SpinButton For Images Control

Sep 28, 2009

The script it's almost all complete and it'already working. How works this script:
From the Combobox_click i load a txt file, the script from the txt file get only the first column of the file. Its a list of numbers.

When this list of code numbers it's loaded in the Combobox_click, for each code number in the image combo box there is a one corrisponding image. For the images folder in the cell J2 the is a one Path reader. the scrip work perfectly.

What i need:

As you can see, under the image combo box, there is a SpinButton.
I need that by clicking the Forward or Back button i can go forward or back of the images list.

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Spinbutton Unprotect...

Dec 25, 2008

When I protect the worksheet with the spinbutton, the spinbutton is no longer accessible. How can I modify the code below (provided by Leith Ross) to make the spinbutton accessible in a protected sheet?

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Jun 12, 2014

I have a spinbutton on a userform. Here is the section of code for SpinUp:


Normally, I wouldn't hard code an address in like this, but I was given a last minute project to present on Monday, so it's down,dirty, and quick. Anyways, the adjacent cell "O7" has a formula referencing another page. When I spin the spinner it activates the correct cell (and continues to do so as long as I press the button), but here's the wierdness: cell "07" formula disappears, leaving the existing value in it. It's like it copy pastespecial values.

I've stepped through the code and it's not referencing any other procedure. It happens on this line:

[Code] ....

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Spinbutton Incrementing Crashes Workbook

Apr 3, 2008

I use spinbuttons to increment 3 data cells (C7:C9). These cells are used as entry data for some calculations and also trigger some macros via change event. Every time I use them the workbook crashes, this is only since I modified one of the instantiated macros that sorts a table on another sheet. See below the spinbutton code with the call of the macro and further the code of the sorting macro:

Private Sub SpinButton1_SpinDown()
Range("C7").Value = Range("C7").Value - 0.05
End Sub

Private Sub SpinButton1_SpinUp()
Range("C7").Value = Range("C7").Value + 0.05
End Sub

Private Sub SpinButton2_SpinDown()
Range("C8").Value = Range("C8").Value - 0.05
End Sub......................................................

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SpinButton To Increment By Decimals Not Whole Number

Sep 2, 2006

Iím using this code to change the value of an active cell with a spinner named: 1.

Private Sub Worksheet_SelectionChange(ByVal Target As Range)
Dim lNum As Long
If IsNumeric(Target) Then
lNum = Target
If lNum = Target And Target >= 0 Then
With Me.Shapes("1").ControlFormat
.LinkedCell = vbNullString
.Value = Target
.LinkedCell = Target.Address
End With
Me.Shapes("1").ControlFormat.LinkedCell = vbNullString
End If
End If
End Sub

The problem is, that whenever I click or activate a cell its value automatically changes to 0. The spinner works just fine modifying the value of the activated cell. The problem is that this code somehow causes all the decimals such as 0,3 0,1 or 0,8, entered manually, to change to 0. This way only integral numbers, such as 1, 45 or 100 are accepted. I must truly say I have no [no need to swear - mod] idea how to fix these problems meaning the automatically inserted 0 and the fact that the sheet doesnít accept decimals changing them to an integral number.

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Jan 1, 2009

I don't know if title is understandable, English not being my tongue, anyway here's my problem, the current value must be increased or decreased by 0.01 if it's between 1 and 2, by 0.02 between 2 and 3 and so on. I'm really new to VBA and after a few hours I came up with the following code which works fine till the value of 6 and then gets stuck: ....

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I'm developing a local timesheet userform application and want to capture times which may be greater than 24hrs using a textbox/spinbutton pairing.

I've managed to pair up and work with times up to 24hrs but the output always resets after 23:55.

I've also tried formatting the output as "[h]:mm" but without success.

Private Sub sbDTime_SpinUp()

With ctrl2
If .Text = vbNullString Then
.Text = Format(TimeSerial(0, 5, 0), "hh:mm")
.Text = Format(TimeValue(.Text) + 5, "hh:mm")
End If
End With
End Sub

Private Sub sbDTime_SpinDown()
With ctrl2
If .Text = vbNullString Then
.Text = Format(TimeSerial(0, 5, 0), "hh:mm")
.Text = Format(TimeValue(.Text) + 5, "hh:mm")
End If
End With
End Sub

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For example, if my graph currently shows B1:L1 range, how by clicking a spin button to make the graph show B2:L2 range?


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Feb 17, 2010

I have an Active X SpinButton control directly on a spreadsheet that changes the input cell. (The idea is that later on, there'll be a bunch of these input cells, accompanied by their respective SpinButton controls).

I'm allowing the user to define the Min, Max, and Step (SmallChange) value of the SpinButton because (1) I need it to do decimal points and negative numbers and (2) that's what my boss would have wanted.

So I set the Min, Max, SmallChange value in the SpinButton properties to "0" then try to manipulate them in the VBA code.

What went wrong with the code is hard to explain. But basically, when I use the SpinButton to increment or decrement, it didn't quite do it correctly. If I fix the increment part of code, then the decrement part of the code goes wrong and vice versa.

An example: I have Min as "0.5%" in cell B7; Max as "4.5%" in cell B8; and Step (SmallChange) as "0.5%" in cell B9. The Input cell is in cell B10 where user can either type in a value within the defined range (enforced by data validation) or use the SpinButton to change the value.

To replicate the problem: I type in "1.0" in the Input cell and click on the left SpinButton and it would not allow me to go to the defined lower limit (which is 0.5%) in this case.

Here are my codes:

Private Sub SpinButton1_SpinUp()

Dim MyMax As Variant
Dim MyStep As Variant
Dim MyInput As Variant

MyMax = SpinButton1.Max + Range("B8").Value
MyStep = SpinButton1.SmallChange + Range("B9").Value

MyInput = Range("B10").Value...................................

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Private Sub ListBox1_Change()
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Me.Height = 180
End If
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End If
If Me.ListBox1.Value = 3 Then
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I have tried using click/after change events however I get the same response. Am I missing something from my code or should I be using another control (SpinButton for instance).

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[Code] ......

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solve this problem using either formulas or code

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