Using FIND To Locate Second Occurrence Of Character

May 28, 2013

7900 Personnel:7980 PR taxes:7985 Medicare

I can use the FIND function to find the first occurrence of ":" and therefore select everything to the right of it, but how do I locate the second occurrence of ":"?

I want to segregate the 7985 Medicare. What if the data varies, i.e. some rows have one occurrence of ":" and others have two?

7900 Personnel: 7970 Bonus. I always want to segregate the last 4-digit account number and description.

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Find Last Occurrence Of Character In A String

May 23, 2007

I would like to find the position of the last occurrence of a character in a string. For example, I have a string with the following:

"c:wwgpeToolbidsTest File.GP$".

I would like to find out the position of the last '' in the string because I want to pull the filename, 'Test File.GP$' into a variable. I would like to avoid writing code to do this. Are there some Excel functions I can use for this?

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Mar 17, 2009

The purpose of the formula is to locate the 2nd occurrence of an entry where criteria in other columns are met (used to determine whether people can qualify for an item based on attendance and another condition).

I am using this formula but I know it needs some adjustments and can't seem to work it out or maybe am going about it completely wrong.

=IF(COUNTIF(D2:D205,D2)>1,AND(T2="Y",U2="Y")*1,0)

I need the formula to indicate the second occurrence of this cell with the criteria that BOTH first & second occurrences have T2="Y" and U2="Y". My formula only indicates the first occurrence and the first occurrence if T2 and U2 meet the conditions.

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Dec 12, 2012

This is a re-submission of a question previously submitted because the title for the first submission was so poorly worded.

I have a column that has numerical values in random order. I want to locate the first occurance of a value in that column.

I have unsuccessfully tried an Index-Match function - apparently unsuccessful because the values must be in ascending or descending order?

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Aug 24, 2012

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Jun 29, 2008

on the web I've found this formula, which returns the postion of the last occurrence of the character in cell B1 in the string in cell A1:

=MAX((MID(A1,ROW(INDIRECT("A1:A"&LEN(A1))),1)=B1)*ROW(INDIRECT("A1:A"&LEN(A1))))

How do I turn this into a VBA function?

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Jul 30, 2013

I need to remove the first character in each row of a column, but only its first occurrence in each row. For instance:

Say, column 2 has following data (lots of rows, by the way):

First Text" - "blabla"
=SomeText2 = "blabla"
SomeText3 = "blabla"
=SomeText4 = "blabla"
-SomeText5 --- "blabla"
........
....

I would like to use the VBA code to remove ONLY the FIRST occurrence of the FIRST character specified (either "=" or "-") in each row in that column, so that I get:

First Text" - "blabla"
SomeText2 = "blabla"
SomeText3 = "blabla"
SomeText4 = "blabla"
SomeText5 --- "blabla"
......
...and so on...

I tried to use this:

Code:
Columns(2).Cells.Replace What:="-", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
Columns(2).Cells.Replace What:="=", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
but it replaces ALL occurrences of "=" and "-" and that is not what I need.

I also tried this code:

Code:
With Range("B:B")
.Value = Replace(.Value, "=", "", 1, 1)
End With

But It doesn't work either.

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I have a column of text where I need to remove all the characters to the right of the last occurance of a special character.

I think a process like reading from right to left, look for the first occurance of the special character, and return the characters to the left of this position.

If I can determine the position of the last occurance of the special character, I could use the LEFT function.

The SEARCH function is close. It finds the position of the first occurance of text inside text but it reads from left to right. I need to read from right to left.

Another approach is to examine each character one by one from right to left. If the character is not the special character, delete it. When the character is the special character, delete it and stop the process.

There is no consistency in the text. The total lengths vary. The number of times the special character occurs in the text vary. The number of characters to the right or left of the last special character vary.

I much prefer not to have the solution be some VBA because I need to share it with others who are even less capable than I am. We are using Excel 2003.

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Nov 12, 2013

I understand that the function FIND(find_text, within_text, start_num) will find the first occurrence of a stated string. And by adjusting the start_num, you can skip a set number of characters before the search begins.

But, is there a way to find the Last occurrence of said string? In my case the find_text string may occur multiple times in the variable length within_text cell to be searched.

Sample: Find the last occurrence of MDU

Code:
Sample string1 - ABDJ FFU MDU WWW AEH JJF MDU JJI LLK OOI HAHA QWAS
Sample string2 - HFUR MDU HDS IGH RJR KDHF LLDE MDU KKJ MDU GGG

In the above 2 sample strings the output of the Find() function needs to be 26 & 40. Having a cell formula would be desirable, but if it can only be done by VBA that is acceptable, also.

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I cant just use an autofilter, because the row below can and sometimes does appear elsewhere in the spreadsheet, but refers to something else. It is all because this is an imported text file.

I have attached the spreadsheet to show you what I mean.....

here is the code I have so far, modified from another thread I posted.

Sub dogs()
Dim rd As Worksheet, dg As Worksheet, i As Long
Dim fRng As Range, Crit

Application. ScreenUpdating = False

Set rd = Sheets("Pets")
Set dg = Sheets("Dog")

The attached is a very cut down version of my spreadsheet...

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The search is in a single column.

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Set c = .Find(rCell, LookIn:=xlValues, lookat:=xlWhole)
Set c = .Find(rCell, After:=c, lookat:=xlWhole)
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Sub NumberOfReceiptFlowsAfterInitial4()

Dim my_cell As Range
Dim first_one As Double
Dim second_one As Double
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Dim final_total As Double
Dim result As Double

I need something similar to this routine that will find the last occurrence of a cell that contains the value greater than or = 1%.

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I've also attached my project to better understand what I'm trying to accomplish which is the use of a Gantt Chart as an employee scheduler as opposed to a task (or project) scheduler.

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myDynRange = myFirstCell & myLastCell

im having a problem with the last line
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the reason why my range declaration is so strage is because i was trying to change the dimensions of the range with an offset function because i had many ranges to average but the offset function didnt want to work. this way goes like this....................

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Sheets("Summary").Range("A1").FormulaR1C1 = "=COUNTIF(Sheet1!C,""TOTAL"")" ....

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My problem is what happens if the file has the same value more than once. Ideally, I'd like to display a message box that returns the addresses of both cells with the same value and then prompts the user to select one of these values as the value they are looking for. I am not sure if a msgbox or a msgbox and then an input box are most appropriate for this situation. Once the user does this, the macro continues. The rest of my macro is built on the cell where this value is, so it is crucial that I make sure there is at least one value selected. Any help is much appreciated. I have included a sample worksheet of what this situation might look like.

Here is the code I presently have for this part of my macro.

Sub GetOpenFileName()
strFind = InputBox("Please enter the job title you wish to search for:", "Search for job title in this file")

If strFind = vbNullString Then Exit Sub

With Sheets(strSheetsMainCompProfile)
If WorksheetFunction. CountIf(Range(Cells(1, 1), Cells(100, 100)), "*" & strFind & "*") = 0 Then
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At first this looks pretty easy. I just make a sum of all the times they called to 511, then a sum of all time they called to 512 and finally I substract those values and I end up with the correct time spend in the queue.

The problem comes when they call multiple times to 512 without actually logging off. For example, they type the wrong password or simply hang up.

Result is this in the CDR

FROM TO DATE TIME
101 511 23/12 08:34
101 512 23/12 11:58
101 511 23/12 12:34
101 512 23/12 14:45
101 512 23/12 14:47
101 512 23/12 15:00

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Attached a sample worksheet.

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