String Value Sum Function Vba
Jan 26, 2007
I have a Sum function in a cell on a spreadsheet and a bit of code which checks it using an If statement. If the Sum equals 1 (100%) it should do one thing, if not do another. However, if I put in the If statement that the Sum cell value should equal 1, it doesn't work. If I put it should equal "1", it does work. Why?
Example that works:
If Range("LocalBirthTypes").Value <> "1" Then
MsgBox "To use your own data the split between the birth types must total 100%", vbExclamation, "Maternity service planning tool"
Goto Exiting
End If
Example that doesn't work:
If Range("LocalBirthTypes").Value <> 1 Then
MsgBox "To use your own data the split between the birth types must total 100%", vbExclamation, "Maternity service planning tool"
Goto Exiting
End If
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Oct 13, 2009
On sheet 1 I have a list of 1000 firstnames
On sheet 2 I have a list of 1000 emails,
I need a function that states If a cell in the email column contains a string or value from the names column, it will result in a true statement so that I can separate out the emails that have these peoples first names.
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Jan 5, 2009
i have a question regarding the right function. can you use a string within the function. i know that the function is written =right(A3,2). is it possible to write the function as =right(a3:z3,2). i keep geting an error with this function
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Feb 26, 2014
I'm trying to create a formula to return the number of cells where the last 8 characters of a cell end with the string "landline"
My (failed) attempt at creating this is as follows:
=COUNTIF RIGHT(A2:A322,8)="Landline"
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Oct 19, 2009
I am trying to make a function to take 3 Cells and using the initial Cell(say A1 with value of 100) as the inital value of a sum. Take Cell two(say A2 with value of 10) and add the value of A1 to Value of A2 in a constant increase. In otherwords A1+A2*A3= next increase. A3 is the value I want to change. But I want to add these values together as many times as the value of A3. so with current numbers will be 100+110+120+130+140 with A3 being a value of 5.
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Mar 7, 2014
I would like to express an empty string with the expression .
[Code] .....
=if(D6='';0;1)"
[Code] ....
but I have an error message.
I don't know what is the error?
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Jun 10, 2014
I try to merge two sting (one from function). the output of the following sub should be "ttgood". but instead, i got "good" only.
Code:
Function cs()
Dim sv As String
sv = "tt"
End Function
Sub ts()
Dim s As String
s = sv & "good"
MsgBox s
End Sub
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May 3, 2007
I have a problem when using the function of text(). I set "=TEXT(SUM(A1:A5), 0) + 5" in Cell A6. Assume the answer of SUM(A1:A5) is 10, the result in A6 will be 15.
My question is how to prohibit a string value [Text(SUM(A1:A5),0)] add a number value [5] to form the result 15.....
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Dec 18, 2008
I know I have to use FIND and MID but I can't work out the right syntax: how do I extract Michael or Dave from the following strings:
F - Michael 8735
M - Dave 093
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Feb 21, 2009
Cell A1 contains 012345678 ** Customer of 987654321 **
Cell B2 contains 087654321
My formula =MID(A1,FIND("of",A1)+2,10) works perfect if it has a "customer of...". How to revise my formula that when it gets to cell B2 and if there is no "** Customer of ..." it would leave it blank or zero rather than #Value!?
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Feb 8, 2007
The following concatenate function was working, then mysteriously stopped. When working it returned the data that I requested, now if I click on any concatenated cell and hit enter I get the function string, see below.
='Input DATA'!C2&" "&'Input DATA'!B2&" "&'Input DATA'!F2
InputData is my tab that is being referenced. All other functions/formulas are working as designed. The data in the referenced cells is still there and I changed from text to number to general, etc but I still get the same result.
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Apr 11, 2007
I do not know if this is possible in VBA, but I am hoping it is as it will make my life much easier.
Is it possible to say have a TextBox and a CommandButton, that does the following?
Public Sub Execute()
Dim ObjectName As String
Dim Object As Object
ObjectName = txtObject.Text
Set Object = ObjectName
Object.Execute
End Sub
Or to take it a step further:
Public Sub Execute()
Dim ObjectName As String
Dim FunctionName As String
Dim Object As Object
ObjectName = txtObject.Text
FunctionName = txtFunction.Text
Set Object = ObjectName
Object.FunctionName
End Sub
Are there any inbuilt functions that will create/reference an object based on a string containing the name of the object or function?
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Apr 10, 2008
I have a series of codes, such as:
xxx-xxx-xx/xy-xxx
yy-yy-yy/yz
zzz-zz/za-zz/za-zzz
The /'s represent variations on the same code, so the first one is shorthand for:
xxx-xxx-xx-xxx
xxx-xxx-xy-xxx
I would like to be able to split the code into a new line (or lines) wherever a / occurs.
There are any number of dashes and slashes within the code, however, there are none at the beginning or end of the code.
The slashes will be always surronded by dashes eg xxx-xx/xy-xxx.
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Oct 1, 2008
I have a string that I need to sort.
Below code works beautifully but doesn't sort numbers, any advice to get this to sort numbers as well?
Function Alphabetize(ByVal sText As String) As String
Dim sWords() As String, sTemp As String
Dim i As Long, j As Long, n As Long
'-- clean up text
For i = 1 To Len(sText)
Select Case Mid$(sText, i, 1)
Case " ", "a" To "z", "A" To "Z"
Case Else: Mid$(sText, i, 1) = " "
End Select
Next
'-- remove leading and trailing spaces....................
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Dec 3, 2009
My knowledge of functions is pretty limited, or negligible to be honest. I require a function to extract numbers from each cell in a selected range.
Eg.
cells contain the following data:
cell 1: xxxxxx 45,59
cell 2: x xxxxx xx 6,45,27
cell 3: x xxxx 28
were x represents text
I need to loop through each cell and extract each of the numbers and list them in a separate range. If applied to the above range of cells the function would show the below in the ouput range. Each number in its own cell.
6
27
28
45
45
59
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Sep 28, 2006
The following afterupdate procedure for my txtStart1 text box sends the value to the FormatTimeValue function that is coded in a module.
Private Sub txtStart1_AfterUpdate()
MsgBox Len(Trim(Me.txtStart1.vaue)) '<= outputs 1
Me.txtStart1.Value = FormatTimeValue(Trim(Me.txtStart1.Value))
End Sub
As you can see from the bolded text, the length of the value is 1 when outputted from the forms code.
However, when I pass it to the following function in a module it outputs 2 as the length.
Function FormatTimeValue(vTarget As Integer) As String
Dim TimeStr As String
If IsNumeric(vTarget) Then
MsgBox Len(vTarget) '<= outputs 2
Select Case Len(vTarget)
Case 1 ' e.g., user entered 1 so time should be 01:00
TimeStr = "0" & vTarget & ":00"
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Dec 2, 2013
In the attached workbook i need to take out the % numbers from the text to populate the cells.
the Pay % cell is the % before the / and the receive % is after the /.
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Dec 15, 2013
I am trying to put text form 3 cells into 1 string. I got the 1st 2 but the 3rd I only want to extra the first part of the cell up to the 1st comma. This is what i have so far:
[Code] ......
For example cell E81 would contain "abc, def, ghi" . I want to add to the string above only "abc" and not the entire cell content.
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Jan 28, 2014
I'm trying to come up with a VBA function that would return cell values based on another cell value.
I can do this by comparing a range (column of cells) with the cell value to match and then return the value of the cell next to it.
For instance,
The function should search a column for partial text, as follows:
TS ID
PDT ID
TS 1.1
PDT 1
TS 1.2
PDT 2
TS 1.3
PDT 3
TS 2.1
PDT 4
TS 2.2
PDT 5
TS 3.1
PDT 6
TS 3.2
PDT 7
In the above table, the function should for partial text and return string as follows:
TS covered
PDTs
TS 1.1, TS 1.2, TS 1.3
PDT 1, PDT 2, PDT 3
TS 2.1, TS 2.2
PDT 4, PDT 5
TS 3.1, TS 3.2
PDT 6, PDT 7
So basically I am searching for partial text TS 1. and so on
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Mar 10, 2008
I'm currently working on a spreadsheet (see attached) which will have both numeric and text string data. This will be sorted by calender month and linked to another spreadsheet.
Could someone please list 2 functions for me.
The 1st would allow act like a filter allowing only data to be counted for a selected month from a drop down list.
The 2nd allows a counting of pre-set (drop down list) text strings to be counted.
Sorry seems a bit complicated and really I should have either a created a pivot report or used access but I'd like to continue with Excel for this exercise.
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Sep 11, 2012
Is it possible to create a string with a range of numbers
1
3
4
5
6
8
10
Result: 1,3:6,8,10
Or
1
2
3
4
Result: 1:4
Or
1
3
5
7
Result: 1,3,5,7
Where consecutive numbers are separated by a ":" and other numbers by a ",". I use the following function to create the ","-concatenate, but I don't know how to create the ":"-ranges.
Function AConcat(a As Variant, Optional Sep As String = "") As String
'By Harlan Grove, March 2002
Dim Y As Variant
If TypeOf a Is Range Then
For Each Y In a.Cells
[Code] .........
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Mar 12, 2008
Is there a function in VBA that is similar to either the FIND function or SEARCH function in Excel? The arguments for the FIND function in Excel are FIND(find_text, within_text, [position]).
I have a text string in VBA ("$A1:$D$13") that I want to be able to identify the first "$" and then later the ":". I'm getting tripped up on the 3rd line of code. Thanks a million.
Sub page_set_print_area()
ActiveSheet.PageSetup.PrintArea = "$A$1:$D$13"
x = ActiveSheet.PageSetup.PrintArea
Position$ = Search("$", x, 0)
End Sub
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May 13, 2008
I wrote this function to see if a user selected string contained certain phrases. It keeps returning united states so i am guessing its not cycling through the entire list.
Function region2(searchString As String)
Dim result As String
result = "None"
Dim lng() As String
lng = Array("arabic", "belg", "bul", "czech", "dan", "dut", "dutch", "euro", "finnish", "french", "ger", "greek", "greenland", "hebrew", "hung", "iceland", "international", "ital", "nor", "pol", "portu", "russ", "slov", "spanish", "swe", "swi", "turk", "UK", "united kingdom", "states")
Dim Country() As String..........
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Jun 23, 2006
I have a spreadsheet with 2 sheets. The first just links to another file and pulls in the contents of a particular sheet, cell for cell. The second sheet is a formatted report that I'm creating to put that data into a different format for presenting to others. I'm using the Index and Match function along with range names. All is fine except where the string that should be returned is very long. When that happens, I get "######" all the way across the cell. It doesn't matter how wide I make the column or how tall I make the row, the "#s" do not go away. Is there a limit on the number of characters the Index function can return?
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Aug 6, 2012
I have a column A with following values below:
Column A
"VL50s"
"M50s"
"H50s"
"VL50s"
"H50s"
I would like to extract the numbers and run the following arithmetic function below into column B.
key:
x is a number
VLx --> (x) + 1
Mx -->(x) + 2
Hx --> (x) + 3
the output should look like the following using the key above:
column B
51
52
53
51
53
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Nov 4, 2012
I don't have to keep using the ridiculous Substitute() work-around when I need to grab cell text after the nth instance of a character. In doing data cleanup I'm constantly having to grab text between, say, the 4th space character and the 6th one. Since Search() doesn't have an instance parameter, I end up having to use the 'Substitute trick', since it's the only string function that does have one.
See below for a typical example of the convoluted formula I need, and another example of it if Search only had 'instance' available. Simplifies the formula quite a bit.
*Typical real example, here to find the word between the 4th and 5th spaces in A1:
"=MID(A1, SEARCH("^", SUBSTITUTE(A1, " ", "^", 4)),
SEARCH("^", SUBSTITUTE(A1, " ", "^", 5))-SEARCH("^", SUBSTITUTE(A1, " ", "^", 4)))
Fantasy, 'fixed' example after MS adds instance:
=MID(a1, SEARCH(" ", a1, [instance #4]), SEARCH(" ", a1, [instance # 5])-SEARCH(" ", a1, [instance # 4]))
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Feb 26, 2007
I found what looks to be a BASIC or perhaps early C form of code that will do exactly this, however I am finding it out of my grasp to 'convert' the below code over to VB for Excel, and I was hoping someone would be able to piece it together for me. Code128B is a barcode font that requires a 'computed' start and end bit, as well as a checksum character(s) in order for the barcode to be valid and readable by barcode scanners. This code (in whatever it is written, I don't really know), is said to do just that. Code:..................
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Oct 2, 2006
i did some VBA quite a while back, and picking it up again.
I'm trying to get a function to read in a string, and return a value based on the string value.
Public Function value(ItemType As String) As Integer
If ItemType = " Upper" Then
value = 40
ElseIf ItemType = "Middle" Then
value = 50
ElseIf ItemType = "Lower" Then
value = 25
End If
End Function
When i tried using it at the Cell level, it keep giving error i.e. Invalid Name Error
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Feb 19, 2014
I need a VBA function to extract number sequences from a string and separate them with hyphens In the example below cell A1 has the value 'xx2 yyy34 zz515' The code must produce the value '2-34-515' from the above example I have the following function that extracts the numbers but need a way to separate the groups with a hyphen
Code:
Function parseNum(strSearch As String) As String
Dim i As Integer, tempVal As String
For i = 1 To Len(strSearch)
[Code]....
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Sep 19, 2012
I have a udf that returns a string to the cell. The string is made up of multiple string "objects". What I am wondering is if I can set the font color of certain objects so that when the final string is built and returned, the font of those portions is set.
Ex. of simple idea (this is not actually my code, just a way to illustrate. I realize there is no point to this UDF):
VB:
Function StringReturn (Str1 As String, Str2 As String, Str3 As String) As String
StringReturn = Str1 & Str2 & Str3
End Function
Now what if I wanted Str1 and Str3 to be blue, and Str2 to be red for example. So that when the UDF calculates it would return: Str1Str2Str3
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