SpinButton For Images Control

Sep 28, 2009

The script it's almost all complete and it'already working. How works this script:
From the Combobox_click i load a txt file, the script from the txt file get only the first column of the file. Its a list of numbers.

When this list of code numbers it's loaded in the Combobox_click, for each code number in the image combo box there is a one corrisponding image. For the images folder in the cell J2 the is a one Path reader. the scrip work perfectly.

What i need:

As you can see, under the image combo box, there is a SpinButton.
I need that by clicking the Forward or Back button i can go forward or back of the images list.

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When I protect the worksheet with the spinbutton, the spinbutton is no longer accessible. How can I modify the code below (provided by Leith Ross) to make the spinbutton accessible in a protected sheet?

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I have a spinbutton on a userform. Here is the section of code for SpinUp:

[Code]....

Normally, I wouldn't hard code an address in like this, but I was given a last minute project to present on Monday, so it's down,dirty, and quick. Anyways, the adjacent cell "O7" has a formula referencing another page. When I spin the spinner it activates the correct cell (and continues to do so as long as I press the button), but here's the wierdness: cell "07" formula disappears, leaving the existing value in it. It's like it copy pastespecial values.

I've stepped through the code and it's not referencing any other procedure. It happens on this line:

[Code] ....

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Private Sub SpinButton1_SpinDown()
Range("C7").Value = Range("C7").Value - 0.05
End Sub

Private Sub SpinButton1_SpinUp()
Range("C7").Value = Range("C7").Value + 0.05
End Sub

Private Sub SpinButton2_SpinDown()
Range("C8").Value = Range("C8").Value - 0.05
End Sub......................................................

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Private Sub Worksheet_SelectionChange(ByVal Target As Range)
Dim lNum As Long
If IsNumeric(Target) Then
lNum = Target
If lNum = Target And Target >= 0 Then
With Me.Shapes("1").ControlFormat
.LinkedCell = vbNullString
.Value = Target
.LinkedCell = Target.Address
End With
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Me.Shapes("1").ControlFormat.LinkedCell = vbNullString
End If
End If
End Sub

The problem is, that whenever I click or activate a cell its value automatically changes to 0. The spinner works just fine modifying the value of the activated cell. The problem is that this code somehow causes all the decimals such as 0,3 0,1 or 0,8, entered manually, to change to 0. This way only integral numbers, such as 1, 45 or 100 are accepted. I must truly say I have no [no need to swear - mod] idea how to fix these problems meaning the automatically inserted 0 and the fact that the sheet doesnít accept decimals changing them to an integral number.

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[URL]

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I've also tried formatting the output as "[h]:mm" but without success.

Private Sub sbDTime_SpinUp()

With ctrl2
If .Text = vbNullString Then
.Text = Format(TimeSerial(0, 5, 0), "hh:mm")
Else
.Text = Format(TimeValue(.Text) + 5, "hh:mm")
End If
End With
End Sub

Private Sub sbDTime_SpinDown()
With ctrl2
If .Text = vbNullString Then
.Text = Format(TimeSerial(0, 5, 0), "hh:mm")
Else
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...

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What went wrong with the code is hard to explain. But basically, when I use the SpinButton to increment or decrement, it didn't quite do it correctly. If I fix the increment part of code, then the decrement part of the code goes wrong and vice versa.

An example: I have Min as "0.5%" in cell B7; Max as "4.5%" in cell B8; and Step (SmallChange) as "0.5%" in cell B9. The Input cell is in cell B10 where user can either type in a value within the defined range (enforced by data validation) or use the SpinButton to change the value.

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Here are my codes:

Private Sub SpinButton1_SpinUp()

Dim MyMax As Variant
Dim MyStep As Variant
Dim MyInput As Variant

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