I am having difficulty with creating an IF formula that will only show 9 digit numbers. If the cell the formula is looking at has less or more than a 9 digit number in it, or the cell ha no value, the result will be blank.
View 6 RepliesHow to create a code formula to calculate the arc length from a given chord length?
If you know the radius of the major circle.
Say the chord is 50mm and major circle dia is 72mm (radius 36mm)
arc from chord.jpg
Can I limit the text length in a cell that contains a formula? You may say "Limit the text length in the input cell". That can't be done because the formula in the resultant cell takes text from two other cells in addition to the input cell. I need to limit the overall text length to, let say, 50 characters.
View 7 Replies View RelatedI have a column that begins in the same place all of the time (Cell C6) however the length of this column can vary. How can I copy the column using VBA?
View 2 Replies View RelatedI need to find text within middle of a string.
Character before required text is say AAA
Character after required text is say BBB
Text required can vary in length.
Extract text and place in another column.
All text in a single column, required text not in every line. but
does repeat.
I have a cell (B2) I would like to apply multiple data validations to.
I know I need to use the custom formula option but don't know how to write the formula.
I don't even know if it is possible, but here is what I'm after
I need to make sure the cell is 4 digits long
I need to make sure the cell starts with a zero (Because the cell starts with a zero I have it as a text cell)
I need to make sure the 2nd number is not 0 if A2 begins with 5 (A2 is also a text cell).
I've set up a filing system which saves sheets/ workbooks based on the value of a cell - Range("B1") Everything works great apart from when ThisFile String length exceeds 31 characters which you may know is the max useable character length for a sheet name - I had no idea! 8-0
Is there a way i can check if string length exceeds 31 characters then, if it does, shorten it to 31 characters?
[Code] .....
If I have a cell with this info: [6126]BOB SMITH
What formula can I use to get BOB SMITH. The length of the name will vary. The number will change, but will always be 4 digits and will have the brackets. [XXXX]
i have tried to create a userform thru which data is to be entered. so that the data will be printed on a worksheet. here there are few text boxes, in which the number of digits should be equal to 14. after filling the userform when i click the print button if it is less than or more than 14 a pop up msgbox should be displayed with OK button and the cursor should go back to that particular text box. i have written the following code, but it has a problem. even if the total no of digits are 14 the msgbox is displayed.
say the text box name is Roll no
If txtRollNo.MaxLength 14 Then
MsgBox "Roll No should be of 14 digits", vbInformation + vbOKOnly
txtRollNo.SetFocus
Exit Sub
End If
My worksheet contains data with the reaction times on a psychological test. Each respondent in the test has 280 rows in my excel sheet.
The 'perfect' length of the row, is from A to M. When an error is made in the test, the length of the row will increase. So the error length can be A to AA.
For me it is important to analyse the error. So I would like to give a perfect row length, the value 1, and an error row length a value 2.
So, in conclusion:
If:
Cell length = A1 - M1? --> Copy A1 B1 C1 (A B Cof that row) to Sheet3, and give D1 in sheet 3 the value 1
Cell length >= A1 - M1? --> Copy A1 B1 C1 (A B C of that row) to Sheet3, and give D1 in sheet 3 the value 2
Column M:
##/##/#### | Variable Length Text-####
Example:
01/06/2014 | Daniel Trimble-4048
I need to parse out the different parts of Column M.
In Column R -- "Close Date", I'm successfully using:
=LEFT(M2,FIND(" | ",M2)-1)
...to extract the close date of the donation.
In Column S, I want to list the donor name--which is all of the text after " | ", and before the "-".
I don't need anything after the hyphen, and fortunately in this data, no one's name has a hyphen in it.
The Close Date is working fine for the LEFT and FIND functions, but for the life of me, I can't seem to get MID to work for the variable-length text. The text will always start in the same position -- 14, as the date and delimiter are standardized. And the last 5 characters of the text are not variable in length, so they can be cut out completely.
How do I use MID to extract everything starting at position 14, and stopping 5 characters short of the end of the text?
I'm trying to avoid using merged cells or text wrapping with altered row height to display some text in multiple rows - similar to using centre across selection to have a header across multiple columns without merging. The guys that use the sheet type a comment that is relevant to five rows and the easy solution here would be to just type the first portion of the comment in the first row (about 30 characters will display in the column width available), then put the next 30 characters in the next row and so on but the guys keep getting lazy and merging the cells so they can type the comments more easily. I can lock the sheet or force validation but I think there's a better solution.
I can effectively "wrap" the text across the five rows the header is relevant to by using a formula to pick up everything except the first 30 characters of each cell. Ie if they type whatever they want in cell B16 then I can use this formula to break it in to 30 character lengths to "wrap" it in to the next four rows:
=IF(LEN(B17)>30,RIGHT(B17,(LEN(B17)-30)),""),
And I'm sure it would be easy enough to use search with the formula to break it where there is a space in the text so partial words don't flow over.
BUT because the text ends up slightly different widths I want to use formats to force only 30 characters to display (whilst keeping the remainder of the text string intact). I can't figure out the syntax to format only 30 text characters to display but you can easily do it with numbers and dates and so on.
I have a range of text data in a column and need to get the text lengths to no longer than 60 characters.
The remaining data then need to be copied in a cell inserted below the original.
I have been playing with the following code…
I use VLOOKUP with text (to return comments made by people that I have copied in another sheet). The problem is that sometimes, it doesnt copy the whole comment.
Apparently there is a limit for the amount of text VLOOKUP can copy: after a LEN() test I have found that I cant copy texts longer than 255 characters.
Is there a simple way to make the VLOOKUP work even if the text is more than 255 characters long ?
I have a cell with 200+ character, I only want the 40 first character is there a function that will give me only those 40 first character or do I have to use a "=len" and manually remove the extra characters?)
View 2 Replies View RelatedI have 5 columns with data in each
I want to create a 6th column that looks to the columns on the left with data in ti and concatenates all data in the 5 columns and puts it into one cell in the 6th column however put a space between each break of data so that it can be distinguished which bit of data was in what column previously.
The challenge is the new 6th column can only contain 30 characters - When it exceeds 30 characters then create a 7th column and put the rest of data in the 7th column, again the 7th column can only have 30 characters so if exceeds this then put the remaining characters in a 8th column
There will never be more than a total of 90 characters in the original 5 columns so there will only need to be scope for a maximum of 3 additional columns
So for example
Column A had two words in it that totaled 20 characters (the space between the two words is also counted as a character)
Column B had two words in it that totaled 20 characters (the space between the two words is also counted as a character)
Column C had a word that contained 10 characters
Column D had a word that contained 5 characters
Column E had a word that contained 10 characters
Then the result would be
Column F would only have the data originally held in Column A (because it can't include Column B's data as this would exceed the 30 characters)
Column G would have data that was originally held in column B and column C - with a space between B and C data
Column H would have data that was originally held C, D and E - with a space between C, D and E data
Another point to consider is if in one of the orginal 5 columns had say 3 words in it and lets say the 3rd word is the word that exceeds the 30 character limit, then the whole of the third word is to be carried oved to the next new column, I can't have words cut in hlaf with one half in Column 'F' and the other half in Column 'H' for example.
I am using the code below to import a fixed-length text file into Excel. As the macro is written, it imports starting at the first line of the text file. How do i tell it to start importing at line 1000 and above?
View 2 Replies View RelatedI'm having a bit of trouble with a macro designed to read the length text in a cell and if it = a certain length then perform an action (in this case Text to column)
Here is a small sample of the data I'm working with:
Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<
Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<
Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<
Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<
Tue 02/11/2014
LastBootUpTime
Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<
*End Sample*
The text length I want it to perform the action on is highlighted with "<<" if the length of text does not meet the required number then I want the statement to skip and move onto the next one.
I have the text to column code already done with relative references however the long text string I want the statement activated on is not always present which means that the pattern (0,3) is not always consistent.
I am trying to use a For loop to measure the lenght of text in 10 text boxes on a user form so I can run a check but can't think of a way to do it. This is the best I have so far...
View 4 Replies View RelatedWhen a number is entered in cell S3, it triggers formulas throughout the worksheet to populate the it with information from another sheet. If the length of the text in B6 is greater than 80, the font size for B6 only should be 8; if the length of the text in B6 is less than or equal to 80, the font size for B6 should be 10. Regardless of the length of the text in B6, the font size for the rest of the sheet should not be changed.
I tried the following
Option Explicit
Private Sub Worksheet_Change(ByVal Target As Range)
If Target.Address "$B$6" And Target.Count > 1 Then Exit Sub
Dim cnt As Long
cnt = Len(Cells(6, 2).Value)
If cnt > 80 Then Cells(6, 2).Font.Size = 8
ElseIf cnt < 80 Then
Cells(6, 2).Font.Size = 10
End If
End Sub
Am trying to devise a formula that will allow me to extract a date (not stored in date format or recognizable by excel as such: "DEC1/09") and then manipulate it so that excel can recognize it and change it to a "1-Jan-01" form. Problem for me is that functions such as LEFT MID and RIGHT are very specific and sensitive obviously to any additional characters. some of my dates are preceded by "CAN BND 4.25/09"; "CANB BND 4.25/09"; "BC BND 4.25/09" and so on, you get the idea im sure that they are of differing lengths. The dates are equally strewn around as some (these are bond maturities) are 1st of the month while others may hold dates in the middle-end...15th, 30th, 31st etc.
is there a formula that will recognize the dates in the text strings regardless of string length and then a subsequent formula to manipulate the date to proper format?
i.e. "CAN BND 4.25/09 DEC1/09" and "CANB BND 4.25/07 JUN15/07"
Converted into: "01-Dec-09" and "15-Jun-07"
Not that the other parts of the string don't matter, already have macro that can recognize and rip bond coupons.
Hey I got a long String like this "[...] increase of x.xx% [...]".
I am trying to extract only the percentage number which can be of variable length, so maybe 900.99% or 9.99%.
I tried this formula:
=MID(G14,SEARCH("%",G14)-5,5)
but this one doesnt bring the right results as the percentage figure is often not exactly 5 characters long.
I think it's an easy one but for the life of me I can't get around it. ccasionally while re-typing data in fields with the intention of saving-as a new file, an error message appears saying "no more than 20 characters" This happens even when the number of characters is LESS than 20! I have tried clearing cell contents, copying & pasting, re-setting conditions/parameters for columns/rows etc., and nothing seems to work with any consistency. Instead of looking for a work-around solution I'd like to find the actual corrective action.
View 5 Replies View RelatedI need to write a Excel VBA (2003) code that can arrange the cells of one column based on the character length. An example is this:
Column Data before Running VBA
(Column A)
cat
oranges
apple
Column Data after Running VBA
(Column A)
cat
apple
oranges
I been doing this manually by using the LEN() command in an adjacent column (Column B) and sorting Column A. based on Column B. However, I wish to do this all in a VBA code that does not rely on how many rows are in Column A. I have dozens of excel sheets with various number of rows for Column A. Therefore, the VBA code has to also figure out when the last non-empty row is in Column A. Can anyone offer their suggestions to my problem?
i need a formula that looks up a range on sheet 1 coloum a and returns the value in column b, unless the value in column c is less than 5 letters long/ or not equal to a time format if this is the case it should return the value in column c
[code]
=IF(LEN(VLOOKUP(A6,'look up'!A6:C18,3,FALSE)>6),VLOOKUP(A6,'look up'!A6:C18,3,FALSE),VLOOKUP(A6,'look up'!A6:C18,2,FALSE))
[code]
this is my effort but it returns value in the the middle every time
I'm trying to use an if statement with a LEN function, i want to say if column O2 is 5 characters long then populate with Y if not populate with N.
I have tried.
=IF(LEN(O2,5),"Y","N"
but it doesn't work?
Excel 2007-2010. I'm using match(string, range,0) but there must be a limitation on the length of the string since I know the string is in the range but it returns #value as if it is not found. Is there a VBA solution to get around this without having to loop/cycle through the entire range?
View 4 Replies View RelatedCan anyone provide a formula to be used in data validation that will control text length (6 digits) and restrict duplicate entries. The best formula will prevent anything other that 6 digits, but question the user regarding a duplicate entry.
For example: if the user enters 123456 no problem, but if 12345 is entered, Excel validation would not allow. If the user enters 123456 again, Excel's validation window would allow but the window will pop-up and ask to confirm.
Imagine that I have this list of thousands of customers, who are listed in column B in the format "customer no+space+customer name".
Now I want to extract ONLY the customer no from the text string in column B and insert it as number value in column A on the same row.
Would have been easy with "Left" command, but as the customer numbers have variable length, I have a problem.
Is there a way to change the text in a cell to proper apart from 2/3 letter words which I want to keep as upper? Basically can it ignore all words that are 2 or 3 letters long, but change all other words to proper text?
View 3 Replies View Related