 10 250
RAPITONE M2 76 EI 42 X 100 ROLL
Formula on how to limit character length limit in a column in excel. I would like to limit the column to 32 characters
View 2 Replies View RelatedUsing Excel 2003, Column E has a varying and unpredictable number of rows, which only the final 252 rows are of significance. I need to compute the following formulas, here written in English as I can't determine the proper terminology to accomplish this task in Excel:
Final Row with a number in Column E/average (final 252 rows with numbers in column E)+
Final Row with a number in Column E/average (final 126 rows with numbers in column E)+
Final Row with a number in Column E/average (final 63 rows with numbers in column E)
Once again, what makes this not straightforward for me is the column may have wildly varying numbers of rows.
I have a set of data in Which in column A is the name of organisation.
If string in col A is longer than 50 I need to split in and put in col B.
That would be simple however I need to do it in a smart manner: i.e. cut it to the nearest full word.
Example:
THIS EXAMPLE NAME IS TOO LONG TO FIT INTO 50-TEXT CRITERIA SO I NEED TO DIVIDE IT INTO TWO STRINGS
Incorrect; length = 98
THIS EXAMPLE NAME IS TOO LONG TO FIT INTO 50-TEXT
Correct; trimmed down to 48.
My question is about formula that can detect spaces and depending on those trim the string down adequatly:
to 50 if 50th char is preceeded by space; if not then check where is the next space going towards left. Once you find it cut the string there.
What formula I can use to get desired effect?
I have a table in excel in which every line has as many values as the days of the month (e.g. 31 values first row, 28 the second..) and it goes from January 1948 to July 2014. So it ends up having around 800 rows.
I need to put all of those into a column, but it gets hard because the rows have different lengths. I have seen in this forum some solutions that apply well when the table is regular, but I'm stuck in trying to get a solution for when it's not. I have tried to record a macro using TRANSPOSE, but then I cannot change the cells into this formula in the editor in order to create a loop.
I also have to consider leap years.
I have a spreadsheet with numbers like this
9404388
9404374
9404391
9405695
38301663
9409724
1791016
9435145
9530758
9440464
9441182
71000569
9467438
There are a thousand numbers like this, I was wondering how I can move the cells with 7 numbers to the right column, and keep the cells with 8 numbers where they are (or move them to the 3rd column to the right)
I'm trying to sort by a column with one to four digit numbers, any of which may be followed by a single letter, i.e. 1,2,3 4A,5, 10,11A,75,101A,600,705,1010B,1011A.
I'd like them to sort in the above order. I am only able to have excel 2003 sort all of the numeric cells first, followed by the cells with the alpha character.
I've recorded this Macro to sort the cells in a column alphabetically if any cells have content.
I would like to use the Macro on the whole workbook however the AB column range varies between the worksheets.
How should I adapt this Macro to sort simply to the END of AB column??
' PWRII Macro
'
'
Cells.Select
[Code]....
I have a column of contract numbers of varying length. I want to run a sumif of all of the values on my reference sheet that have the contract number beginning with the contract number in my listing. All of the the contract values in my reference sheet are very long. Since the numbers I am working with vary in length, i don't know how to match this string in the sumif function
I want something like this
=SUMIF('Reference Sheet!$A$5:$A$13410,LEFT("", LEN('Select Contracts'!$C6))='Select Contracts'!$C6,'FINALIZED DATA'!$H$5:$H$13410)
Is there a way to refer to the range in the sumif function,
Ive written the macro below to sort Column A according to the length of the cell values in Ascending order. Ive done this by writing the length to Column B for each value and then sorting on column B. Surely there is a more elegant method, perhaps using arrays.
Sub SortIt()
Range("A1").Select
Do Until IsEmpty(ActiveCell)
ActiveCell.Offset(0, 1).Value = Len(ActiveCell)
ActiveCell.Offset(1, 0).Select
Loop
Columns("A:B").Sort Key1:=Range("B1"), Order1:=xlAscending
End Sub
I'm trying to write a simple VBA code to loop through values in the range A14:A138 and based on the value (of a possible four values) in any row of that range, populate the adjacent column in the same row with a conditional result. For example if A14 = "Cat", then B14 = "I"; if instead A14 = "Dog", B14 = "II", etc. If there is no value in column A, the result should be blank (i.e. "").
I believe are in coding the destination range since I can get it to work for just one cell in B! Below is my code that is not working...
[Code].....
I have 02 separate excel workbooks
01 = source file
02 = data list
The workbook "source file" contains all the data
The workbook "data list" contains data for work with Drop-down list. And i can easily select my required description by just dropping down the list.
In case, i have new description i add it in the source file and it is updated in the working "data list" sheet.
This applies to Field device column also. But i want to improve the selection criteria by creating such script or formula which could check the input of the description and automatically selects the field device and its relevant signal (output type).
Screen shot is attached : Automatic Selection.jpg‎
I am trying to find a macro that look for last non empty cell in column A and them paste a formula/comment in all cells of column B.
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