Text To A Unique Number
Nov 27, 2008I want to convert a text in a cell into a unique number.
View 9 RepliesI want to convert a text in a cell into a unique number.
View 9 RepliesI am trying to find a formula that will count the number of unique entries there. I have tried the solutions posted on various websites to no avail (most recently:
Code:
=SUM(IF(FREQUENCY(MATCH(A1:A10,A1:A10,0),MATCH(A1:A10,A1:A10,0))>0,1))
).
The answer should be 4,457.
Ticket Number
T20110819.0527
T20110830.0339
T20110901.0060
T20110901.0060
T20110907.0042
T20110907.0042
T20110908.0186
T20110908.0186
T20110908.0186
T20110908.0186
[code].....
I have a list of around 50000 names. I need to count how many are unique.
I have been using this function to count the number of unique text values in a data set:
=SUM(IF(FREQUENCY(MATCH(B2:B10,B2:B10,0),MATCH(B2:B10,B2:B10,0))>0,1))
It works great if I want to count number of unique text values overall. However, I want to count the occurrences of unique text values if they meet specific criteria. (Like a countifs function would if it could count unique text).
If I have multiple entries with different but repeatable text values in one column - how do I count all unique ones ? Is there a function or does it have to be a pivot table of sth ?
View 14 Replies View RelatedI have a large amount of data and I'm trying to count how many unique values I have in one column. I also want to know how many times each duplicate appears. I tried using a pivot table but it's not working for me.
I also tried the following formula: =SUM(IF(FREQUENCY(H:H,H:H)>0,1)) but it's not quite working.
Need to find a way to flag the unique number in column with 641892
2057988-0380121611AAAAA########70002057988-0380121611641892########59262057988-0380121611642176########53442057988-0380121611646570########63032057988-0380121611645812########56232057988-0380121611643573########55912057988-0380121611640502########62482057988-0380121611645723########58592057988-0380121611645818########61662057988-0380121611641295########55712057988-0380121611643574########61452057988-0380121611640079########63042057988-0380121611640450########61252057988-0380121611645494########57392057988-0380121611644573########51832057988-0380121611643595########51842057988-0380121611645404########56442057988-0380121611646669########57812057988-0380121611646890########63052057988-0380121611646013########63022057988-0380121611646755########51822057988-0380121611642278########52732057988-0380121611641892########79262057988-0380121611640787########51802057988-0380121611640774########5426
Client Id Contact No. Unique Contacts 111123 12 3 111123 12 3 221123 2 2 111123 34 3 111123 5 3 221123 1 2 821123 4 1 221123 2 2
I am trying to calculate the number of unique contacts that each client has made. So in the example above Client No. 111123 has made 3 unique contacts - numbers 12,34 and 5.
However I'm not having any luck - as I suspect it will be a fiendish array formulae. Alternatively I'd settle for some VBA.
I want to count the number of unique companies that joined in different months. I have two columns to work with - date [in time stamp/data format] and company name.
DATE
COMPANY NAME
10:42 02/01/14
A
11:33 02/01/14
B
16:14 07/01/14
The results should equal -
Jan 14 - 2
Feb 14 - 2
Mar 14 - 1
The closest I have gotten it to remove duplicates =SUMPRODUCT((B1:B15<>"")/COUNTIF(B1:B15,B1:B15&"")) and to count the months =COUNTIF(A1:A15,"*01/14") but I cant seem to link the two.
I'm wanting some sort of formula to generate a reference number that relates to numbers i put in a cell. i want the end result to look something like this:
Reference number
362 3620001
456 4560001
362 3620002
487 4870001
456 4540002
As you can see id like it to generate a reference number to the number that i input, and also when i input that number twice or three times it picks that up on the reference number also.
I am looking to be able to count if prices have changed between periods
See the example below, I am assuming it is an If statement...
Here is a sample of data that I have:
code name lastname
TS19SylvainBrook
TS19SylvainBrook
TV04ValérieMusoni
TV04ValérieMusoni
VB05BenValiquette
VB05BenValiquette
VB05BenValiquette
VI02IsabelleVanasse
VR07RichardVivo
VR07RichardVivo
VR07RichardVivo
WD01DanyWilliams
WD01DanyWilliams
WD01DanyWilliams
How can I quickly get the total number of employees from a list like this one? the first field is a unique key (1 code per employee)
In this case, the desired result would be 6. (the count function does NOT give the desired result..)
I'm currrently using column I and col J
in col I are all the units of measurement: KG, PKT, BAG
in ColJ is the formula to return:
KG as 9999999
PKT as 8888888
BAg as 7777777
if(i2=kg, 999999999,"false!")
i was thinking of using if....but triple if formulas would be long isn't it?
PART2 of this would be using:
=IF((SUMPRODUCT(--(db!$A$2:$A$36000=$B$1),--(db!$F$2:$F$36000=C$5),--(db!$G$2:$G$36000=C$6),--(db!$E$2:$E$36000=$A7),--(db!$D$2:$D$36000=$B7),db!$I$2:$I$36000))=9999999,"KG","Invalid")
to check 5 values and if it is 999999999 it'll return KG
8888888 PKT
7777777 BAg
I want to paste a list of customers into a sheet and then have a formula that counts the number of customers. So, even if a customer appears 10 times it would only count it once and and continues down the column and counts the next company name and so on. Then it gives me a total of the number of different companies in that column.
View 9 Replies View RelatedI have an excel sheet that has multiple rows for one PO number. I've created a row at the top to calculate all of the unique PO numbers in the sheet. However, I want to create another column that will give each unique PO number it's own ID number starting at 1. For instance:
Column B (PO Number)
4 - Counts unique values in B
219
219
219
220
220
221
222
222
Then in Column C I'd want
1 (unique number for 219)
1 (unique number for 219)
1 (unique number for 219)
2 (unique number for 220)
2 (unique number for 220)
3 (unique number for 221)
4 (unique number for 222)
4 (unique number for 222)
Im trying to lookup the first unique number in a column in a separate workbook and then return the value then the cell below would lookup the next unique number and return the value
91010111112121313700
700
700
7009929921442144218341834185018501892189219181918333433343400
3400
3400
3400347634763534
VBA that autogenerates a unique number when a cell in excel is filled?
View 5 Replies View RelatedI found the following formula online while searching for how to count unique instances of a number in a list. The list may have blank cells or repeated numbers but this formula works. =SUMPRODUCT((A1:100<>"")/COUNTIF(A1:A100,A1:A100&""))
So my question is...can someone verbally explain just exactly what is going on? i.e. I don't understand the <>"" in the sumproduct argument or the &"" in the second argument of the countif.
I would like a function that checks an input number to see if it contains unique digits. If the digits are unique the output is 1 else the output is -1. Thus, supposing we call the function UNIQ(), we find UNIQ(15423) = 1 but UNIQ(154532) = -1. The input is always a positive integer.
View 7 Replies View RelatedI am looking for an efficient solution to the following problem. I have a sales table with two columns, titled C1 and C2. The first column lists the product sold, and the second column lists the associated customer.
Here's what I mean (though I can't figure out how to create neat columns in this post):
[C1] [C2]
Prod1 CharlieCo
Prod3 AlphaCorp
Prod2 BetaInc
Prod3 BetaInc
Prod1 AlphaCopr......................
On worksheet1 I have the following
joe | apple
joe | pear
joe | lettuce
joe | orange
tom| apple
tom| lettuce
abe| apple
abe| orange
abe| lemon
On worksheet2 I would like
apple | 3
pear | 1
lettuce | 2
orange | 2
lemon | 1
The file which I want to send as a CSV needs to be named in a certain way. It would be the contents of cell A2, then the date it was sent and the time. Here is my current code. How can I get it to pick up data from a cell and then add it to the list. Also, the list has to be one string, so for example, 23459 Cell A2, 1310 Date and 192859 would be time. So the renamed file would be named 234591310192859. Here is my code which may make what I'm saying a bit more into a bit more sense. Currently the name which is outputted is 'Name of Spreadsheet.xls 13-Jan-10 19-31-59'.
View 6 Replies View Relatedi'm currently trying to count the number of unique numbers in a Column using this formula:
=SUMPRODUCT((A3:A3002<>"")/COUNTIF(A3:A4002;A3:A3002&""))
So far so good.....But I want to add some conditions like only count the numbers that meet the condition say N1:N3000="SE*"
=SUMPRODUCT((A1:A3000<>"");(AND(OR(N1:N3000="SE*";N1:N3000="INC*")/COUNTIF(A1:A3000;A1:A3000&""))))
On this one I get #VALUE! and i can't figure out why.
I have also tried to put the AND/OR condition before the actual starting of the array of the SUMPRODUCT but nothing.
I am trying to count the number of unique items in a single column (~5,000 rows of data). For example, I may have the following data
a1 = apples
a2 = pears
a3 = oranges
a4 = apples
a5 = apples
a6 = apples
a7 = pears
in this case number of uniques items is 3
Right now I am using a Pivot Table to figure out the number of unique items but I am sure there is an easier way to do this.
Column A = numerical IDs, multiple entries, may have duplicates that should only be counted once in comparison
Column B = numerical IDs, multiple entries, may have duplicates that should only be counted once in comparison
Need: 1 cell that compares all of the A range to all of the B range and returns a a percentage of repeats. So, if there are 50 entries in A, and only 40 are unique, and B includes 10 repeats (unique, not multiple), then the returned value would be 25%.
Is it possible to add letters to this "Unique random number" generator it is very fast and takes only 5s to run on 50,000 rows, I have a different "Unique random Sequence generator" macro but it takes about 30 minutes to run on 50,000 rows
Code:
Sub generateuniquerandom()
Dim b() As Boolean, e As Range, k&, x&
Dim lRow As Long
With Sheets(1)
lRow = .Range("F" & .Rows.Count).End(xlUp).Row
[Code]...
I'm needing to generate a unique random value for a database with 3546 cases. The unique random values cannot be duplicates of each other. I tried the =RANDLOTTO function that I learned of in an old post on this board, but that results in "#NAME?" appearing in the first cell. I tried to install the Add-Ins (both the Analysis ToolPak and the Analysis ToolPak - VBA, but nothing seems to happen. Is there another way to generate these numbers?
View 9 Replies View Relatedhow to calculate the number of unique entries in a column? I have a column of email addresses and i would like to know how many of them are unique.
View 9 Replies View RelatedI have a column where I have record numbers. The record number can end up duplicate in some cells.
PROBLEM_ID
IBM-02204732
IBM-03252238
IBM-03252238
IBM-03335648
IBM-03534918
IBM-03534918
IBM-03862015
IBM-03862015
IBM-12737629
IBM-12737629
IBM-17269762
I would like the get a formula that can count the number of unique numbers in that column?
I would like to get if possible to get a formula that summarize the number into a single cell.
I run a report that dumps from data from an ERP system. I've attached a sample of this report in excel that has two sheets. A summary and the data.
I am able to report on the total number of Purchase order lines and total purchase orders using various formulas. I am also able to use formulas to report on the number of lines associated with each product in the I column.
However I cannot, how to calculate the number of unique Po# (B Column) numbers based on the Product (I Column) .....