I did post a problem where I have a number like 123456 and I need to have Excel change it so that it puts a comma before the last two digits .. like so: 1234,56
I got a reply where I got the solution to use 0","00 and this works in Excel (using the custom format)
The only problem is that although the number changes in the cell to 1234,56 it doesn΄t do so in the FX window and thus when I use the number to multiply it is actually 123456 instead of 1234,56 like it want it to be.
I have a macro that takes the column of data from D on Sheet 1, pastes it into A on Sheet 3, gets rid of duplicates and then, in B1, combines all the numbers from A into a comma-separated string. The only problem is that it puts a comma at the beginning of the string. Is there something I can do to make that first comma not be there?
I need to list 4 digit numbers in each section followed by commas, but whatever I do it goes to 3digits (e.g. I need "1234,5678,9123" and as soon as I hit Enter it goes to "123,456,789,123"). It wont work to format as text because I have a whole bunch of 12 digit numbers to break up into 4.
Column A = persons name Column B = number of hours Column C = trade Column D = shift (as in day, night or weekend) Column E = I would like the formula that looks at the trade and time and then puts the correct rate.
I have a little table on the site with trades/times and rates. IF and IF THEN do something
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...). Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay 07 De Wetshof Sauvignon Blanc 07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage 01 Bouchard Finlayson Tete de Cuvee Pinot Noir 07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon 05 DuToitskloof Pinotage/Merlot/Ruby Cabernet 1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay 07 De Wetshof Sauvignon Blanc 07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage 01 Bouchard Finlayson Tete de Cuvee Pinot Noir 07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 2003 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon 05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2))) As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
I wish to get data after the last comma in each row (my data does not have any spaces). So my result would look like this:
432 4 43
I have 2 formula which I feel should do the work:
1. =RIGHT(A1,(FIND(",",A1))) --> However, this is only giving the last 2 characters in the result (including comma). How to fine tune it?
2. =TRIM(RIGHT(SUBSTITUTE(A1,",",REPT(" ",99)),99)) --> works nice and gives exact result. However, this was designed for extracting data from string with spaces, so not sure what trim and substitute would be doing here. How to make it simpler/ reduce its length by chopping off the un-necessary code?
I am working with large sequences of letters and I'm trying to put them into their own columns. I know about the 'text to columns' tool but the problem is my sequences are not delimited by anything. I would have to think the easiest way to accomplish what I want to do is to insert a comma, space or other delimiter between every letter, then use the text to columns feture.
I can't seem to find a way to find the max of only the last four digits of a cell, matching the first 8. As an example:
I have thousands of cells in a column like this, (and I can't add any columns to the sheet), and I have a cell with the first three digits and the second three digits. So, out of all these numbers, I want the MAX of ONLY the numbers with the first 8 digits of "800-123-". Also, the decimal on the end is how many times the number was called, and any the decimal and any number after it is to be ignored. The answer would be "800-123-0024", or "0024", I just need a faster way to find it without searching for it.
But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:
I would like to take the first three digits of column A and do a lookup of column B that would return the corresponding number from column C. For example, if I entered the formula for 103PH, the lookup would find the 103 in column B and return "2775.00" from column C...........
I was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
I have a column with social security numbers, i.e. 555-33-2222 and I need to change to show only the last four digits, i.e. xxx-xx-2222. Can this be done in excel?
I want to have column J with values from column A grouped by the first 9 digits and column J with the totals for these groups. It would look something like this:
I have a column of numbers, all with varying numbers of digits. I want to make them all have only 4 DIGITS in total (regardless of where the decimal is located... so there could be 4,3, 2, 1,or, 0 decimal places). I just want to make everything the same number of digits.
In this worksheet , in Columns B4:F2615, there are rows of digits that range from 1-36, I have a need to find the 10 digits that were drawn togather the most. I have no idea how to do this in Excel or can it be done? ....
I have a pair of digits in col B, that I would like to match with the digits in in col D, and display those matches in col E. If possible I would delete the duplicates in col E, and show results in col F.
I have a formula now that is =right(C2,5)+0 that is working well. However the data has grown and sometimes there is also 6 digits now instead of 5. So I need it to pick up either one 5 or 6. When I change the formula to 6 it works but picks up a / which happens to be before the 5 digit # sequence when there is only 5 digits. It works great for the 6. Is there another way around this so I only get the numbre digits if there are 5 or 6 and not the /. Maybe an if statement. I've tried several ways but none work right. The only other thing I can think of is to get it as above with the =right(C2,6)+0 and then afterwards to a find and replace and remove the / from the data. I was just tryign not to add an extra step to the process. Any ideas please?
Example of the data in coloumn C2 is: 15/2000/4567/NA/NA/97305or with 6 digits at the end15/2000/4567/NA/NA/973052there is always just 5 or 6 digits at the end that I need.
1. Remove the first 4 digits from each "Appeal ID"
2. Insert a new column (first column) called "Chapter"
3. Run a v-lookup down the new column against a file that is stored on my desktop. The v-lookup will cross check the Appeal ID against the file to identify the Chapter
4. Sort the data alphabetically by Chapter
5. Create seperate Excel files for each Chapter ...
I've recorded a macro to replace the Australian telephone number area codes (at the beginning of each phone number) with international dialling codes. I also need to replace the first two digits ONLY of mobile ( cell) phone numbers which, in Australia, all begin with "04" (see last part of macro code below - column L:L).
With the code the way I've recorded it, if it finds "04" in another part of the number (e.g. 0411 104 111), the second occurrence of the "04" will automatically be replaced with "614" as well which I don't want. So I need some code to add so that the macro only searches and replaces those first two digits in that column. I hope I'm making sense?!
Sub ConvPhNo() ' ' ConvPhNo Macro ' Macro recorded 12/12/2007 by xxxxxxxxx '
